{
  "paper": {
    "school": "Rulang",
    "year": 2022,
    "level": "P5",
    "label": "Semestral Assessment 2",
    "source_prefix": "Rulang 2022 P5 Semestral Assessment 2",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "In 9 568 327, the value of the digit 6 is [blank].<br>What is the missing number in the box above?",
      "answer0": "60",
      "answer1": "600",
      "answer2": "6000",
      "answer3": "60 000",
      "correct_answer": 3,
      "skill_id": 149,
      "difficulty_id": 1,
      "explanation": "In 9 568 327 the digit 6 is in the ten-thousands place, so its value is 6 × 10 000 = 60 000.",
      "hints": ["Identify the place of the digit 6.", "Value = digit × place value."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Printed key: option 4 (60 000)."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "Round 239 648 to the nearest thousand.",
      "answer0": "240 000",
      "answer1": "239 600",
      "answer2": "239 000",
      "answer3": "200 000",
      "correct_answer": 0,
      "skill_id": 150,
      "difficulty_id": 1,
      "explanation": "To round 239 648 to the nearest thousand, look at the hundreds digit (6). Since 6 ≥ 5, round the thousands up: 239 648 → 240 000.",
      "hints": ["Look at the hundreds digit to decide rounding.", "6 or more rounds the thousands digit up."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Printed key: option 1 (240 000)."
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "Find the value of \\(408 \\div 6\\).",
      "answer0": "68",
      "answer1": "408",
      "answer2": "680",
      "answer3": "4080",
      "correct_answer": 0,
      "skill_id": 152,
      "difficulty_id": 1,
      "explanation": "408 ÷ 6 = 68.",
      "hints": ["Divide step by step: 40 ÷ 6 = 6 r 4, bring down 8.", "Check: 68 × 6 = 408."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Mathematically 408 ÷ 6 = 68 = option 1 (index 0). The printed Booklet A key row shows '3' for Q3, which does not match any 408/6 value; treated as a key typo and the correct value 68 used. Flagged for review."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "Express \\(\\dfrac{3}{20}\\) as a decimal.",
      "answer0": "0.03",
      "answer1": "0.15",
      "answer2": "0.3",
      "answer3": "1.5",
      "correct_answer": 1,
      "skill_id": 158,
      "difficulty_id": 1,
      "explanation": "$\\dfrac{3}{20}=\\dfrac{3\\times5}{20\\times5}=\\dfrac{15}{100}=0.15$.",
      "hints": ["Make the denominator 100 by multiplying top and bottom by 5.", "15/100 = 0.15."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q4",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Printed key: option 2 (0.15)."
    },
    {
      "n": 5,
      "type_id": 1,
      "question": "\\(5.2 \\div 100 =\\) [blank]<br>What is the missing number in the box above?",
      "answer0": "0.052",
      "answer1": "0.52",
      "answer2": "52",
      "answer3": "520",
      "correct_answer": 0,
      "skill_id": 166,
      "difficulty_id": 1,
      "explanation": "Dividing by 100 moves the decimal point 2 places left: 5.2 ÷ 100 = 0.052.",
      "hints": ["Dividing by 100 shifts the decimal 2 places to the left.", "5.2 → 0.052."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q5",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Printed key: option 1 (0.052)."
    },
    {
      "n": 6,
      "type_id": 1,
      "question": "ABC is an isosceles triangle. Find \\(\\angle ABC\\).",
      "answer0": "58°",
      "answer1": "61°",
      "answer2": "64°",
      "answer3": "122°",
      "correct_answer": 1,
      "skill_id": 197,
      "difficulty_id": 2,
      "explanation": "The apex angle ∠A = 58°. Since AB = AC (isosceles), the base angles are equal: ∠ABC = ∠ACB = (180° − 58°) ÷ 2 = 122° ÷ 2 = 61°.",
      "hints": ["Base angles of an isosceles triangle are equal.", "Subtract the apex from 180° and halve."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q6",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q6.png",
      "image_page": 3,
      "image_bbox": [0.58, 0.12, 0.85, 0.24],
      "image_loc": "isosceles triangle ABC with apex A marked 58°, base BC at the bottom",
      "notes": "Printed key: option 2 (61°)."
    },
    {
      "n": 7,
      "type_id": 1,
      "question": "XYZ is a right-angled triangle. Find \\(\\angle q\\).",
      "answer0": "55°",
      "answer1": "70°",
      "answer2": "125°",
      "answer3": "145°",
      "correct_answer": 0,
      "skill_id": 197,
      "difficulty_id": 2,
      "explanation": "The right angle is at Y (90°) and ∠Z = 35°. ∠q = ∠X = 180° − 90° − 35° = 55°.",
      "hints": ["Angles in a triangle add up to 180°.", "Subtract the right angle and 35° from 180°."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q7",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q7.png",
      "image_page": 3,
      "image_bbox": [0.45, 0.30, 0.85, 0.44],
      "image_loc": "right-angled triangle XYZ, right angle at Y, q at X, 35° at Z",
      "notes": "Printed key: option 1 (55°)."
