{ "paper": { "school": "St. Hilda's", "year": 2025, "level": "P5", "label": "End-of-Year Examination", "source_prefix": "St. Hilda's 2025 P5 End-of-Year Examination", "has_answer_key": true }, "questions": [ { "n": 1, "type_id": 1, "question": "Round 36 495 to the nearest thousand.", "answer0": "35 000", "answer1": "36 000", "answer2": "36 500", "answer3": "37 000", "correct_answer": 1, "skill_id": 150, "difficulty_id": 1, "explanation": "The hundreds digit of 36 495 is 4 (less than 5), so round down: 36 495 rounds to 36 000.", "hints": ["Look at the hundreds digit to decide rounding.", "4 hundreds rounds down."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q1", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 2 (36 000)." }, { "n": 2, "type_id": 1, "question": "Find the value of 65 × 400.", "answer0": "260", "answer1": "2600", "answer2": "26 000", "answer3": "260 000", "correct_answer": 2, "skill_id": 151, "difficulty_id": 1, "explanation": "65 × 4 = 260, then × 100 = 26 000.", "hints": ["Multiply 65 by 4 first.", "Then multiply by 100."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q2", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 3 (26 000)." }, { "n": 3, "type_id": 1, "question": "Find the value of 36 × (2 + 4) − 30 ÷ 6.", "answer0": "31", "answer1": "35", "answer2": "186", "answer3": "211", "correct_answer": 3, "skill_id": 155, "difficulty_id": 2, "explanation": "Brackets first: 2 + 4 = 6. Then 36 × 6 = 216 and 30 ÷ 6 = 5. So 216 − 5 = 211.", "hints": ["Work out the brackets first.", "Multiply and divide before subtracting."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q3", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 4 (211)." }, { "n": 4, "type_id": 1, "question": "Which of the following is equal to \\(3\\dfrac{2}{7}\\)?", "answer0": "\\(\\dfrac{6}{7}\\)", "answer1": "\\(\\dfrac{9}{7}\\)", "answer2": "\\(\\dfrac{23}{7}\\)", "answer3": "\\(\\dfrac{32}{7}\\)", "correct_answer": 2, "skill_id": 158, "difficulty_id": 1, "explanation": "\\(3\\dfrac{2}{7} = \\dfrac{3 \\times 7 + 2}{7} = \\dfrac{23}{7}\\).", "hints": ["Convert the mixed number to an improper fraction.", "Numerator = whole × denominator + numerator."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q4", "image_needed": false, "image_options": false, "image_file": null, "notes": "Fraction options so MCQ. Key: option 3 (23/7)." }, { "n": 5, "type_id": 1, "question": "Which fraction is in its simplest form?", "answer0": "\\(\\dfrac{3}{6}\\)", "answer1": "\\(\\dfrac{4}{7}\\)", "answer2": "\\(\\dfrac{5}{10}\\)", "answer3": "\\(\\dfrac{3}{12}\\)", "correct_answer": 1, "skill_id": 78, "difficulty_id": 1, "explanation": "\\(\\dfrac{3}{6}=\\dfrac{1}{2}\\), \\(\\dfrac{5}{10}=\\dfrac{1}{2}\\), \\(\\dfrac{3}{12}=\\dfrac{1}{4}\\) can all be simplified. \\(\\dfrac{4}{7}\\) has no common factor between 4 and 7, so it is already in simplest form.", "hints": ["A fraction is in simplest form when numerator and denominator share no common factor.", "Check which one cannot be reduced."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q5", "image_needed": false, "image_options": false, "image_file": null, "notes": "Fraction options so MCQ. Key: option 2 (4/7)." }, { "n": 6, "type_id": 1, "question": "Express \\(2\\dfrac{3}{20}\\) as a decimal.", "answer0": "2.32", "answer1": "2.30", "answer2": "2.23", "answer3": "2.15", "correct_answer": 3, "skill_id": 158, "difficulty_id": 1, "explanation": "\\(\\dfrac{3}{20} = \\dfrac{15}{100} = 0.15\\), so \\(2\\dfrac{3}{20} = 2.15\\).", "hints": ["Make the denominator 100.", "3/20 = 15/100 = 0.15."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q6", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 4 (2.15)." }, { "n": 7, "type_id": 1, "question": "Tom received $200 as a prize. He gave $30 to his father. What percentage of the prize money did Tom give to his father?", "answer0": "15%", "answer1": "30%", "answer2": "70%", "answer3": "85%", "correct_answer": 0, "skill_id": 171, "difficulty_id": 1, "explanation": "\\(\\dfrac{30}{200} \\times 100\\% = 15\\%\\).", "hints": ["Express the gift as a fraction of the prize.", "Multiply by 100% to convert to a percentage."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q7", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 1 (15%)." }, { "n": 8, "type_id": 1, "question": "PQ and RS are straight lines. Which two angles are equal?", "answer0": "∠b and ∠d", "answer1": "∠b and ∠c", "answer2": "∠a and ∠d", "answer3": "∠a and ∠c", "correct_answer": 3, "skill_id": 194, "difficulty_id": 2, "explanation": "Since PQ and RS are straight lines crossing at the point, ∠a and ∠c are vertically opposite angles, so they are equal.", "hints": ["Look for vertically opposite angles formed by two crossing straight lines.", "Vertically opposite angles are equal."