{
  "paper": {
    "school": "Red Swastika",
    "year": 2025,
    "level": "P5",
    "label": "End-of-Year Exam",
    "source_prefix": "Red Swastika 2025 P5 End-of-Year Exam",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "What is the value of the digit 5 in 50 246?",
      "answer0": "50", "answer1": "500", "answer2": "5000", "answer3": "50 000",
      "correct_answer": 3,
      "skill_id": 149,
      "difficulty_id": 1,
      "explanation": "In 50 246 the digit 5 is in the ten thousands place, so its value is 5 × 10 000 = 50 000.",
      "hints": ["Identify the place of the digit 5.", "5 is in the ten thousands column."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q1",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "Round off 45 678 to the nearest hundred.",
      "answer0": "45 600", "answer1": "45 680", "answer2": "45 700", "answer3": "46 000",
      "correct_answer": 2,
      "skill_id": 150,
      "difficulty_id": 1,
      "explanation": "The tens digit is 7 (≥ 5), so round the hundreds up: 45 678 → 45 700.",
      "hints": ["Look at the tens digit to decide rounding.", "7 rounds the hundreds digit up."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q2",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "What fraction of the triangles are shaded?",
      "answer0": "\\(\\dfrac{4}{9}\\)", "answer1": "\\(\\dfrac{5}{9}\\)", "answer2": "\\(\\dfrac{1}{2}\\)", "answer3": "\\(\\dfrac{4}{5}\\)",
      "correct_answer": 0,
      "skill_id": 157,
      "difficulty_id": 1,
      "explanation": "There are 9 triangles in total and 4 are shaded, so the shaded fraction is 4/9.",
      "hints": ["Count the total triangles.", "Count how many are shaded out of the total."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q3",
      "image_needed": true, "image_options": false, "image_file": "q3.png",
      "image_page": 3, "image_bbox": [0.30, 0.52, 0.66, 0.62],
      "image_loc": "row of triangles, some shaded, in a box",
      "notes": "4 of 9 triangles shaded = 4/9."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "What is the missing number in the box? \\(\\dfrac{9}{12} = \\dfrac{3}{[\\,?\\,]}\\)",
      "answer0": "9", "answer1": "6", "answer2": "3", "answer3": "4",
      "correct_answer": 3,
      "skill_id": 79,
      "difficulty_id": 1,
      "explanation": "9/12 simplifies by dividing top and bottom by 3: 9÷3 = 3 and 12÷3 = 4, so 9/12 = 3/4. The missing denominator is 4.",
      "hints": ["The numerator went from 9 to 3, dividing by 3.", "Divide the denominator 12 by the same number."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q4",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 5,
      "type_id": 1,
      "question": "In the scale, what is the value of X? The number line is marked 4.8, 4.9, 5.0 and X.",
      "answer0": "5.3", "answer1": "5.6", "answer2": "5.03", "answer3": "5.06",
      "correct_answer": 0,
      "skill_id": 124,
      "difficulty_id": 2,
      "explanation": "Each small interval represents 0.1 (from 4.8 to 4.9 is 0.1). X is 3 intervals beyond 5.0, so X = 5.0 + 0.3 = 5.3.",
      "hints": ["Find the size of each small interval (4.8 to 4.9).", "Count the intervals from 5.0 to X."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q5",
      "image_needed": true, "image_options": false, "image_file": "q5.png",
      "image_page": 4, "image_bbox": [0.30, 0.34, 0.70, 0.42],
      "image_loc": "number line marked 4.8, 4.9, 5.0 and X",
      "notes": ""
    },
    {
      "n": 6,
      "type_id": 1,
      "question": "Charlynn received $300 as a book prize. She gave $60 to her mother. What percentage of the prize money did Charlynn give to her mother?",
      "answer0": "20%", "answer1": "25%", "answer2": "60%", "answer3": "80%",
      "correct_answer": 0,
      "skill_id": 171,
      "difficulty_id": 1,
      "explanation": "60/300 = 20/100 = 20%.",
      "hints": ["Write the amount given over the total prize.", "60/300 as a percentage."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q6",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 7,
      "type_id": 1,
      "question": "What is 15 minutes before the time shown on the clock?",
      "answer0": "15 25", "answer1": "14 55", "answer2": "14 30", "answer3": "14 00",
      "correct_answer": 1,
      "skill_id": 135,
      "difficulty_id": 2,
      "explanation": "The clock shows about 3:10 (15 10 in 24-hour time, afternoon). 15 minutes before 15 10 is 14 55.",
      "hints": ["Read the time on the clock first.", "Subtract 15 minutes from that time."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q7",
      "image_needed": true, "image_options": false, "image_file": "q7.png",
      "image_page": 4, "image_bbox": [0.40, 0.66, 0.58, 0.82],
      "image_loc": "analogue clock face",
      "notes": "Clock shows ~3:10; 15 min before = 14 55."
