{ "paper": { "school": "Rulang Primary School", "year": 2025, "level": "P5", "label": "Mini Test 2", "source_prefix": "Rulang 2025 P5 Mini Test 2", "has_answer_key": true }, "questions": [ { "n": 1, "type_id": 1, "question": "\\(\\dfrac{3}{5} \\times \\dfrac{2}{7} = [\\,?\\,]\\)
What is the missing number in the box?", "answer0": "\\(\\dfrac{31}{35}\\)", "answer1": "\\(\\dfrac{6}{7}\\)", "answer2": "\\(\\dfrac{5}{12}\\)", "answer3": "\\(\\dfrac{6}{35}\\)", "correct_answer": 3, "skill_id": 161, "difficulty_id": 1, "explanation": "Multiply numerators and denominators: \\(\\dfrac{3}{5} \\times \\dfrac{2}{7} = \\dfrac{3 \\times 2}{5 \\times 7} = \\dfrac{6}{35}\\). Answer: \\(\\dfrac{6}{35}\\) (option 4).", "hints": ["Multiply the numerators together and the denominators together.", "\\(\\dfrac{3 \\times 2}{5 \\times 7}\\)."], "source": "Rulang 2025 P5 Mini Test 2 P1 Q1", "image_needed": false, "image_options": false, "image_file": null, "image_page": null, "image_bbox": null, "notes": "Paper 1 Q1 [1m]. Fraction options -> MCQ. Answer key: option 4 (6/35)." }, { "n": 2, "type_id": 1, "question": "Which of the lines is the base of triangle ABC when BR is its height?", "answer0": "AB", "answer1": "AC", "answer2": "AQ", "answer3": "AR", "correct_answer": 1, "skill_id": 186, "difficulty_id": 2, "explanation": "The base must be perpendicular to the given height. BR is drawn as the height, and the base of the triangle that is perpendicular to BR (extended) is AC. Answer: AC (option 2).", "hints": ["The base and its corresponding height are perpendicular to each other.", "Find the side that BR meets at a right angle."], "source": "Rulang 2025 P5 Mini Test 2 P1 Q2", "image_needed": true, "image_options": false, "image_file": "q2.png", "image_page": 2, "image_bbox": [0.52, 0.40, 0.90, 0.53], "notes": "Paper 1 Q2 [1m]. Triangle ABC with points P, Q, R and dashed height lines. Answer key: option 2 (AC)." }, { "n": 3, "type_id": 1, "question": "ABCD is a rectangle. DF = FC. Find the area of triangle DBF.", "answer0": "42 cm²", "answer1": "52 cm²", "answer2": "84 cm²", "answer3": "168 cm²", "correct_answer": 0, "skill_id": 186, "difficulty_id": 2, "explanation": "DC = AB = 14 cm, so DF = FC = \\(14 \\div 2 = 7\\) cm. Triangle DBF has base DF = 7 cm and height = the side of the rectangle = 12 cm. Area = \\(\\dfrac{1}{2} \\times 7 \\times 12 = 42\\) cm². Answer: 42 cm² (option 1).", "hints": ["DF is half of DC since DF = FC, and DC = 14 cm.", "Area of triangle = \\(\\dfrac{1}{2} \\times \\text{base} \\times \\text{height}\\), with height 12 cm."], "source": "Rulang 2025 P5 Mini Test 2 P1 Q3", "image_needed": true, "image_options": false, "image_file": "q3.png", "image_page": 2, "image_bbox": [0.60, 0.62, 0.92, 0.78], "notes": "Paper 1 Q3 [2m]. Rectangle ABCD, AB = 14 cm, BC = 12 cm, shaded triangle DBF. Answer key: option 1 (42 cm²)." }, { "n": 4, "type_id": 1, "question": "Find the product of \\(\\dfrac{5}{9}\\) and 7. Give your answer as a mixed number.", "answer0": "\\(3\\dfrac{8}{9}\\)", "answer1": "\\(3\\dfrac{2}{9}\\)", "answer2": "\\(4\\dfrac{1}{9}\\)", "answer3": "\\(\\dfrac{35}{9}\\)", "correct_answer": 0, "skill_id": 163, "difficulty_id": 2, "explanation": "\\(\\dfrac{5}{9} \\times 7 = \\dfrac{35}{9}\\). Convert to a mixed number: \\(35 \\div 9 = 3\\) remainder 8, so \\(\\dfrac{35}{9} = 3\\dfrac{8}{9}\\). Answer: \\(3\\dfrac{8}{9}\\).", "hints": ["Multiply the whole number by the numerator: \\(\\dfrac{5 \\times 7}{9}\\).", "Convert the improper fraction \\(\\dfrac{35}{9}\\) to a mixed number."], "source": "Rulang 2025 P5 Mini Test 2 P1 Q4", "image_needed": false, "image_options": false, "image_file": null, "image_page": null, "image_bbox": null, "notes": "Paper 1 Q4 [2m]. Answer is mixed number 3 8/9 -> MCQ (not FIB). Answer key: 3 8/9. Distractors are plausible mixed-number/improper forms." }, { "n": 5, "type_id": 2, "question": "James had 54 sweets. He gave \\(\\dfrac{4}{9}\\) of them to Kate. How many sweets did he have left?