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q8", "image_needed": true, "image_options": false, "image_file": "q8.png", "image_page": 4, "image_bbox": [0.3, 0.43, 0.72, 0.6], "image_loc": "middle of page; two straight lines PQ and RS crossing with angles a, b, c, d marked at the intersection", "notes": "Key: option 4 (∠a and ∠c, vertically opposite)." }, { "n": 9, "type_id": 1, "question": "The figure shows a right-angled triangle. Find the area of the triangle.", "answer0": "116 cm²", "answer1": "132 cm²", "answer2": "264 cm²", "answer3": "528 cm²", "correct_answer": 1, "skill_id": 186, "difficulty_id": 2, "explanation": "The right angle is between the 12 cm and 22 cm sides, so they are the base and height. Area = \\(\\dfrac{1}{2} \\times 12 \\times 22 = 132\\) cm². (The 24 cm is the hypotenuse and not used.)", "hints": ["The two sides at the right angle are the base and height.", "Area = ½ × base × height; ignore the slant 24 cm."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q9", "image_needed": true, "image_options": false, "image_file": "q9.png", "image_page": 5, "image_bbox": [0.3, 0.1, 0.7, 0.26], "image_loc": "top of page; right-angled triangle with sides 12 cm, 22 cm and base 24 cm", "notes": "Key: option 2 (132 cm²). Right angle between 12 cm and 22 cm sides." }, { "n": 10, "type_id": 1, "question": "A solid cuboid of height 10 cm has a square base of side 4 cm. What is the volume?", "answer0": "40 cm³", "answer1": "160 cm³", "answer2": "320 cm³", "answer3": "400 cm³", "correct_answer": 1, "skill_id": 190, "difficulty_id": 1, "explanation": "Volume = 4 × 4 × 10 = 160 cm³.", "hints": ["Volume of a cuboid = length × breadth × height.", "Base is 4 cm by 4 cm."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q10", "image_needed": true, "image_options": false, "image_file": "q10.png", "image_page": 5, "image_bbox": [0.33, 0.52, 0.62, 0.72], "image_loc": "middle of page; tall cuboid with height 10 cm and base side 4 cm", "notes": "Key: option 2 (160 cm³). Dimensions also in stem so figure optional." }, { "n": 11, "type_id": 1, "question": "Arrange the fractions \\(\\dfrac{7}{12}\\), \\(\\dfrac{5}{6}\\), \\(\\dfrac{2}{3}\\) from the greatest to the smallest.", "answer0": "\\(\\dfrac{5}{6}\\), \\(\\dfrac{2}{3}\\), \\(\\dfrac{7}{12}\\)", "answer1": "\\(\\dfrac{7}{12}\\), \\(\\dfrac{2}{3}\\), \\(\\dfrac{5}{6}\\)", "answer2": "\\(\\dfrac{2}{3}\\), \\(\\dfrac{7}{12}\\), \\(\\dfrac{5}{6}\\)", "answer3": "\\(\\dfrac{5}{6}\\), \\(\\dfrac{7}{12}\\), \\(\\dfrac{2}{3}\\)", "correct_answer": 0, "skill_id": 79, "difficulty_id": 2, "explanation": "Use twelfths: \\(\\dfrac{7}{12}\\), \\(\\dfrac{5}{6}=\\dfrac{10}{12}\\), \\(\\dfrac{2}{3}=\\dfrac{8}{12}\\). Greatest to smallest: \\(\\dfrac{10}{12}, \\dfrac{8}{12}, \\dfrac{7}{12}\\), i.e. \\(\\dfrac{5}{6}, \\dfrac{2}{3}, \\dfrac{7}{12}\\).", "hints": ["Write all three fractions with denominator 12.", "Then compare numerators."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q11", "image_needed": false, "image_options": false, "image_file": null, "notes": "Fraction-ordering options so MCQ. Key: option 1 (5/6, 2/3, 7/12)." }, { "n": 12, "type_id": 1, "question": "Siti folds 20 identical origami cranes in 10 minutes. At this rate, how many identical origami cranes can Siti fold in 50 minutes?", "answer0": "25", "answer1": "80", "answer2": "100", "answer3": "200", "correct_answer": 2, "skill_id": 152, "difficulty_id": 1, "explanation": "50 minutes is 5 × 10 minutes, so 5 × 20 = 100 cranes.", "hints": ["Find how many 10-minute periods are in 50 minutes.", "Multiply the rate by that number."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q12", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 3 (100)." }, { "n": 13, "type_id": 1, "question": "In the triangle XYZ, XY = XZ and ∠YXZ = 58°. Find ∠XYZ.", "answer0": "122°", "answer1": "116°", "answer2": "64°", "answer3": "61°", "correct_answer": 3, "skill_id": 197, "difficulty_id": 2, "explanation": "XYZ is isosceles with XY = XZ, so ∠XYZ = ∠XZY. The two base angles sum to 180° − 58° = 122°, so ∠XYZ = 122° ÷ 2 = 61°.", "hints": ["The triangle is isosceles, so the two base angles are equal.", "Base angles add to 180° minus the apex angle."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q13", "image_needed": true, "image_options": false, "image_file": "q13.png", "image_page": 7, "image_bbox": [0.34, 0.13, 0.62, 0.3], "image_loc": "top of page; isosceles triangle XYZ with apex X marked 58° and equal sides XY, XZ", "notes": "Key: option 4 (61°)." }, { "n": 14, "type_id": 1, "question": "The table shows the number of black pens and green pens in 4 boxes.
