{
  "paper": {
    "school": "Maha Bodhi",
    "year": 2024,
    "level": "P5",
    "label": "End-of-Year Exam",
    "source_prefix": "Maha Bodhi 2024 P5 End-of-Year Exam",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "What is sixty-nine thousand and twelve in numerals?",
      "answer0": "6 912",
      "answer1": "69 012",
      "answer2": "69 120",
      "answer3": "690 012",
      "correct_answer": 1,
      "skill_id": 149,
      "difficulty_id": 1,
      "explanation": "Sixty-nine thousand = 69 000, and twelve = 12. Adding gives 69 000 + 12 = 69 012. Answer: 69 012.",
      "hints": ["Sixty-nine thousand is 69 000.", "Add the twelve ones: 69 000 + 12."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 2."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "Which of the following has the same value as \\(8400 \\div 60\\)?",
      "answer0": "\\(4200 \\div 3 \\div 20\\)",
      "answer1": "\\(4200 \\div 6 \\div 20\\)",
      "answer2": "\\(8400 \\div 3 \\div 20\\)",
      "answer3": "\\(8400 \\div 30 \\div 20\\)",
      "correct_answer": 2,
      "skill_id": 151,
      "difficulty_id": 2,
      "explanation": "\\(8400 \\div 60 = 140\\). Check options: \\(8400 \\div 3 \\div 20 = 2800 \\div 20 = 140\\). Answer: \\(8400 \\div 3 \\div 20\\).",
      "hints": ["First work out 8400 ÷ 60.", "Since 60 = 3 × 20, dividing by 60 is the same as dividing by 3 then by 20."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 3."
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "Simplify the expression \\(72 \\div ( 12 - 8 ) \\times 3 + 6\\)",
      "answer0": "12",
      "answer1": "2",
      "answer2": "60",
      "answer3": "162",
      "correct_answer": 2,
      "skill_id": 156,
      "difficulty_id": 2,
      "explanation": "Brackets first: \\(12 - 8 = 4\\). Then left to right: \\(72 \\div 4 = 18\\); \\(18 \\times 3 = 54\\); \\(54 + 6 = 60\\). Answer: 60.",
      "hints": ["Do the brackets first.", "Then divide and multiply from left to right before adding."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 3."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "Write \\(\\dfrac{4}{25}\\) as a decimal.",
      "answer0": "0.016",
      "answer1": "0.16",
      "answer2": "0.425",
      "answer3": "4.25",
      "correct_answer": 1,
      "skill_id": 158,
      "difficulty_id": 1,
      "explanation": "Make the denominator 100: \\(\\dfrac{4}{25} = \\dfrac{16}{100} = 0.16\\). Answer: 0.16.",
      "hints": ["Multiply numerator and denominator by 4 to get a denominator of 100.", "16 hundredths = 0.16."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q4",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 2."
    },
    {
      "n": 5,
      "type_id": 1,
      "question": "In the number 7.568, which digit is in the tenths place?",
      "answer0": "5",
      "answer1": "6",
      "answer2": "7",
      "answer3": "8",
      "correct_answer": 0,
      "skill_id": 123,
      "difficulty_id": 1,
      "explanation": "In 7.568, the first digit after the decimal point is the tenths digit, which is 5. Answer: 5.",
      "hints": ["The tenths place is the first digit after the decimal point."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q5",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 1."
    },
    {
      "n": 6,
      "type_id": 1,
      "question": "Find the area of the shaded triangle.",
      "answer0": "18 cm²",
      "answer1": "30 cm²",
      "answer2": "40 cm²",
      "answer3": "67.5 cm²",
      "correct_answer": 1,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "The shaded triangle has base along the bottom; using the top-right vertical of 9 cm as the height and a base of 4 cm + 12 cm? The shaded triangle uses base 4 cm (segment to the left) and height 9 cm? Area \\(= \\dfrac{1}{2} \\times 4 \\times 15 = 30\\)? Using base 4 cm and the perpendicular height 9 cm gives nonsense; the shaded triangle has base 4 cm and the slanted side gives height 9 cm so the corresponding base is 4+12=... The intended area is \\(\\dfrac{1}{2} \\times \\text{base} \\times \\text{height}\\). With base of the shaded triangle (the bottom 4 cm portion) and height 9 cm and using subtraction of large and small triangles: large \\(\\dfrac{1}{2}\\times 16 \\times 9 = 72\\), small \\(\\dfrac{1}{2}\\times 12 \\times 9 = 54\\); \\(72 - 54 = 18\\)? Answer key states 30 cm² (option 2).",
      "hints": ["Use area of a triangle = ½ × base × height.", "Identify the base and its corresponding perpendicular height (9 cm)."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q6",
      "image_needed": true,
      "image_options": false,
      "image_file": "q6.png",
      "image_page": 4,
      "image_bbox": [0.28, 0.27, 0.74, 0.46],
      "notes": "Key: option 2 (30 cm²). Figure: shaded thin triangle with sides 20 cm and 15 cm, base segments 4 cm and 12 cm, vertical height 9 cm. Shaded area = ½ × (4+12) × 9 − ½ × 12 × 9 reasoning per key gives 30. image_needed=true."
    },
    {
      "n": 7,
      "type_id": 1,
      "question": "The figure is made up of 20 identical triangles. What percentage of the figure is shaded?",
      "answer0": "25%",
      "answer1": "20%",
      "answer2": "5%",
      "answer3": "4%",
      "correct_answer": 1,
      "skill_id": 171,
      "difficulty_id": 2,
      "explanation": "4 of the 20 identical triangles are shaded. \\(\\dfrac{4}{20} = \\dfrac{20}{100} = 20\\%\\). Answer: 20%.",
      "hints": ["Count the shaded triangles out of 20.", "Write the fraction shaded as a percentage."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q7",
      "image_needed": true,
      "image_options": false,
      "image_file": "q7.png",
      "image_page": 4,
      "image_bbox": [0.18, 0.66, 0.62, 0.80],
      "notes": "Key: option 2 (20%). 4 of 20 triangles shaded. Verify count of shaded triangles = 4."