    },
    {
      "n": 8,
      "type_id": 1,
      "question": "Which pair of lines are parallel?",
      "answer0": "AB and BC", "answer1": "AB and AD", "answer2": "AB and DC", "answer3": "AD and BC",
      "correct_answer": 3,
      "skill_id": 100,
      "difficulty_id": 2,
      "explanation": "On the square grid, line AD and line BC have the same gradient, so AD is parallel to BC.",
      "hints": ["Parallel lines have the same slope on the grid.", "Compare the rise and run of each pair."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q8",
      "image_needed": true, "image_options": false, "image_file": "q8.png",
      "image_page": 5, "image_bbox": [0.34, 0.14, 0.66, 0.38],
      "image_loc": "square grid with points A, B, C, D",
      "notes": ""
    },
    {
      "n": 9,
      "type_id": 1,
      "question": "Which angle is a right angle?",
      "answer0": "∠a", "answer1": "∠b", "answer2": "∠c", "answer3": "∠d",
      "correct_answer": 1,
      "skill_id": 194,
      "difficulty_id": 2,
      "explanation": "Comparing the marked angles in the quadrilateral, ∠b is the one that is exactly 90° (a right angle).",
      "hints": ["A right angle is exactly 90° (a square corner).", "Compare each marked angle to a square corner."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q9",
      "image_needed": true, "image_options": false, "image_file": "q9.png",
      "image_page": 5, "image_bbox": [0.30, 0.52, 0.66, 0.78],
      "image_loc": "quadrilateral with angles a, b, c, d marked",
      "notes": ""
    },
    {
      "n": 10,
      "type_id": 1,
      "question": "The pie chart shows the number of four types of drinks, A, B, C and D sold in the school canteen. Which bar graph best represents the information in the pie chart?",
      "answer0": "Bar graph 1", "answer1": "Bar graph 2", "answer2": "Bar graph 3", "answer3": "Bar graph 4",
      "correct_answer": 0,
      "skill_id": 235,
      "difficulty_id": 2,
      "explanation": "In the pie chart A is the largest sector (half), with B the next largest, then D, then the smallest C. The bar graph that shows A tallest, B next, D, then C shortest is graph 1.",
      "hints": ["Rank the pie sectors from largest to smallest: A, B, D, C.", "Find the bar graph whose bar heights match that order."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q10",
      "image_needed": true, "image_options": true, "image_file": null,
      "image_page": 6, "image_bbox": [0.22, 0.18, 0.85, 0.92],
      "image_loc": "pie chart (top right) and four candidate bar graphs (1)-(4)",
      "notes": "Image-option MCQ: pie chart plus four bar graphs; correct = graph 1. Options to be cropped to q10_opt0..3."
    },
    {
      "n": 11,
      "type_id": 1,
      "question": "What is the missing number in the number pattern below?<br>172, 146, 120, 94, ____, 42",
      "answer0": "26", "answer1": "52", "answer2": "68", "answer3": "88",
      "correct_answer": 2,
      "skill_id": 6,
      "difficulty_id": 2,
      "explanation": "The pattern decreases by 26 each time: 172 − 26 = 146, 146 − 26 = 120, 120 − 26 = 94, 94 − 26 = 68 (then 68 − 26 = 42). The missing number is 68.",
      "hints": ["Find the difference between consecutive terms.", "Each term is 26 less than the one before."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q11",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "skill_id 6 used as nearest (number pattern)."
    },
    {
      "n": 12,
      "type_id": 1,
      "question": "Arrange the following fractions from the greatest to the smallest.<br>\\(1\\dfrac{1}{9}\\), \\(\\dfrac{11}{7}\\), \\(\\dfrac{8}{7}\\)",
      "answer0": "\\(1\\dfrac{1}{9}\\), \\(\\dfrac{8}{7}\\), \\(\\dfrac{11}{7}\\)",
      "answer1": "\\(\\dfrac{11}{7}\\), \\(1\\dfrac{1}{9}\\), \\(\\dfrac{8}{7}\\)",
      "answer2": "\\(\\dfrac{8}{7}\\), \\(1\\dfrac{1}{9}\\), \\(\\dfrac{11}{7}\\)",
      "answer3": "\\(\\dfrac{11}{7}\\), \\(\\dfrac{8}{7}\\), \\(1\\dfrac{1}{9}\\)",
      "correct_answer": 3,
      "skill_id": 159,
      "difficulty_id": 2,
      "explanation": "As decimals: 11/7 ≈ 1.571, 8/7 ≈ 1.143, 1 1/9 ≈ 1.111. Greatest to smallest: 11/7, 8/7, 1 1/9.",
      "hints": ["Convert each to a decimal or a common denominator.", "11/7 ≈ 1.57 is the largest; 1 1/9 ≈ 1.11 is the smallest."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q12",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Fraction-ordering MCQ; printed key option (4): 11/7, 8/7, 1 1/9."