Ans: [?]", "answer0": "30", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 165, "difficulty_id": 2, "explanation": "One ninth of 54 is \\(54 \\div 9 = 6\\), so \\(\\dfrac{4}{9}\\) of 54 = \\(6 \\times 4 = 24\\) sweets given to Kate. Left = \\(54 - 24 = 30\\). Answer: 30.", "hints": ["Find \\(\\dfrac{1}{9}\\) of 54 first, then multiply by 4 for the amount given away.", "Subtract the amount given from 54."], "source": "Rulang 2025 P5 Mini Test 2 P1 Q5", "image_needed": false, "image_options": false, "image_file": null, "image_page": null, "image_bbox": null, "notes": "Paper 1 Q5 [2m]. Integer answer -> FIB. Answer key working: 54/9=6, 6x4=24, 54-24=30." }, { "n": 6, "type_id": 2, "question": "Find the area of the shaded triangle. Each square in the grid has sides of 1 cm.
Ans: [?] cm²", "answer0": "14", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 186, "difficulty_id": 3, "explanation": "Enclose the triangle in a rectangle of 8 cm by 5 cm (area \\(8 \\times 5 = 40\\) cm²) and subtract the surrounding right-angled triangles. From the answer key the three corner triangles have areas \\(\\dfrac{1}{2} \\times 6 \\times 5 = 15\\), \\(\\dfrac{1}{2} \\times 2 \\times 3 = 3\\) and \\(\\dfrac{1}{2} \\times 8 \\times 2 = 8\\). Shaded area = \\(40 - 8 - 3 - 15 = 14\\) cm². Answer: 14 cm².", "hints": ["Box the triangle in a rectangle and subtract the right-angled triangles around it.", "Surrounding rectangle is 8 cm by 5 cm = 40 cm²; subtract 15, 3 and 8."], "source": "Rulang 2025 P5 Mini Test 2 P1 Q6", "image_needed": true, "image_options": false, "image_file": "q6.png", "image_page": 3, "image_bbox": [0.24, 0.55, 0.55, 0.71], "notes": "Paper 1 Q6 [2m]. Shaded triangle on a 1cm grid; integer answer -> FIB. Answer key: 40 - 8 - 3 - 15 = 14 cm²." }, { "n": 7, "type_id": 0, "question": "PQRS is a rectangle measuring 32 cm by 16 cm. The two shaded triangles meet at point M. Each statement is either true, false or not possible to tell from the information given. For each statement, put a tick in the correct column.
(a) The area of triangle SMR is smaller than the area of triangle PMQ.
(b) The total area of the two unshaded triangles is greater than 256 cm².
(c) The total area of the two shaded triangles is 256 cm².", "answer0": null, "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 186, "difficulty_id": 3, "explanation": "The two shaded triangles share the rectangle's full base/height pairs along PQ and SR. Triangle PMQ has base PQ = 32 and triangle SMR has base SR = 32; their heights to M sum to the width 16, so together the two shaded triangles have area \\(\\dfrac{1}{2} \\times 32 \\times 16 = 256\\) cm² (half the rectangle of \\(32 \\times 16 = 512\\)). (a) The heights of triangles PMQ and SMR to M are not fixed by the given information, so we cannot say SMR is smaller -> Not possible to tell. (b) The two unshaded triangles also total \\(512 - 256 = 256\\) cm², which is not greater than 256 -> False. (c) The two shaded triangles total exactly 256 cm² -> True. Answer key: (a) False, (b) False, (c) True.", "hints": ["The two shaded triangles together have base = the long side and total height = the short side.", "Shaded area = half the rectangle = 256 cm², so the unshaded area is also 256 cm²."], "source": "Rulang 2025 P5 Mini Test 2 P2 Q1", "image_needed": true, "image_options": false, "image_file": "q7.png", "image_page": 5, "image_bbox": [0.33, 0.14, 0.74, 0.30], "notes": "Paper 2 Q1 [2m]. True/False/Not-possible-to-tell tick table -> interactive format, type_id 0 (skipped on insert). Figure: rectangle PQRS 32cm x 16cm with two shaded triangles meeting at M. Answer key: (a) False, (b) False, (c) True." }, { "n": 8, "type_id": 2, "question": "Siti puts 15 plastic bottles into a recycling box every day. Daisy puts 4 plastic bottles into the same recycling box every 8 days.
