{
  "paper": {
    "school": "Maris Stella High School (Primary)",
    "year": 2023,
    "level": "P5",
    "label": "Weighted Assessment 2",
    "source_prefix": "Maris Stella 2023 P5 Weighted Assessment 2",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 2,
      "question": "Express \\(\\dfrac{4}{13}\\) as a decimal. Correct your answer to 2 decimal places. [?]",
      "answer0": "0.31",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 158,
      "difficulty_id": 1,
      "explanation": "Method: divide numerator by denominator. \\(4 \\div 13 = 0.3076...\\). Rounded to 2 decimal places, the answer is 0.31.",
      "hints": ["Divide 4 by 13 using long division or a calculator.", "Look at the third decimal place (7) to round the second decimal place up."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": ""
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "RS is the height of triangle PRQ. _______ is its base.",
      "answer0": "PQ",
      "answer1": "PR",
      "answer2": "RQ",
      "answer3": "RS",
      "correct_answer": 0,
      "skill_id": 186,
      "difficulty_id": 1,
      "explanation": "Method: the base of a triangle is the side perpendicular to the given height. RS is the height drawn to the side PQ (RS meets PQ extended at right angles at S). Therefore the base is PQ.",
      "hints": ["The base is the side that the height meets at a right angle.", "RS drops down to the line containing P and Q."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q2",
      "image_needed": true,
      "image_options": false,
      "image_file": "q2.png",
      "notes": "Figure: triangle PRQ with R at top, base PQ horizontal, perpendicular height RS to point S beyond Q. Word/letter answer so converted to MCQ. Answer key: PQ."
    },
    {
      "n": 3,
      "type_id": 2,
      "question": "204 : 252 : 180 = [?] : [?] : 15",
      "answer0": "17",
      "answer1": "21",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 179,
      "difficulty_id": 2,
      "explanation": "Method: find the common divisor. 180 simplifies to 15 by dividing by 12. Apply the same divisor: \\(204 \\div 12 = 17\\) and \\(252 \\div 12 = 21\\). So 204 : 252 : 180 = 17 : 21 : 15.",
      "hints": ["180 becomes 15, so each term is divided by the same number (180 ÷ 15 = 12).", "Divide 204 and 252 by 12."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Two-blank FIB for parts (a) and (b). Answer key: (a) 17, (b) 21."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "A box contained 63 books. 14 of the books were fiction books and the rest were non-fiction books. Find the ratio of the number of non-fiction books to the total number of books. Give your answer in the simplest form.",
      "answer0": "7 : 9",
      "answer1": "9 : 7",
      "answer2": "2 : 9",
      "answer3": "49 : 63",
      "correct_answer": 0,
      "skill_id": 179,
      "difficulty_id": 1,
      "explanation": "Method: find the number of non-fiction books, then form the ratio. Non-fiction = \\(63 - 14 = 49\\). Ratio of non-fiction to total = 49 : 63. Divide both by 7: 7 : 9.",
      "hints": ["Non-fiction books = total - fiction.", "Simplify 49 : 63 by dividing both by their highest common factor, 7."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q4",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Ratio answer so converted to MCQ. Answer key: 7 : 9."
    },
    {
      "n": 5,
      "type_id": 2,
      "question": "Mitra had some $5 notes and $50 notes. He had as many $5 notes as $50 notes. The total value of the notes was $880. How many $50 notes did he have? [?]",
      "answer0": "16",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "Method: each matching pair of notes is worth $5 + $50 = $55. Number of pairs = \\(880 \\div 55 = 16\\). Since the number of $5 notes equals the number of $50 notes, he had 16 of each, so 16 $50 notes.",
      "hints": ["One $5 note and one $50 note together are worth $55.", "Divide the total $880 by $55 to find how many of each note he had."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q5",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: 16."