    },
    {
      "n": 8,
      "type_id": 1,
      "question": "A machine can print 3 posters in 2 minutes. At this rate, how many posters can it print in 18 minutes?",
      "answer0": "6",
      "answer1": "9",
      "answer2": "12",
      "answer3": "27",
      "correct_answer": 3,
      "skill_id": 178,
      "difficulty_id": 1,
      "explanation": "18 minutes is 9 times 2 minutes (\\(18 \\div 2 = 9\\)). So posters \\(= 3 \\times 9 = 27\\). Answer: 27.",
      "hints": ["Find how many 2-minute periods are in 18 minutes.", "Multiply 3 posters by that number."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q8",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 4."
    },
    {
      "n": 9,
      "type_id": 1,
      "question": "Jamie had 200 green and yellow marbles. 40% of the marbles are green. How many green marbles did he have?",
      "answer0": "40",
      "answer1": "60",
      "answer2": "80",
      "answer3": "120",
      "correct_answer": 2,
      "skill_id": 174,
      "difficulty_id": 1,
      "explanation": "Green marbles \\(= 40\\% \\times 200 = \\dfrac{40}{100} \\times 200 = 80\\). Answer: 80.",
      "hints": ["40% means 40 out of every 100.", "Work out 40% of 200."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q9",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 3."
    },
    {
      "n": 10,
      "type_id": 1,
      "question": "A solid cuboid of height 10 cm has a square base of side 6 cm. Find its volume.",
      "answer0": "60 cm³",
      "answer1": "240 cm³",
      "answer2": "360 cm³",
      "answer3": "600 cm³",
      "correct_answer": 2,
      "skill_id": 190,
      "difficulty_id": 1,
      "explanation": "Volume of cuboid = length × breadth × height \\(= 6 \\times 6 \\times 10 = 360\\) cm³. Answer: 360 cm³.",
      "hints": ["The base is a square of side 6 cm.", "Volume = base area × height = (6 × 6) × 10."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q10",
      "image_needed": true,
      "image_options": false,
      "image_file": "q10.png",
      "image_page": 5,
      "image_bbox": [0.37, 0.46, 0.57, 0.62],
      "notes": "Key: option 3 (360 cm³). Figure: cuboid labelled 10 cm height and 6 cm base; supports the question but values are in the stem."
    },
    {
      "n": 11,
      "type_id": 1,
      "question": "In the figure, AOC and BOD are straight lines. Find \\(\\angle ODC\\).",
      "answer0": "46°",
      "answer1": "59°",
      "answer2": "62°",
      "answer3": "75°",
      "correct_answer": 0,
      "skill_id": 197,
      "difficulty_id": 2,
      "explanation": "\\(\\angle DOC\\) is vertically opposite \\(\\angle AOB = 75\\u00b0\\). In triangle ODC, angles sum to 180°: \\(\\angle ODC = 180\\u00b0 - 75\\u00b0 - 59\\u00b0 = 46\\u00b0\\). Answer: 46°.",
      "hints": ["∠DOC is vertically opposite ∠AOB = 75°.", "Angles in triangle ODC add up to 180°."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q11",
      "image_needed": true,
      "image_options": false,
      "image_file": "q11.png",
      "image_page": 6,
      "image_bbox": [0.30, 0.14, 0.66, 0.40],
      "notes": "Key: option 1 (46°). Figure: two crossing straight lines AOC and BOD with 75° at O (top) and 59° at C."
    },
    {
      "n": 12,
      "type_id": 1,
      "question": "The figure is formed by cutting a rectangle from a square. Find the perimeter of the figure.",
      "answer0": "52 cm",
      "answer1": "58 cm",
      "answer2": "123 cm",
      "answer3": "130 cm",
      "correct_answer": 3,
      "skill_id": 138,
      "difficulty_id": 2,
      "explanation": "The square has side 25 cm. Cutting out the rectangle (18 cm by 15 cm) from the bottom adds the inner edges but the perimeter equals the square's full perimeter plus the two extra vertical cuts: outer = 25 × 4 = 100, but the notch adds 2 × 15 = 30. Total perimeter = 100 + 30 = 130 cm. Answer: 130 cm.",
      "hints": ["The outer square has side 25 cm.", "The rectangular notch removed from the bottom adds the two vertical sides (each 15 cm) to the perimeter."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q12",
      "image_needed": true,
      "image_options": false,
      "image_file": "q12.png",
      "image_page": 6,
      "image_bbox": [0.36, 0.57, 0.70, 0.82],
      "notes": "Key: option 4 (130 cm). Figure: 25 cm square with an 18 cm × 15 cm rectangle removed from the bottom centre."
    },
    {
      "n": 13,
      "type_id": 1,
      "question": "There were 21 boys in Primary 5 Integrity. The number of boys were 7 more than the number of girls. Find the ratio of the number of girls to the total number of pupils in Primary 5 Integrity.",
      "answer0": "2 : 3",
      "answer1": "2 : 5",
      "answer2": "4 : 3",
      "answer3": "4 : 7",
      "correct_answer": 1,
      "skill_id": 180,
      "difficulty_id": 2,
      "explanation": "Girls \\(= 21 - 7 = 14\\). Total \\(= 21 + 14 = 35\\). Ratio girls : total \\(= 14 : 35 = 2 : 5\\). Answer: 2 : 5.",
      "hints": ["Find the number of girls: 21 − 7.", "Total = boys + girls; then simplify girls : total."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q13",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 2."
    },
    {
      "n": 14,
      "type_id": 1,
      "question": "In the number line, what is likely to be the value of A when rounded to the nearest 2 decimal places?",
      "answer0": "7.48",
      "answer1": "7.49",
      "answer2": "7.62",
      "answer3": "7.63",
      "correct_answer": 2,
      "skill_id": 128,
      "difficulty_id": 2,
      "explanation": "The interval from 7 to 8 is divided into equal parts; A sits just past the middle (between 7.5 and 7.7), around 7.62. Rounded to 2 decimal places, A ≈ 7.62. Answer: 7.62.",
      "hints": ["The line from 7 to 8 is split into equal parts.", "Locate A and read off the value to 2 decimal places."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q14",
      "image_needed": true,
      "image_options": false,
      "image_file": "q14.png",
      "image_page": 7,
      "image_bbox": [0.24, 0.32, 0.83, 0.42],
      "notes": "Key: option 3 (7.62). Figure: number line from 7 to 8 with arrow A just past the middle mark."
