{
  "paper": {
    "school": "Tao Nan",
    "year": 2024,
    "level": "P5",
    "label": "End-of-Year Exam",
    "source_prefix": "Tao Nan 2024 P5 End-of-Year Exam",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "Which of the following is six million, thirty-five thousand and twenty in numerals?",
      "answer0": "6 035 020",
      "answer1": "6 035 200",
      "answer2": "6 350 020",
      "answer3": "6 350 200",
      "correct_answer": 0,
      "skill_id": 149,
      "difficulty_id": 1,
      "explanation": "Six million = 6 000 000; thirty-five thousand = 35 000; twenty = 20. Adding: 6 000 000 + 35 000 + 20 = 6 035 020.",
      "hints": ["Write each part separately: 6 million, 35 thousand, 20.", "Line up the place values: millions, thousands, hundreds, tens, ones."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: option 1 (0-based index 0)."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "Find the value of \\(8.16 \\div 40\\).",
      "answer0": "0.204",
      "answer1": "0.240",
      "answer2": "2.04",
      "answer3": "2.40",
      "correct_answer": 0,
      "skill_id": 166,
      "difficulty_id": 2,
      "explanation": "8.16 ÷ 40 = 8.16 ÷ 4 ÷ 10 = 2.04 ÷ 10 = 0.204.",
      "hints": ["Divide by 4 first, then by 10.", "Dividing by 10 shifts the decimal point one place left."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: option 1 (index 0)."
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "Which of the following is equal to \\(6\\dfrac{2}{7}\\)?",
      "answer0": "\\(\\dfrac{12}{7}\\)",
      "answer1": "\\(\\dfrac{16}{7}\\)",
      "answer2": "\\(\\dfrac{44}{7}\\)",
      "answer3": "\\(\\dfrac{48}{7}\\)",
      "correct_answer": 2,
      "skill_id": 119,
      "difficulty_id": 1,
      "explanation": "\\(6\\dfrac{2}{7} = \\dfrac{6\\times 7 + 2}{7} = \\dfrac{42 + 2}{7} = \\dfrac{44}{7}\\).",
      "hints": ["Multiply the whole number by the denominator, then add the numerator.", "Keep the same denominator (7)."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: option 3 (index 2)."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "Which of the following is symmetrical?",
      "answer0": "Spider web",
      "answer1": "Hourglass",
      "answer2": "Butterfly with decorated wings",
      "answer3": "Flower with a line through it",
      "correct_answer": 3,
      "skill_id": 144,
      "difficulty_id": 2,
      "explanation": "A figure is symmetrical if one half is the mirror image of the other along a line of symmetry. The flower figure (option 4) has matching halves about the vertical line drawn through it. The web, hourglass and decorated butterfly are not symmetrical as drawn.",
      "hints": ["Look for a line that divides the figure into two matching mirror-image halves.", "Check if folding along that line makes both halves overlap exactly."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q4",
      "image_needed": true,
      "image_options": true,
      "image_file": null,
      "image_page": 4,
      "image_bbox": [0.22, 0.13, 0.50, 0.62],
      "image_loc": "left-centre of page; four boxed picture options (1) web (2) hourglass (3) butterfly (4) flower, stacked vertically",
      "notes": "Image-option MCQ; crop each option to q4_opt0..3.png. Answer key: option 4 (index 3)."
    },
    {
      "n": 5,
      "type_id": 1,
      "question": "The figure is divided into 25 equal squares. What percentage of the figure is shaded?",
      "answer0": "11%",
      "answer1": "25%",
      "answer2": "44%",
      "answer3": "56%",
      "correct_answer": 2,
      "skill_id": 171,
      "difficulty_id": 2,
      "explanation": "The shaded region (the tilted square plus the shaded small squares) covers 11 of the 25 equal squares. \\(\\dfrac{11}{25} = \\dfrac{44}{100} = 44\\%\\).",
      "hints": ["Count the equal squares' worth that are shaded out of 25.", "Convert the fraction out of 25 to a fraction out of 100."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q5",
      "image_needed": true,
      "image_options": false,
      "image_file": "q5.png",
      "image_page": 4,
      "image_bbox": [0.58, 0.66, 0.86, 0.86],
      "image_loc": "lower-right of page; 5x5 grid with a black tilted square and several black small squares",
      "notes": "Answer key: option 3 (44%, index 2)."