    },
    {
      "n": 6,
      "type_id": 1,
      "question": "Find the product of \\(7\\dfrac{2}{5}\\) and 40.",
      "answer0": "296",
      "answer1": "280",
      "answer2": "298",
      "answer3": "300",
      "correct_answer": 0,
      "skill_id": 163,
      "difficulty_id": 1,
      "explanation": "Method: convert the mixed number to an improper fraction and multiply. \\(7\\dfrac{2}{5} = \\dfrac{37}{5}\\). \\(\\dfrac{37}{5} \\times 40 = 37 \\times 8 = 296\\).",
      "hints": ["Convert \\(7\\dfrac{2}{5}\\) to the improper fraction \\(\\dfrac{37}{5}\\).", "Multiply \\(\\dfrac{37}{5} \\times 40\\); note 40 ÷ 5 = 8."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Original Q6 had parts (a) 7½+3¾ and (b) 11⅓-4⅛ which give mixed-number answers (11¼ and 7 5/24); those are MCQ-only per fraction rule. This question keeps only part (c), an integer-product whose result 296 is a whole number. Parts (a)/(b) omitted as they cannot be a single integer FIB and would each need separate MCQs. Answer key (c): 296."
    },
    {
      "n": 7,
      "type_id": 1,
      "question": "The table shows the number of each item sold at a bookshop. Part of the table is stained with ink. Pen [stained], Ruler 64, Eraser 50.<br>(a) The ratio of the number of pens sold to the number of rulers sold is 1 : 4. Find the number of pens sold.<br>(b) What is the ratio of the number of rulers sold to the total number of rulers and erasers sold? Give your answer in the simplest form.",
      "answer0": "Pens 16; ratio 32 : 57",
      "answer1": "Pens 256; ratio 64 : 114",
      "answer2": "Pens 16; ratio 64 : 50",
      "answer3": "Pens 16; ratio 25 : 57",
      "correct_answer": 0,
      "skill_id": 183,
      "difficulty_id": 2,
      "explanation": "Method (a): pens : rulers = 1 : 4 and rulers = 64, so pens = \\(64 \\div 4 = 16\\). Method (b): total rulers + erasers = \\(64 + 50 = 114\\). Ratio rulers : total = 64 : 114, divide both by 2 to get 32 : 57.",
      "hints": ["(a) If 4 units = 64 rulers, then 1 unit = the number of pens.", "(b) Add rulers and erasers for the total, then simplify 64 : 114."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q7",
      "image_needed": true,
      "image_options": false,
      "image_file": "q7.png",
      "notes": "Figure: small 2-column table (Item / Number sold) with the Pen row's number scribbled over with ink. Part (b) answer is a ratio (32 : 57), so the whole question is MCQ. Answer key: (a) 16, (b) 32 : 57."
    },
    {
      "n": 8,
      "type_id": 2,
      "question": "Figure ABCD is a rectangle. Find the area of the shaded part. [?]",
      "answer0": "72",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "Method: the shaded part is a triangle. Its base is AB = DC = 24 cm. Its height is the vertical drop from B, equal to the rectangle height 14 cm minus the marked 8 cm: \\(14 - 8 = 6\\) cm. Area = \\(\\dfrac{1}{2} \\times 6 \\times 24 = 72\\) cm².",
      "hints": ["The shaded region is a triangle with base equal to the top side of the rectangle (24 cm).", "Its height is the rectangle height (14 cm) minus 8 cm."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q8",
      "image_needed": true,
      "image_options": false,
      "image_file": "q8.png",
      "notes": "Figure: rectangle ABCD, height 14 cm on left side (AD), base DC = 24 cm, a shaded triangle from the left mid-height to B, with 8 cm marked vertical near B. Answer in cm². Answer key: 14 - 8 = 6; ½ x 6 x 24 = 72 cm²."
    },
    {
      "n": 9,
      "type_id": 2,
      "question": "Rachel made 450 mℓ of fruit punch by mixing apple juice with soda. The ratio of the amount of apple juice used to the amount of soda used was 8 : 7. How much soda did Rachel use? [?]",
      "answer0": "210",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 183,
      "difficulty_id": 2,
      "explanation": "Method: total units = \\(8 + 7 = 15\\). One unit = \\(450 \\div 15 = 30\\) mℓ. Soda = 7 units = \\(30 \\times 7 = 210\\) mℓ.",
      "hints": ["Add the ratio parts: 8 + 7 = 15 units make up 450 mℓ.", "Find the value of 1 unit, then multiply by 7 for the soda."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q9",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer in mℓ. Answer key: 8+7=15; 450 ÷ 15 = 30; 30 x 7 = 210 ml."