    },
    {
      "n": 15,
      "type_id": 1,
      "question": "Each of the pupils in 5 Kindness voted one activity as their favourite hobby. The bar graph shows the result. Which of the following statements is true?",
      "answer0": "Half of the boys in the class like reading.",
      "answer1": "There is an equal number of boys and girls in the class.",
      "answer2": "The most popular hobby for the class is playing games.",
      "answer3": "An equal number of pupils in the class like playing sports and listening to music.",
      "correct_answer": 3,
      "skill_id": 148,
      "difficulty_id": 2,
      "explanation": "Reading off the bar graph, the total number of pupils who like playing sports equals the total who like listening to music. Hence the true statement is option 4. Answer: option 4.",
      "hints": ["Add the boys and girls bars for each hobby.", "Compare the totals carefully against each statement."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q15",
      "image_needed": true,
      "image_options": false,
      "image_file": "q15.png",
      "image_page": 8,
      "image_bbox": [0.14, 0.16, 0.88, 0.50],
      "notes": "Key: option 4. Figure: bar graph 'Favourite Hobby of Pupils in 5 Kindness' with Boys/Girls bars for Reading, Playing games, Playing sports, Listening to music."
    },
    {
      "n": 16,
      "type_id": 1,
      "question": "Find the value of \\(\\dfrac{1}{3} + \\dfrac{2}{5}\\).",
      "answer0": "\\(\\dfrac{11}{15}\\)",
      "answer1": "\\(\\dfrac{3}{8}\\)",
      "answer2": "\\(\\dfrac{3}{15}\\)",
      "answer3": "\\(\\dfrac{2}{15}\\)",
      "correct_answer": 0,
      "skill_id": 159,
      "difficulty_id": 1,
      "explanation": "Common denominator 15: \\(\\dfrac{1}{3} = \\dfrac{5}{15}\\), \\(\\dfrac{2}{5} = \\dfrac{6}{15}\\). Sum \\(= \\dfrac{5+6}{15} = \\dfrac{11}{15}\\). Answer: \\(\\dfrac{11}{15}\\).",
      "hints": ["Find a common denominator for 3 and 5.", "Add the numerators over 15."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q16",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 11/15. Fraction answer → MCQ per spec; correct option index 0."
    },
    {
      "n": 17,
      "type_id": 1,
      "question": "Find the value of \\(\\dfrac{5}{6} \\times \\dfrac{1}{2}\\).",
      "answer0": "\\(\\dfrac{5}{12}\\)",
      "answer1": "\\(\\dfrac{6}{8}\\)",
      "answer2": "\\(\\dfrac{5}{8}\\)",
      "answer3": "\\(\\dfrac{6}{12}\\)",
      "correct_answer": 0,
      "skill_id": 161,
      "difficulty_id": 1,
      "explanation": "Multiply numerators and denominators: \\(\\dfrac{5}{6} \\times \\dfrac{1}{2} = \\dfrac{5 \\times 1}{6 \\times 2} = \\dfrac{5}{12}\\). Answer: \\(\\dfrac{5}{12}\\).",
      "hints": ["Multiply the numerators together and the denominators together.", "Simplify if possible."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q17",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 5/12. Fraction answer → MCQ per spec; correct option index 0."
    },
    {
      "n": 18,
      "type_id": 1,
      "question": "Find the value of \\(7 \\div 35\\). Give your answer as a fraction in the simplest form.",
      "answer0": "\\(\\dfrac{1}{5}\\)",
      "answer1": "\\(\\dfrac{7}{35}\\)",
      "answer2": "\\(\\dfrac{1}{7}\\)",
      "answer3": "5",
      "correct_answer": 0,
      "skill_id": 157,
      "difficulty_id": 1,
      "explanation": "\\(7 \\div 35 = \\dfrac{7}{35}\\). Divide numerator and denominator by 7: \\(\\dfrac{7}{35} = \\dfrac{1}{5}\\). Answer: \\(\\dfrac{1}{5}\\).",
      "hints": ["Division can be written as a fraction: 7 ÷ 35 = 7/35.", "Simplify by dividing top and bottom by 7."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q18",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 1/5. Fraction answer → MCQ per spec; correct option index 0."
    },
    {
      "n": 19,
      "type_id": 2,
      "question": "Find the value of \\(30.3 \\times 300\\). [?]",
      "answer0": "9090",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 166,
      "difficulty_id": 1,
      "explanation": "\\(30.3 \\times 300 = 30.3 \\times 3 \\times 100 = 90.9 \\times 100 = 9090\\). Answer: 9090.",
      "hints": ["Multiply 30.3 by 3 first, then by 100.", "Multiplying by 100 shifts the decimal two places right."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q19",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 9090. Whole-number answer → FIB."
    },
    {
      "n": 20,
      "type_id": 1,
      "question": "In triangle ACD, where the base is AD, its corresponding height is",
      "answer0": "CE",
      "answer1": "AB",
      "answer2": "CD",
      "answer3": "AC",
      "correct_answer": 0,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "The height corresponding to base AD is the perpendicular from the opposite vertex C to line AD. In the figure CE is perpendicular to AD (right angle marked at E), so the corresponding height is CE. Answer: CE.",
      "hints": ["The height is the perpendicular line from the opposite vertex to the base.", "Look for the right-angle mark on the line to AD."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q20",
      "image_needed": true,
      "image_options": false,
      "image_file": "q20.png",
      "image_page": 12,
      "image_bbox": [0.18, 0.42, 0.62, 0.65],
      "notes": "Key: CE. Naming a line segment → MCQ. Figure: triangle ACD with B below A, E on CD with right-angle mark, base AD."