    },
    {
      "n": 6,
      "type_id": 1,
      "question": "What is 25 minutes before the time shown on the clock?",
      "answer0": "16 30",
      "answer1": "16 40",
      "answer2": "17 30",
      "answer3": "17 40",
      "correct_answer": 1,
      "skill_id": 135,
      "difficulty_id": 2,
      "explanation": "The clock shows 5 minutes past 5, i.e. 17 05. 25 minutes before 17 05 is 17 05 − 25 min = 16 40.",
      "hints": ["Read the clock time first (hour hand just past 5, minute hand at 1).", "Subtract 25 minutes from that time."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q6",
      "image_needed": true,
      "image_options": false,
      "image_file": "q6.png",
      "image_page": 5,
      "image_bbox": [0.47, 0.13, 0.68, 0.28],
      "image_loc": "right of the question; analogue clock showing about 5:05",
      "notes": "Answer key: option 2 (16 40, index 1)."
    },
    {
      "n": 7,
      "type_id": 1,
      "question": "The figure shows a right-angled triangle. Find the area of the triangle.",
      "answer0": "480 cm²",
      "answer1": "520 cm²",
      "answer2": "960 cm²",
      "answer3": "1248 cm²",
      "correct_answer": 0,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "The two perpendicular sides (base and height) are 20 cm and 48 cm. Area \\(= \\dfrac{1}{2}\\times 48\\times 20 = 480\\) cm². (52 cm is the hypotenuse and is not used.)",
      "hints": ["Use the two sides that meet at the right angle as base and height.", "Area of triangle \\(= \\dfrac{1}{2}\\times \\text{base}\\times \\text{height}\\)."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q7",
      "image_needed": true,
      "image_options": false,
      "image_file": "q7.png",
      "image_page": 5,
      "image_bbox": [0.47, 0.40, 0.90, 0.55],
      "image_loc": "right of the question; right-angled triangle labelled 20 cm, 48 cm, 52 cm",
      "notes": "Answer key: option 1 (480 cm², index 0)."
    },
    {
      "n": 8,
      "type_id": 1,
      "question": "Betty used \\(\\dfrac{3}{8}\\) of her flour to bake a cake and \\(\\dfrac{1}{5}\\) of the remaining flour to bake cookies. What fraction of her flour did she use to bake cookies?",
      "answer0": "\\(\\dfrac{1}{5}\\)",
      "answer1": "\\(\\dfrac{1}{8}\\)",
      "answer2": "\\(\\dfrac{4}{5}\\)",
      "answer3": "\\(\\dfrac{5}{8}\\)",
      "correct_answer": 1,
      "skill_id": 161,
      "difficulty_id": 2,
      "explanation": "Remaining flour after the cake \\(= 1 - \\dfrac{3}{8} = \\dfrac{5}{8}\\). Cookies use \\(\\dfrac{1}{5}\\) of this: \\(\\dfrac{1}{5}\\times \\dfrac{5}{8} = \\dfrac{1}{8}\\).",
      "hints": ["First find the fraction of flour remaining after the cake.", "Multiply that remaining fraction by \\(\\dfrac{1}{5}\\)."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q8",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: option 2 (1/8, index 1)."
    },
    {
      "n": 9,
      "type_id": 1,
      "question": "The number of people visiting the funfair decreased by 30 from January to February and increased by 60 from February to March. Which graph shows the number of people at the funfair from January to March?",
      "answer0": "Graph 1 (rise then fall)",
      "answer1": "Graph 2 (steady decrease)",
      "answer2": "Graph 3 (fall then larger rise)",
      "answer3": "Graph 4 (fall then return to level)",
      "correct_answer": 2,
      "skill_id": 147,
      "difficulty_id": 2,
      "explanation": "From Jan to Feb the value goes down (decrease of 30), then from Feb to Mar it goes up by more than it fell (increase of 60), ending higher than January. Only graph 3 shows a fall followed by a larger rise to a point above the starting level.",
      "hints": ["Jan→Feb the line must go down; Feb→Mar it must go up.", "The rise (60) is bigger than the fall (30), so March must end above January."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q9",
      "image_needed": true,
      "image_options": true,
      "image_file": null,
      "image_page": 6,
      "image_bbox": [0.18, 0.16, 0.68, 0.92],
      "image_loc": "four line graphs stacked vertically down the page, options (1)-(4)",
      "notes": "Image-option MCQ; crop each option line graph to q9_opt0..3.png. Answer key: option 3 (index 2)."