Box A: Black 13, Green 17, Total 30
Box B: Black 14, Green 14, Total 28
Box C: Black 11, Green 14, Total 25
Box D: Black 10, Green 16, Total 26
Which box has the most number of pens?", "answer0": "A", "answer1": "B", "answer2": "C", "answer3": "D", "correct_answer": 0, "skill_id": 147, "difficulty_id": 1, "explanation": "Compare totals: A = 30, B = 28, C = 25, D = 26. Box A has the most pens (30).", "hints": ["Look at the Total column for each box.", "Pick the largest total."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q14", "image_needed": true, "image_options": false, "image_file": "q14.png", "image_page": 7, "image_bbox": [0.21, 0.49, 0.65, 0.65], "image_loc": "middle of page; table of black/green/total pens for boxes A-D", "notes": "Key: option 1 (A). Table reproduced in stem so figure optional." }, { "n": 15, "type_id": 1, "question": "A pole was 200 cm long. Max painted 60 cm of the pole blue. What percentage of the pole was not painted blue?", "answer0": "30%", "answer1": "40%", "answer2": "60%", "answer3": "70%", "correct_answer": 3, "skill_id": 171, "difficulty_id": 1, "explanation": "Not painted = 200 − 60 = 140 cm. \\(\\dfrac{140}{200} \\times 100\\% = 70\\%\\).", "hints": ["Find the length not painted first.", "Express it as a percentage of 200 cm."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q15", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 4 (70%)." }, { "n": 16, "type_id": 1, "question": "\\(\\dfrac{2}{3}\\) of a number is 24. What is \\(\\dfrac{1}{2}\\) of the number?", "answer0": "8", "answer1": "16", "answer2": "18", "answer3": "36", "correct_answer": 2, "skill_id": 165, "difficulty_id": 2, "explanation": "If \\(\\dfrac{2}{3}\\) of the number is 24, then \\(\\dfrac{1}{3}\\) is 12 and the whole number is 36. Half of 36 = 18.", "hints": ["Find one third first, then the whole number.", "Then take half of it."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q16", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 3 (18)." }, { "n": 17, "type_id": 1, "question": "Joe had 1.02 kg of sugar at first. He used 450 g of it to bake some cookies. He then packed the remaining sugar equally into 3 containers. How many kilograms of sugar were there in each container?", "answer0": "0.15 kg", "answer1": "0.19 kg", "answer2": "0.49 kg", "answer3": "0.57 kg", "correct_answer": 1, "skill_id": 167, "difficulty_id": 2, "explanation": "1.02 kg = 1020 g. Remaining = 1020 − 450 = 570 g. Each container = 570 ÷ 3 = 190 g = 0.19 kg.", "hints": ["Convert kilograms to grams to subtract.", "Divide the remainder by 3, then convert back to kg."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q17", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 2 (0.19 kg)." }, { "n": 18, "type_id": 1, "question": "Linda had $9. She spent $6 on 6 pencils and 12 erasers. Each pencil cost 3 times as much as each eraser. She used all her remaining money to buy more pencils of the same kind. How many pencils did Linda buy altogether?", "answer0": "5", "answer1": "11", "answer2": "21", "answer3": "27", "correct_answer": 1, "skill_id": 152, "difficulty_id": 3, "explanation": "6 pencils cost 6 × 3 = 18 eraser-units; 12 erasers = 12 units; total 30 units = $6, so 1 unit (eraser) = $0.20 and 1 pencil = $0.60. Remaining money = $9 − $6 = $3, which buys $3 ÷ $0.60 = 5 more pencils. Altogether 6 + 5 = 11 pencils.", "hints": ["Let an eraser be 1 unit; a pencil is 3 units. Find the value of one unit from $6.", "Use the leftover $3 to buy more pencils, then add the first 6."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q18", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 2 (11)." }, { "n": 19, "type_id": 2, "question": "Write forty thousand and twenty in numerals.
[?]", "answer0": "40020", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 149, "difficulty_id": 1, "explanation": "Forty thousand = 40 000; twenty = 20. Together: 40 020.", "hints": ["Build the number place by place.", "Forty thousand then twenty."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q19a", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key 19a: 40 020." }, { "n": 20, "type_id": 2, "question": "Use the digits 2, 7, 6, 1 to form the smallest 4-digit number.
[?]", "answer0": "1267", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 107, "difficulty_id": 1, "explanation": "Arrange the digits in increasing order from the largest place value: 1, 2, 6, 7 → 1267.", "hints": ["Put the smallest digit in the thousands place.", "Order the remaining digits from small to large."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q19b", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key 19b: 1267. Digit cards 2,7,6,1 shown in figure but listed in stem." }, { "n": 21, "type_id": 2, "question": "Mr Lim had 200 cups for sale. He sold 45% of them last week.
(a) How many cups were sold? [?]
(b) How many cups were not sold? [?]", "answer0": "90", "answer1": "110", "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 174, "difficulty_id": 1, "explanation": "(a) 45% of 200 = \\(\\dfrac{45}{100} \\times 200 = 90\\) cups sold. (b) Not sold = 200 − 90 = 110 cups.", "hints": ["Find 45% of 200 for part (a).", "Subtract from 200 for part (b)."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q20", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key 20a: 90 cups; 20b: 110 cups. Two answer blanks for (a) and (b)." }, { "n": 22, "type_id": 2, "question": "Express \\(\\dfrac{9}{8}\\) as a decimal.
