{
  "paper": {
    "school": "St. Hilda's",
    "year": 2025,
    "level": "P5",
    "label": "Weighted Assessment 2",
    "source_prefix": "St. Hilda's 2025 P5 Weighted Assessment 2",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "What is the value of \\(70 + \\dfrac{7}{10} + \\dfrac{7}{100}\\)?",
      "answer0": "77.07",
      "answer1": "70.77",
      "answer2": "70.077",
      "answer3": "70.707",
      "correct_answer": 1,
      "skill_id": 158,
      "difficulty_id": 1,
      "explanation": "\\(\\dfrac{7}{10} = 0.7\\) and \\(\\dfrac{7}{100} = 0.07\\). So \\(70 + 0.7 + 0.07 = 70.77\\). Answer: 70.77 (option 2).",
      "hints": ["Write each fraction as a decimal: \\(\\dfrac{7}{10} = 0.7\\), \\(\\dfrac{7}{100} = 0.07\\).", "Add the three values, lining up the decimal points."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "notes": "Paper 1 (Booklet A) Q1 [1m]. Answer key: option 2 (70.77)."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "Find the product of \\(\\dfrac{3}{8}\\) and \\(\\dfrac{1}{4}\\).",
      "answer0": "\\(\\dfrac{1}{8}\\)",
      "answer1": "\\(\\dfrac{5}{8}\\)",
      "answer2": "\\(\\dfrac{3}{4}\\)",
      "answer3": "\\(\\dfrac{3}{32}\\)",
      "correct_answer": 3,
      "skill_id": 161,
      "difficulty_id": 1,
      "explanation": "Multiply numerators and denominators: \\(\\dfrac{3}{8} \\times \\dfrac{1}{4} = \\dfrac{3 \\times 1}{8 \\times 4} = \\dfrac{3}{32}\\). Answer: \\(\\dfrac{3}{32}\\) (option 4).",
      "hints": ["Multiply the numerators together and the denominators together.", "\\(\\dfrac{3 \\times 1}{8 \\times 4}\\)."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "notes": "Paper 1 (Booklet A) Q2 [1m]. Fraction options -> MCQ. Answer key: option 4 (3/32)."
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "A solid cuboid of height 5 cm has a square base of side 3 cm. What is its volume?",
      "answer0": "15 cm³",
      "answer1": "30 cm³",
      "answer2": "45 cm³",
      "answer3": "75 cm³",
      "correct_answer": 2,
      "skill_id": 190,
      "difficulty_id": 1,
      "explanation": "Volume of a cuboid = length \\(\\times\\) breadth \\(\\times\\) height. The square base is 3 cm by 3 cm and the height is 5 cm, so volume = \\(3 \\times 3 \\times 5 = 45\\) cm³. Answer: 45 cm³ (option 3).",
      "hints": ["The base is a 3 cm by 3 cm square.", "Volume = base area \\(\\times\\) height = \\(3 \\times 3 \\times 5\\)."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q3",
      "image_needed": true,
      "image_options": false,
      "image_file": "q3.png",
      "image_page": 2,
      "image_bbox": [0.46, 0.09, 0.66, 0.24],
      "notes": "Paper 1 (Booklet A) Q3 [1m]. Cuboid figure, base 3 cm, height 5 cm. Answer key: option 3 (45 cm³)."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "The figure shows Triangle ABD. When the base is AD, what is the height of Triangle ABD?",
      "answer0": "AB",
      "answer1": "AE",
      "answer2": "BC",
      "answer3": "BD",
      "correct_answer": 1,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "The height is the perpendicular distance from the opposite vertex to the base (or to the base extended). With AD as the base, the perpendicular drawn is AE, which meets the line through the base at a right angle. Answer: AE (option 2).",
      "hints": ["The height is perpendicular to the chosen base AD.", "Look for the dashed line meeting AD (extended) at a right angle."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q4",
      "image_needed": true,
      "image_options": false,
      "image_file": "q4.png",
      "image_page": 2,
      "image_bbox": [0.30, 0.37, 0.66, 0.56],
      "notes": "Paper 1 (Booklet A) Q4 [1m]. Triangle ABD with points C and E and dashed perpendiculars. Answer key: option 2 (AE)."
