{
  "paper": {
    "school": "Nan Hua",
    "year": 2025,
    "level": "P5",
    "label": "Weighted Assessment 2",
    "source_prefix": "Nan Hua 2025 P5 Weighted Assessment 2",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "Find the value of \\(\\dfrac{2}{3} \\times \\dfrac{15}{6}\\). Express the answer as a mixed number in the simplest form.",
      "answer0": "\\(1\\dfrac{2}{3}\\)",
      "answer1": "\\(1\\dfrac{8}{9}\\)",
      "answer2": "\\(2\\dfrac{1}{3}\\)",
      "answer3": "\\(2\\dfrac{1}{2}\\)",
      "correct_answer": 0,
      "skill_id": 161,
      "difficulty_id": 2,
      "explanation": "Method: multiply numerators and denominators, then simplify. \\(\\dfrac{2}{3} \\times \\dfrac{15}{6} = \\dfrac{2 \\times 15}{3 \\times 6} = \\dfrac{30}{18} = \\dfrac{5}{3} = 1\\dfrac{2}{3}\\). Answer: \\(1\\dfrac{2}{3}\\).",
      "hints": ["Multiply the numerators together and the denominators together.", "Simplify \\(\\dfrac{30}{18}\\) and convert to a mixed number."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 1 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: option 1 (1 2/3)."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "In the figure, ABD is a triangle. Given that BE is the height of Triangle ABD, which of the following is the base of Triangle ABD?",
      "answer0": "AB",
      "answer1": "AD",
      "answer2": "BC",
      "answer3": "BD",
      "correct_answer": 1,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "The base is the side perpendicular to the height. BE is drawn perpendicular from vertex B, meeting side AD at E. Therefore the base corresponding to height BE is AD. Answer: AD.",
      "hints": ["The base and its corresponding height are always perpendicular.", "BE meets the line AD at a right angle, so AD is the base."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 1 Q2",
      "image_needed": true,
      "image_options": false,
      "image_file": "q2.png",
      "image_page": 2,
      "image_bbox": [0.18, 0.50, 0.78, 0.73],
      "image_loc": "triangle ABD with vertices A (lower-left), B (lower-middle), D (top-right); dashed height BE from B to E on AD",
      "notes": "Answer key: option 2 (AD)."
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "The solid is made up of 1-cm cubes. Find the volume of the solid.",
      "answer0": "12 cm³",
      "answer1": "10 cm³",
      "answer2": "8 cm³",
      "answer3": "6 cm³",
      "correct_answer": 0,
      "skill_id": 188,
      "difficulty_id": 2,
      "explanation": "Count every unit cube in the solid (including the hidden cubes that support the upper layers). The arrangement of 1-cm cubes totals 12 cubes, so the volume is \\(12 \\times 1 = 12\\) cm³. Answer: 12 cm³.",
      "hints": ["Each small cube has a volume of 1 cm³.", "Count carefully, including cubes hidden behind or beneath others."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 1 Q3",
      "image_needed": true,
      "image_options": false,
      "image_file": "q3.png",
      "image_page": 3,
      "image_bbox": [0.18, 0.16, 0.50, 0.33],
      "image_loc": "isometric drawing of a solid built from unit cubes, upper-left of page",
      "notes": "Answer key: option 1 (12 cm³). Count-to-verify: the printed key gives 12 cubes."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "The diagram shows a packet of drink. Which of the following could be the volume of the packet of drink?",
      "answer0": "2.5 ml",
      "answer1": "25 ml",
      "answer2": "250 ml",
      "answer3": "2500 ml",
      "correct_answer": 2,
      "skill_id": 191,
      "difficulty_id": 1,
      "explanation": "A typical packet drink holds about 250 ml. 2.5 ml and 25 ml are far too small (a teaspoon is about 5 ml) and 2500 ml (2.5 litres) is far too large for a single drink packet. The reasonable estimate is 250 ml. Answer: 250 ml.",
      "hints": ["Think about how much a normal carton of drink holds.", "1 litre = 1000 ml; a small packet drink is around a quarter of a litre."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 1 Q4",
      "image_needed": true,
      "image_options": false,
      "image_file": "q4.png",
      "image_page": 3,
      "image_bbox": [0.40, 0.52, 0.55, 0.65],
      "image_loc": "photo of a tall rectangular drink packet, centre of page",
      "notes": "Answer key: option 3 (250 ml)."