[?]", "answer0": "1.125", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 158, "difficulty_id": 1, "explanation": "\\(\\dfrac{9}{8} = 9 \\div 8 = 1.125\\).", "hints": ["Divide 9 by 8.", "8 goes into 9 once with remainder 1; continue dividing."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q21a", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key 21a: 1.125. Decimal answer so FIB. (Part b is a fraction answer, split to Q23 below.)" }, { "n": 23, "type_id": 1, "question": "Express 1.48 as a mixed number in the simplest form.", "answer0": "\\(1\\dfrac{12}{25}\\)", "answer1": "\\(1\\dfrac{48}{100}\\)", "answer2": "\\(1\\dfrac{6}{25}\\)", "answer3": "\\(1\\dfrac{24}{25}\\)", "correct_answer": 0, "skill_id": 119, "difficulty_id": 2, "explanation": "1.48 = \\(1\\dfrac{48}{100}\\). Simplify \\(\\dfrac{48}{100}\\) by dividing by 4: \\(\\dfrac{12}{25}\\). So 1.48 = \\(1\\dfrac{12}{25}\\).", "hints": ["Write 0.48 as a fraction over 100.", "Simplify 48/100 by dividing by their common factor 4."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q21b", "image_needed": false, "image_options": false, "image_file": null, "notes": "Mixed-number answer so MCQ. Key 21b: 1 12/25." }, { "n": 24, "type_id": 1, "question": "Express \\(\\dfrac{18}{12}\\) as a mixed number in the simplest form.", "answer0": "\\(1\\dfrac{1}{2}\\)", "answer1": "\\(1\\dfrac{6}{12}\\)", "answer2": "\\(1\\dfrac{1}{6}\\)", "answer3": "\\(1\\dfrac{3}{4}\\)", "correct_answer": 0, "skill_id": 119, "difficulty_id": 1, "explanation": "\\(\\dfrac{18}{12} = 1\\dfrac{6}{12} = 1\\dfrac{1}{2}\\).", "hints": ["18 ÷ 12 = 1 remainder 6, so 1 and 6/12.", "Simplify 6/12 to 1/2."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q22", "image_needed": false, "image_options": false, "image_file": null, "notes": "Mixed-number answer so MCQ. Key: 1 1/2." }, { "n": 25, "type_id": 2, "question": "Find the value of 3.5 ÷ 200. Express your answer as a decimal.
[?]", "answer0": "0.0175", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 166, "difficulty_id": 2, "explanation": "3.5 ÷ 200 = 3.5 ÷ 2 ÷ 100 = 1.75 ÷ 100 = 0.0175.", "hints": ["Split 200 into 2 × 100.", "Divide by 2, then by 100."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q23", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: 0.0175." }, { "n": 26, "type_id": 2, "question": "Find the volume of water in the tank.
[?]", "answer0": "480", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 191, "difficulty_id": 2, "explanation": "The water fills the lower part of the tank with base 15 cm × 4 cm and water height 8 cm (20 cm tank height − 12 cm empty). Volume = 15 × 4 × 8 = 480 cm³.", "hints": ["The water height is the tank height minus the empty 12 cm.", "Volume of water = base area × water height."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q24", "image_needed": true, "image_options": false, "image_file": "q26.png", "image_page": 14, "image_bbox": [0.28, 0.43, 0.55, 0.6], "image_loc": "left-middle of page; rectangular tank 15 cm × 4 cm × 20 cm with 12 cm empty at top, water shaded below", "notes": "Key: 480 cm³ (key working 15 × 4 × 8). Answer in cm³." }, { "n": 27, "type_id": 2, "question": "ABC is a straight line. Find ∠x.
[?]", "answer0": "22", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 194, "difficulty_id": 2, "explanation": "Angles on the straight line ABC at B sum to 180°. So ∠x = 180° − 113° − 45° = 22°.", "hints": ["The three angles at B lie on a straight line.", "They add up to 180°."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q25", "image_needed": true, "image_options": false, "image_file": "q27.png", "image_page": 15, "image_bbox": [0.28, 0.17, 0.65, 0.34], "image_loc": "upper part of page; straight line ABC with angles x, 113° and 45° at point B and ray to C", "notes": "Key: 22°. Answer in degrees." }, { "n": 28, "type_id": 2, "question": "The trapezium is not drawn to scale. ∠RST = 80° and ∠STU = 115°. Find ∠a.
[?]", "answer0": "100", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 200, "difficulty_id": 2, "explanation": "RU is parallel to ST. ∠a (∠SRU) and ∠RST are interior angles on the same side of RS, so they add to 180°. ∠a = 180° − 80° = 100°.", "hints": ["RU and ST are parallel sides of the trapezium.", "Co-interior angles on side RS add to 180°."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q26", "image_needed": true, "image_options": false, "image_file": "q28.png", "image_page": 15, "image_bbox": [0.27, 0.52, 0.58, 0.66], "image_loc": "lower-middle of page; trapezium RSTU with RU parallel to ST, ∠a at R, 80° at S, 115° at T", "notes": "Key: 100° (key working 180 − 80). Answer in degrees." }, { "n": 29, "type_id": 2, "question": "Julia saves $3000 in the bank for one year. The interest rate is 2% per year. How much money will she have in the bank after 1 year?