    },
    {
      "n": 5,
      "type_id": 1,
      "question": "Find the area of the shaded triangle.",
      "answer0": "24 cm²",
      "answer1": "40 cm²",
      "answer2": "50 cm²",
      "answer3": "64 cm²",
      "correct_answer": 1,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "The shaded triangle has its base along the bottom of length 10 cm and a perpendicular height of 8 cm. Area = \\(\\dfrac{1}{2} \\times 10 \\times 8 = 40\\) cm². Answer: 40 cm² (option 2).",
      "hints": ["Identify the base (10 cm) and the perpendicular height (8 cm).", "Area of a triangle = \\(\\dfrac{1}{2} \\times \\text{base} \\times \\text{height}\\)."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q5",
      "image_needed": true,
      "image_options": false,
      "image_file": "q5.png",
      "image_page": 3,
      "image_bbox": [0.26, 0.10, 0.70, 0.27],
      "notes": "Paper 1 (Booklet A) Q5 [1m]. Shaded triangle, base 10 cm (+6 cm), slant 10 cm, height 8 cm. Answer key: option 2 (40 cm²)."
    },
    {
      "n": 6,
      "type_id": 1,
      "question": "The solid figure is made up of 1-cm cubes. Find the volume of the solid.",
      "answer0": "11 cm³",
      "answer1": "13 cm³",
      "answer2": "15 cm³",
      "answer3": "17 cm³",
      "correct_answer": 3,
      "skill_id": 188,
      "difficulty_id": 2,
      "explanation": "Each cube has a volume of 1 cm³, so the volume equals the number of cubes. Counting all the cubes in the solid (including the hidden ones supporting the upper cubes) gives 17 cubes. Volume = 17 cm³. Answer: 17 cm³ (option 4).",
      "hints": ["Each small cube is 1 cm³, so just count the cubes.", "Remember to count hidden cubes that support the ones on top."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q6",
      "image_needed": true,
      "image_options": false,
      "image_file": "q6.png",
      "image_page": 3,
      "image_bbox": [0.39, 0.50, 0.66, 0.68],
      "notes": "Paper 1 (Booklet A) Q6 [1m]. Stacked unit-cube solid; count = 17. Answer key: option 4 (17 cm³)."
    },
    {
      "n": 7,
      "type_id": 1,
      "question": "Jimmy had 60 marbles. He gave away \\(\\dfrac{2}{3}\\) of his marbles to 5 friends. Each friend received the same number of marbles. How many marbles did each friend get?",
      "answer0": "8",
      "answer1": "12",
      "answer2": "20",
      "answer3": "4",
      "correct_answer": 0,
      "skill_id": 165,
      "difficulty_id": 2,
      "explanation": "Marbles given away = \\(\\dfrac{2}{3} \\times 60 = 40\\). Shared equally among 5 friends: \\(40 \\div 5 = 8\\). Answer: 8 (option 1).",
      "hints": ["Find \\(\\dfrac{2}{3}\\) of 60 to get the total given away.", "Divide that total by the 5 friends."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q7",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "notes": "Paper 1 (Booklet A) Q7 [2m]. Answer key: option 1 (8)."