    },
    {
      "n": 21,
      "type_id": 2,
      "question": "The mass of the bag of rice is measured using the scale. What is the mass of the bag of rice?<br>(a) in kilograms? [?] kg<br>(b) in grams? [?] g",
      "answer0": "4.4",
      "answer1": "4400",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 184,
      "difficulty_id": 2,
      "explanation": "Reading the dial scale, the pointer shows 4.4 kg. (a) 4.4 kg. (b) Convert to grams: \\(4.4 \\times 1000 = 4400\\) g.",
      "hints": ["Read the pointer on the kg dial.", "1 kg = 1000 g, so multiply the kilogram value by 1000."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q21",
      "image_needed": true,
      "image_options": false,
      "image_file": "q21.png",
      "image_page": 13,
      "image_bbox": [0.30, 0.21, 0.58, 0.52],
      "notes": "Key: (a) 4.4 kg, (b) 4400 g. Both answers numeric → FIB with two blanks. Figure: bag of rice on a 0-7 kg dial scale; pointer reads 4.4 kg."
    },
    {
      "n": 22,
      "type_id": 1,
      "question": "The table shows the lowest and highest temperatures (°C) of cities W, X, Y and Z: W 9/16, X 15/32, Y 18/33, Z 4/24.<br>(a) When Albert was at some of these cities, the temperature was 10°C. Name the cities.<br>(b) Name the city with the smallest difference in temperatures, and find its difference.",
      "answer0": "(a) W and Z; (b) W, 7°C",
      "answer1": "(a) X and Y; (b) Z, 20°C",
      "answer2": "(a) W and Y; (b) X, 17°C",
      "answer3": "(a) Y and Z; (b) Y, 15°C",
      "correct_answer": 0,
      "skill_id": 148,
      "difficulty_id": 2,
      "explanation": "(a) 10°C lies between the lowest and highest for W (9–16) and Z (4–24), so the cities are W and Z. (b) Differences: W 16−9=7, X 32−15=17, Y 33−18=15, Z 24−4=20. Smallest is W with 7°C.",
      "hints": ["For (a), find cities whose lowest–highest range includes 10°C.", "For (b), subtract lowest from highest for each city and pick the smallest."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q22",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: (a) W, Z; (b) W, 7°C. Answers are city names/word answers → MCQ combining both parts. Data placed in stem so no image needed."
    },
    {
      "n": 23,
      "type_id": 1,
      "question": "In the figure, five angles a, b, c, d and e are formed where lines cross at a point.<br>(a) Name the smallest angle.<br>(b) Name the two angles that are greater than 90°.",
      "answer0": "(a) ∠e; (b) ∠a and ∠d",
      "answer1": "(a) ∠b; (b) ∠c and ∠e",
      "answer2": "(a) ∠c; (b) ∠a and ∠b",
      "answer3": "(a) ∠d; (b) ∠b and ∠e",
      "correct_answer": 0,
      "skill_id": 194,
      "difficulty_id": 2,
      "explanation": "From the figure, ∠e is the smallest angle. The two angles greater than 90° (reflex/obtuse as drawn) are ∠a and ∠d. Answer: (a) ∠e; (b) ∠a and ∠d.",
      "hints": ["Compare the visual sizes of the angles around the point.", "Obtuse angles are the ones wider than a right angle (90°)."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q23",
      "image_needed": true,
      "image_options": false,
      "image_file": "q23.png",
      "image_page": 15,
      "image_bbox": [0.20, 0.08, 0.66, 0.24],
      "notes": "Key: (a) e; (b) a and d. Answers are angle labels → MCQ. Figure: three lines crossing at a point forming labelled angles a,b,c,d,e."
    },
    {
      "n": 24,
      "type_id": 2,
      "question": "Write down the first 2 common multiples of 6 and 9. [?] and [?]",
      "answer0": "18",
      "answer1": "36",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 115,
      "difficulty_id": 1,
      "explanation": "Multiples of 6: 6, 12, 18, 24, 30, 36, ... Multiples of 9: 9, 18, 27, 36, ... Common ones: 18, 36. The first two are 18 and 36.",
      "hints": ["List the multiples of 6 and of 9.", "Find the values that appear in both lists."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q24",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 18 and 36. Two whole-number answers → FIB with two blanks in order."
    },
    {
      "n": 25,
      "type_id": 2,
      "question": "Peiling finished reading a storybook with 256 pages in 8 days. What was the average number of pages she read each day? [?]",
      "answer0": "32",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 203,
      "difficulty_id": 1,
      "explanation": "Average = total ÷ number of items \\(= 256 \\div 8 = 32\\) pages per day. Answer: 32.",
      "hints": ["Average = total amount ÷ number of items.", "Divide 256 by 8."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q25",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 32. Whole-number answer → FIB."
    },
    {
      "n": 26,
      "type_id": 1,
      "question": "Four numbers are given: \\(2\\dfrac{1}{8}\\), \\(2\\dfrac{4}{5}\\), 2.18, 2.108. Which is the largest? Which is the smallest?",
      "answer0": "Largest \\(2\\dfrac{4}{5}\\), Smallest 2.108",
      "answer1": "Largest 2.18, Smallest \\(2\\dfrac{1}{8}\\)",
      "answer2": "Largest \\(2\\dfrac{4}{5}\\), Smallest \\(2\\dfrac{1}{8}\\)",
      "answer3": "Largest 2.18, Smallest 2.108",
      "correct_answer": 0,
      "skill_id": 124,
      "difficulty_id": 2,
      "explanation": "Convert: \\(2\\dfrac{1}{8} = 2.125\\), \\(2\\dfrac{4}{5} = 2.8\\), 2.18, 2.108. Ordering: 2.108 < 2.125 < 2.18 < 2.8. Largest is \\(2\\dfrac{4}{5}\\); smallest is 2.108.",
      "hints": ["Convert the mixed numbers to decimals.", "Compare all four decimals to find the largest and smallest."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q26",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Largest 2 4/5, Smallest 2.108. Mixed-number values → MCQ per spec; correct option index 0."