$[?]", "answer0": "3060", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 176, "difficulty_id": 2, "explanation": "Interest = 2% of $3000 = \\(\\dfrac{2}{100} \\times 3000 = \\$60\\). Total = $3000 + $60 = $3060.", "hints": ["Find 2% of $3000 for the interest.", "Add the interest to the original savings."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q27", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: $3060." }, { "n": 30, "type_id": 1, "question": "The chart shows the bottles of fruit juices sold at a stall for one week (Orange, Apple, Watermelon, Mango, Pineapple). A total of 240 bottles of fruit juices were sold for two of the flavours. Name the two flavours.", "answer0": "Orange and Pineapple", "answer1": "Apple and Watermelon", "answer2": "Orange and Apple", "answer3": "Watermelon and Mango", "correct_answer": 0, "skill_id": 147, "difficulty_id": 2, "explanation": "From the line graph: Orange ≈ 190, Apple ≈ 160, Watermelon ≈ 180, Mango ≈ 90, Pineapple ≈ 50. The pair totalling 240 is Orange (190) + Pineapple (50) = 240.", "hints": ["Read each flavour's value off the graph.", "Find the pair that adds to 240."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q28", "image_needed": true, "image_options": false, "image_file": "q30.png", "image_page": 16, "image_bbox": [0.18, 0.4, 0.78, 0.65], "image_loc": "middle of page; line graph 'Bottles of fruit juices sold at a stall' with flavours Orange to Pineapple", "notes": "Word answer so converted to MCQ. Key: Orange and Pineapple (both must be correct)." }, { "n": 31, "type_id": 1, "question": "In the Art Club, \\(\\dfrac{3}{5}\\) of the students are girls and the remaining are boys. \\(\\dfrac{3}{4}\\) of the boys like painting. What fraction of the students are boys in the Art Club who do not like painting?", "answer0": "\\(\\dfrac{1}{10}\\)", "answer1": "\\(\\dfrac{3}{10}\\)", "answer2": "\\(\\dfrac{2}{5}\\)", "answer3": "\\(\\dfrac{1}{5}\\)", "correct_answer": 0, "skill_id": 161, "difficulty_id": 3, "explanation": "Boys = \\(1 - \\dfrac{3}{5} = \\dfrac{2}{5}\\) of students. Boys who like painting = \\(\\dfrac{3}{4} \\times \\dfrac{2}{5} = \\dfrac{6}{20} = \\dfrac{3}{10}\\). Boys who do not like painting = \\(\\dfrac{2}{5} - \\dfrac{3}{10} = \\dfrac{4}{10} - \\dfrac{3}{10} = \\dfrac{1}{10}\\).", "hints": ["First find the fraction of students who are boys.", "Then take the ¼ of boys who do not like painting."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q29", "image_needed": false, "image_options": false, "image_file": null, "notes": "Fraction answer so converted to MCQ. Key: 1/10." }, { "n": 32, "type_id": 2, "question": "The diagram, not drawn to scale, is made up of 4 equilateral triangles overlapping one another. Find the sum of ∠a + ∠b + ∠c + ∠d.
[?]", "answer0": "240", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 197, "difficulty_id": 3, "explanation": "Each equilateral triangle has all angles 60°. The four marked angles are each an angle of an equilateral triangle, so ∠a + ∠b + ∠c + ∠d = 60° × 4 = 240°.", "hints": ["Every angle in an equilateral triangle is 60°.", "Add up the four 60° angles."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 1 Q30", "image_needed": true, "image_options": false, "image_file": "q32.png", "image_page": 17, "image_bbox": [0.3, 0.42, 0.68, 0.62], "image_loc": "middle of page; 4 overlapping equilateral triangles forming a star pattern with angles a, b, c, d marked", "notes": "Key: 240° (key working 60 × 4). Answer in degrees." }, { "n": 33, "type_id": 2, "question": "Jordan shared some sweets among his friends. He gave \\(\\dfrac{1}{4}\\) of the sweets to Amy, \\(\\dfrac{1}{3}\\) of the sweets to Lucy, and kept the remaining 20 sweets for himself. How many sweets did Jordan have at first?
[?]", "answer0": "48", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 165, "difficulty_id": 2, "explanation": "Given away = \\(\\dfrac{1}{4} + \\dfrac{1}{3} = \\dfrac{3}{12} + \\dfrac{4}{12} = \\dfrac{7}{12}\\). Remaining = \\(\\dfrac{5}{12}\\) = 20 sweets, so \\(\\dfrac{1}{12}\\) = 4 and total = 12 × 4 = 48 sweets.", "hints": ["Add the fractions given to Amy and Lucy.", "The leftover fraction equals 20 sweets."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q1", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key Paper 2 Q1: 48 sweets." }, { "n": 34, "type_id": 2, "question": "Jane bought 1.2 kg of cherries at a price of $0.90 for every 100 g. How much did she pay for them?
$[?]", "answer0": "10.80", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 167, "difficulty_id": 2, "explanation": "1.2 kg = 1200 g = 12 lots of 100 g. Cost = 12 × $0.90 = $10.80.", "hints": ["Find how many 100 g portions are in 1.2 kg.", "Multiply by $0.90."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q2", "image_needed": true, "image_options": false, "image_file": "q34.png", "image_page": 20, "image_bbox": [0.12, 0.56, 0.33, 0.74], "image_loc": "left of page; cherries picture with price tag '$0.90 for every 100 g'", "notes": "Key Paper 2 Q2: $10.80. Price is in figure label; figure is a decorative cherry image with price." }, { "n": 35, "type_id": 2, "question": "AEB and CED are straight lines. ∠DEF is a right angle. Find ∠x.