    },
    {
      "n": 8,
      "type_id": 1,
      "question": "The figure is made up of a square and a triangle with 2 equal sides. The length of the square is 4 cm. What is the area of the total figure?",
      "answer0": "8 cm²",
      "answer1": "16 cm²",
      "answer2": "24 cm²",
      "answer3": "32 cm²",
      "correct_answer": 2,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "Area of the square = \\(4 \\times 4 = 16\\) cm². The right-angled isosceles triangle has its two equal sides of 4 cm, so its area = \\(\\dfrac{1}{2} \\times 4 \\times 4 = 8\\) cm². Total area = \\(16 + 8 = 24\\) cm². Answer: 24 cm² (option 3).",
      "hints": ["Find the area of the 4 cm square first.", "The triangle has two equal sides of 4 cm; area = \\(\\dfrac{1}{2} \\times 4 \\times 4\\), then add."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q8",
      "image_needed": true,
      "image_options": false,
      "image_file": "q8.png",
      "image_page": 4,
      "image_bbox": [0.46, 0.43, 0.66, 0.62],
      "notes": "Paper 1 (Booklet A) Q8 [2m]. Square (side 4 cm) plus an isosceles right triangle. Answer key: option 3 (24 cm²)."
    },
    {
      "n": 9,
      "type_id": 2,
      "question": "Find the value of \\(3 \\div 7\\). Round your answer to 2 decimal places.<br>Ans: [?]",
      "answer0": "0.43",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 158,
      "difficulty_id": 2,
      "explanation": "\\(3 \\div 7 = 0.4285...\\) Rounded to 2 decimal places, the third digit is 8, so round up: 0.43. Answer: 0.43.",
      "hints": ["Divide 3 by 7 to several decimal places.", "Round 0.4285... to 2 decimal places."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q9",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "notes": "Paper 1 (Booklet B) Q9 [2m]. Decimal answer -> FIB. Answer key: 0.43."
    },
    {
      "n": 10,
      "type_id": 1,
      "question": "In a class, \\(\\dfrac{3}{8}\\) of the students are girls and the remaining are boys. \\(\\dfrac{2}{5}\\) of the boys wear spectacles. What fraction of the students are boys who do not wear spectacles?",
      "answer0": "\\(\\dfrac{3}{8}\\)",
      "answer1": "\\(\\dfrac{2}{5}\\)",
      "answer2": "\\(\\dfrac{1}{4}\\)",
      "answer3": "\\(\\dfrac{3}{20}\\)",
      "correct_answer": 0,
      "skill_id": 161,
      "difficulty_id": 2,
      "explanation": "Boys = \\(1 - \\dfrac{3}{8} = \\dfrac{5}{8}\\) of the students. Boys who do NOT wear spectacles = \\(1 - \\dfrac{2}{5} = \\dfrac{3}{5}\\) of the boys. So the fraction of all students who are boys without spectacles = \\(\\dfrac{3}{5} \\times \\dfrac{5}{8} = \\dfrac{3}{8}\\). Answer: \\(\\dfrac{3}{8}\\).",
      "hints": ["Boys are \\(\\dfrac{5}{8}\\) of the class; \\(\\dfrac{3}{5}\\) of them do not wear spectacles.", "Multiply \\(\\dfrac{3}{5} \\times \\dfrac{5}{8}\\)."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q10",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "notes": "Paper 1 (Booklet B) Q10 [2m]. Fraction answer (3/8) -> MCQ. Answer key: 3/8. Distractors are plausible fraction values."
    },
    {
      "n": 11,
      "type_id": 0,
      "question": "John glued 9 unit cubes together to form the solid shown, with the Top View, Front View and Side View marked. Draw the top view in the grid.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 188,
      "difficulty_id": 2,
      "explanation": "The top view is the footprint of the solid seen from above: an L-shaped arrangement of unit squares matching the positions of the 9 cubes seen from the top. This is a drawing task. Answer key shows the shaded top-view grid (an L-shape of squares).",
      "hints": ["Imagine looking straight down on the solid.", "Shade one square for every column of cubes you can see from above."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q11",
      "image_needed": true,
      "image_options": false,
      "image_file": "q11.png",
      "image_page": 6,
      "image_bbox": [0.34, 0.12, 0.66, 0.32],
      "notes": "Paper 1 (Booklet B) Q11(a) [drawing]. 'Draw the top view in the grid' is an interactive drawing task with no app question type -> type_id 0 (skipped on insert). Part (b) is captured as the next question."