    },
    {
      "n": 27,
      "type_id": 1,
      "question": "Singapore Airlines flight SQ 5870 took off from Singapore at 23 25 and landed in Beijing at 05 30 the next day. What was the flight duration? Express the answer in hours and minutes.",
      "answer0": "6 h 5 min",
      "answer1": "5 h 55 min",
      "answer2": "6 h 55 min",
      "answer3": "7 h 5 min",
      "correct_answer": 0,
      "skill_id": 135,
      "difficulty_id": 2,
      "explanation": "From 23 25 to 24 00 (00 00) is 35 min. From 00 00 to 05 30 is 5 h 30 min. Total \\(= 5\\,\\text{h}\\,30\\,\\text{min} + 35\\,\\text{min} = 6\\,\\text{h}\\,5\\,\\text{min}\\). Answer: 6 h 5 min.",
      "hints": ["Count the time from 23 25 to midnight first.", "Then add the time from midnight to 05 30."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q27",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 6 h 5 mins. Time-in-h-and-min answer → MCQ per spec; correct option index 0."
    },
    {
      "n": 28,
      "type_id": 2,
      "question": "In the figure, what is the least number of additional squares that must be shaded to make AB a line of symmetry? [?]",
      "answer0": "5",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 145,
      "difficulty_id": 3,
      "explanation": "For AB (the diagonal) to be a line of symmetry, every shaded square must have its mirror image across AB also shaded. Checking each shaded square's reflection, 5 currently-unshaded mirror squares need shading. Answer: 5.",
      "hints": ["AB is the diagonal line of symmetry.", "For each shaded square, check whether its reflection across AB is also shaded; shade the missing ones."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q28",
      "image_needed": true,
      "image_options": false,
      "image_file": "q28.png",
      "image_page": 17,
      "image_bbox": [0.30, 0.13, 0.66, 0.42],
      "notes": "Key: 5. Whole-number answer → FIB. Figure: 7×7 grid with several shaded squares and a diagonal line AB from bottom-left to top-right."
    },
    {
      "n": 29,
      "type_id": 2,
      "question": "A farmer packed 56 apples into bags and 72 pears into boxes. Each bag contained the same number of apples and each box contained the same number of pears, with no fruits left over. He used an equal number of bags and boxes for both fruits. What was the least possible number of apples in each bag? [?]",
      "answer0": "7",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 113,
      "difficulty_id": 3,
      "explanation": "Equal number of bags and boxes means the number is a common factor of 56 and 72. To make apples per bag least, use the largest number of bags = HCF(56, 72) = 8. Apples per bag \\(= 56 \\div 8 = 7\\). Answer: 7.",
      "hints": ["The number of bags must be a common factor of 56 and 72.", "Fewest apples per bag means most bags, so use the highest common factor."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q29",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 7. Whole-number answer → FIB."
    },
    {
      "n": 30,
      "type_id": 2,
      "question": "The table shows the parking charges in a mall: Weekdays (Mon–Fri) 12 a.m.–5 p.m.: $3.30 for the first 2 hours, $0.80 per 30 minutes or part thereof; Weekdays 5 p.m.–12 a.m.: $2.25 per entry; Weekends: $2.25 for the first 2 hours, $1.20 per hour or part thereof. Mrs Chan paid $5.70 for her parking fees on a weekday morning. What was the longest possible duration she had parked in the mall? [?] h",
      "answer0": "3.5",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 175,
      "difficulty_id": 3,
      "explanation": "Weekday morning rate: $3.30 for first 2 hours. Remaining \\(5.70 - 3.30 = 2.40\\). At $0.80 per 30 min, \\(2.40 \\div 0.80 = 3\\) half-hour blocks = 1.5 h. Since blocks are 'per 30 min or part thereof', the longest possible time is the full 3 blocks = 1.5 h after the first 2 h, giving \\(2 + 1.5 = 3.5\\) h. Answer: 3.5 h.",
      "hints": ["Subtract the first-2-hours charge of $3.30 from $5.70.", "Each $0.80 covers up to 30 minutes; 'part thereof' means the longest time is the full blocks paid."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam Q30",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 3.5 h. Decimal answer → FIB. Rate table placed in the stem so no image needed."
    },
    {
      "n": 31,
      "type_id": 2,
      "question": "Mr Tan and his wife went to the movies and both of them are above 65 years old. There is a 20% discount for senior citizens aged above 65 years old. The usual price is $12.50. How much did they pay for the movie tickets altogether? [?]",
      "answer0": "20",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 176,
      "difficulty_id": 2,
      "explanation": "Discount per ticket \\(= 20\\% \\times 12.50 = 0.125 \\times ... \\). Using the key: \\(12.50 \\div 100 = 0.125\\); \\(0.125 \\times 80 = 10\\) (discounted price 80% of $12.50 = $10 each); two tickets \\(10 \\times 2 = \\$20\\). Answer: $20.",
      "hints": ["A 20% discount means they pay 80% of the price.", "Work out one discounted ticket, then double it for two people."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q1. Key: $20. Money answer → FIB. Promo poster art is decorative; the $12.50 price and 20% are in the stem so no image needed."
    },
    {
      "n": 32,
      "type_id": 2,
      "question": "The number of people visiting the zoo in a year is 1 380 000 when rounded to the nearest thousand. What is the largest possible number of people visiting the zoo? [?]",
      "answer0": "1380499",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 150,
      "difficulty_id": 2,
      "explanation": "Rounding to the nearest thousand gives 1 380 000, so the actual value is from 1 379 500 to 1 380 499. The largest possible value is 1 380 499. Answer: 1 380 499.",
      "hints": ["Values rounding to 1 380 000 lie within 500 above or below it.", "The largest value still rounds down: 1 380 499."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q2. Key: 1380499. Whole-number answer → FIB."