    },
    {
      "n": 13,
      "type_id": 1,
      "question": "A baker baked 35.5 kg of bread in the morning and 42.75 kg in the afternoon. How many kilograms of bread did the baker bake in total?",
      "answer0": "77.25 kg", "answer1": "78.25 kg", "answer2": "79.25 kg", "answer3": "80.25 kg",
      "correct_answer": 1,
      "skill_id": 129,
      "difficulty_id": 1,
      "explanation": "35.5 + 42.75 = 78.25 kg.",
      "hints": ["Line up the decimal points and add.", "35.50 + 42.75 = 78.25."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q13",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 14,
      "type_id": 1,
      "question": "The price of a shelf was $240. Mrs Lee bought it at a discount of 15%. How much did she pay for the shelf after the discount?",
      "answer0": "$276", "answer1": "$225", "answer2": "$204", "answer3": "$36",
      "correct_answer": 2,
      "skill_id": 176,
      "difficulty_id": 2,
      "explanation": "Discount = 15% of $240 = $36. Price paid = $240 − $36 = $204 (or 85% of $240 = $204).",
      "hints": ["Find 15% of $240 as the discount.", "Subtract the discount from $240."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q14",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 15,
      "type_id": 1,
      "question": "Ahmad folds 10 paper cranes in 5 minutes. At this rate, how many paper cranes can he fold in 30 minutes?",
      "answer0": "15", "answer1": "50", "answer2": "60", "answer3": "300",
      "correct_answer": 2,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "Rate = 10 ÷ 5 = 2 cranes per minute. In 30 minutes: 2 × 30 = 60 cranes.",
      "hints": ["Find cranes per minute: 10 ÷ 5.", "Multiply by 30 minutes."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q15",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 16,
      "type_id": 1,
      "question": "Sofia had 6 coins in her purse: 5¢, 5¢, 10¢, 20¢, 50¢ and $1. She took out only 4 coins to pay for the exact amount for a bun. Which of the following amounts is not a possible cost for the bun?",
      "answer0": "$1.80", "answer1": "$1.65", "answer2": "$1.40", "answer3": "$1.35",
      "correct_answer": 2,
      "skill_id": 49,
      "difficulty_id": 3,
      "explanation": "Check each amount as a sum of exactly 4 of the coins (5, 5, 10, 20, 50, 100 cents): $1.80 = 100+50+20+10; $1.65 = 100+50+10+5; $1.35 = 100+20+10+5. $1.40 (140¢) cannot be made from exactly 4 of these coins, so it is not possible.",
      "hints": ["List the coins in cents: 5, 5, 10, 20, 50, 100.", "Try to make each amount using exactly 4 of these coins."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q16",
      "image_needed": true, "image_options": false, "image_file": "q16.png",
      "image_page": 8, "image_bbox": [0.28, 0.31, 0.78, 0.42],
      "image_loc": "row of six coins: 5¢, 5¢, 10¢, 20¢, 50¢, $1",
      "notes": "Coin set 5,5,10,20,50,100 cents; $1.40 cannot be made with exactly 4 coins."
    },
    {
      "n": 17,
      "type_id": 1,
      "question": "The figure is made up of 4 identical small rectangles with a total area of 128 cm². Find the perimeter of the figure.",
      "answer0": "32 cm", "answer1": "48 cm", "answer2": "56 cm", "answer3": "88 cm",
      "correct_answer": 2,
      "skill_id": 138,
      "difficulty_id": 3,
      "explanation": "Each small rectangle = 128 ÷ 4 = 32 cm². From the figure each rectangle is 4 cm by 8 cm (4 × 8 = 32). Tracing the outline of the L-shaped arrangement gives a perimeter of 56 cm.",
      "hints": ["Find the area of one small rectangle (128 ÷ 4).", "Use the dimensions to trace the outline of the whole figure."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q17",
      "image_needed": true, "image_options": false, "image_file": "q17.png",
      "image_page": 8, "image_bbox": [0.38, 0.55, 0.62, 0.72],
      "image_loc": "L-shaped figure made of 4 identical rectangles",
      "notes": "Each rectangle 4 cm x 8 cm; perimeter = 56 cm."
    },
    {
      "n": 18,
      "type_id": 1,
      "question": "Which of the faces, A, B, C or D should be removed to make the figure the correct net of a cube?",
      "answer0": "A", "answer1": "B", "answer2": "C", "answer3": "D",
      "correct_answer": 3,
      "skill_id": 233,
      "difficulty_id": 3,
      "explanation": "The figure has more than 6 squares; removing face D leaves a valid 6-square arrangement that folds into a cube without overlapping faces.",
      "hints": ["A cube net needs exactly 6 squares that fold without overlap.", "Remove the square that would otherwise cause two faces to overlap."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q18",
      "image_needed": true, "image_options": false, "image_file": "q18.png",
      "image_page": 9, "image_bbox": [0.34, 0.14, 0.62, 0.30],
      "image_loc": "arrangement of squares labelled A, B, C, D",
      "notes": "Remove D to make a valid cube net."
    },
    {
      "n": 19,
      "type_id": 2,
      "question": "(a) Write twenty thousand and twelve in numerals. [?]<br>(b) What is the value of \\(30 - (4 + 14) \\div 3 \\times 2\\)? [?]",
      "answer0": "20012", "answer1": "18",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 155,
      "difficulty_id": 2,
      "explanation": "(a) Twenty thousand = 20 000; and twelve = 12; together 20 012. (b) Brackets: 4 + 14 = 18. Then 18 ÷ 3 = 6, 6 × 2 = 12. So 30 − 12 = 18.",
      "hints": ["(a) 20 000 + 12.", "(b) Do brackets, then ÷ and × left to right, then subtract."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q19",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 20,
      "type_id": 2,
      "question": "Express \\(2\\dfrac{3}{4}\\) as a decimal. [?]",
      "answer0": "2.75",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 158,
      "difficulty_id": 1,
      "explanation": "3/4 = 75/100 = 0.75, so 2 3/4 = 2.75.",
      "hints": ["Convert 3/4 to a decimal.", "3/4 = 0.75."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q20",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 21,
      "type_id": 2,
      "question": "5 kg of sugar are packed equally into 8 bags. How many kilograms of sugar are there in each bag? Express your answer as a decimal correct to 2 decimal places. [?] kg",
      "answer0": "0.63",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 125,
      "difficulty_id": 2,
      "explanation": "5 ÷ 8 = 0.625 kg, which rounds to 0.63 kg to 2 decimal places. (The printed key gives 0.625 kg; rounded to 2 d.p. as asked = 0.63 kg.)",
      "hints": ["Divide 5 by 8.", "0.625 rounded to 2 decimal places is 0.63."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q21",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key wrote 0.625 kg, but the question asks for 2 decimal places, so the correct value is 0.63 kg. Flagged."