    },
    {
      "n": 12,
      "type_id": 2,
      "question": "John glued 9 unit cubes together to form a solid. He glued more unit cubes to the solid to form a big cube. What was the least number of unit cubes John added to form the cube?<br>Ans: [?]",
      "answer0": "18",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 188,
      "difficulty_id": 3,
      "explanation": "The smallest cube that can contain the 9-cube solid is a 3 by 3 by 3 cube, which needs \\(3 \\times 3 \\times 3 = 27\\) unit cubes. He already has 9, so he must add \\(27 - 9 = 18\\) cubes. Answer: 18.",
      "hints": ["The smallest big cube that fits the solid is 3 by 3 by 3 = 27 cubes.", "Subtract the 9 cubes he already has."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "notes": "Paper 1 (Booklet B) Q11(b). Integer answer -> FIB. Answer key working: 27 - 9 = 18."
    },
    {
      "n": 13,
      "type_id": 2,
      "question": "A tank contains 14 ℓ 70 mℓ of water. Susan pours 3 bottles of water, each containing 500 mℓ of water, into the tank, without spilling. What is the volume of water in the tank in the end? Give your answer in millilitres.<br>Ans: [?] mℓ",
      "answer0": "15570",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 192,
      "difficulty_id": 2,
      "explanation": "14 ℓ 70 mℓ = \\(14 \\times 1000 + 70 = 14\\,070\\) mℓ. The 3 bottles add \\(3 \\times 500 = 1500\\) mℓ. Total = \\(14\\,070 + 1500 = 15\\,570\\) mℓ. Answer: 15 570 mℓ.",
      "hints": ["Convert 14 ℓ 70 mℓ to millilitres: \\(14 \\times 1000 + 70\\).", "Add the 3 bottles of 500 mℓ each."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q12",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "notes": "Paper 1 (Booklet B) Q12 [2m]. Integer answer (in mL) -> FIB. Answer key working: 3x500=1500, 14070+1500=15570 mL."
    },
    {
      "n": 14,
      "type_id": 2,
      "question": "A shaded triangle is drawn inside 5 identical squares of side 12 cm. Find the area of the shaded triangle.<br>Ans: [?] cm²",
      "answer0": "144",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Using the working in the answer key: the larger right triangle has base and height 24 cm, area \\(\\dfrac{1}{2} \\times 24 \\times 24 = 288\\) cm²; the smaller triangle has dimensions 12 cm and 24 cm, area \\(\\dfrac{1}{2} \\times 12 \\times 24 = 144\\) cm². Shaded area = \\(288 - 144 = 144\\) cm². Answer: 144 cm².",
      "hints": ["Each square has side 12 cm, so combined lengths are multiples of 12.", "Find the big triangle's area and subtract the unshaded triangle: \\(288 - 144\\)."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P1 Q13",
      "image_needed": true,
      "image_options": false,
      "image_file": "q14.png",
      "image_page": 7,
      "image_bbox": [0.22, 0.50, 0.36, 0.64],
      "notes": "Paper 1 (Booklet B) Q13 [2m]. Shaded triangle inside 5 squares of side 12 cm; integer answer -> FIB. Answer key working: 24x24x1/2=288, 12x24x1/2=144, 288-144=144 cm²."
    },
    {
      "n": 15,
      "type_id": 2,
      "question": "A roll of ribbon of length 14 m is cut into 5 equal parts. What is the length of each part in metres? Express your answer as a decimal.<br>Ans: [?] m",
      "answer0": "2.8",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 158,
      "difficulty_id": 1,
      "explanation": "Length of each part = \\(14 \\div 5 = 2.8\\) m. Answer: 2.8 m.",
      "hints": ["Divide the total length by the number of equal parts.", "\\(14 \\div 5\\)."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P2 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "notes": "Paper 2 Q1 [2m]. Decimal answer -> FIB. Answer key: 14/5 = 2.8 m."
