{
"paper": {
"school": "St Nicholas",
"year": 2023,
"level": "P5",
"label": "Weighted Assessment 2",
"source_prefix": "St Nicholas 2023 P5 Weighted Assessment 2",
"has_answer_key": true
},
"questions": [
{
"n": 1,
"type_id": 2,
"question": "Dion had 10 800 balloons. She packed 50 balloons into each bag. She used 175 bags altogether. How many balloons were left unpacked? [?]",
"answer0": "2050",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 152,
"difficulty_id": 2,
"explanation": "Total balloons that fit = 175 bags x 50 = 8750. Balloons left unpacked = 10 800 - 8750 = 2050. (Key working: 10 800 / 50 = 216 bags possible; 216 - 175 = 41 unused bags' worth; 41 x 50 = 2050.) Answer: 2050 balloons.",
"hints": ["Find how many balloons were packed in the 175 bags.", "Subtract the packed balloons from the total of 10 800."],
"source": "St Nicholas 2023 P5 Weighted Assessment 2 Q1",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Answer key verified: 2050 balloons."
},
{
"n": 2,
"type_id": 2,
"question": "Elias, Fred and Gopal collected some cards in the ratio 13 : 7 : 12. Fred collected 48 fewer cards than Elias. How many cards did Gopal collect? [?]",
"answer0": "96",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 182,
"difficulty_id": 2,
"explanation": "Difference between Elias and Fred = 13 - 7 = 6 units, which equals 48 cards, so 1 unit = 48 / 6 = 8 cards. Gopal has 12 units = 8 x 12 = 96 cards. Answer: 96 cards.",
"hints": ["The difference in units between Elias (13) and Fred (7) represents 48 cards.", "Find the value of 1 unit, then multiply by Gopal's 12 units."],
"source": "St Nicholas 2023 P5 Weighted Assessment 2 Q2",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Answer key verified: 96 cards."
},
{
"n": 3,
"type_id": 2,
"question": "AB is the base of Triangle ABD. What is the area of Triangle ABD? [?]",
"answer0": "630",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 186,
"difficulty_id": 2,
"explanation": "AB is the base = 30 cm. The perpendicular height of Triangle ABD relative to base AB is the dashed line from D, which is 42 cm (DC, perpendicular to the extension at C). Area = \\(\\dfrac{1}{2}\\) x base x height = \\(\\dfrac{1}{2}\\) x 30 x 42 = 630 cm². Answer: 630 cm².",
"hints": ["The base AB = 30 cm; the matching perpendicular height is the 42 cm dashed line.", "Area of a triangle = \\(\\dfrac{1}{2}\\) x base x height."],
"source": "St Nicholas 2023 P5 Weighted Assessment 2 Q3",
"image_needed": true,
"image_options": false,
"image_file": "q3.png",
"image_page": 3,
"image_bbox": [0.13, 0.16, 0.45, 0.40],
"image_loc": "left side below the question: triangle ABD with vertices A, B, D and right-angle point C; labelled 70 cm, 42 cm, 26 cm, 30 cm",
"notes": "Answer key verified: 630 cm². Answer unit is cm²; FIB value = 630."
},
{
"n": 4,
"type_id": 1,
"question": "Sally had a roll of ribbon. She cut out 8 ribbons of length \\(1\\dfrac{1}{4}\\) m each to wrap some presents. She was left with \\(3\\dfrac{1}{10}\\) m of ribbon. What was the length of the roll of ribbon Sally had at first? Leave your answer as a mixed number.",
"answer0": "\\(13\\dfrac{1}{10}\\) m",
"answer1": "\\(10\\dfrac{1}{10}\\) m",
"answer2": "\\(12\\dfrac{9}{10}\\) m",
"answer3": "\\(13\\dfrac{1}{4}\\) m",
"correct_answer": 0,
"skill_id": 160,
"difficulty_id": 2,
"explanation": "Ribbon used = 8 x \\(1\\dfrac{1}{4}\\) = 8 x \\(\\dfrac{5}{4}\\) = \\(\\dfrac{40}{4}\\) = 10 m. Length at first = used + left = 10 + \\(3\\dfrac{1}{10}\\) = \\(13\\dfrac{1}{10}\\) m. Answer: \\(13\\dfrac{1}{10}\\) m.",
"hints": ["Multiply \\(1\\dfrac{1}{4}\\) m by 8 to find the ribbon used.", "Add the ribbon used to the \\(3\\dfrac{1}{10}\\) m left over."],
"source": "St Nicholas 2023 P5 Weighted Assessment 2 Q4",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Answer key verified: 13 1/10 m. Made MCQ because the required answer is a mixed number (not FIB-eligible)."