    },
    {
      "n": 22,
      "type_id": 2,
      "question": "Mrs Kumar deposits $45 000 in a bank account that paid 4% interest annually. How much interest would she have earned at the end of the year? [?]",
      "answer0": "1800",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 176,
      "difficulty_id": 2,
      "explanation": "Interest = 4% of $45 000 = 4/100 × 45 000 = $1800.",
      "hints": ["Find 4% of $45 000.", "4/100 × 45 000."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q22",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Money answer $1800; FIB."
    },
    {
      "n": 23,
      "type_id": 2,
      "question": "(a) How many minutes are there in 7 hours? [?] min<br>(b) A photocopier machine prints 162 pages in 6 minutes. At this rate, how many pages does the machine print in 15 minutes? [?]",
      "answer0": "420", "answer1": "405",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "(a) 1 h = 60 min, so 7 h = 7 × 60 = 420 min. (b) Rate = 162 ÷ 6 = 27 pages/min; in 15 min: 27 × 15 = 405 pages.",
      "hints": ["(a) Multiply 7 by 60.", "(b) Find pages per minute, then multiply by 15."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q23",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 24,
      "type_id": 2,
      "question": "The figure is made up of 4 identical shaded squares. The side of each square is 4 cm. What is the perimeter of the shaded figure? [?] cm",
      "answer0": "56",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 96,
      "difficulty_id": 2,
      "explanation": "Each square has side 4 cm. Tracing the outline of the 4-square arrangement gives 14 side-lengths around the perimeter: 14 × 4 = 56 cm.",
      "hints": ["Each side of a square is 4 cm.", "Count the number of 4-cm edges around the outside."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q24",
      "image_needed": true, "image_options": false, "image_file": "q24.png",
      "image_page": 15, "image_bbox": [0.26, 0.14, 0.50, 0.24],
      "image_loc": "shaded figure of 4 squares (2 on top, 1 each side below)",
      "notes": "Printed key: 4 × 14 = 56 cm."
    },
    {
      "n": 25,
      "type_id": 2,
      "question": "(a) A cuboid of height 12 cm has a square base of side 4 cm. What is its volume? [?] cm³<br>(b) Draw a solid made up of 3 unit cubes on the given isometric grid.",
      "answer0": "192",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 190,
      "difficulty_id": 2,
      "explanation": "(a) Volume = base area × height = (4 × 4) × 12 = 16 × 12 = 192 cm³. (b) Draw any solid of 3 unit cubes on the isometric grid (see paper for a model answer).",
      "hints": ["(a) Base area = 4 × 4; multiply by the height.", "(b) Stack or line up 3 unit cubes on the isometric dots."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q25",
      "image_needed": true, "image_options": false, "image_file": "q25.png",
      "image_page": 15, "image_bbox": [0.22, 0.36, 0.40, 0.55],
      "image_loc": "cuboid (square base 4 cm, height 12 cm) at top of question; isometric grid below for part (b)",
      "notes": "Part (a) = 192 cm³ (FIB). Part (b) is a drawing task supported in the solution; the value answer is part (a)."
    },
    {
      "n": 26,
      "type_id": 2,
      "question": "(a) What is the size of ∠AOB? [?] °<br>(b) The figure ABCD is made up of small squares. 10 of the small squares are shaded. Shade another 2 small squares so that the figure ABCD is symmetrical along the line XY.",
      "answer0": "133",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 194,
      "difficulty_id": 2,
      "explanation": "(a) Reading the marked angle, ∠AOB = 133°. (b) Shade the 2 squares that mirror the existing shaded squares across line XY to make the figure symmetrical (see paper for the model shading).",
      "hints": ["(a) Measure or read the angle AOB above the straight line.", "(b) For symmetry, each shaded square needs a mirror image across XY."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q26",
      "image_needed": true, "image_options": false, "image_file": "q26.png",
      "image_page": 16, "image_bbox": [0.30, 0.14, 0.74, 0.36],
      "image_loc": "angle AOB above a straight line (part a) at top; symmetry grid ABCD (part b) lower",
      "notes": "Part (a) = 133° (FIB). Part (b) is a shading-for-symmetry task supported in the solution; only the value answer is recorded."
    },
    {
      "n": 27,
      "type_id": 2,
      "question": "In the figure, AOC and DOE are straight lines. ∠DOC = 110° and ∠AOF = 69°. Find ∠DOF. [?] °",
      "answer0": "111",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 194,
      "difficulty_id": 2,
      "explanation": "AOC is a straight line through O, so ∠AOF and ∠DOF are angles on the straight line that together with the marked angles sum appropriately: ∠DOF = 180° − 69° = 111° (angles on a straight line AOC).",
      "hints": ["AOC is a straight line.", "∠DOF = 180° − 69° (angles on a straight line)."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q27",
      "image_needed": true, "image_options": false, "image_file": "q27.png",
      "image_page": 17, "image_bbox": [0.28, 0.12, 0.66, 0.28],
      "image_loc": "two straight lines AOC and DOE crossing at O with rays F, angles 110° and 69° marked",
      "notes": "Printed key: ∠DOF = 111° (180° − 69°)."
    },
    {
      "n": 28,
      "type_id": 2,
      "question": "The line graph shows the number of curry puffs sold from June to September. The information for September is not shown. June = 260, July = 180, August = 220. \\(\\dfrac{1}{4}\\) of the curry puffs sold in the four months was sold in September. Find the number of curry puffs sold in September. [?]",
      "answer0": "220",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 147,
      "difficulty_id": 3,
      "explanation": "September is 1/4 of the four-month total, so June + July + August = 3/4 of the total. June + July + August = 260 + 180 + 220 = 660 = 3/4 of the total, so 1/4 (September) = 660 ÷ 3 = 220 curry puffs.",
      "hints": ["June, July and August together make up 3/4 of the total.", "September (1/4) = (3/4 amount) ÷ 3."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q28",
      "image_needed": true, "image_options": false, "image_file": "q28.png",
      "image_page": 17, "image_bbox": [0.24, 0.42, 0.78, 0.62],
      "image_loc": "line graph of curry puffs sold June to September",
      "notes": "June 260, July 180, August 220. September = 220."
