{
  "paper": {
    "school": "Rulang",
    "year": 2025,
    "level": "P5",
    "label": "Weighted Assessment 3",
    "source_prefix": "Rulang 2025 P5 Weighted Assessment 3",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "Find the value of \\(2210 \\div 200\\).",
      "answer0": "1.105",
      "answer1": "1.15",
      "answer2": "11.05",
      "answer3": "11.5",
      "correct_answer": 2,
      "skill_id": 166,
      "difficulty_id": 2,
      "explanation": "Method: split 200 into 2 \\(\\times\\) 100. \\(2210 \\div 2 = 1105\\), then \\(1105 \\div 100 = 11.05\\). Answer: 11.05.",
      "hints": ["Divide by 2 first, then by 100.", "Dividing by 100 moves the decimal point two places left."],
      "source": "Rulang 2025 P5 Weighted Assessment 3 Paper 1 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key Paper 1 Q1: option 3 (11.05)."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "Ali can read 210 words in 3 minutes. At this rate, how many words can he read in 5 minutes?",
      "answer0": "70",
      "answer1": "150",
      "answer2": "350",
      "answer3": "1050",
      "correct_answer": 2,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "Method: find words per minute, then multiply by 5. \\(210 \\div 3 = 70\\) words per minute. \\(70 \\times 5 = 350\\). Answer: 350.",
      "hints": ["Find how many words Ali reads in 1 minute.", "Multiply the per-minute rate by 5."],
      "source": "Rulang 2025 P5 Weighted Assessment 3 Paper 1 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key Paper 1 Q2: option 3 (350)."
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "What is the volume of the solid?",
      "answer0": "11 cm³",
      "answer1": "12 cm³",
      "answer2": "30 cm³",
      "answer3": "36 cm³",
      "correct_answer": 3,
      "skill_id": 190,
      "difficulty_id": 1,
      "explanation": "Method: volume of a cuboid = length \\(\\times\\) width \\(\\times\\) height. \\(6 \\times 2 \\times 3 = 36\\) cm³. Answer: 36 cm³.",
      "hints": ["Volume of a cuboid = length \\(\\times\\) width \\(\\times\\) height.", "Multiply 6 cm, 2 cm and 3 cm together."],
      "source": "Rulang 2025 P5 Weighted Assessment 3 Paper 1 Q3",
      "image_needed": true,
      "image_options": false,
      "image_page": 2,
      "image_bbox": [0.27, 0.52, 0.56, 0.64],
      "image_loc": "cuboid diagram below the question on page 2, labelled 6 cm, 2 cm, 3 cm",
      "image_file": "q3.png",
      "notes": "Answer key Paper 1 Q3: option 4 (36 cm³). Cuboid dimensions: 6 cm (length) x 2 cm (depth) x 3 cm (height)."
    },
    {
      "n": 4,
      "type_id": 2,
      "question": "A rectangular tank measuring 40 cm by 10 cm by 20 cm contains \\(5\\,\\ell\\) of water. How much more water is needed to fill the tank completely? Give your answer in cubic centimetres. Ans: [?] cm³",
      "answer0": "3000",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 191,
      "difficulty_id": 2,
      "explanation": "Method: find the tank capacity, convert the water to cm³, then subtract. Capacity = 40 \\(\\times\\) 10 \\(\\times\\) 20 = 8000 cm³. Water = 5 \\(\\ell\\) = 5000 cm³ (since 1 \\(\\ell\\) = 1000 cm³). More needed = 8000 \\(-\\) 5000 = 3000 cm³. Answer: 3000 cm³.",
      "hints": ["Find the full capacity of the tank (40 \\(\\times\\) 10 \\(\\times\\) 20).", "1 litre = 1000 cm³; subtract the water already inside."],
      "source": "Rulang 2025 P5 Weighted Assessment 3 Paper 1 Q4",
      "image_needed": true,
      "image_options": false,
      "image_page": 3,
      "image_bbox": [0.24, 0.21, 0.55, 0.34],
      "image_loc": "rectangular tank diagram below the question on page 3, labelled 40 cm, 10 cm, 20 cm",
      "image_file": "q4.png",
      "notes": "Answer key Paper 1 Q4: 8000 - 5000 = 3000 cm³."
    },
    {
      "n": 5,
      "type_id": 2,
      "question": "The mass of an empty box is 1.05 kg. The mass of the same box containing 5 identical books is 1.5 kg. What is the mass of each book? Ans: [?] kg",
      "answer0": "0.09",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 2,
      "explanation": "Method: find the total mass of the books, then divide by 5. Books together = 1.5 \\(-\\) 1.05 = 0.45 kg. Each book = 0.45 \\(\\div\\) 5 = 0.09 kg. Answer: 0.09 kg.",
      "hints": ["Subtract the empty box mass from the full mass to get the mass of 5 books.", "Divide by 5 to find the mass of one book."],
      "source": "Rulang 2025 P5 Weighted Assessment 3 Paper 1 Q5",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key Paper 1 Q5: 1.5 - 1.05 = 0.45; 0.45 / 5 = 0.09."
    },
    {
      "n": 6,
      "type_id": 2,
      "question": "A machine can pack 80 packets of rice in 15 minutes. At this rate, how long will the machine take to pack 400 packets of rice? Ans: [?] min",
      "answer0": "75",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "Method: find how many 80-packet batches make 400, then multiply the time. 400 \\(\\div\\) 80 = 5 batches. Each batch takes 15 min, so 15 \\(\\times\\) 5 = 75 min. Answer: 75 min.",
      "hints": ["Find how many groups of 80 packets are in 400.", "Multiply that number of groups by 15 minutes."],
      "source": "Rulang 2025 P5 Weighted Assessment 3 Paper 1 Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key Paper 1 Q6: 15 x 5 = 75 min."