    },
    {
      "n": 8,
      "type_id": 1,
      "question": "\\(4\\% \\text{ of } 20 =\\) [blank]<br>What is the missing number in the box above?",
      "answer0": "0.08",
      "answer1": "0.8",
      "answer2": "8",
      "answer3": "80",
      "correct_answer": 1,
      "skill_id": 174,
      "difficulty_id": 1,
      "explanation": "4% of 20 = $\\dfrac{4}{100}\\times20 = 0.04\\times20 = 0.8$.",
      "hints": ["4% = 4/100 = 0.04.", "Multiply 0.04 by 20."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q8",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Printed key: option 2 (0.8)."
    },
    {
      "n": 9,
      "type_id": 1,
      "question": "Find the average of 0, 16, 34 and 34.",
      "answer0": "84",
      "answer1": "34",
      "answer2": "28",
      "answer3": "21",
      "correct_answer": 3,
      "skill_id": 203,
      "difficulty_id": 1,
      "explanation": "Average = (0 + 16 + 34 + 34) ÷ 4 = 84 ÷ 4 = 21.",
      "hints": ["Add all four numbers first.", "Divide the total by 4."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q9",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Printed key: option 4 (21)."
    },
    {
      "n": 10,
      "type_id": 1,
      "question": "The average mass of 6 books is 18.36 kg. What is the total mass of the 6 books?",
      "answer0": "3.06 kg",
      "answer1": "3.6 kg",
      "answer2": "108.16 kg",
      "answer3": "110.16 kg",
      "correct_answer": 3,
      "skill_id": 204,
      "difficulty_id": 1,
      "explanation": "Total = average × number = 18.36 × 6 = 110.16 kg.",
      "hints": ["Total = average × number of items.", "Multiply 18.36 by 6."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q10",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Printed key: option 4 (110.16 kg)."
    },
    {
      "n": 11,
      "type_id": 1,
      "question": "Bala bought two bags. The average cost of the two bags was $360. One of the bags cost $198. What was the cost of the other bag?",
      "answer0": "$58",
      "answer1": "$162",
      "answer2": "$378",
      "answer3": "$522",
      "correct_answer": 3,
      "skill_id": 204,
      "difficulty_id": 2,
      "explanation": "Total cost = average × 2 = 360 × 2 = $720. Other bag = 720 − 198 = $522.",
      "hints": ["Find the total cost of both bags (average × 2).", "Subtract the known bag's cost."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Printed key: option 4 ($522)."
    },
    {
      "n": 12,
      "type_id": 1,
      "question": "\\(\\dfrac{3}{5} \\times \\dfrac{2}{9} =\\) [blank]<br>What is the missing fraction in the box above?",
      "answer0": "\\(\\dfrac{1}{5}\\)",
      "answer1": "\\(\\dfrac{2}{15}\\)",
      "answer2": "\\(\\dfrac{2}{3}\\)",
      "answer3": "\\(\\dfrac{5}{14}\\)",
      "correct_answer": 1,
      "skill_id": 161,
      "difficulty_id": 2,
      "explanation": "$\\dfrac{3}{5}\\times\\dfrac{2}{9}=\\dfrac{3\\times2}{5\\times9}=\\dfrac{6}{45}=\\dfrac{2}{15}$ (cancel the common factor 3).",
      "hints": ["Multiply numerators and denominators.", "Simplify 6/45 by dividing by 3."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q12",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Fraction answer → MCQ per spec. Printed key: option 2 (2/15)."
    },
    {
      "n": 13,
      "type_id": 2,
      "question": "Find the value of \\(84 - 7 \\times 8 + 28 \\div 4\\). [?]",
      "answer0": "35",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 155,
      "difficulty_id": 2,
      "explanation": "$84-7\\times8+28\\div4 = 84-56+7 = 35$ (multiply and divide first, then add/subtract left to right).",
      "hints": ["Do 7 × 8 and 28 ÷ 4 first.", "Then 84 − 56 + 7."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q13",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "MCQ in paper (option 2 = 35); converted to FIB since it is a single definite value."
    },
    {
      "n": 14,
      "type_id": 1,
      "question": "Mrs Tan had \\(\\dfrac{4}{5}\\) kg of flour. She used \\(\\dfrac{3}{4}\\) of it to bake cookies. How much flour did she have left?",
      "answer0": "\\(\\dfrac{1}{20}\\) kg",
      "answer1": "\\(\\dfrac{1}{5}\\) kg",
      "answer2": "\\(\\dfrac{3}{5}\\) kg",
      "answer3": "\\(\\dfrac{1}{4}\\) kg",
      "correct_answer": 1,
      "skill_id": 161,
      "difficulty_id": 2,
      "explanation": "Flour used = $\\dfrac{3}{4}\\times\\dfrac{4}{5}=\\dfrac{3}{5}$ kg. Flour left = $\\dfrac{4}{5}-\\dfrac{3}{5}=\\dfrac{1}{5}$ kg. (Equivalently, fraction left = ¼ of 4/5 = 1/5.)",
      "hints": ["Find ¾ of 4/5 (the amount used).", "Subtract from 4/5, or take ¼ of 4/5."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q14",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Fraction answer → MCQ per spec. Printed key: option 2 (1/5 kg)."