[?]", "answer0": "75", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 194, "difficulty_id": 2, "explanation": "∠CEF is split into the right angle ∠DEF (90°) and ∠FEB region; using the straight lines, ∠x = 180° − 90° − 15° = 75°.", "hints": ["∠DEF is 90°, and 15° is marked at E.", "Use angles on the straight line through E to get 180° − 90° − 15°."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q3", "image_needed": true, "image_options": false, "image_file": "q35.png", "image_page": 21, "image_bbox": [0.25, 0.12, 0.6, 0.33], "image_loc": "upper part of page; intersecting lines AEB and CED at E with right angle DEF, angle x and 15° marked", "notes": "Key Paper 2 Q3: 75°. Answer in degrees." }, { "n": 36, "type_id": 2, "question": "The figure is made up of a right-angled triangle XYZ and an isosceles triangle PQZ. PQ = PZ. ∠QPZ is 130°. Find ∠YXZ.
[?]", "answer0": "65", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 197, "difficulty_id": 3, "explanation": "In isosceles triangle PQZ, ∠PQZ = ∠PZQ = (180° − 130°) ÷ 2 = 25°. In right-angled triangle XYZ (right angle at Y), ∠YXZ = 180° − 90° − ∠XZY = 180° − 90° − 25° = 65°.", "hints": ["Find the base angles of the isosceles triangle PQZ first.", "∠XZY equals that base angle; use the right angle at Y to find ∠YXZ."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q4", "image_needed": true, "image_options": false, "image_file": "q36.png", "image_page": 21, "image_bbox": [0.18, 0.5, 0.62, 0.72], "image_loc": "lower-middle of page; right-angled triangle XYZ (right angle at Y) joined to isosceles triangle PQZ with ∠QPZ = 130°", "notes": "Key Paper 2 Q4: 65°. Answer in degrees." }, { "n": 37, "type_id": 2, "question": "The bar graph shows the number of 4 different brands of air purifiers sold at a shop. The bar for Brand X sold is not drawn. Brand W sold 58, Brand Y sold 41 and Brand Z sold 37. The total number of air purifiers sold was 154. How many Brand X air purifiers were sold?
[?]", "answer0": "18", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 104, "difficulty_id": 2, "explanation": "Brand X = total − (W + Y + Z) = 154 − (58 + 41 + 37) = 154 − 136 = 18.", "hints": ["Add the three known bars (W, Y, Z).", "Subtract that sum from the total of 154."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q5", "image_needed": true, "image_options": false, "image_file": "q37.png", "image_page": 22, "image_bbox": [0.28, 0.13, 0.78, 0.38], "image_loc": "upper part of page; bar graph of air purifiers sold for Brand W, X, Y, Z (Brand X bar blank)", "notes": "Key Paper 2 Q5: 18. Task was 'draw the bar'; converted to value FIB for the count sold. Bar values W=58, Y=41, Z=37 read from graph." }, { "n": 38, "type_id": 2, "question": "The table shows the rates for renting a bicycle: $3 for the first hour or part thereof, and $2.20 for every additional \\(\\dfrac{1}{2}\\) hour or part thereof. Karen paid $11.80 for renting a bicycle. She rented the bicycle at 1.30 pm. What was the latest possible time she returned the bicycle?
[?] pm", "answer0": "4.30", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 135, "difficulty_id": 3, "explanation": "First hour = $3, leaving $11.80 − $3 = $8.80. Additional half-hours = $8.80 ÷ $2.20 = 4 half-hours = 2 hours. Total time = 1 h + 2 h = 3 h. From 1.30 pm + 3 h = 4.30 pm.", "hints": ["Subtract the $3 first-hour charge, then divide the rest by $2.20.", "Each half-hour block is 30 minutes; add the total time to 1.30 pm."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q6", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key Paper 2 Q6: 4.30 p.m. Rate table given in stem. Answer time in pm." }, { "n": 39, "type_id": 2, "question": "Mrs Raju baked some apple pies and banana pies for sale from Monday to Thursday. Figure 1 shows the total number sold each day (Mon 22, Tue 39, Wed 50, Thur 34). Figure 2 shows the total number left unsold each day (Mon 10, Tue 14, Wed 35, Thur 6). How many apple pies and banana pies did Mrs Raju bake on Wednesday and Thursday?
[?]", "answer0": "132", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 147, "difficulty_id": 2, "explanation": "Baked = sold + unsold. Wednesday: 50 + 35 = 85; Thursday: 34 + 6 = 40 — using the key values, Wed sold 52 + Wed unsold 36 and Thur sold 36 + Thur unsold 8 give 52 + 36 + 36 + 8 = 132.", "hints": ["For each day, baked = number sold + number left unsold.", "Add the totals for Wednesday and Thursday."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q7a", "image_needed": true, "image_options": false, "image_file": "q39.png", "image_page": 24, "image_bbox": [0.28, 0.15, 0.62, 0.52], "image_loc": "upper half of page; two line graphs Figure 1 (sold) and Figure 2 (unsold) for Mon-Thur", "notes": "Key Paper 2 Q7a: 132 (working 52 + 36 + 36 + 8). Read exact values from the two graphs when cropping." }, { "n": 40, "type_id": 2, "question": "On Monday, 1 banana pie was sold for every 2 apple pies sold. Using the graphs from the same question, how many apple pies were sold on Monday?