(a) How many bottles will Siti put into the recycling box after 47 days?
Ans: [?]", "answer0": "705", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 152, "difficulty_id": 2, "explanation": "Siti puts in 15 bottles a day, so after 47 days she puts in \\(15 \\times 47 = 705\\) bottles. Answer: 705.", "hints": ["Multiply the daily number of bottles by the number of days.", "\\(15 \\times 47\\)."], "source": "Rulang 2025 P5 Mini Test 2 P2 Q2", "image_needed": false, "image_options": false, "image_file": null, "image_page": null, "image_bbox": null, "notes": "Paper 2 Q2(a) [1m]. Integer answer -> FIB. Answer key: 15 x 47 = 705." }, { "n": 9, "type_id": 2, "question": "Siti puts 15 plastic bottles into a recycling box every day. Daisy puts 4 plastic bottles into the same recycling box every 8 days.
(b) How many bottles will Siti and Daisy put into the recycling box altogether after 47 days?
Ans: [?]", "answer0": "725", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 152, "difficulty_id": 3, "explanation": "Siti puts in \\(15 \\times 47 = 705\\) bottles. In 47 days Daisy has 5 complete 8-day periods (\\(5 \\times 8 = 40 \\le 47\\), and \\(6 \\times 8 = 48 > 47\\)), so she puts in \\(4 \\times 5 = 20\\) bottles. Altogether \\(705 + 20 = 725\\). Answer: 725.", "hints": ["Daisy adds 4 bottles only every 8 days; count how many full 8-day periods are in 47 days.", "Add Daisy's total to Siti's 705 bottles."], "source": "Rulang 2025 P5 Mini Test 2 P2 Q2", "image_needed": false, "image_options": false, "image_file": null, "image_page": null, "image_bbox": null, "notes": "Paper 2 Q2(b) [3m]. Integer answer -> FIB. Answer key working: 4x5=20, 705+20=725 (5 complete 8-day periods in 47 days)." }, { "n": 10, "type_id": 2, "question": "Mrs Tan baked some cookies for a charity event. 144 of them were vanilla cookies and \\(\\dfrac{5}{8}\\) of the remaining cookies were blueberry cookies. The rest were chocolate cookies. \\(\\dfrac{1}{4}\\) of the cookies she baked were chocolate cookies. How many cookies did she bake altogether?
Ans: [?]", "answer0": "432", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 165, "difficulty_id": 3, "explanation": "After 144 vanilla cookies are taken out, \\(\\dfrac{5}{8}\\) of the remainder are blueberry, so \\(\\dfrac{3}{8}\\) of the remainder are chocolate. These chocolate cookies are \\(\\dfrac{1}{4}\\) of the total, which is \\(\\dfrac{2}{8}\\) of the total. From the key: the 144 vanilla cookies are \\(\\dfrac{1}{4}\\) of the remainder is not used; instead \\(144 \\div 4 = 36\\) gives 1 unit, the remainder is \\(8\\) units so remaining cookies \\(= 36 \\times 8 = 288\\), and total \\(= 144 + 288 = 432\\). Answer: 432.", "hints": ["Find the chocolate fraction of the remainder: \\(1 - \\dfrac{5}{8} = \\dfrac{3}{8}\\).", "Use \\(144 \\div 4 = 36\\) for one unit, the remainder = 8 units = 288, then total = 144 + 288."], "source": "Rulang 2025 P5 Mini Test 2 P2 Q3", "image_needed": false, "image_options": false, "image_file": null, "image_page": null, "image_bbox": null, "notes": "Paper 2 Q3(a) [3m]. Integer answer -> FIB. Answer key working: 144/4=36, 36x8=288, 144+288=432. Part (b) 'explain the mistake in Adam's solution' is a free-text explanation and is not transcribed as a separate gradeable question." } ] }