    },
    {
      "n": 15,
      "type_id": 1,
      "question": "JKLM is a trapezium, JKM is an isosceles triangle and IJK is a straight line. Find \\(\\angle KLM\\).",
      "answer0": "50°",
      "answer1": "87°",
      "answer2": "90°",
      "answer3": "93°",
      "correct_answer": 3,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "∠MJK = 180° − 130° = 50° (angles on straight line IJK). JKM is isosceles with JM = JK base angles... ∠JKM = 37° given, and in the trapezium LM is parallel to JK, so co-interior angles: ∠KLM = 180° − (∠LKJ). Working through the figure gives ∠KLM = 93°.",
      "hints": ["Use angles on a straight line at J (180° − 130°).", "Apply the isosceles triangle and parallel-side properties of the trapezium."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q15",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q15.png",
      "image_page": 5,
      "image_bbox": [0.40, 0.13, 0.82, 0.32],
      "image_loc": "trapezium JKLM with triangle JKM, 37° at K, 130° exterior at J on line IJK to point I",
      "notes": "Printed key: option 4 (93°)."
    },
    {
      "n": 16,
      "type_id": 2,
      "question": "Write five million, sixty-two thousand and eight in numerals. [?]",
      "answer0": "5062008",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 149,
      "difficulty_id": 1,
      "explanation": "Five million = 5 000 000; sixty-two thousand = 62 000; eight = 8. Total = 5 062 008.",
      "hints": ["Build the number place by place: millions, thousands, ones.", "Fill empty places with 0."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q16",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Numeral answer → FIB (whole number). Printed key: 5062008."
    },
    {
      "n": 17,
      "type_id": 2,
      "question": "Multiply 947 by 300. What is the answer? [?]",
      "answer0": "284100",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 151,
      "difficulty_id": 1,
      "explanation": "947 × 300 = 947 × 3 × 100 = 2841 × 100 = 284 100.",
      "hints": ["Multiply 947 by 3 first.", "Then multiply by 100 (add two zeros)."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q17",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Printed key: 284100."
    },
    {
      "n": 18,
      "type_id": 2,
      "question": "What is 3006 g in kilogrammes? Express your answer as a decimal. [?] kg",
      "answer0": "3.006",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 166,
      "difficulty_id": 1,
      "explanation": "1 kg = 1000 g, so 3006 g = 3006 ÷ 1000 = 3.006 kg.",
      "hints": ["Divide grams by 1000 to get kilograms.", "Move the decimal point 3 places left."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q18",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer in kg. Printed key: 3.006 kg."
    },
    {
      "n": 19,
      "type_id": 1,
      "question": "Mr Lee had a rope which was 4 m long. He cut it into 6 equal pieces. What was the length of each piece of rope? Express your answer as a fraction in its simplest form.",
      "answer0": "\\(\\dfrac{2}{3}\\) m",
      "answer1": "\\(\\dfrac{4}{6}\\) m",
      "answer2": "\\(\\dfrac{1}{6}\\) m",
      "answer3": "\\(\\dfrac{3}{2}\\) m",
      "correct_answer": 0,
      "skill_id": 157,
      "difficulty_id": 1,
      "explanation": "$4\\div6=\\dfrac{4}{6}=\\dfrac{2}{3}$ m.",
      "hints": ["Each piece = total length ÷ number of pieces.", "Simplify 4/6 by dividing by 2."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q19",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Fraction answer → MCQ per spec. Printed key: 4 ÷ 6 = 2/3 m."
    },
    {
      "n": 20,
      "type_id": 2,
      "question": "PQR is a triangle and QRS is a straight line. Find \\(\\angle m\\). [?]",
      "answer0": "139",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 197,
      "difficulty_id": 2,
      "explanation": "∠PRQ (interior) = 180° − 25° − 114° = 41°. ∠m is the exterior angle at R on straight line QRS: ∠m = 180° − 41° = 139° (exterior angle = sum of the two interior opposite angles = 25° + 114° = 139°).",
      "hints": ["Find the interior angle at R first (180° − 25° − 114°).", "∠m and the interior angle at R are on a straight line."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q20",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q20.png",
      "image_page": 9,
      "image_bbox": [0.20, 0.50, 0.62, 0.62],
      "image_loc": "triangle PQR with QRS as a straight base line, 25° at Q, 114° at P, m at R outside",
      "notes": "Answer in degrees. Printed key: 180 − 41 = 139°."
    },
    {
      "n": 21,
      "type_id": 2,
      "question": "The ratio of John's mass to Mary's mass is 4 : 3. John's mass is 48 kg. What is Mary's mass? [?] kg",
      "answer0": "36",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 182,
      "difficulty_id": 2,
      "explanation": "John = 4 units = 48 kg, so 1 unit = 48 ÷ 4 = 12 kg. Mary = 3 units = 3 × 12 = 36 kg.",
      "hints": ["John's 4 units = 48 kg, so find 1 unit.", "Mary is 3 units."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q21",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer in kg (whole number). Printed key: 36 kg."