    },
    {
      "n": 5,
      "type_id": 1,
      "question": "Find the area of triangle ABC.",
      "answer0": "45.5 cm²",
      "answer1": "32.5 cm²",
      "answer2": "30.0 cm²",
      "answer3": "17.5 cm²",
      "correct_answer": 3,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "Triangle ABC has base AC = 7 cm and the perpendicular height = 5 cm (the vertical from B). Area \\(= \\dfrac{1}{2} \\times 7 \\times 5 = 17.5\\) cm². Answer: 17.5 cm².",
      "hints": ["The base is AC = 7 cm; the corresponding perpendicular height is 5 cm.", "Area of a triangle = \\(\\dfrac{1}{2} \\times \\text{base} \\times \\text{height}\\)."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 1 Q5",
      "image_needed": true,
      "image_options": false,
      "image_file": "q5.png",
      "image_page": 4,
      "image_bbox": [0.25, 0.16, 0.70, 0.33],
      "image_loc": "triangle ABC with A lower-left, C on base, B top-right; labels 13 cm (slant AB), 7 cm (AC), 5 cm (CB horizontal), 5 cm (vertical height)",
      "notes": "Answer key: option 4 (17.5 cm²)."
    },
    {
      "n": 6,
      "type_id": 1,
      "question": "Mother gave Mary $64 for her pocket money last month. Mary spent \\(\\dfrac{3}{8}\\) of it on food and \\(\\dfrac{1}{4}\\) of it on transport. How much did she spend altogether?",
      "answer0": "$16",
      "answer1": "$24",
      "answer2": "$40",
      "answer3": "$48",
      "correct_answer": 2,
      "skill_id": 174,
      "difficulty_id": 2,
      "explanation": "Fraction spent \\(= \\dfrac{3}{8} + \\dfrac{1}{4} = \\dfrac{3}{8} + \\dfrac{2}{8} = \\dfrac{5}{8}\\). Amount \\(= \\dfrac{5}{8} \\times \\$64 = \\$40\\). Answer: $40.",
      "hints": ["Add the two fractions using a common denominator of 8.", "Multiply the total fraction by $64."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 1 Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: option 3 ($40)."
    },
    {
      "n": 7,
      "type_id": 0,
      "question": "Draw Cube A on the isometric grid provided.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 187,
      "difficulty_id": 2,
      "explanation": "Draw a 2-unit by 2-unit by 2-unit cube on the isometric dot grid, matching the dimensions of Cube A shown.",
      "hints": ["Each edge of Cube A is 2 units long.", "Use the isometric dots to keep the edges parallel."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 1 Q7",
      "image_needed": true,
      "image_options": false,
      "image_file": "q7.png",
      "image_page": 5,
      "image_bbox": [0.18, 0.33, 0.45, 0.52],
      "image_loc": "drawing of Cube A labelled 2 units on each visible edge, left of an isometric dot grid",
      "notes": "Interactive draw-on-grid task — no app question type. Answer key (Paper 1 Q7): a 2x2x2 cube drawn on the isometric grid. type_id 0; skipped on insert."
    },
    {
      "n": 8,
      "type_id": 0,
      "question": "Solid A is made of 1-cm cubes. Draw the top view of the solid on the grid provided.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 188,
      "difficulty_id": 2,
      "explanation": "Looking straight down on Solid A, draw the outline of the top view (the footprint of cube positions seen from above), as shown in the answer key grid.",
      "hints": ["The top view shows the shape you see looking directly down from above.", "Mark a square for each cube position visible from the top."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 1 Q8",
      "image_needed": true,
      "image_options": false,
      "image_file": "q8.png",
      "image_page": 5,
      "image_bbox": [0.18, 0.60, 0.45, 0.82],
      "image_loc": "isometric drawing of Solid A with Front View / Side View / Top View arrows, lower-left",
      "notes": "Interactive draw-the-top-view task — no app question type. type_id 0; skipped on insert."
    },
    {
      "n": 9,
      "type_id": 2,
      "question": "A rectangular tank measuring 20 cm by 10 cm by 9 cm is filled with water to a height of 7 cm. How much more water is needed to fill the tank completely? [?] cm³",
      "answer0": "400",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 191,
      "difficulty_id": 2,
      "explanation": "The unfilled height \\(= 9 - 7 = 2\\) cm. Extra water needed \\(= 20 \\times 10 \\times 2 = 400\\) cm³. Answer: 400 cm³.",
      "hints": ["Find the empty height: 9 cm - 7 cm.", "Volume of the empty space = length × breadth × empty height."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 1 Q9",
      "image_needed": true,
      "image_options": false,
      "image_file": "q9.png",
      "image_page": 6,
      "image_bbox": [0.28, 0.20, 0.72, 0.36],
      "image_loc": "cuboid water tank labelled 20 cm (length), 10 cm (depth), 9 cm (full height), 7 cm (water height)",
      "notes": "Answer key (Paper 1 Q9): 9-7=2; 2 x 20 x 20 = 400 cm³ (key wrote 20 x 20 by slip but result 400 is correct since 20 x 10 x 2 = 400)."