    },
    {
      "n": 33,
      "type_id": 2,
      "question": "Sue had a bottle of cooking oil. She used an equal amount of oil each day. At the end of the 2nd day, she had 1240 ml of oil left. At the end of the 4th day, she had 1.09 \\(\\ell\\) of oil left. How much oil did Sue use each day? Leave your answer in ml. [?] ml",
      "answer0": "75",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 2,
      "explanation": "Convert 1.09 \\(\\ell = 1090\\) ml. From end of day 2 to end of day 4 is 2 days; oil used \\(= 1240 - 1090 = 150\\) ml over 2 days. Per day \\(= 150 \\div 2 = 75\\) ml. Answer: 75 ml.",
      "hints": ["Convert 1.09 litres to millilitres (×1000).", "Find the oil used between day 2 and day 4, then divide by the 2 days."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q3. Key: 75 ml. Whole-number answer → FIB."
    },
    {
      "n": 34,
      "type_id": 2,
      "question": "A pail with a capacity of 12 \\(\\ell\\) was filled to the brim with paint. Caleb transferred the paint from the pail into some containers. Each container could hold 400 ml of paint. In the end, 2 \\(\\ell\\) of paint was left in the pail. How many containers did he use? [?]",
      "answer0": "25",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 192,
      "difficulty_id": 2,
      "explanation": "Paint transferred \\(= 12 - 2 = 10\\) \\(\\ell = 10000\\) ml. Each container holds 400 ml, so containers \\(= 10000 \\div 400 = 25\\). Answer: 25.",
      "hints": ["Find the paint transferred: 12 ℓ − 2 ℓ.", "Convert to ml and divide by 400 ml per container."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q4",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q4. Key: 25. Whole-number answer → FIB. Pail/container art is decorative; values in stem so no image needed."
    },
    {
      "n": 35,
      "type_id": 2,
      "question": "The table shows the overseas postage rate to Malaysia and Brunei: up to 20 g $0.80; up to 50 g $1.00; up to 100 g $1.50; for every additional 100 g or part thereof $1.20. Mrs Chan sent a set of cards weighing 260 g to her friend in Malaysia. How much did she pay for sending the cards? [?]",
      "answer0": "3.90",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 175,
      "difficulty_id": 3,
      "explanation": "First 100 g costs $1.50. Remaining \\(260 - 100 = 160\\) g; at $1.20 per 100 g or part thereof, 160 g = 2 blocks = \\(2 \\times 1.20 = 2.40\\). Total \\(= 1.50 + 2.40 = \\$3.90\\). Answer: $3.90.",
      "hints": ["The first 100 g costs $1.50.", "The remaining 160 g is charged per 100 g 'or part thereof' — round up to 2 blocks."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q5",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q5. Key: $3.90. Money answer → FIB. Rate table placed in stem so no image needed."
    },
    {
      "n": 36,
      "type_id": 2,
      "question": "Alistair and Bevan had stickers in the ratio 13 : 3. Both of them had a total of 272 stickers.<br>(a) How many stickers did Bevan have? [?]<br>(b) Edwin had 3 times as many stickers as Bevan. How many stickers did Edwin have? [?]",
      "answer0": "51",
      "answer1": "153",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 182,
      "difficulty_id": 2,
      "explanation": "(a) Total units \\(= 13 + 3 = 16\\); 1 unit \\(= 272 \\div 16 = 17\\). Bevan \\(= 3 \\times 17 = 51\\). (b) Edwin \\(= 3 \\times 51 = 153\\).",
      "hints": ["Add the ratio parts to find the value of 1 unit (272 ÷ 16).", "Bevan = 3 units; Edwin = 3 × Bevan."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q6. Key: (a) 51, (b) 153. Two whole-number answers → FIB with two blanks."
    },
    {
      "n": 37,
      "type_id": 1,
      "question": "The square grid shows the positions of 8 points (A, B, C, D, E, F, G, H), with North pointing up.<br>(a) B is ____ of A and ____ of E.<br>(b) Faris stood at one of the points facing B. After he turned 90° clockwise, he faced Point C. Which point was Faris at?<br>(c) Meiling was standing at Point E facing Point D. She turned 135° anti-clockwise. Which point was Meiling facing in the end?",
      "answer0": "(a) East, North; (b) D; (c) H",
      "answer1": "(a) West, South; (b) A; (c) G",
      "answer2": "(a) North, East; (b) C; (c) A",
      "answer3": "(a) East, South; (b) B; (c) F",
      "correct_answer": 0,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "(a) On the grid B is to the right of A (East) and directly above E (North). (b) Facing B then turning 90° clockwise to face C places Faris at Point D. (c) From E facing D, a 135° anti-clockwise turn ends facing Point H.",
      "hints": ["Use the North arrow: up = North, right = East.", "Track the facing direction carefully through each turn using the grid positions."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q7",
      "image_needed": true,
      "image_options": false,
      "image_file": "q37.png",
      "image_page": 24,
      "image_bbox": [0.33, 0.10, 0.80, 0.33],
      "notes": "Paper 2 Q7. Key: (a) East, North; (b) D; (c) H. Direction/point-label answers → MCQ. Figure: 5×5 grid with points A,B,C,D,E,F,G,H plus a North compass arrow on the right."
    },
    {
      "n": 38,
      "type_id": 2,
      "question": "Sandy spent \\(\\dfrac{5}{7}\\) of her money and Kevin spent \\(\\dfrac{2}{5}\\) of his money. After that, they had the same amount of money left. The total amount of money left was $180. How much did they have altogether at first? [?]",
      "answer0": "465",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Sandy left \\(1 - \\dfrac{5}{7} = \\dfrac{2}{7}\\); Kevin left \\(1 - \\dfrac{2}{5} = \\dfrac{3}{5}\\). They each have half of $180 = $90 left. Sandy's total \\(= 90 \\div \\dfrac{2}{7} = 315\\); Kevin's total \\(= 90 \\div \\dfrac{3}{5} = 150\\). Altogether \\(= 315 + 150 = \\$465\\). Answer: $465.",
      "hints": ["Each person has half of the $180 left.", "Work out each person's original amount from the fraction left, then add."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q8",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q8. Key: $465. Money answer → FIB."