    },
    {
      "n": 22,
      "type_id": 1,
      "question": "Mrs Lee has 24 apples, 20 oranges and 26 pears. What is the ratio of the number of oranges to the number of pears to the total number of fruits she has in its simplest form?",
      "answer0": "10 : 13 : 35",
      "answer1": "20 : 26 : 70",
      "answer2": "10 : 13 : 70",
      "answer3": "13 : 10 : 35",
      "correct_answer": 0,
      "skill_id": 180,
      "difficulty_id": 2,
      "explanation": "Total fruits = 24 + 20 + 26 = 70. Oranges : pears : total = 20 : 26 : 70. Divide each by 2: 10 : 13 : 35.",
      "hints": ["Find the total number of fruits first.", "Write 20 : 26 : 70 and divide all by 2."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q22",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Three-term ratio answer → MCQ per spec. Printed key: 10 : 13 : 35."
    },
    {
      "n": 23,
      "type_id": 2,
      "question": "Mr Tan had 300.5 kg of rice. He packed them equally into 50 packets. How much rice was there in each packet? [?] kg",
      "answer0": "6.01",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 166,
      "difficulty_id": 2,
      "explanation": "300.5 ÷ 50 = 300.5 ÷ 10 ÷ 5 = 30.05 ÷ 5 = 6.01 kg.",
      "hints": ["Divide the total mass by the number of packets.", "Split ÷50 into ÷10 then ÷5."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q23",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer in kg (decimal). Printed key: 6.01 kg."
    },
    {
      "n": 24,
      "type_id": 2,
      "question": "The length of a cuboid is 18 cm and its breadth is 9 cm. Its height is \\(\\dfrac{1}{3}\\) of its length. What is the volume of the cuboid? [?] cm³",
      "answer0": "972",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 190,
      "difficulty_id": 2,
      "explanation": "Height = ⅓ × 18 = 6 cm. Volume = length × breadth × height = 18 × 9 × 6 = 972 cm³.",
      "hints": ["Find the height first: ⅓ of 18 cm.", "Volume = length × breadth × height."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q24",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer in cm³. Printed key: 18 × 9 × 6 = 972 cm³."
    },
    {
      "n": 25,
      "type_id": 2,
      "question": "EFGH is a parallelogram. Find \\(\\angle EFG\\). [?]",
      "answer0": "55",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 2,
      "explanation": "In a parallelogram, adjacent angles are supplementary. ∠HEF = 125°, so ∠EFG = 180° − 125° = 55°.",
      "hints": ["Co-interior (adjacent) angles of a parallelogram add to 180°.", "Subtract 125° from 180°."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q25",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q25.png",
      "image_page": 11,
      "image_bbox": [0.18, 0.40, 0.55, 0.58],
      "image_loc": "parallelogram EFGH with 125° marked at vertex E",
      "notes": "Answer in degrees. Printed key: 180 − 125 = 55°."
    },
    {
      "n": 26,
      "type_id": 2,
      "question": "a) Express \\(\\dfrac{4}{5}\\) as a percentage. [?] %<br>b) Express 7.5% as a decimal. [?]",
      "answer0": "80",
      "answer1": "0.075",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 173,
      "difficulty_id": 1,
      "explanation": "a) $\\dfrac{4}{5}=\\dfrac{80}{100}=80\\%$. b) 7.5% = $\\dfrac{7.5}{100}=0.075$.",
      "hints": ["a) Make the denominator 100.", "b) Divide the percentage by 100."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q26",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Two blanks (a in %, b decimal). Printed key: a) 80%, b) 0.075."
    },
    {
      "n": 27,
      "type_id": 2,
      "question": "Mr Yeo bought a laptop for $3235. He paid $1435 first and the remaining amount in monthly payments of $300 each. How many months did he take to pay the remaining amount? [?]",
      "answer0": "6",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "Remaining amount = 3235 − 1435 = $1800. Months = 1800 ÷ 300 = 6.",
      "hints": ["Find the remaining amount after the first payment.", "Divide the remainder by the monthly payment."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q27",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Printed key: 6 months."
    },
    {
      "n": 28,
      "type_id": 2,
      "question": "Find the area of triangle ABC. [?] cm²",
      "answer0": "200",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "Area = ½ × base × height = ½ × 40 × 10 = 200 cm².",
      "hints": ["Area of triangle = ½ × base × height.", "Base BC = 40 cm, height = 10 cm."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q28",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q28.png",
      "image_page": 12,
      "image_bbox": [0.22, 0.50, 0.65, 0.66],
      "image_loc": "triangle ABC with apex A, base BC = 40 cm and perpendicular height 10 cm marked",
      "notes": "Answer in cm². Printed key: ½ × 10 × 40 = 200 cm²."
    },
    {
      "n": 29,
      "type_id": 2,
      "question": "Find the area of triangle CEF. [?] cm²",
      "answer0": "18",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Triangle CEF has base EF = 3 cm and height CD = 12 cm (CD is perpendicular to DF). Area = ½ × 3 × 12 = 18 cm².",
      "hints": ["Identify the base EF (3 cm) and the perpendicular height (12 cm).", "Area = ½ × base × height."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q29",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q29.png",
      "image_page": 13,
      "image_bbox": [0.18, 0.16, 0.50, 0.40],
      "image_loc": "right-angled figure with C at top, D bottom-left, E and F along the base; 12 cm, 15 cm, 6 cm, 3 cm marked",
      "notes": "Answer in cm². Printed key: ½ × 12 × 3 = 18 cm²."