    },
    {
      "n": 10,
      "type_id": 2,
      "question": "Find the area of the shaded part. [?] cm²",
      "answer0": "8",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "The shaded triangle has base = 10 - 2 = 8 cm (along the top, since the bottom-right corner is 2 cm in) and height = 2 cm. Area \\(= \\dfrac{1}{2} \\times 8 \\times 2 = 8\\) cm². Answer: 8 cm².",
      "hints": ["Work out the base of the shaded triangle: 10 cm - 2 cm.", "Area of triangle = \\(\\dfrac{1}{2} \\times \\text{base} \\times \\text{height}\\), height = 2 cm."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 1 Q10",
      "image_needed": true,
      "image_options": false,
      "image_file": "q10.png",
      "image_page": 6,
      "image_bbox": [0.30, 0.50, 0.68, 0.72],
      "image_loc": "rectangle 10 cm wide with a shaded triangle inside; labels 2 cm and 4 cm on left side, 2 cm at bottom-right",
      "notes": "Answer key (Paper 1 Q10): 10-2=8; 1/2 x 2 x 8 = 8 cm²."
    },
    {
      "n": 11,
      "type_id": 2,
      "question": "Tom goes to work 5 times a week. Each time, Tom travels \\(3\\dfrac{3}{4}\\) km from his house to his workplace and returns on the same route.<br>(a) How far does Tom travel from his house to his workplace in a day? [?] km<br>(b) How far does Tom travel from his house to his workplace in a week? Give your answer in kilometres and metres. [?] km [?] m",
      "answer0": "7.5",
      "answer1": "37",
      "answer2": "500",
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 2,
      "explanation": "(a) A return trip is two journeys: \\(3\\dfrac{3}{4} \\times 2 = \\dfrac{15}{4} \\times 2 = \\dfrac{15}{2} = 7\\dfrac{1}{2}\\) km = 7.5 km. (b) In a week: \\(7\\dfrac{1}{2} \\times 5 = \\dfrac{75}{2} = 37\\dfrac{1}{2}\\) km = 37 km 500 m. Answers: (a) 7.5 km; (b) 37 km 500 m.",
      "hints": ["A day means there and back, so multiply the one-way distance by 2.", "0.5 km = 500 m when converting the weekly total."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 2 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key (Paper 2 Q1): (a) 7 1/2 km; (b) 37 km 500 m. Part (a) answer entered as decimal 7.5 km (FIB integers/decimals only)."
    },
    {
      "n": 12,
      "type_id": 2,
      "question": "The figure is made up of two identical squares and a rectangle. The breadth of the rectangle is 40 cm. The side of the square is 20 cm. Find the area of the shaded part. [?] cm²",
      "answer0": "1100",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Rectangle length = 70 cm, breadth = 40 cm, area = \\(40 \\times 70 = 2800\\) cm². The two unshaded triangles: triangle A = \\(\\dfrac{1}{2} \\times 20 \\times 70 = 700\\) cm²; triangle B = \\(\\dfrac{1}{2} \\times 50 \\times 40 = 1000\\) cm² (using length 70 - 20 = 50). Unshaded total = 700 + 1000 = 1700 cm². Shaded part = 2800 - 1700 = 1100 cm². Answer: 1100 cm².",
      "hints": ["Find the whole rectangle area first (70 cm by 40 cm).", "Subtract the two unshaded triangles from the rectangle."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 2 Q2",
      "image_needed": true,
      "image_options": false,
      "image_file": "q12.png",
      "image_page": 9,
      "image_bbox": [0.25, 0.24, 0.72, 0.42],
      "image_loc": "rectangle 70 cm wide by 40 cm tall containing two identical 20 cm squares (top-left) and a shaded region",
      "notes": "Answer key (Paper 2 Q2): 70-20=50; 40x70=2800; 1/2x20x70=700(A); 1/2x50x40=1000(B); 2800-1700=1100 cm²."
    },
    {
      "n": 13,
      "type_id": 0,
      "question": "In Primary 5K, \\(\\dfrac{2}{5}\\) of the students are boys. \\(\\dfrac{1}{3}\\) of the boys and \\(\\dfrac{1}{6}\\) of the girls in the class wear spectacles. Each of the statements is either true, false or not possible to tell from the information given. State your answer for: (i) There are more boys than girls in Primary 5K. (ii) There are more boys than girls who wear spectacles. (iii) The number of girls who do not wear spectacles is twice the number of boys who do not wear spectacles.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 174,
      "difficulty_id": 3,
      "explanation": "Take 30 students: boys = 12, girls = 18. (i) 12 < 18, so 'more boys than girls' is FALSE. (ii) Boys with spectacles = 1/3 x 12 = 4; girls with spectacles = 1/6 x 18 = 3. 4 > 3, so 'more boys than girls who wear spectacles' is TRUE. (iii) Boys without spectacles = 8; girls without spectacles = 15. 15 is not twice 8, so FALSE. Answers: (i) False, (ii) True, (iii) False.",
      "hints": ["Pick a convenient total such as 30 students so the fractions divide evenly.", "Compare actual numbers for each statement."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 2 Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "True/False/Not-possible tick-table — interactive format, no app question type (type_id 0; skipped on insert). Printed key shows only two 'False' lines (mapping to statements (i) and (iii)); statement (ii) is mathematically True (boys' spectacle count 4 > girls' 3). Answers: (i) False, (ii) True, (iii) False."