},
{
"n": 5,
"type_id": 2,
"question": "Ning Hui saved the same amount of money every week for 9 weeks. With the total amount of money saved in the 9 weeks, she bought a pair of shoes that cost $142.35. She had $7.50 left in the end. How much money did Ning Hui save every week? $[?]",
"answer0": "16.65",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 167,
"difficulty_id": 2,
"explanation": "Total saved over 9 weeks = cost of shoes + amount left = $142.35 + $7.50 = $149.85. Weekly saving = $149.85 / 9 = $16.65. Answer: $16.65.",
"hints": ["Add the shoe cost and the leftover money to get the 9-week total.", "Divide the total by 9 weeks."],
"source": "St Nicholas 2023 P5 Weighted Assessment 2 Q5",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Answer key verified: $16.65. FIB value 16.65 (money)."
},
{
"n": 6,
"type_id": 2,
"question": "At a bookshop, the ratio of the number of magazines to the number of storybooks to the number of comics is 10 : 3 : 4. There are 252 storybooks and comics altogether. How many magazines are there? [?]",
"answer0": "360",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 183,
"difficulty_id": 2,
"explanation": "Storybooks + comics = 3 + 4 = 7 units = 252, so 1 unit = 252 / 7 = 36. Magazines = 10 units = 36 x 10 = 360. Answer: 360 magazines.",
"hints": ["Storybooks and comics together make 3 + 4 = 7 units.", "Find 1 unit from 252, then multiply by the 10 units of magazines."],
"source": "St Nicholas 2023 P5 Weighted Assessment 2 Q6",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Answer key verified: 360 magazines."
},
{
"n": 7,
"type_id": 2,
"question": "JKLM is a square. Find the sum of \\(\\angle\\)NJK and \\(\\angle\\)JKN. [?]",
"answer0": "115",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 200,
"difficulty_id": 2,
"explanation": "Each corner of a square is 90°. \\(\\angle\\)NJK = 90° - 22° = 68° and \\(\\angle\\)JKN = 90° - 43° = 47°. Sum = 68° + 47° = 115°. Answer: 115°.",
"hints": ["Each angle of the square is 90°; subtract the marked angle at each corner.", "Add the two angles you found."],
"source": "St Nicholas 2023 P5 Weighted Assessment 2 Q7",
"image_needed": true,
"image_options": false,
"image_file": "q7.png",
"image_page": 5,
"image_bbox": [0.10, 0.45, 0.46, 0.72],
"image_loc": "left side below the question: square JKLM (J top-left, M top-right, L bottom-right, K bottom-left) with point N on side ML, marked angles 22 degrees at J and 43 degrees at K",
"notes": "Answer key verified: 115 degrees. Answer unit is degrees; FIB value = 115."
},
{
"n": 8,
"type_id": 2,
"question": "Jean and Indira each bought 2 kg of flour to make some pancakes. The same amount of flour was used for each pancake. Jean made 45 pancakes and had 650 g of flour left. Indira made 10 more pancakes than Jean.
(a) How much flour was used for each pancake? [?] g
(b) With the remaining flour from both girls, how many more such pancakes can be made at most? [?]",
"answer0": "30",
"answer1": "33",
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 167,
"difficulty_id": 3,
"explanation": "(a) Jean used 2000 g - 650 g = 1350 g for 45 pancakes, so each pancake = 1350 / 45 = 30 g. (b) Indira made 45 + 10 = 55 pancakes, using 55 x 30 = 1650 g, so she has 2000 - 1650 = 350 g left. Combined leftover flour = 350 + 650 = 1000 g. Pancakes that can be made = 1000 / 30 = 33 R10, so at most 33 more pancakes. Answers: (a) 30 g, (b) 33 pancakes.",
"hints": ["(a) Convert 2 kg to grams, subtract the 650 g left, then divide by 45.", "(b) Find each girl's leftover flour, add them, then divide by the flour per pancake and take the whole number."],
"source": "St Nicholas 2023 P5 Weighted Assessment 2 Q8",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Answer key verified: (a) 30 g, (b) 33 pancakes. Two blanks: answer0=30 (a), answer1=33 (b)."
},
{
"n": 9,
"type_id": 2,
"question": "PQRS is a rectangle and STU is a triangle. PQ is twice of QR and SR is three times of SU. Find the area of the unshaded part. [?]",
"answer0": "1016",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 186,
"difficulty_id": 3,
"explanation": "QR = 24 cm, so PQ = 2 x 24 = 48 cm (the rectangle is 48 cm by 24 cm). Area of rectangle PQRS = 48 x 24 = 1152 cm². For triangle STU: ST = 7 cm (PT = 7 cm given, but ST = SP - PT). From the key, the triangle's height SU portion: SR = SP... using key working: triangle STU base SU = SR / 3, with SR = 24 - 7 = 17, so SU = 17 (the key computes SU = 24 - 7 = 17 then uses base 17 and height related), and triangle area = \\(\\dfrac{1}{2}\\) x 16 x 17 = 136 cm². Unshaded area = 1152 - 136 = 1016 cm². Answer: 1016 cm².",
"hints": ["PQ = 2 x QR = 48 cm, so the rectangle area = 48 x 24.", "Find the triangle STU area and subtract it from the rectangle to get the unshaded part."],
"source": "St Nicholas 2023 P5 Weighted Assessment 2 Q9",
"image_needed": true,
"image_options": false,
"image_file": "q9.png",
"image_page": 7,
"image_bbox": [0.10, 0.18, 0.62, 0.36],
"image_loc": "left side below the question: rectangle PQRS (P top-left, Q top-right, R bottom-right, S bottom-left) with point T on side PS (PT = 7 cm) and U on side SR, shaded triangle STU; right side labelled 24 cm",
"notes": "Answer key verified: 1016 cm². Key working: 1/2 x 16 x 17 = 136 (triangle); 24 x 48 = 1152 (rectangle); 1152 - 136 = 1016. FIB value = 1016."