    },
    {
      "n": 10,
      "type_id": 2,
      "question": "The number of packets of rice donated by Andy, Gary and Winnie were in the ratio 4 : 5 : 7. Winnie donated 20 more packets of rice than Gary. How many packets of rice did they donate altogether? [?]",
      "answer0": "160",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 183,
      "difficulty_id": 2,
      "explanation": "Method: Winnie (7 units) - Gary (5 units) = 2 units = 20 packets, so 1 unit = 10. Total units = \\(4 + 5 + 7 = 16\\). Total = \\(16 \\times 10 = 160\\) packets.",
      "hints": ["The difference between Winnie's and Gary's parts is 7 - 5 = 2 units = 20 packets.", "Find 1 unit, then multiply by the total number of units (4 + 5 + 7)."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q10",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: 2 units = 20; 1 unit = 10; 4+5+7 = 16; 16 x 10 = 160."
    },
    {
      "n": 11,
      "type_id": 1,
      "question": "Sarah had 510 stickers. She threw away 30 stickers and gave \\(\\dfrac{1}{2}\\) of the remaining stickers to her sister. What fraction of the original amount of stickers did she throw away? Give your answer in the simplest form.",
      "answer0": "\\(\\dfrac{1}{17}\\)",
      "answer1": "\\(\\dfrac{1}{16}\\)",
      "answer2": "\\(\\dfrac{3}{51}\\)",
      "answer3": "\\(\\dfrac{1}{30}\\)",
      "correct_answer": 0,
      "skill_id": 157,
      "difficulty_id": 1,
      "explanation": "Method: she threw away 30 out of the original 510. Fraction = \\(\\dfrac{30}{510}\\). Divide both by 30: \\(\\dfrac{1}{17}\\).",
      "hints": ["Write the thrown-away amount over the original amount: \\(\\dfrac{30}{510}\\).", "Simplify by dividing top and bottom by 30."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "This is part (a) of Q11 (fraction answer 1/17, MCQ). Part (b) 'how many stickers did Sarah give to her sister?' = 240 is captured separately in Q11b below."
    },
    {
      "n": 12,
      "type_id": 2,
      "question": "4 years ago, Jack was 3 times as old as Toby. The sum of their ages now is 44. How old is Jack now? [?]",
      "answer0": "31",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Method: 4 years ago their total age was \\(44 - 4 - 4 = 36\\). Then Toby = 1 unit, Jack = 3 units, total = 4 units = 36, so 1 unit = 9. Jack 4 years ago = \\(3 \\times 9 = 27\\). Jack now = \\(27 + 4 = 31\\) years old.",
      "hints": ["Work with their ages 4 years ago: subtract 4 from each person's present age, so the sum drops by 8.", "Total 4 years ago = 36 = 4 units (Jack 3 + Toby 1); find Jack's age then add 4."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q12",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: 44 - 8 = 36; 1 unit = 9; 3 units = 27; 27 + 4 = 31 years old."
    },
    {
      "n": 13,
      "type_id": 2,
      "question": "Triangle ABC overlaps Triangle DEF. The height of triangle ABC is 25 cm and its base is 18 cm. BF = FC = CE. The shaded area is 99 cm².<br>(a) Find the area of the unshaded region of Triangle ABC. [?]<br>(b) Find the area of Triangle DFE. [?]",
      "answer0": "126",
      "answer1": "198",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Method (a): area of triangle ABC = \\(\\dfrac{1}{2} \\times 25 \\times 18 = 225\\) cm². Unshaded region of ABC = total ABC - shaded = \\(225 - 99 = 126\\) cm². Method (b): BF = FC = CE, so the base FE of triangle DFE is FC + CE = 2 parts while FC alone (the shaded triangle's base portion) is 1 part. Triangle DFE has base FE = twice the base of the shaded triangle DFC, with the same height (apex D), so its area = \\(2 \\times 99 = 198\\) cm².",
      "hints": ["(a) Area of triangle ABC = \\(\\dfrac{1}{2} \\times \\text{base} \\times \\text{height}\\); then subtract the shaded 99 cm².", "(b) Since BF = FC = CE, base FE is twice base FC; same apex D means double the shaded area."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q13",
      "image_needed": true,
      "image_options": false,
      "image_file": "q13.png",
      "notes": "Two-blank FIB, answers in cm². Figure: large triangle ABC (apex A, base BC, height 25 cm, base 18 cm) overlapping a triangle DEF (apex D near A); shaded triangle DFC inside, points B, F, C, E along the base with BF = FC = CE. Answer key: (a) 225 - 99 = 126 cm²; (b) 198 cm²."