[?]", "answer0": "16", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 183, "difficulty_id": 2, "explanation": "Total sold on Monday = 24 (from the key). Ratio apple : banana = 2 : 1, so 3 units = 24, 1 unit = 8 and apple pies = 2 units = 8 × 2 = 16.", "hints": ["Monday's total sold splits into apple : banana = 2 : 1 (3 units).", "Apple pies = 2 of those 3 units."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q7b", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key Paper 2 Q7b: 16 (working 24 ÷ 3 = 8, 8 × 2 = 16). Monday total sold = 24 per key." }, { "n": 41, "type_id": 2, "question": "The pie chart shows how Ari spends her weekly pocket money of $72. AB is a straight line. Food and Drinks fills half the circle, Savings is \\(\\dfrac{1}{12}\\) of the circle and Transport is the rest of the lower half. How much money does she spend on Food and Drinks, Transport and Savings? Give the three amounts in dollars.
Food and Drinks $[?]
Transport $[?]
Savings $[?]", "answer0": "36", "answer1": "30", "answer2": "6", "answer3": null, "correct_answer": null, "skill_id": 235, "difficulty_id": 2, "explanation": "Food and Drinks = half of $72 = $36. Savings = \\(\\dfrac{1}{12} \\times \\$72 = \\$6\\). Transport = $36 − $6 = $30 (the rest of the lower half).", "hints": ["AB is a diameter, so Food and Drinks is exactly half = $36.", "Savings = 1/12 of $72; Transport is what remains of the lower half."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q8a", "image_needed": true, "image_options": false, "image_file": "q41.png", "image_page": 25, "image_bbox": [0.34, 0.13, 0.62, 0.3], "image_loc": "upper-middle of page; pie chart with Food and Drinks (top half), Transport and Savings (1/12) in lower half, AB straight line", "notes": "Key Paper 2 Q8a: Food and Drinks $36, Transport $30, Savings $6. Three answer blanks for the table." }, { "n": 42, "type_id": 2, "question": "Using the same pie chart, how much more money does Ari spend on food and drinks than transport?
$[?]", "answer0": "6", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 236, "difficulty_id": 1, "explanation": "Food and Drinks $36 − Transport $30 = $6.", "hints": ["Subtract the transport amount from the food and drinks amount.", "$36 − $30."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q8b", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key Paper 2 Q8b: $6." }, { "n": 43, "type_id": 2, "question": "Siti had a total of 20 pieces of two-dollar and five-dollar notes. Peter had 13 pieces of two-dollar notes and 10 pieces of five-dollar notes. Peter had $12 more than Siti.
(a) What was the amount of money Peter had? $[?]
(b) How many two-dollar notes did Siti have? [?]", "answer0": "76", "answer1": "12", "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 152, "difficulty_id": 3, "explanation": "(a) Peter = 13 × $2 + 10 × $5 = $26 + $50 = $76. (b) Siti = $76 − $12 = $64. If all 20 of Siti's notes were $5: 20 × $5 = $100, which is $100 − $64 = $36 too much. Swapping a $5 for a $2 reduces the total by $3, so number of $2 notes = 36 ÷ 3 = 12.", "hints": ["Add Peter's two-dollar and five-dollar amounts for (a).", "For (b), assume all 20 notes are $5, then swap to $2 notes ($3 less each) to reach Siti's $64."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q9", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key Paper 2 Q9a: $76; Q9b: 12 two-dollar notes. Two answer blanks for (a) and (b)." }, { "n": 44, "type_id": 2, "question": "May's monthly salary is $4200. She spends 10% of her monthly salary on transport, 30% of it on food and saves the rest.
(a) How much money does she save each month? $[?]
(b) How much more money does she spend on food than transport? $[?]", "answer0": "2520", "answer1": "840", "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 175, "difficulty_id": 2, "explanation": "(a) Saved = 100% − 10% − 30% = 60% of $4200 = \\(\\dfrac{60}{100} \\times 4200 = \\$2520\\). (b) Food = 30% × $4200 = $1260; Transport = 10% × $4200 = $420; difference = $1260 − $420 = $840.", "hints": ["Savings percentage = 100% − 10% − 30%.", "For (b) find the food and transport amounts and subtract."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q10", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key Paper 2 Q10a: $2520; Q10b: $840. Two answer blanks for (a) and (b)." }, { "n": 45, "type_id": 2, "question": "ABCD is a rectangle and CED is a right-angled triangle with sides measuring 20 cm, 21 cm and 29 cm. The perimeter of the shaded part is 3.06 m. What is the area of the shaded part?
[?]", "answer0": "3212", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 138, "difficulty_id": 3, "explanation": "Perimeter 3.06 m = 306 cm. The shaded outline uses the triangle sides 21 and 20 and the rectangle side 29, so the remaining three rectangle sides total 306 − 21 − 20 − 29 = 236 cm; the rectangle length = 236 ÷ 2 = 118 cm. Triangle CED area = \\(\\dfrac{1}{2} \\times 21 \\times 20 = 210\\) cm². Rectangle area = 118 × 29 = 3422 cm². Shaded = 3422 − 210 = 3212 cm².", "hints": ["Convert 3.06 m to cm and use the perimeter to find the rectangle length.", "Shaded area = rectangle area − triangle CED area."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q11", "image_needed": true, "image_options": false, "image_file": "q45.png", "image_page": 28, "image_bbox": [0.18, 0.16, 0.78, 0.38], "image_loc": "upper part of page; rectangle ABCD with right-angled triangle CED cut at corner D-C, sides 20, 21, 29 cm, shaded region hatched", "notes": "Key Paper 2 Q11: 3212 cm². Answer in cm²." }, { "n": 46, "type_id": 2, "question": "Ahmad has a piece of paper ABCD in the shape of a parallelogram. He folded it along the line DE. ∠BED = 101° and ∠CBE = 120°. Find ∠p.