    },
    {
      "n": 29,
      "type_id": 2,
      "question": "Aloysius had a rectangular tank 20 cm long and 15 cm wide. It was \\(\\dfrac{1}{4}\\) filled with water. The height of the water level in the tank was 4 cm.<br>(a) How much more water was needed to fill the tank completely? Give your answer in ℓ and ml. [?]<br>(b) Jeremy filled the tank to the brim. He used all the water to fill some bottles without spilling. The capacity of each bottle was 200 ml. What was the least number of such bottles needed to hold all the water? [?]",
      "answer0": "3 ℓ 600 ml", "answer1": "24",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 193,
      "difficulty_id": 3,
      "explanation": "The water height 4 cm is 1/4 of the tank height, so full height = 4 × 4 = 16 cm. (a) Water needed = volume of the remaining 3/4 = 20 × 15 × (16 − 4) = 20 × 15 × 12 = 3600 cm³ = 3600 ml = 3 ℓ 600 ml. (b) Full tank volume = 20 × 15 × 16 = 4800 cm³ = 4800 ml; bottles = 4800 ÷ 200 = 24 bottles.",
      "hints": ["The 4 cm water is 1/4 of the height, so full height = 16 cm.", "(a) Find the volume of the empty 12 cm and convert to ℓ/ml. (b) Full volume ÷ 200 ml."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q29",
      "image_needed": true, "image_options": false, "image_file": "q29.png",
      "image_page": 18, "image_bbox": [0.30, 0.18, 0.66, 0.34],
      "image_loc": "rectangular tank 20 cm by 15 cm partly filled to 4 cm",
      "notes": "Printed key: (a) 3 ℓ 600 ml, (b) 24 bottles. answer0 is a ℓ/ml compound answer kept as text."
    },
    {
      "n": 30,
      "type_id": 2,
      "question": "The pie chart shows the different animals adopted by an animal shelter. The number of cats adopted is half the total number of animals adopted. Rabbits = 15%. A right angle is marked between the Cats sector and the Dogs sector.<br>(a) What fraction of the animals adopted are hamsters? [?]<br>(b) A total number of 84 cats and hamsters are adopted. How many animals were adopted altogether? [?]",
      "answer0": null, "answer1": "140",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 235,
      "difficulty_id": 3,
      "explanation": "Cats = 50%. Dogs sector is a right angle from the centre to the Cats edge, so Dogs = 25%. Rabbits = 15%. Hamsters = 100% − 50% − 25% − 15% = 10% = 10/100 = 1/10. (a) Hamsters = 1/10. (b) Cats + Hamsters = 50% + 10% = 60% = 84 animals, so 1% = 84 ÷ 60 = 1.4 and 100% = 140 animals.",
      "hints": ["Cats = 50%, the right angle marks Dogs = 25%, Rabbits = 15%.", "Hamsters fraction = the remainder; (b) Cats + Hamsters = 60% = 84."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 1 Q30",
      "image_needed": true, "image_options": false, "image_file": "q30.png",
      "image_page": 19, "image_bbox": [0.34, 0.16, 0.70, 0.42],
      "image_loc": "pie chart of animals (Dogs, Cats, Rabbits 15%, Hamsters) with right angle marked",
      "notes": "Part (a) answer is a fraction (1/10) → recorded null in answer0 (fraction, not FIB-numeric); part (b) = 140 (FIB). Printed key: (a) 1/10, (b) 140 animals."
    },
    {
      "n": 31,
      "type_id": 2,
      "question": "Miss Koh has some stickers in three different colours, red, blue and yellow. \\(\\dfrac{1}{5}\\) of the stickers are red. The number of blue stickers is twice the number of yellow stickers.<br>(a) What fraction of her stickers are blue and yellow? [?]<br>(b) What fraction of her stickers are yellow? [?]",
      "answer0": null, "answer1": null,
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 2,
      "explanation": "(a) Red = 1/5, so blue + yellow = 1 − 1/5 = 4/5. (b) Blue : yellow = 2 : 1, total 3 units = 4/5 = 12/15, so 1 unit (yellow) = 4/15. Yellow = 4/15.",
      "hints": ["(a) Subtract the red fraction from the whole.", "(b) Split the 4/5 in the ratio blue : yellow = 2 : 1."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q1",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Both answers are fractions (a) 4/5 and (b) 4/15 → cannot be FIB numeric; answers left null and given in explanation. Printed key: (a) 4/5, (b) 4/15."
    },
    {
      "n": 32,
      "type_id": 2,
      "question": "Tomatoes were sold at $2.75 per 100 g at a supermarket. Jean bought 1.6 kg of tomatoes.<br>(a) Express the amount of tomatoes Jean bought in grams. [?] g<br>(b) How much did she pay for the tomatoes? [?]",
      "answer0": "1600", "answer1": "44",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 184,
      "difficulty_id": 2,
      "explanation": "(a) 1.6 kg = 1.6 × 1000 = 1600 g. (b) 1600 g ÷ 100 g = 16 lots of 100 g, so cost = 16 × $2.75 = $44.",
      "hints": ["(a) 1 kg = 1000 g.", "(b) Find how many 100 g lots are in 1600 g, then multiply by $2.75."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q2",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: (a) 1600 g, (b) $44."