    },
    {
      "n": 7,
      "type_id": 2,
      "question": "The table shows the parking charges at a car park.<br>Mr Chen parked his car from 4:00 pm to 6:20 pm. How much did he have to pay? Ans: $[?]",
      "answer0": "7.50",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "Method: charge the first hour, then the additional 15-minute blocks. 4:00 pm to 6:20 pm is 2 h 20 min. First hour = $3.30. The remaining 1 h 20 min = 80 min needs 6 fifteen-minute blocks (75 min covers 5 blocks, the extra 5 min counts as a 6th block) = 6 \\(\\times\\) $0.70 = $4.20. Total = $3.30 + $4.20 = $7.50. Answer: $7.50.",
      "hints": ["Charge the first hour separately, then look at the time after the first hour.", "After the first hour, count 15-minute blocks (every part block is charged): 80 min = 6 blocks."],
      "source": "Rulang 2025 P5 Weighted Assessment 3 Paper 2 Q1",
      "image_needed": true,
      "image_options": false,
      "image_page": 5,
      "image_bbox": [0.21, 0.16, 0.72, 0.22],
      "image_loc": "parking charges table below the question on page 5",
      "image_file": "q7.png",
      "notes": "Answer key Paper 2 Q1: $3.30 + ($0.70 x 6) = $7.50. Table: first hour $3.30; every additional 15 minutes or part thereof $0.70."
    },
    {
      "n": 8,
      "type_id": 2,
      "question": "Pail A contained \\(3.5\\,\\ell\\) of water at first. Sam poured \\(2.1\\,\\ell\\) of water from Pail A to Pail B which was empty.<br>(a) What was the difference in the volume of water between Pail A and Pail B in the end? Give your answer in litres. Ans: [?] l<br>(b) Sam poured the water left in Pail A into identical bottles, each with a capacity of 335 ml. How many such bottles could be filled completely with water? Ans: [?]",
      "answer0": "0.7",
      "answer1": "4",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 2,
      "explanation": "(a) Water left in Pail A = 3.5 \\(-\\) 2.1 = 1.4 \\(\\ell\\); Pail B = 2.1 \\(\\ell\\). Difference = 2.1 \\(-\\) 1.4 = 0.7 \\(\\ell\\). (b) Pail A has 1.4 \\(\\ell\\) = 1400 ml. 1400 \\(\\div\\) 335 = 4.17..., so only 4 bottles can be filled completely. Answers: (a) 0.7 l, (b) 4.",
      "hints": ["For (a), find how much is left in Pail A, then compare with Pail B's 2.1 l.", "For (b), change 1.4 l to ml and divide by 335; round DOWN since bottles must be filled completely."],
      "source": "Rulang 2025 P5 Weighted Assessment 3 Paper 2 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key Paper 2 Q2: a) 3.5-2.1=1.4; 2.1-1.4=0.7 l. b) 1400/335=4.179 approx 4 bottles (printed key writes '3.15-2.1=1.4' but the working value is 1.4 and difference 0.7)."
    },
    {
      "n": 9,
      "type_id": 2,
      "question": "A rectangular tank 30 cm long, 25 cm wide and 15 cm high was \\(\\dfrac{2}{3}\\) filled with water at first. Dan poured water out from the tank until the height of the water level in the tank became 3 cm. How much water did Dan pour out of the rectangular tank? Ans: [?] cm³<br>(a) How much water did Dan pour out of the rectangular tank if the tank measured 20 cm by 25 cm by 15 cm instead? Ans: [?] cm³<br>(b) How much water did Dan pour out of the rectangular tank if the tank was \\(\\dfrac{3}{4}\\) filled with water at first? Ans: [?] cm³",
      "answer0": "5250",
      "answer1": "3500",
      "answer2": "6187.5",
      "answer3": null,
      "correct_answer": null,
      "skill_id": 193,
      "difficulty_id": 3,
      "explanation": "Main: initial water height = \\(\\dfrac{2}{3}\\) of 15 cm = 10 cm; water poured out drops it to 3 cm, so 10 \\(-\\) 3 = 7 cm of water is removed. Volume out = 30 \\(\\times\\) 25 \\(\\times\\) 7 = 5250 cm³. (a) Same 7 cm removed, base 20 \\(\\times\\) 25: 20 \\(\\times\\) 25 \\(\\times\\) 7 = 3500 cm³. (b) Now initial height = \\(\\dfrac{3}{4}\\) of 15 = 11.25 cm; removed height = 11.25 \\(-\\) 3 = 8.25 cm; volume out = 30 \\(\\times\\) 25 \\(\\times\\) 8.25 = 6187.5 cm³. Answers: 5250 cm³; (a) 3500 cm³; (b) 6187.5 cm³.",
      "hints": ["Find the starting water height (a fraction of 15 cm), then subtract the final 3 cm to get the drop.", "Volume poured out = base area \\(\\times\\) drop in height."],
      "source": "Rulang 2025 P5 Weighted Assessment 3 Paper 2 Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key Paper 2 Q3: 15/3x2=10; 10-3=7; 30x25x7=5250. a) 20x25x7=3500. b) 15/4x3=11.25; 11.25-3=8.25; 30x25x8.25=6187.5 cm³. Three numeric blanks, all decimals/whole numbers so FIB is valid."
    }
  ]
}