    },
    {
      "n": 14,
      "type_id": 2,
      "question": "Triangles X and Y are two different triangles with the same area. Triangle X has base 12 cm and height 8 cm.<br>(a) What is the area of Triangle Y? [?] cm²<br>(b) Give one possible base and height of Triangle Y. Base = [?] cm, Height = [?] cm",
      "answer0": "48",
      "answer1": "96",
      "answer2": "1",
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "(a) Triangle Y has the same area as Triangle X: \\(\\dfrac{1}{2} \\times 12 \\times 8 = 48\\) cm². (b) Any base x height = 96 works; the key gives base = 96 cm, height = 1 cm (since \\(\\dfrac{1}{2} \\times 96 \\times 1 = 48\\) cm²). Answers: (a) 48 cm²; (b) base 96 cm, height 1 cm.",
      "hints": ["Same area means Triangle Y's area equals Triangle X's area.", "For part (b) choose any base and height whose product is 96 (since 1/2 x base x height = 48)."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 2 Q4",
      "image_needed": true,
      "image_options": false,
      "image_file": "q14.png",
      "image_page": 11,
      "image_bbox": [0.40, 0.15, 0.68, 0.32],
      "image_loc": "Triangle X, an isosceles triangle labelled 12 cm (base) and 8 cm (dashed height)",
      "notes": "Answer key (Paper 2 Q4): (a) 48 cm²; (b) Base = 96 cm, Height = 1 cm (one valid pair). Part (b) accepts any base x height = 96; recorded the key's pair."
    },
    {
      "n": 15,
      "type_id": 1,
      "question": "Mrs Tan spent \\(\\dfrac{1}{4}\\) of her money on a necklace and \\(\\dfrac{1}{5}\\) of the remainder on a bag. She gave her daughter $60 and had $156 left. What fraction of her money did Mrs Tan spend on the bag?",
      "answer0": "\\(\\dfrac{3}{20}\\)",
      "answer1": "\\(\\dfrac{1}{5}\\)",
      "answer2": "\\(\\dfrac{1}{4}\\)",
      "answer3": "\\(\\dfrac{1}{20}\\)",
      "correct_answer": 0,
      "skill_id": 161,
      "difficulty_id": 2,
      "explanation": "After the necklace, the remainder is \\(1 - \\dfrac{1}{4} = \\dfrac{3}{4}\\) of her money. The bag is \\(\\dfrac{1}{5}\\) of this remainder: \\(\\dfrac{1}{5} \\times \\dfrac{3}{4} = \\dfrac{3}{20}\\). Answer: \\(\\dfrac{3}{20}\\).",
      "hints": ["First find the fraction left after buying the necklace.", "Take one-fifth of that remainder for the bag."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 2 Q5a",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key (Paper 2 Q5a): 1 - 1/4 = 3/4; 1/5 x 3/4 = 3/20. Made MCQ because the answer is a fraction (FIB is integers/decimals only)."
    },
    {
      "n": 16,
      "type_id": 2,
      "question": "Mrs Tan spent \\(\\dfrac{1}{4}\\) of her money on a necklace and \\(\\dfrac{1}{5}\\) of the remainder on a bag. She gave her daughter $60 and had $156 left. How much money did Mrs Tan have at first? $[?]",
      "answer0": "360",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Let total = 20 units. Necklace = 1/4 = 5u; remainder = 15u; bag = 1/5 of 15u = 3u. Money left after necklace and bag = 15u - 3u = 12u. This 12u = $60 (daughter) + $156 (left) = $216. So 1u = $216 ÷ 12 = $18, and total = 20u = $18 × 20 = $360. Answer: $360.",
      "hints": ["Use 20 units for the total so the quarter and the fifth divide evenly.", "The 12 units remaining equal $60 + $156."],
      "source": "Nan Hua 2025 P5 Weighted Assessment 2 Paper 2 Q5b",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key (Paper 2 Q5b): $156 + $60 = $216; 12u = $216; 1u = $18; 20u = $360."
    }
  ]
}