    },
    {
      "n": 39,
      "type_id": 2,
      "question": "Mr Sunil's salary was $4250. He donated part of it to Charity A and Charity B in the ratio of 4 : 1. The amount he donated to Charity A was $340.<br>(a) How much did he donate to both charities? [?]<br>(b) Find the percentage of Mr Sunil's salary that was donated to both charities. [?]",
      "answer0": "425",
      "answer1": "10",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 175,
      "difficulty_id": 2,
      "explanation": "(a) Charity A is 4 units = $340, so 1 unit \\(= 340 \\div 4 = 85\\); total 5 units \\(= 85 \\times 5 = \\$425\\). (b) Percentage \\(= \\dfrac{425}{4250} = \\dfrac{1}{10} = \\dfrac{10}{100} = 10\\%\\).",
      "hints": ["Charity A = 4 units = $340; find 1 unit then the 5-unit total.", "Percentage = donation ÷ salary × 100."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q9",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q9. Key: (a) $425, (b) 10%. Two numeric answers → FIB with two blanks (b's % entered as the number 10)."
    },
    {
      "n": 40,
      "type_id": 2,
      "question": "The table shows the prices of tickets for a concert: Adult $23, Child $15. The number of adult tickets sold was 6 times as many as the number of child tickets sold. A total of $20 196 was collected from the sale of tickets. How much was collected from the sale of the adult tickets? [?]",
      "answer0": "18216",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Let child tickets = 1 unit, adult = 6 units. Value per 'set' (1 child + 6 adults) \\(= 15 + 6 \\times 23 = 15 + 138 = 153\\). Number of sets \\(= 20196 \\div 153 = 132\\). Adult tickets \\(= 132 \\times 6 = 792\\); adult sales \\(= 792 \\times 23 = \\$18\\,216\\). Answer: $18 216.",
      "hints": ["Group 1 child ticket with 6 adult tickets and find that group's total value.", "Divide $20 196 by the group value, then find the adult ticket revenue."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q10",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q10. Key: $18216. Money answer → FIB. Price table placed in stem so no image needed."
    },
    {
      "n": 41,
      "type_id": 2,
      "question": "Miss Lim bought some identical notebooks from the bookshop. For every 4 notebooks bought, she received the 5th notebook free. Each notebook cost $2.45. She gave the cashier $65 and received a change of $3.75. How many notebooks did Miss Lim get from the bookshop altogether? [?]",
      "answer0": "31",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "Amount spent \\(= 65 - 3.75 = 61.25\\). Cost of 4 paid notebooks \\(= 2.45 \\times 4 = 9.80\\). Number of full groups of 4 paid \\(= 58.80 \\div 9.80 = 6\\) (after accounting for the leftover paid notebook): 61.25 − 2.45 = 58.80; 58.80 ÷ 9.80 = 6 groups. Paid notebooks \\(= 6 \\times 4 + 1 = 25\\)? Per key: 6 groups give 6 free, so total \\(= 30 + 1 = 31\\). Answer: 31.",
      "hints": ["Money spent = $65 − $3.75.", "Every group of 4 paid notebooks earns 1 free; count paid + free notebooks."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q11. Key: 31. Whole-number answer → FIB. Key working: 65−3.75=61.25; 2.45×4=9.80; 61.25−2.45=58.80; 58.80÷9.80=6; 6×5=30; 30+1=31."
    },
    {
      "n": 42,
      "type_id": 1,
      "question": "In the figure, ABC and ADE are identical equilateral triangles. \\(\\angle AHE\\) is a right angle. G and F are points on line BC. \\(\\angle BAF = \\angle CAF\\).<br>(a) Find \\(\\angle CAF\\).<br>(b) Find \\(\\angle FGD\\).",
      "answer0": "(a) 30°; (b) 30°",
      "answer1": "(a) 60°; (b) 30°",
      "answer2": "(a) 30°; (b) 60°",
      "answer3": "(a) 60°; (b) 60°",
      "correct_answer": 0,
      "skill_id": 197,
      "difficulty_id": 3,
      "explanation": "(a) \\(\\angle BAC = 60\\u00b0\\) (equilateral) and AF bisects it, so \\(\\angle CAF = 60\\u00b0 \\div 2 = 30\\u00b0\\). (b) \\(\\angle AGH = 90\\u00b0 + 60\\u00b0\\) reasoning per key: in triangle, \\(180\\u00b0 - 150\\u00b0 = 30\\u00b0\\), so \\(\\angle FGD = 30\\u00b0\\).",
      "hints": ["Each angle of an equilateral triangle is 60°; AF bisects ∠BAC.", "Use the right angle at H and angle-sum of a triangle for part (b)."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q12",
      "image_needed": true,
      "image_options": false,
      "image_file": "q42.png",
      "image_page": 29,
      "image_bbox": [0.22, 0.16, 0.74, 0.40],
      "notes": "Paper 2 Q12. Key: (a) 30°, (b) 30°. Angle (degree) answers → MCQ. Figure: two overlapping identical equilateral triangles ABC and ADE with points H, G, F and a right angle at H."
    },
    {
      "n": 43,
      "type_id": 2,
      "question": "Mark received 2 Bs and 2 Cs in a public speaking competition. His average score was 74. The grade bands are: 85 and above = A, 70–84 = B, 50–69 = C, below 50 = D. His scores were Content 68, Audience Engagement 80, Body Language ?, Delivery ?. Based on the table, what was the lowest possible score he received for Delivery? [?]",
      "answer0": "64",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 204,
      "difficulty_id": 3,
      "explanation": "Total of 4 scores \\(= 74 \\times 4 = 296\\). Known Content + Audience \\(= 68 + 80 = 148\\), so Body Language + Delivery \\(= 296 - 148 = 148\\). Both are a B or C; for the lowest Delivery, make Body Language the highest possible B = 84, giving Delivery \\(= 148 - 84 = 64\\). Answer: 64.",
      "hints": ["Average × 4 gives the total of all four scores.", "Subtract the two known scores; to make Delivery lowest, make Body Language as high as the band allows (84)."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q13",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q13. Key: 64. Whole-number answer → FIB. Grade and score tables placed in stem so no image needed."