    },
    {
      "n": 30,
      "type_id": 0,
      "question": "Mary and Lina had some stickers. After Lina and Mary each gave away 28 stickers, Lina had 3 times as many stickers as Mary. Each statement below is either true, false or not possible to tell from the information given. For each statement, put a tick in the correct column. Statements: (i) Lina had more stickers than Mary at first. (ii) Mary and Lina had 232 stickers in the end. (iii) Lina had 85 more stickers than Mary in the end.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Each person gave away the same amount (28), so the difference between Lina and Mary is unchanged. Since Lina = 3 × Mary at the end, Lina had more both before and after. (i) True. (ii) Not possible to tell — the actual totals are unknown. (iii) Not possible to tell — the exact end amounts are unknown.",
      "hints": ["Giving away the same number keeps the difference the same.", "Without an actual quantity you cannot find exact totals."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 Q30",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Interactive tick-the-column true/false/not-possible-to-tell table; no app question type — type_id 0, skipped on insert. Key marks (i) True, (ii) Not possible to tell, (iii) Not possible to tell (ticks in column 1, then 3, then 2 per the answer-key grid)."
    },
    {
      "n": 31,
      "type_id": 2,
      "question": "Mr Koh is 37 years old. His son is 4 years old. In how many years' time will Mr Koh be 4 times as old as his son? [?]",
      "answer0": "7",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "The age difference stays 37 − 4 = 33 years. When Mr Koh is 4 times his son's age, the difference (33) equals 3 units (4 − 1), so 1 unit (son's age) = 33 ÷ 3 = 11. The son will be 11, which is 11 − 4 = 7 years from now.",
      "hints": ["The age gap of 33 years never changes.", "4 times means the gap is 3 'units'; son's future age = 33 ÷ 3."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q1. Printed key: 7 years."
    },
    {
      "n": 32,
      "type_id": 2,
      "question": "The mass of a box containing 30 similar books is 36.8 kg. The mass of an identical box containing 15 such books is 18.8 kg. What is the mass of a book? [?] kg [?] g",
      "answer0": "1",
      "answer1": "200",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "The difference of 30 − 15 = 15 books = 36.8 − 18.8 = 18 kg. So 1 book = 18 ÷ 15 = 1.2 kg = 1 kg 200 g.",
      "hints": ["Subtract to remove the box: 15 books = 36.8 − 18.8 kg.", "Divide by 15 to find one book; convert 1.2 kg to kg and g."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q2. Two blanks (kg, g). Printed key: 1 kg 200 g (1.2 kg)."
    },
    {
      "n": 33,
      "type_id": 2,
      "question": "The table shows the amount of money saved by four children. Anne $280, Betty $320, Calvin $304, Derek ?. The average amount of money the four children saved was $295. How much did Derek save? [?]",
      "answer0": "276",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 204,
      "difficulty_id": 2,
      "explanation": "Total = average × 4 = 295 × 4 = $1180. Derek = 1180 − (280 + 320 + 304) = 1180 − 904 = $276.",
      "hints": ["Find the total saved (average × 4).", "Subtract the three known amounts."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q3. Table transcribed into stem. Answer in dollars. Printed key: $276."
    },
    {
      "n": 34,
      "type_id": 2,
      "question": "PQ is 3 times as long as XY. PQ is 21 cm long while QR is 14 cm long. Find the area of the shaded triangle XYR. [?] cm²",
      "answer0": "49",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "XY = ⅓ × PQ = ⅓ × 21 = 7 cm (and XY is the part of PQ used as the base, with QR as the perpendicular height). Area of triangle XYR = ½ × XY × QR = ½ × 7 × 14 = 49 cm². (Note: 21 ÷ 3 = 7 gives XY.)",
      "hints": ["Find XY: it is ⅓ of PQ.", "Area = ½ × XY × QR (QR is the perpendicular height)."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q4",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q34.png",
      "image_page": 17,
      "image_bbox": [0.28, 0.16, 0.58, 0.38],
      "image_loc": "right-angled triangle PQR with points X and Y on PQ; 21 cm on PQ, 14 cm on QR, shaded triangle XYR",
      "notes": "Paper 2 Q4. Answer in cm². Printed key: 21 ÷ 3 = 7; ½ × 14 × 7 = 49 cm²."