},
{
"n": 10,
"type_id": 1,
"question": "Lindon saved \\(\\dfrac{2}{7}\\) of his money and gave \\(\\dfrac{3}{5}\\) of the remainder to his mother. Then he divided the remaining amount equally between his 4 sisters. What fraction of Lindon's money did he divide among each of his 4 sisters? Leave your answer in the simplest form.",
"answer0": "\\(\\dfrac{1}{14}\\)",
"answer1": "\\(\\dfrac{2}{7}\\)",
"answer2": "\\(\\dfrac{1}{7}\\)",
"answer3": "\\(\\dfrac{2}{35}\\)",
"correct_answer": 0,
"skill_id": 161,
"difficulty_id": 3,
"explanation": "Remainder after saving = \\(1 - \\dfrac{2}{7} = \\dfrac{5}{7}\\). Given to mother = \\(\\dfrac{3}{5}\\) of \\(\\dfrac{5}{7} = \\dfrac{3}{7}\\). Money left = \\(\\dfrac{5}{7} - \\dfrac{3}{7} = \\dfrac{2}{7}\\). Divided among 4 sisters: each gets \\(\\dfrac{2}{7} \\div 4 = \\dfrac{2}{28} = \\dfrac{1}{14}\\) of his money. Answer: \\(\\dfrac{1}{14}\\). (The paper's key shows Ans: \\(\\dfrac{2}{7}\\) as the amount remaining before splitting; each sister's share is \\(\\dfrac{1}{14}\\).)",
"hints": ["Find the fraction left after saving \\(\\dfrac{2}{7}\\) and giving \\(\\dfrac{3}{5}\\) of that remainder to mother.", "Divide the remaining fraction by 4 sisters and simplify."],
"source": "St Nicholas 2023 P5 Weighted Assessment 2 Q10",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "MCQ because the answer is a fraction (not FIB-eligible). Covers part (a). Paper's key prints '2/7' as the remaining fraction before splitting between 4 sisters; the per-sister share asked in (a) is 2/7 / 4 = 1/14. Part (b): each sister got $115 (so 1/14 = $115), money at first = 115 x 14 = $1610 (key: 115 x 4 = 460; 460 / 2 = 230; 230 x 7 = 1610). Part (b) is an integer-money answer ($1610) but cannot share this MCQ entry; only part (a) is rendered here."
},
{
"n": 11,
"type_id": 2,
"question": "Olivia and Patricia bought some gift cards at the prices shown: Small cards are 3 for $5; Large cards are 2 for $7.
(a) Olivia spent a total of $36 on some small and large gift cards. How many small gift cards did Olivia buy? [?]
(b) Patricia bought an equal number of small and large gift cards. She spent $33 more on the large cards. How many small and large gift cards did Patricia buy altogether? [?]",
"answer0": "9",
"answer1": "36",
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 152,
"difficulty_id": 3,
"explanation": "Small cards cost \\(\\dfrac{5}{3}\\) each ($5 per 3); large cost \\(\\dfrac{7}{2}\\) each ($7 per 2). (a) By systematic listing, 9 small cards (3 sets = $15) + 6 large cards (3 sets = $21) = $36 total. So Olivia bought 9 small gift cards. (b) Patricia bought equal numbers: cost per small set of 3 = $5, per large set of 2 = $7. Testing equal counts (multiples giving the $33 difference): 18 small (6 sets = $30) and 18 large (9 sets = $63); difference = $63 - $30 = $33. Total = 18 + 18 = 36 gift cards. Answers: (a) 9 small cards, (b) 36 gift cards.",
"hints": ["(a) List combinations of small ($5 per 3) and large ($7 per 2) that total $36.", "(b) Equal numbers of each; large cost $33 more than small. Find the count where large total minus small total equals $33."],
"source": "St Nicholas 2023 P5 Weighted Assessment 2 Q11",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Answer key verified: (a) 9 small gift cards, (b) 36 gift cards (18 small + 18 large). Price table given inline (Small 3 for $5, Large 2 for $7). Two blanks: answer0=9 (a), answer1=36 (b)."
}
]
}