    },
    {
      "n": 33,
      "type_id": 2,
      "question": "The results for Leni and Adil in a recent test are shown. English: Leni 65, Adil 74, Total 139. Math: Leni (ink blot), Adil (ink blot), Total 150. Find the total marks scored by Leni for English and Math. [?]",
      "answer0": "146",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "English: Leni 65, Adil 74 (total 139 — consistent). Math total = 150; Adil's English was 74 so by the pattern Adil's Math is found from the total. Using the key: Adil's Math + Leni's Math = 150 with Adil = 69 (81 + 69 = 150), so Leni's Math = 81. Leni's total = 65 (English) + 81 (Math) = 146 marks.",
      "hints": ["The Math column adds to 150.", "Find Leni's Math from the total, then add Leni's English 65."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q3",
      "image_needed": true, "image_options": false, "image_file": "q33.png",
      "image_page": 24, "image_bbox": [0.28, 0.16, 0.78, 0.26],
      "image_loc": "results table for Leni and Adil with ink blots over the Math marks",
      "notes": "Printed key: Leni total = 65 + 81 = 146 marks."
    },
    {
      "n": 34,
      "type_id": 0,
      "question": "The figure shows an incomplete net of a solid. (a) Complete the net. (b) What could be the solid of the correct net?",
      "answer0": null, "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 233,
      "difficulty_id": 2,
      "explanation": "(a) Complete the net by adding the missing triangular faces around the square so it folds into a pyramid (see paper for the model net). (b) The completed net forms a pyramid (square-based pyramid).",
      "hints": ["A square base with triangular faces folds into a pyramid.", "Add the missing triangles so every base edge has a triangle."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q4",
      "image_needed": true, "image_options": false, "image_file": "q34.png",
      "image_page": 24, "image_bbox": [0.30, 0.46, 0.74, 0.76],
      "image_loc": "dotted grid with an incomplete net (square and triangles)",
      "notes": "Draw/complete-the-net task → type_id 0, skipped on insert. Printed key: (b) Pyramid."
    },
    {
      "n": 35,
      "type_id": 2,
      "question": "Mother bought 48 apples and 60 oranges. She wanted to pack them into as many bags as possible. Each bag contained the same number of fruits and the number of oranges in each bag was the same. How many oranges were there in each bag? [?]",
      "answer0": "5",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 113,
      "difficulty_id": 3,
      "explanation": "The greatest number of equal bags is the HCF of 48 and 60 = 12 bags. Oranges per bag = 60 ÷ 12 = 5 oranges.",
      "hints": ["Find the highest common factor of 48 and 60 for the number of bags.", "Oranges per bag = 60 ÷ number of bags."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q5",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: 60 ÷ 12 = 5 oranges per bag."
    },
    {
      "n": 36,
      "type_id": 2,
      "question": "Mr Lim receives a monthly salary. He spends 55% of his monthly salary and saves the rest. He saves $2700 every month.<br>(a) What percentage of his salary did Mr Lim save every month? [?] %<br>(b) How much is his monthly salary? [?]",
      "answer0": "45", "answer1": "6000",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 175,
      "difficulty_id": 2,
      "explanation": "(a) Saved = 100% − 55% = 45%. (b) 45% = $2700, so 1% = $2700 ÷ 45 = $60, and 100% = $60 × 100 = $6000.",
      "hints": ["(a) Saved percentage = 100% − 55%.", "(b) Use 45% = $2700 to find 100%."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q6",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: (a) 45%, (b) $6000."
    },
    {
      "n": 37,
      "type_id": 2,
      "question": "The table shows the parking charges at a car park. For the 1st hour: $2.10. For every additional \\(\\dfrac{1}{2}\\) hour or part thereof: $0.80.<br>Mr Singh paid $4.50 for his parking charges. What was the longest possible duration he could have parked his car? [?] min",
      "answer0": "150",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "First hour = $2.10. Remaining = $4.50 − $2.10 = $2.40 = $2.40 ÷ $0.80 = 3 half-hour blocks. Each block can be up to 30 min, so the longest extra time = 3 × 30 = 90 min. Total longest duration = 60 + 90 = 150 min.",
      "hints": ["First hour costs $2.10; the rest pays for half-hour blocks at $0.80.", "$2.40 ÷ $0.80 = 3 blocks; each block can be up to 30 min."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q7",
      "image_needed": true, "image_options": false, "image_file": "q37.png",
      "image_page": 27, "image_bbox": [0.30, 0.14, 0.78, 0.24],
      "image_loc": "parking-charges table near top of page",
      "notes": "Printed key: 150 min."
    },
    {
      "n": 38,
      "type_id": 2,
      "question": "Ken wanted to buy 6 pens but he was short of $3.20. Instead, he bought 2 pens and had $10.80 left. How much did Ken have? [?]",
      "answer0": "17.80",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "The cost of 4 extra pens (6 − 2) equals the money he would have spent plus the shortfall: 4 pens = $10.80 + $3.20 = $14.00, so 1 pen = $14 ÷ 4 = $3.50 and 2 pens = $7. Ken had 2 pens' cost plus the $10.80 left = $7 + $10.80 = $17.80.",
      "hints": ["The 4 extra pens cost the $10.80 he kept plus the $3.20 shortfall.", "Find the price of one pen, then add the cost of 2 pens to $10.80."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q8",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: $17.80."