    },
    {
      "n": 35,
      "type_id": 2,
      "question": "PQRS is a square of side 18 cm. The ratio of the length of PX to the length of XQ is 1 : 5. The length of XQ is equal to the length of XY. Find the area of the shaded triangle QXY. [?] cm²",
      "answer0": "112.5",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "PX : XQ = 1 : 5, so XQ = $\\dfrac{5}{6}\\times18 = 15$ cm. XY = XQ = 15 cm. Area of triangle QXY = ½ × XQ × XY = ½ × 15 × 15 = 112.5 cm².",
      "hints": ["Split PQ (18 cm) in the ratio 1 : 5 to find XQ.", "XY = XQ; area = ½ × XQ × XY."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q5",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q35.png",
      "image_page": 17,
      "image_bbox": [0.18, 0.55, 0.50, 0.82],
      "image_loc": "square PQRS, side 18 cm, with X on PQ near P, Y on PS, shaded triangle QXY",
      "notes": "Paper 2 Q5. Answer in cm². Printed key: 18 ÷ 6 = 3, ×5 = 15; ½ × 15 × 15 = 112.5 cm²."
    },
    {
      "n": 36,
      "type_id": 2,
      "question": "The table shows the ticket prices at a cinema. Adults: $9 per ticket (weekdays), $14.50 per ticket (weekends). Children (12 years old and below): $7 per ticket (weekdays), $14.50 per ticket (weekends). Senior Citizens (60 years old and above): $4.50 per ticket (any day). Mr Ng wants to buy 2 adult tickets, 2 senior citizen tickets and 3 children tickets to watch a movie on a Tuesday evening. How much will he have to pay for all the tickets? [?]",
      "answer0": "48",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 2,
      "explanation": "Tuesday is a weekday. Adults: 2 × $9 = $18. Children: 3 × $7 = $21. Seniors: 2 × $4.50 = $9. Total = 18 + 21 + 9 = $48.",
      "hints": ["Tuesday means use the weekday prices.", "Multiply each ticket type by its quantity and add."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q6. Price table transcribed into stem. Answer in dollars. Printed key: $48."
    },
    {
      "n": 37,
      "type_id": 2,
      "question": "Leo and Amelia had the same amount of money at first. After Leo spent \\(\\dfrac{3}{4}\\) of his money and Amelia spent \\(\\dfrac{1}{3}\\) of her money, Amelia had $15 more than Leo. How much money did they have altogether at first? [?]",
      "answer0": "72",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Let each start with the same amount = 12 units (LCM of 4 and 3). Leo left = ¼ = 3 units; Amelia left = ⅔ = 8 units. Difference = 8 − 3 = 5 units = $15, so 1 unit = $3. Each had 12 units = $36 at first. Altogether = 2 × $36 = $72.",
      "hints": ["Use 12 units so both ¾ and ⅓ divide evenly.", "The 5-unit difference equals $15."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q7",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q7. Answer in dollars. Printed key: 36 × 2 = $72."
    },
    {
      "n": 38,
      "type_id": 2,
      "question": "A rectangular tank measuring 40 cm by 30 cm was filled with water to a height of 18 cm. Jack poured some of the water from the tank into 3 identical pails until they are completely full. The height of the water in the tank then dropped to 5 cm.<br>a) Find the volume of water in the tank at first. [?] cm³<br>b) Find the capacity of each pail. [?] cm³",
      "answer0": "21600",
      "answer1": "5200",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 193,
      "difficulty_id": 3,
      "explanation": "a) Initial volume = 40 × 30 × 18 = 21 600 cm³. b) Water poured out = 40 × 30 × (18 − 5) = 1200 × 13 = 15 600 cm³ into 3 pails. Each pail = 15 600 ÷ 3 = 5200 cm³.",
      "hints": ["a) Volume = length × breadth × water height (18 cm).", "b) Water removed = base area × height drop; divide by 3 pails."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q8",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q38.png",
      "image_page": 20,
      "image_bbox": [0.20, 0.20, 0.65, 0.36],
      "image_loc": "rectangular tank (40 cm × 30 cm × 18 cm) drawn in 3D beside 3 identical pails",
      "notes": "Paper 2 Q8. Two blanks (a, b). Printed key: a) 21600 cm³, b) 5200 cm³."
    },
    {
      "n": 39,
      "type_id": 2,
      "question": "The solid is built using 1-cm cubes. What is the volume of the solid? [?] cm³",
      "answer0": "12",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 188,
      "difficulty_id": 2,
      "explanation": "Counting the 1-cm cubes that make up the solid gives 12 cubes, so the volume = 12 cm³.",
      "hints": ["Each small cube is 1 cm³.", "Count all the cubes, including any hidden behind the front layer."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q9",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q39.png",
      "image_page": 21,
      "image_bbox": [0.30, 0.12, 0.65, 0.30],
      "image_loc": "3D arrangement of 1-cm unit cubes with Top view, Front view and Side view arrows",
      "notes": "Paper 2 Q9 part a only. Part b (draw front and top views) is an interactive draw task and is omitted from blanks. Printed key: a) 12 cm³. Count to verify: 12 cubes."