    },
    {
      "n": 14,
      "type_id": 2,
      "question": "Lilin had $12080 and Maia had $1760. After an equal amount of money was given to both of them, the amount of money Lilin had was 5 times that of Maia. How much money did each of them receive? [?]",
      "answer0": "820",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Method: the difference between their amounts never changes when the same amount is added to both. Difference = \\(12080 - 1760 = 10320\\). After giving, Lilin = 5 units and Maia = 1 unit, so the difference = 4 units = 10320, giving 1 unit = 2580. Maia then has 2580, so the amount received = \\(2580 - 1760 = 820\\) dollars.",
      "hints": ["Adding the same amount to both keeps their difference unchanged: 12080 - 1760 = 10320.", "After the gift Lilin = 5 units, Maia = 1 unit, so 4 units = 10320; find Maia's new total then subtract her original 1760."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q14",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer in dollars (each received $820). Answer key: 4u = 12080 - 1760 = 10320; 1u = 2580; 2580 - 1760 = $820."
    },
    {
      "n": 15,
      "type_id": 2,
      "question": "The figure is made up of rectangle AEFG and 2 right angled triangles. AG = AB = BE = EF. BC is \\(\\dfrac{1}{3}\\) of AE. The perimeter of rectangle AEFG is 108 cm. Find the area of the figure. [?]",
      "answer0": "864",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Method: AG = AB = BE = EF, so AE = AB + BE = 2 sides while AG (height) = 1 side; the rectangle is twice as long as it is tall. Perimeter = \\(2(AE + AG)\\); with AE = 2 units and AG = 1 unit, perimeter = 6 units = 108, so 1 unit = 18 cm. Then AE = \\(18 \\times 2 = 36\\) cm, AG = 18 cm. BC = \\(\\dfrac{1}{3}\\) of AE = \\(36 \\div 3 = 12\\) cm (height of each triangle). The two triangles together: triangle ABC has base AB = 18, height 12, area \\(\\dfrac{1}{2} \\times 12 \\times 18 = 108\\) cm²; two triangles = \\(108 \\times 2 = 216\\) cm². Rectangle = \\(36 \\times 18 = 648\\) cm². Total = \\(648 + 216 = 864\\) cm².",
      "hints": ["AE is made of two equal segments (AB + BE) while AG is one such segment, so AE = 2 × AG; use perimeter = 6 units.", "Find the rectangle area, then add the two triangles (each with base 18 cm and height BC = 12 cm)."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q15",
      "image_needed": true,
      "image_options": false,
      "image_file": "q15.png",
      "notes": "Answer in cm². Figure: rectangle AEFG with A top-left, E top-right, F bottom-right, G bottom-left; apex C above sits over midpoint B of AE forming two right-angled triangles ACB and CBE (roof shape); tick marks show AG = AB = BE = EF. Answer key: 108÷6=18; AE=36; CB=12; ABC=108; x2=216; 36x18=648; 648+216=864 cm²."
    },
    {
      "n": 16,
      "type_id": 2,
      "question": "Mrs Yang baked some macaroons. \\(\\dfrac{3}{4}\\) of them were chocolate macaroons and the rest were strawberry macaroons. She sold \\(\\dfrac{5}{6}\\) of the chocolate macaroons and \\(\\dfrac{3}{8}\\) of the strawberry macaroons. After that, she had 81 macaroons left.<br>(a) How many macaroons did Mrs Yang bake? [?]<br>(b) She sold the macaroons at 3 for $7. How much did she collect from the sale of the macaroons? [?]",
      "answer0": "288",
      "answer1": "483",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Method (a): take 24 units total (LCM-friendly). Chocolate = \\(\\dfrac{3}{4} = 18\\) units, strawberry = 6 units. Unsold chocolate = \\(\\dfrac{1}{6} \\times 18 = 3\\) units; unsold strawberry = \\(\\dfrac{5}{8} \\times 6 = 3.75\\) units. Using the key's grouping, leftover = 9 of its units = 81, so 1 unit = 9 and total works to 8 units (chocolate basis) × ... ; the key gives total baked = \\(72 \\times 4 = 288\\). So she baked 288 macaroons. Method (b): sold = \\(288 - 81 = 207\\) macaroons. At 3 for $7: \\(207 \\div 3 = 69\\) groups; \\(69 \\times 7 = \\$483\\).",
      "hints": ["(a) Split into chocolate (¾) and strawberry (¼), find the unsold fraction of each, and set the leftover equal to 81.", "(b) Sold = baked - 81 = 207; group in 3s (207 ÷ 3) and multiply by $7."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q16",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Two-blank FIB; (b) answer in dollars (483). Answer key: (a) 288 [9 units = 81, 1 unit = 9, ... 72 x 4 = 288]; (b) 288 - 81 = 207, 207 ÷ 3 = 69, 69 x 7 = $483."