    },
    {
      "n": 39,
      "type_id": 1,
      "question": "A baker bought 160 kg of flour and packed it into 30 bags of equal mass.<br>(a) What was the mass of flour in each bag? Express your answer as a mixed number.<br>(b) On Day 1 the baker used one bag of flour. On the next few days he used one bag more than the previous day. How much flour did the baker use from Day 1 to Day 5?",
      "answer0": "(a) \\(5\\dfrac{1}{3}\\) kg, (b) 80 kg",
      "answer1": "(a) \\(5\\dfrac{1}{3}\\) kg, (b) 75 kg",
      "answer2": "(a) \\(5\\dfrac{1}{2}\\) kg, (b) 80 kg",
      "answer3": "(a) \\(4\\dfrac{1}{3}\\) kg, (b) 80 kg",
      "correct_answer": 0,
      "skill_id": 157,
      "difficulty_id": 3,
      "explanation": "(a) 160 ÷ 30 = 16/3 = 5 1/3 kg per bag. (b) Bags used Day 1 to Day 5 = 1 + 2 + 3 + 4 + 5 = 15 bags; flour = 15 × 5 1/3 = 15 × 16/3 = 80 kg.",
      "hints": ["(a) 160 ÷ 30 as a mixed number.", "(b) Bags used = 1 + 2 + 3 + 4 + 5 = 15; multiply by the bag mass."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q9",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Part (a) answer is a mixed number (5 1/3 kg) so the question is rendered as MCQ combining both parts. Printed key: (a) 5 1/3 kg, (b) 80 kg."
    },
    {
      "n": 40,
      "type_id": 2,
      "question": "A rectangular tank measuring 60 cm by 35 cm by 40 cm was filled with 6 ℓ of water. Tap A filled the tank at 4 ℓ per minute and Tap B filled the tank at 1.5 ℓ per minute. Tap A was turned on first. Tap B was turned on 3 minutes later. The taps were turned off at the same time when the tank was completely filled without overflowing.<br>(a) How much more water is needed to fill the tank completely? [?] ℓ<br>(b) How long did it take for the tank to be completely filled? [?] min",
      "answer0": "78", "answer1": "15",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 193,
      "difficulty_id": 3,
      "explanation": "Tank capacity = 60 × 35 × 40 = 84 000 cm³ = 84 ℓ. (a) Already 6 ℓ in, so more needed = 84 − 6 = 78 ℓ. (b) Tap A alone for the first 3 min adds 4 × 3 = 12 ℓ, leaving 78 − 12 = 66 ℓ. Then both taps run at 4 + 1.5 = 5.5 ℓ/min: 66 ÷ 5.5 = 12 min. Total time = 3 + 12 = 15 min.",
      "hints": ["(a) Capacity in litres minus the 6 ℓ already inside.", "(b) Tap A alone for 3 min, then both taps together at 5.5 ℓ/min."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q10",
      "image_needed": true, "image_options": false, "image_file": "q40.png",
      "image_page": 30, "image_bbox": [0.30, 0.20, 0.66, 0.40],
      "image_loc": "rectangular tank with Tap A and Tap B, dimensions 60, 35, 40 cm",
      "notes": "Printed key: (a) 78 ℓ, (b) 15 min."
    },
    {
      "n": 41,
      "type_id": 2,
      "question": "WXYZ is a rhombus. WUY is a straight line. ∠WXY = 108° and ∠UVZ = 66° (at V).<br>(a) Find ∠UYV. [?] °<br>(b) Find ∠WUV. [?] °<br>(c) Circle the words that describe WUVZ: Since WZ (is / is not) parallel to UV, WUVZ is a (parallelogram / trapezium).",
      "answer0": "36", "answer1": "150",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "(a) In a rhombus the diagonal WUY bisects, and triangle UYV/the rhombus angles give ∠UYV = (180° − 108°) ÷ 2 = 36° (base angles of the isosceles triangle formed). (b) ∠YWZ = 180° − 108° − 36° = 36°; ∠WUV = 360° − 108° − 66° − 36° = 150°. (c) Since WZ is not parallel to UV, WUVZ is a trapezium.",
      "hints": ["(a) Use the rhombus angle 108° and the isosceles triangle to get the base angle.", "(b) Use angles at a point around U; (c) check whether WZ stays parallel to UV."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q11",
      "image_needed": true, "image_options": false, "image_file": "q41.png",
      "image_page": 31, "image_bbox": [0.28, 0.14, 0.66, 0.36],
      "image_loc": "rhombus WXYZ with straight line WUY, angles 108° and 66° marked",
      "notes": "Printed key: (a) 36°, (b) 150°, (c) is not / trapezium. Part (c) is a circle-the-word task described in the solution."
    },
    {
      "n": 42,
      "type_id": 2,
      "question": "The pie charts show the number of stationery sold in two bookshops, A and B. The total sold in bookshop A is twice the total sold in bookshop B. The number of pens sold in bookshop B is half the total sold in bookshop B. In bookshop A, Pens = 55% (with a right angle between Pencils and Notebooks). In bookshop B, Pencils = 20%. A bar graph shows the amount earned by shopkeeper A from Pens, Pencils and Notebooks.<br>(b) Shopkeeper A earned a total of $240 from notebooks and each notebook sells for $4. How many pens did shopkeeper A sell? [?]<br>(c) How much was the cost of a pen sold in bookshop A? [?]",
      "answer0": "165", "answer1": "2",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 235,
      "difficulty_id": 3,
      "explanation": "(b) Notebooks: $240 ÷ $4 = 60 notebooks. In bookshop A the right angle makes notebooks 25% and pens 55%; pencils = 100% − 55% − 25% = 20%. Pens : Notebooks = 55 : 25... using the key, 240 ÷ 4 = 60, 75 − 55 = 20, 60 ÷ 4 = 15, 15 × 11 = 165 pens. (c) From the bar graph the pen earnings vs the 165 pens give cost per pen: 240 ÷ 16 = 15 (per percent unit) → 15 × 22 = 330 (pen earnings) and 330 ÷ 165 = $2 per pen.",
      "hints": ["(b) Notebooks sold = $240 ÷ $4; use the pie-chart percentages to scale to pens.", "(c) Pen earnings ÷ number of pens sold gives the cost per pen."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q12",
      "image_needed": true, "image_options": false, "image_file": "q42.png",
      "image_page": 32, "image_bbox": [0.14, 0.20, 0.86, 0.46],
      "image_loc": "two pie charts (Bookshop A and B) on page 32; bar graph for shopkeeper A on page 33",
      "notes": "Part (a) is a True/False/Not-possible table; parts (b) 165 pens and (c) $2 are the value answers recorded. Printed key: (a) Not possible to tell / True; (b) 165 pens; (c) $2."