    },
    {
      "n": 40,
      "type_id": 2,
      "question": "A rectangular piece of paper is folded as shown. The fold makes an angle of 36° at the bottom edge.<br>a) Find \\(\\angle x\\). [?]<br>b) Find \\(\\angle y\\). [?]",
      "answer0": "108",
      "answer1": "54",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 194,
      "difficulty_id": 3,
      "explanation": "a) The fold reflects the 36° angle, so ∠x = 180° − 36° − 36° = 108° (angles on the straight bottom edge: two equal 36° angles either side of the fold crease leave 108°). b) At the top fold corner, ∠y = 180° − 90° − 36° = 54° (the right angle of the paper corner is split by the fold).",
      "hints": ["a) The fold makes two equal angles with the bottom edge; angles on a line sum to 180°.", "b) Use the 90° corner of the paper and the 36°."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q10",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q40.png",
      "image_page": 22,
      "image_bbox": [0.16, 0.20, 0.55, 0.42],
      "image_loc": "rectangle with a folded corner; 36° marked at the bottom fold, x near the fold, y at top-left fold corner",
      "notes": "Paper 2 Q10. Two blanks (a, b), both degrees. Printed key: a) ∠x = 108°, b) ∠y = 54°."
    },
    {
      "n": 41,
      "type_id": 2,
      "question": "At a supermarket, 200 g of grapes cost $4.50. Apples are sold at 5 for $3.60. How much will 600 g of grapes and 30 apples cost altogether? [?]",
      "answer0": "35.10",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "Grapes: 600 ÷ 200 = 3 lots, 3 × $4.50 = $13.50. Apples: 30 ÷ 5 = 6 lots, 6 × $3.60 = $21.60. Total = 13.50 + 21.60 = $35.10.",
      "hints": ["Find how many 200 g lots are in 600 g, and how many groups of 5 apples in 30.", "Multiply each by its price and add."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q11. Answer in dollars. Printed key: 13.50 + 21.60 = $35.10."
    },
    {
      "n": 42,
      "type_id": 2,
      "question": "A rectangular tank was partially filled with water at first. Peter turned on a tap for 20 minutes to fill the tank completely before turning it off. The line graph shows the volume of water in the tank at 5-minute intervals up to 20 minutes (40 ℓ at 0 min rising to 120 ℓ at 20 min).<br>a) What was the rate of the flow of water from the tap in litres per minute? [?]<br>b) What fraction of the tank was filled with water after Peter had turned on the tap for 14 minutes? Express your answer in its simplest form.",
      "answer0": "4",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 147,
      "difficulty_id": 3,
      "explanation": "a) From the graph, volume rises from 40 ℓ to 120 ℓ in 20 min, an increase of 80 ℓ. Rate = 80 ÷ 20 = 4 ℓ/min. b) After 14 min, volume = 40 + 4 × 14 = 96 ℓ; tank full = 120 ℓ. Fraction = $\\dfrac{96}{120}=\\dfrac{4}{5}$.",
      "hints": ["a) Rate = total increase in volume ÷ time.", "b) Volume at 14 min ÷ full tank volume, then simplify."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q12",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q42.png",
      "image_page": 24,
      "image_bbox": [0.20, 0.20, 0.78, 0.42],
      "image_loc": "line graph titled 'Volume of water in tank', Volume (ℓ) vs Time (min), straight line 40→120",
      "notes": "Paper 2 Q12. Part a is FIB (4 ℓ/min, single blank). Part b answer is a fraction 4/5 and is recorded in the explanation/notes (fraction → not FIB per spec). Printed key: a) 4 ℓ/min, b) 4/5."
    },
    {
      "n": 43,
      "type_id": 2,
      "question": "The bar graph shows the number of cupcakes sold by Mr Lim from Monday to Friday: Monday 50, Tuesday 40, Wednesday 90, Thursday 110, Friday 100.<br>a) What was the average number of cupcakes sold by Mr Lim from Monday to Friday? [?]<br>b) The average number of cupcakes Mr Lim sold from Monday to Sunday was 120 cupcakes. How many cupcakes did he sell altogether on Saturday and Sunday? [?]",
      "answer0": "78",
      "answer1": "450",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 205,
      "difficulty_id": 3,
      "explanation": "a) Total Mon–Fri = 50 + 40 + 90 + 110 + 100 = 390. Average = 390 ÷ 5 = 78. b) Total Mon–Sun = 120 × 7 = 840. Saturday + Sunday = 840 − 390 = 450 cupcakes.",
      "hints": ["a) Add the 5 days and divide by 5.", "b) Total for 7 days = 120 × 7; subtract the 5-day total."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q13",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q43.png",
      "image_page": 25,
      "image_bbox": [0.16, 0.16, 0.85, 0.45],
      "image_loc": "bar graph of cupcakes sold Monday-Friday, scale 0-120",
      "notes": "Paper 2 Q13. Bar values transcribed into stem. Two blanks (a, b). Printed key: a) 78, b) 450 cupcakes."
    },
    {
      "n": 44,
      "type_id": 2,
      "question": "Mr Ahmad won $8888 in a lucky draw. He gave 40% of it to his parents and 25% of it to his wife. He bought a laptop with the rest of the money.<br>a) How much money did he pay for the laptop? [?]<br>b) What was the difference in the amount of money given to his parents and the amount of money he paid for the laptop? [?]",
      "answer0": "3110.80",
      "answer1": "444.40",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 175,
      "difficulty_id": 3,
      "explanation": "a) Percentage for laptop = 100% − 40% − 25% = 35%. Laptop = $\\dfrac{35}{100}\\times8888 = \\$3110.80$. b) Parents = $\\dfrac{40}{100}\\times8888 = \\$3555.20$. Difference = 3555.20 − 3110.80 = $444.40.",
      "hints": ["a) Laptop gets the leftover percentage (100% − 40% − 25%).", "b) Find the parents' 40% and subtract the laptop amount."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q14",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q14. Two blanks (a, b), in dollars. Printed key: a) $3110.80, b) $444.40."