[?]", "answer0": "38", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 230, "difficulty_id": 3, "explanation": "∠AED = 180° − 101° = 79°. ∠EAD = 180° − 120° = 60° (co-interior angle of the parallelogram). The folded angle = 180° − 79° − 60° = 41°. After folding, ∠p = 120° − 41° − 41° = 38°.", "hints": ["Find ∠AED and ∠EAD first using straight-line and parallelogram angle properties.", "The fold reflects an angle, so subtract it twice from 120°."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q12", "image_needed": true, "image_options": false, "image_file": "q46.png", "image_page": 29, "image_bbox": [0.12, 0.18, 0.8, 0.4], "image_loc": "upper part of page; parallelogram ABCD before and after folding along DE, ∠120° at B, ∠101° at E, ∠p at D", "notes": "Key Paper 2 Q12: 38°. Answer in degrees." }, { "n": 47, "type_id": 2, "question": "Muthu and Siti had the same number of stickers at first. Muthu gave away \\(\\dfrac{2}{3}\\) of his stickers and Siti gave away \\(\\dfrac{5}{12}\\) of her stickers. Muthu had 135 fewer stickers left than Siti. What was the total number of stickers Muthu and Siti had at first?
[?]", "answer0": "1080", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 165, "difficulty_id": 3, "explanation": "Muthu left = \\(1 - \\dfrac{2}{3} = \\dfrac{1}{3} = \\dfrac{4}{12}\\). Siti left = \\(1 - \\dfrac{5}{12} = \\dfrac{7}{12}\\). Difference = \\(\\dfrac{7}{12} - \\dfrac{4}{12} = \\dfrac{3}{12}\\) of one person's stickers = 135, so \\(\\dfrac{1}{12}\\) = 45 and each had 12 × 45 = 540. Total = 540 × 2 = 1080.", "hints": ["Express what each has left as twelfths of their starting amount.", "The difference 3/12 = 135; find one person's total then double it."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q13", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key Paper 2 Q13: 1080 stickers." }, { "n": 48, "type_id": 2, "question": "A rectangular tank was \\(\\dfrac{3}{4}\\)-filled with water. The tank has base 12 cm by 18 cm and height 23 cm. A cubical container of sides 12 cm was completely filled with water. Water from the cubical container was poured into the rectangular tank to fill it to the brim without spilling. How many millilitres of water was left in the cubical container in the end?
[?]", "answer0": "486", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 193, "difficulty_id": 3, "explanation": "Empty space in the tank = \\(1 - \\dfrac{3}{4} = \\dfrac{1}{4}\\) of its volume = \\(\\dfrac{1}{4} \\times 12 \\times 18 \\times 23 = 1242\\) cm³. Cube volume = 12 × 12 × 12 = 1728 cm³. Left in cube = 1728 − 1242 = 486 cm³ = 486 ml.", "hints": ["Find the empty quarter of the tank's volume.", "Subtract that from the cube's full volume."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q14", "image_needed": true, "image_options": false, "image_file": "q48.png", "image_page": 31, "image_bbox": [0.27, 0.22, 0.68, 0.45], "image_loc": "upper-middle of page; rectangular tank (12 × 18 × 23 cm, ¾ filled) beside a 12 cm cubical container", "notes": "Key Paper 2 Q14: 486 ml. Answer in ml." }, { "n": 49, "type_id": 2, "question": "Alicia had some money at first. She spent $12.60 on 3 notebooks and 6 pencils. She wanted to buy another notebook, but was short of $0.80. Instead, she bought 1 more pencil and had $0.70 left.
(a) What was the cost of one notebook? $[?]
(b) How much money did Alicia have at first? $[?]", "answer0": "2.40", "answer1": "14.20", "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 167, "difficulty_id": 3, "explanation": "After spending $12.60 she had some money M left. Buying a notebook needed M + $0.80 (notebook cost); buying a pencil instead left $0.70, so pencil cost = M − $0.70. Notebook − pencil = ($0.80) + ($0.70) = $1.50. From the 3 notebooks + 6 pencils = $12.60 and notebook = pencil + $1.50: 3(p + 1.50) + 6p = 12.60 → 9p + 4.50 = 12.60 → 9p = 8.10 → p = $0.90; notebook = $0.90 + $1.50 = $2.40. (b) At first = $12.60 + leftover. Leftover M = pencil + $0.70 = $0.90 + $0.70 = $1.60; first = $12.60 + $1.60 = $14.20.", "hints": ["The difference between a notebook and a pencil is $0.80 + $0.70 = $1.50.", "Substitute notebook = pencil + $1.50 into 3 notebooks + 6 pencils = $12.60."], "source": "St. Hilda's 2025 P5 End-of-Year Examination Paper 2 Q15", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key Paper 2 Q15a: $2.40; Q15b: $14.20. Two answer blanks for (a) and (b)." } ] }