    },
    {
      "n": 16,
      "type_id": 2,
      "question": "A rectangular container is partially filled with 1-cm cubes. What is the volume of the container that is not filled with cubes?<br>Ans: [?] cm³",
      "answer0": "84",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 193,
      "difficulty_id": 3,
      "explanation": "From the answer key, the empty (unfilled) part of the container measures 7 by 4 by 3 cubes, so its volume = \\(7 \\times 4 \\times 3 = 84\\) cm³. Answer: 84 cm³.",
      "hints": ["Look at the empty space in the container, not the cubes.", "Count its length, breadth and height in cubes, then multiply: \\(7 \\times 4 \\times 3\\)."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P2 Q2",
      "image_needed": true,
      "image_options": false,
      "image_file": "q16.png",
      "image_page": 9,
      "image_bbox": [0.28, 0.16, 0.62, 0.30],
      "notes": "Paper 2 Q2 [2m]. Rectangular container partly filled with 1-cm cubes; integer answer -> FIB. Answer key working: 7x4x3 = 84 cm³."
    },
    {
      "n": 17,
      "type_id": 2,
      "question": "In the figure ABCD, AE = BE = DE = 3 cm and EC = 5 cm. Find the area of the figure.<br>Ans: [?] cm²",
      "answer0": "24",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "BD = BE + ED = \\(3 + 3 = 6\\) cm is the diagonal across the figure. The top triangle ABD has base BD = 6 cm and height AE = 3 cm: area = \\(\\dfrac{1}{2} \\times 6 \\times 3 = 9\\)... using the key's method: top triangles \\(3 \\times 3 \\times \\dfrac{1}{2} = 4.5\\) (\\(\\times 2 = 9\\)); bottom triangles \\(3 \\times 5 \\times \\dfrac{1}{2} = 7.5\\) (\\(\\times 2 = 15\\)). Total = \\(9 + 15 = 24\\) cm². Answer: 24 cm².",
      "hints": ["Split the kite-shaped figure into the two top triangles (height 3 cm) and two bottom triangles (height 5 cm).", "Top: \\(3 \\times 3 \\times \\dfrac{1}{2} = 4.5\\) each; bottom: \\(3 \\times 5 \\times \\dfrac{1}{2} = 7.5\\) each; add all four."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P2 Q3",
      "image_needed": true,
      "image_options": false,
      "image_file": "q17.png",
      "image_page": 9,
      "image_bbox": [0.26, 0.50, 0.48, 0.72],
      "notes": "Paper 2 Q3 [3m]. Kite-shaped figure ABCD with AE=BE=DE=3 cm, EC=5 cm; integer answer -> FIB. Answer key working: (3x5x1/2)x2=15, (3x3x1/2)x2=9, 15+9=24 cm²."
    },
    {
      "n": 18,
      "type_id": 2,
      "question": "\\(\\dfrac{4}{9}\\) of the pies that Mrs Tay baked were apple pies and the rest were pineapple pies. She gave \\(\\dfrac{1}{2}\\) of the apple pies to her neighbour and \\(\\dfrac{3}{5}\\) of the pineapple pies to her children. She had 60 pies left. How many pies did she bake?<br>Ans: [?]",
      "answer0": "135",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Take the total as 9 units: apple = 4 units, pineapple = 5 units. She gave away \\(\\dfrac{1}{2}\\) of 4 units = 2 units of apple and \\(\\dfrac{3}{5}\\) of 5 units = 3 units of pineapple, leaving \\(2 + 2 = 4\\) units. From the key: \\(60 \\div 4 = 15\\) pies per unit, so total = \\(15 \\times 9 = 135\\) pies. Answer: 135.",
      "hints": ["Let the total be 9 units (4 apple, 5 pineapple) and find how many units are left.", "Pies left = 4 units = 60, so 1 unit = 15; total = 9 units."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P2 Q4",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "notes": "Paper 2 Q4 [4m]. Integer answer -> FIB. Answer key working: 60/4=15, 15x9=135 pies."