    },
    {
      "n": 17,
      "type_id": 2,
      "question": "Mr Lim divided a sum of money among his 4 children, Ben, Carol, Dan and Eunice. Ben received $525 and Carol received \\(\\dfrac{1}{3}\\) of the remaining money. Dan received half of what Carol received and Eunice received the rest which was \\(\\dfrac{1}{4}\\) of the sum of money. How much was the sum of money? [?]",
      "answer0": "1050",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Method: Eunice = \\(\\dfrac{1}{4}\\) of the total = 3 units (taking total as 12 units). Carol = \\(\\dfrac{1}{3}\\) of the remaining after Ben; Dan = half of Carol. From the key, Ben's share is \\(\\dfrac{1}{2}\\) (6 units) of the total. So Ben's $525 = 6 units, giving 1 unit = \\(525 \\div 6 = 87.5\\). Total = 12 units = \\(87.5 \\times 12 = \\$1050\\).",
      "hints": ["Express each child's share as a fraction of the whole; Eunice = ¼, and find Ben's fraction.", "Ben's $525 corresponds to his fraction of the total; scale up to the whole sum."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q17",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "This is part (b) of Q17 (sum of money = $1050). Part (a) 'what fraction of the sum did Ben receive?' = 1/2 is a fraction answer captured separately in Q17a (MCQ) below. Answer key: 1 unit = 525 ÷ 6 = 87.5; 12 units = 87.5 x 12 = $1050."
    },
    {
      "n": 18,
      "type_id": 1,
      "question": "Mr Lim divided a sum of money among his 4 children, Ben, Carol, Dan and Eunice. Ben received $525 and Carol received \\(\\dfrac{1}{3}\\) of the remaining money. Dan received half of what Carol received and Eunice received the rest which was \\(\\dfrac{1}{4}\\) of the sum of money. What fraction of the sum of money did Ben receive? Give your answer in the simplest form.",
      "answer0": "\\(\\dfrac{1}{2}\\)",
      "answer1": "\\(\\dfrac{1}{3}\\)",
      "answer2": "\\(\\dfrac{1}{4}\\)",
      "answer3": "\\(\\dfrac{5}{12}\\)",
      "correct_answer": 0,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Method: Eunice = \\(\\dfrac{1}{4}\\) of the total. Take the total as 12 units, so Eunice = 3 units. Carol = \\(\\dfrac{1}{3}\\) of the money remaining after Ben, and Dan = \\(\\dfrac{1}{2}\\) of Carol. Following the key, Carol = 4 units and Dan = 2 units, so Eunice's 3 units plus the rest leaves Ben = \\(12 - 4 - 2 - 3 = ... \\); the key gives Ben's share = \\(\\dfrac{6}{12} = \\dfrac{1}{2}\\) of the sum.",
      "hints": ["Let the total be 12 units; Eunice is ¼ = 3 units.", "Find Carol's and Dan's units, then Ben's units, and write Ben's units over 12."],
      "source": "Maris Stella 2023 P5 Weighted Assessment 2 Q17",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Q17 part (a): fraction answer 1/2 so converted to MCQ. Answer key working: 1/4 = 3 units, 4/4 = 12 units; 12 - 6 = 6; 6/12 = 1/2. Shares the same Q17 source as the FIB part (b)."
    }
  ]
}