    },
    {
      "n": 44,
      "type_id": 1,
      "question": "Anson has a triangular piece of paper ABC, with AB = BC, \\(\\angle ABC = 38\\u00b0\\) and \\(\\angle DEC = 34\\u00b0\\). ADC and BEC are straight lines. He folded the piece of paper along the line DE.<br>(a) Find \\(\\angle x\\).<br>(b) Find \\(\\angle y\\).",
      "answer0": "(a) 75°; (b) 112°",
      "answer1": "(a) 71°; (b) 112°",
      "answer2": "(a) 75°; (b) 104°",
      "answer3": "(a) 105°; (b) 112°",
      "correct_answer": 0,
      "skill_id": 197,
      "difficulty_id": 3,
      "explanation": "(a) In isosceles triangle ABC, base angles \\(= (180\\u00b0 - 38\\u00b0) \\div 2 = 71\\u00b0\\); \\(\\angle ACB = 71\\u00b0\\). \\(71\\u00b0 + 34\\u00b0 = 105\\u00b0\\), so \\(\\angle x = 180\\u00b0 - 105\\u00b0 = 75\\u00b0\\). (b) \\(\\angle y = 180\\u00b0 - 2(34\\u00b0) = 112\\u00b0\\).",
      "hints": ["Use AB = BC to find the equal base angles of triangle ABC.", "After folding, use angle-sum and the fold's equal angles to find x and y."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q14",
      "image_needed": true,
      "image_options": false,
      "image_file": "q44.png",
      "image_page": 31,
      "image_bbox": [0.12, 0.18, 0.92, 0.42],
      "notes": "Paper 2 Q14. Key: (a) x=75°, (b) y=112°. Angle (degree) answers → MCQ. Figure: 'Before folding' and 'After folding' diagrams of triangle ABC with fold line DE, angles 34° and 38°, and marked angles x and y."
    },
    {
      "n": 45,
      "type_id": 2,
      "question": "A rectangular piece of wood had a breadth measuring 112 cm. It was cut into 7 smaller identical rectangles. Find the area of the piece of wood before it was cut. [?]",
      "answer0": "17920",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 138,
      "difficulty_id": 3,
      "explanation": "From the figure, the height 112 cm equals 2.5 small-rectangle lengths: a tall piece (length) + a short piece (= half a length) so 1 length unit relation gives 2.5 units = 112, i.e. each unit = 112 ÷ 3.5 = 32; the 5 vertical strips have width 32, so total length \\(= 32 \\times 5 = 160\\) cm. Area \\(= 160 \\times 112 = 17\\,920\\) cm². Answer: 17 920 cm².",
      "hints": ["Use the arrangement to relate 112 cm to the small rectangle dimensions.", "Find the full length, then area = length × breadth."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q15",
      "image_needed": true,
      "image_options": false,
      "image_file": "q45.png",
      "image_page": 32,
      "image_bbox": [0.30, 0.13, 0.70, 0.33],
      "notes": "Paper 2 Q15. Key: 17920 cm². Whole-number answer → FIB. Key working: 2.5+1=3.5; 112÷3.5=32; 32×5=160; 160×112=17920. Figure: large rectangle split into 5 tall strips on top and 2 wider rectangles below, height 112 cm."
    },
    {
      "n": 46,
      "type_id": 2,
      "question": "Study the pattern. Figure 1 has 3 white and 1 grey square; Figure 2 has 5 white and 4 grey; Figure 3 has 7 white and 9 grey; Figure 4 has 9 white and 16 grey.<br>(a) How many white squares are there in Figure 5? [?]<br>(b) In which figure will there be 101 white squares? [?]<br>(c) In which figure will there be 256 grey squares? [?]",
      "answer0": "11",
      "answer1": "50",
      "answer2": "16",
      "answer3": null,
      "correct_answer": null,
      "skill_id": 108,
      "difficulty_id": 3,
      "explanation": "White squares: \\(2n + 1\\). (a) Figure 5: \\(2 \\times 5 + 1 = 11\\). (b) \\(2n + 1 = 101 \\Rightarrow n = 50\\). Grey squares: \\(n^2\\). (c) \\(n^2 = 256 \\Rightarrow n = 16\\).",
      "hints": ["White squares follow 2 × figure number + 1.", "Grey squares are the square of the figure number (n×n)."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q16",
      "image_needed": true,
      "image_options": false,
      "image_file": "q46.png",
      "image_page": 33,
      "image_bbox": [0.14, 0.09, 0.88, 0.27],
      "notes": "Paper 2 Q16. Key: (a) 11, (b) 50, (c) 16. Three whole-number answers → FIB with three blanks in order. Figure: the four pattern figures with white and grey squares (data also given in the stem)."
    },
    {
      "n": 47,
      "type_id": 2,
      "question": "Aini saves \\(\\dfrac{6}{11}\\) of her salary every month. In December, she saved $50 more than what she usually saves. With the remaining money, she spent \\(\\dfrac{1}{5}\\) of it on a pair of shoes, $40 on transport and $200 on food. How much did she save in December? [?]",
      "answer0": "470",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Per key: usually saves \\(\\dfrac{6}{11}\\), so remaining is \\(\\dfrac{5}{11}\\) (5 − 1 = 4 units after shoes). Remaining after shoes \\(= \\dfrac{4}{5}\\) of remaining = $40 + $200 = $240; so remaining \\(= 240 \\div 4 \\times 5 = 300\\). Usual salary: remaining \\(\\dfrac{5}{11}\\) corresponds, \\(300 \\div 5 = 60\\) per unit → usual save \\(= 60 \\times 6 = 360\\)? Per key: 300+50=350; 350÷5=70; 70×6=420; 420+50=$470. Answer: $470.",
      "hints": ["The money left after saving is spent on shoes (1/5), transport and food.", "Work backwards from $40 + $200 to find the remaining money, then the salary, then add the extra $50 saved."],
      "source": "Maha Bodhi 2024 P5 End-of-Year Exam P2 Q17",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q17. Key: $470. Money answer → FIB. Key working: 200+40=240; 240÷4=60; 60×5=300; 300+50=350; 350÷5=70; 70×6=420; 420+50=470."
    }
  ]
}