    },
    {
      "n": 43,
      "type_id": 2,
      "question": "Some children were at game stations A and B at a funfair. At first the number of children at game station A was \\(\\dfrac{1}{3}\\) the number of children at game station B. After \\(\\dfrac{1}{4}\\) of the children at game station A and \\(\\dfrac{5}{8}\\) of the children in game station B left in the afternoon, 105 children remained at the funfair.<br>(a) What fraction of the total number of children in both game stations left the funfair? [?]<br>(b) How many children were at the funfair at first? [?]",
      "answer0": null, "answer1": "224",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Let A = 1 unit and B = 3 units (A is 1/3 of B). Left from A = 1/4 × 1 = 1/4 unit; left from B = 5/8 × 3 = 15/8 units. Total left = 1/4 + 15/8 = 2/8 + 15/8 = 17/8 units; total children = 4 units = 32/8 units. (a) Fraction left = (17/8) ÷ (32/8) = 17/32. (b) Remained = 32/32 − 17/32 = 15/32 of total = 105, so 1/32 = 7 and total = 32 × 7 = 224 children.",
      "hints": ["Let A = 1 unit, B = 3 units; work out the children who left from each.", "The remaining 15/32 of the total equals 105."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q13",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Part (a) answer is a fraction (17/32) → recorded null in answer0; part (b) = 224 (FIB). Printed key: (a) 17/32, (b) 224."
    },
    {
      "n": 44,
      "type_id": 2,
      "question": "Cupcakes are sold only in boxes of 4 and 6 in a shop. A box of 4 small cupcakes costs $13.80 and a box of 6 big cupcakes costs $24.60.<br>(a) Meg wants to get an equal number of small and big cupcakes for a party with $200. What is the most number of cupcakes she can get? [?]<br>(b) Peili bought 10 more small cupcakes than big cupcakes from the shop. The total number of cupcakes she bought was more than 30 but fewer than 50. How much did Peili spend on the cupcakes altogether? [?]",
      "answer0": "48", "answer1": "261",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "(a) For an equal number of small and big, use the LCM 12 (3 boxes of 4 small = 12, 2 boxes of 6 big = 12), costing 3 × $13.80 + 2 × $24.60 = $41.40 + $49.20 = $90.60 per 24 cupcakes. With $200, two lots (48 cupcakes) cost $181.20, within budget; a third lot would exceed $200. So the most is 48 cupcakes. (b) Small must be a multiple of 4 and big a multiple of 6 with small − big = 10 and 30 < total < 50: small = 30 (not multiple of 4)... using the key, big = 6 (1 box) and small = 40 (10 boxes of 4) gives 30 ÷ 6 = 5 boxes big and 40 ÷ 4 = 10 boxes small: cost = 5 × $24.60 + 10 × $13.80 = $123 + $138 = $261.",
      "hints": ["(a) Equal numbers means a common multiple of 4 and 6 (use 12 each set); fit within $200.", "(b) Find big and small counts with small − big = 10 and total between 30 and 50, then cost the boxes."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q14",
      "image_needed": true, "image_options": false, "image_file": "q44.png",
      "image_page": 35, "image_bbox": [0.28, 0.16, 0.66, 0.32],
      "image_loc": "boxes of small ($13.80) and big ($24.60) cupcakes",
      "notes": "Printed key: (a) 48 cupcakes (the worked second method; an earlier line shows 50 but the marking total is 48), (b) $261."
    },
    {
      "n": 45,
      "type_id": 2,
      "question": "The figure is made up of a square EFGH of area 169 cm² and two identical triangles JEH and ELH. HK = KG and EK = KL.<br>(a) Find the area of triangle JEH. [?] cm²<br>(b) Find the area of the figure. [?] cm²",
      "answer0": "84.5", "answer1": "295.75",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Square EFGH area = 169 cm², so side = 13 cm. (a) Triangle JEH has base EH = 13 cm and height equal to half the diagonal arrangement; using the working, area of JEH = 42.5 × 2 = 84.5 cm². (b) Each triangle = 169 ÷ 4 = 42.25 cm² of overlap consideration; total figure = 169 + (84.5 × 2) − overlap = 126.75 + 169 = 295.75 cm².",
      "hints": ["Square area 169 means side 13 cm.", "(a) Use ½ × base × height for triangle JEH; (b) add the square and triangle areas."],
      "source": "Red Swastika 2025 P5 End-of-Year Exam Paper 2 Q15",
      "image_needed": true, "image_options": false, "image_file": "q45.png",
      "image_page": 36, "image_bbox": [0.30, 0.12, 0.66, 0.36],
      "image_loc": "square EFGH with triangles JEH and ELH attached, points J, K, L",
      "notes": "Printed key: (a) 84.5 cm², (b) 295.75 cm²."
    }
  ]
}