    },
    {
      "n": 19,
      "type_id": 2,
      "question": "The figure, not drawn to scale, shows a rectangular container measuring 25 cm by 8 cm by 12 cm. What is the volume of the container? Give your answer in litres and millilitres.<br>Ans: [?] ℓ [?] mℓ",
      "answer0": "2",
      "answer1": "400",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 192,
      "difficulty_id": 2,
      "explanation": "Volume = \\(25 \\times 8 \\times 12 = 2400\\) cm³. Since 1 cm³ = 1 mℓ, this is 2400 mℓ = 2 ℓ 400 mℓ. Answer: 2 ℓ 400 mℓ.",
      "hints": ["Multiply the three dimensions: \\(25 \\times 8 \\times 12\\).", "1 cm³ = 1 mℓ and 1000 mℓ = 1 ℓ, so convert 2400 mℓ."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P2 Q5",
      "image_needed": true,
      "image_options": false,
      "image_file": "q19.png",
      "image_page": 11,
      "image_bbox": [0.38, 0.10, 0.62, 0.26],
      "notes": "Paper 2 Q5(a) [2m]. Two integer blanks (litres, millilitres) -> FIB. Answer key working: 25x8x12=2400 ml = 2 L 400 ml."
    },
    {
      "n": 20,
      "type_id": 2,
      "question": "The rectangular container measuring 25 cm by 8 cm by 12 cm has 1 ℓ 43 mℓ of water in it. How much more water must be poured into the container so that the container is \\(\\dfrac{3}{4}\\) full? Give your answer in cubic centimetres.<br>Ans: [?] cm³",
      "answer0": "757",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 193,
      "difficulty_id": 3,
      "explanation": "Full volume = \\(25 \\times 8 \\times 12 = 2400\\) cm³. Three-quarters full = \\(2400 \\div 4 \\times 3 = 600 \\times 3 = 1800\\) cm³. There is already 1 ℓ 43 mℓ = 1043 cm³, so the extra water needed = \\(1800 - 1043 = 757\\) cm³. Answer: 757 cm³.",
      "hints": ["Find \\(\\dfrac{3}{4}\\) of the full volume of 2400 cm³.", "1 ℓ 43 mℓ = 1043 cm³; subtract this from the \\(\\dfrac{3}{4}\\)-full amount."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P2 Q5",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "image_page": null,
      "image_bbox": null,
      "notes": "Paper 2 Q5(b) [3m]. Integer answer -> FIB. Answer key working: 2400/4=600, 600x3=1800, 1800-1043=757 cm³."
    },
    {
      "n": 21,
      "type_id": 2,
      "question": "The figure is made up of a square and a rectangle. The rectangle is 80 cm by 30 cm and the square has side 70 cm. Find the area of the shaded part in the figure.<br>Ans: [?] cm²",
      "answer0": "1450",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Using the answer key's working: the whole figure area is found from \\(70 \\times 50 = 3500\\) and \\(30 \\times 30 = 900\\) parts giving \\(3500 + 900 = 4400\\) cm². The unshaded triangular parts are \\(80 \\times 30 \\times \\dfrac{1}{2} = 1200\\) and \\(70 \\times 50 \\times \\dfrac{1}{2} = 1750\\), totalling \\(1200 + 1750 = 2950\\) cm². Shaded part = \\(4400 - 2950 = 1450\\) cm². Answer: 1450 cm².",
      "hints": ["Find the total area of the figure made from the square and rectangle.", "Subtract the unshaded triangles: \\(4400 - 2950\\)."],
      "source": "St. Hilda's 2025 P5 Weighted Assessment 2 P2 Q6",
      "image_needed": true,
      "image_options": false,
      "image_file": "q21.png",
      "image_page": 13,
      "image_bbox": [0.40, 0.13, 0.74, 0.36],
      "notes": "Paper 2 Q6 [4m]. L-shaped figure (rectangle 80x30, square side 70) with shaded triangle; integer answer -> FIB. Answer key working: 4400 - 2950 = 1450 cm²."
    }
  ]
}