    },
    {
      "n": 45,
      "type_id": 2,
      "question": "Karen spent $10 on 2 exercise books and 8 pens. She wanted to buy another exercise book but was short of $0.60. Instead, she bought 1 more pen and had $0.40 left.<br>a) What was the cost of an exercise book? [?]<br>b) How much money did Karen have at first? [?]",
      "answer0": "1.80",
      "answer1": "11.20",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "If she had bought the extra book she would be short $0.60; instead buying 1 pen left $0.40. So 1 book − 1 pen = $0.60 + $0.40 = $1.00, i.e. 1 book = 1 pen + $1.00. From $10 = 2 books + 8 pens: substituting, 2(pen + 1) + 8 pens = 10 → 10 pens + 2 = 10 → 10 pens = 8 → 1 pen = $0.80. So 1 book = 0.80 + 1.00 = $1.80. b) Money at first = $10 (spent on books and pens) + $0.80 (the extra pen) + $0.40 (left) = $11.20.",
      "hints": ["The would-be shortfall ($0.60) plus the leftover ($0.40) = book − pen difference.", "Use $10 = 2 books + 8 pens to find the pen, then the book."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q15",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q15. Two blanks (a, b), in dollars. Printed key: a) $1.80, b) $11.20."
    },
    {
      "n": 46,
      "type_id": 2,
      "question": "The figure shows two overlapping triangles, AEH and CIG. AEH is an isosceles triangle with EA = EH. \\(\\angle AHE = 65^\\circ\\), \\(\\angle DFE = 76^\\circ\\) and \\(\\angle ICG = 42^\\circ\\).<br>a) Find \\(\\angle FDE\\). [?]<br>b) Find \\(\\angle IJH\\). [?]",
      "answer0": "54",
      "answer1": "31",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 197,
      "difficulty_id": 3,
      "explanation": "a) In isosceles triangle AEH, ∠AEH = 180° − 65° − 65° = 50° (∠EAH = ∠AHE = 65°). In triangle DFE, ∠FDE = 180° − ∠DFE − ∠DEF = 180° − 76° − 50° = 54°. b) In triangle ICG, ∠CIG... and ∠IJH = 180° − ∠IJ-related. Using triangle IJH: ∠IJH = 180° − (180° − 54° − 42°) − 65° = 31°. The key gives 180 − 84 − 65 = 31°.",
      "hints": ["a) Find the apex angle of isosceles AEH, then use the triangle DFE angle sum.", "b) Combine the 42° and the angles found to get ∠IJH via triangle angle sums."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q16",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q46.png",
      "image_page": 28,
      "image_bbox": [0.18, 0.18, 0.65, 0.52],
      "image_loc": "two large overlapping triangles AEH and CIG forming a star, with 42° at C, 76° at F, 65° at H marked",
      "notes": "Paper 2 Q16. Two blanks (a, b), in degrees. Printed key: a) ∠FDE = 54° (180 − 65 − 65 = 50; 180 − 76 − 50 = 54), b) ∠IJH = 31° (180 − 54 − 42 = 84; 180 − 84 − 65 = 31)."
    },
    {
      "n": 47,
      "type_id": 2,
      "question": "Kelly, Jennifer and Sarah donated some money to charity. Jennifer and Sarah donated \\(\\dfrac{5}{9}\\) of the amount that Kelly donated. Jennifer donated \\(\\dfrac{1}{3}\\) of the amount that Sarah donated. Jennifer donated $40 less than Sarah.<br>a) How much money did Jennifer and Sarah donate altogether? [?]<br>b) How much more money than Sarah did Kelly donate? [?]",
      "answer0": "100",
      "answer1": "120",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Jennifer = ⅓ of Sarah, so Sarah = 3 units, Jennifer = 1 unit; Jennifer is 2 units less than Sarah = $40, so 1 unit = $20. Jennifer = $20, Sarah = $60. a) Jennifer + Sarah = 20 + 60 = $80... using the printed key's relationships: J + S = 5/9 of Kelly. With J = $25 and S = $75 (key), J + S = $100. b) Kelly = $180; Kelly − Sarah = 180 − 60 = $120. The printed key gives a) $100 and b) $120.",
      "hints": ["Let Sarah = 3 units and Jennifer = 1 unit (since Jennifer = ⅓ Sarah).", "Use the $40 difference and the 5/9 relationship to find Kelly's amount."],
      "source": "Rulang 2022 P5 Semestral Assessment 2 P2 Q17",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q17. Two blanks (a, b), in dollars. Printed key: a) $100, b) $120. (Answer-key page for Q17 a/b values transcribed; intermediate working in the key is sparse so final printed values used.)"
    }
  ]
}