    },
    {
      "n": 10,
      "type_id": 1,
      "question": "Ahmad had $200. He spent $60 on a bag and saved the rest of the money. What percentage of his money did Ahmad save?",
      "answer0": "70%",
      "answer1": "60%",
      "answer2": "30%",
      "answer3": "40%",
      "correct_answer": 0,
      "skill_id": 175,
      "difficulty_id": 2,
      "explanation": "Amount saved \\(= 200 - 60 = 140\\). Percentage saved \\(= \\dfrac{140}{200}\\times 100\\% = 70\\%\\).",
      "hints": ["Find how much he saved first.", "Saved amount over total, times 100%."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q10",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: option 1 (70%, index 0)."
    },
    {
      "n": 11,
      "type_id": 1,
      "question": "What is the value of \\(80 - (15 + 25) \\div 5 + 15\\)?",
      "answer0": "87",
      "answer1": "85",
      "answer2": "33",
      "answer3": "23",
      "correct_answer": 0,
      "skill_id": 155,
      "difficulty_id": 2,
      "explanation": "Brackets first: 15 + 25 = 40. Then divide: 40 ÷ 5 = 8. Then 80 − 8 + 15 = 72 + 15 = 87.",
      "hints": ["Do the brackets first, then division, then add/subtract left to right.", "40 ÷ 5 = 8, so the expression is 80 − 8 + 15."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: option 1 (87, index 0)."
    },
    {
      "n": 12,
      "type_id": 1,
      "question": "Which decimal is greater than 1.07 but smaller than 1.15?",
      "answer0": "1.1",
      "answer1": "1.05",
      "answer2": "1.17",
      "answer3": "1.5",
      "correct_answer": 0,
      "skill_id": 124,
      "difficulty_id": 2,
      "explanation": "A value between 1.07 and 1.15 is needed. 1.1 lies between them (1.07 < 1.1 < 1.15). 1.05 is too small, 1.17 and 1.5 are too large.",
      "hints": ["The number must be more than 1.07 and less than 1.15.", "Compare the digits in the tenths and hundredths places."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q12",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Option texts were not legible/blank in the source PDF; answer key states option 1 is correct. Options reconstructed so option 1 (index 0) is the only value strictly between 1.07 and 1.15. Verify option wording against an original copy if available."
    },
    {
      "n": 13,
      "type_id": 1,
      "question": "Aminah, Ban Leong and Colin share some stickers in the ratio 1 : 6 : 2. The biggest share is 54 stickers. What is Colin's share?",
      "answer0": "6",
      "answer1": "9",
      "answer2": "12",
      "answer3": "18",
      "correct_answer": 3,
      "skill_id": 182,
      "difficulty_id": 2,
      "explanation": "The biggest share belongs to Ban Leong: 6 units = 54, so 1 unit = 9. Colin has 2 units = 2 × 9 = 18.",
      "hints": ["The biggest share corresponds to the largest ratio number (6 units).", "Find the value of 1 unit, then multiply by Colin's units (2)."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q13",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: option 4 (18, index 3)."
    },
    {
      "n": 14,
      "type_id": 1,
      "question": "ABCD is a rectangle and BE = CE. Find \\(\\angle ABE\\).",
      "answer0": "18°",
      "answer1": "36°",
      "answer2": "45°",
      "answer3": "54°",
      "correct_answer": 1,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "\\(\\angle BEC = 72\\degree\\) and triangle BEC is isosceles (BE = CE), so \\(\\angle EBC = \\angle ECB = (180° - 72°)\\div 2 = 54°\\). Since \\(\\angle ABC = 90°\\) (rectangle), \\(\\angle ABE = 90° - 54° = 36°\\).",
      "hints": ["Triangle BEC is isosceles because BE = CE.", "Use the right angle at B of the rectangle: \\(\\angle ABE = 90° - \\angle EBC\\)."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q14",
      "image_needed": true,
      "image_options": false,
      "image_file": "q14.png",
      "image_page": 8,
      "image_bbox": [0.37, 0.11, 0.60, 0.28],
      "image_loc": "centre-top; rectangle ABCD with point E on side AD, lines to B and C, angle 72 marked at E",
      "notes": "Answer key: option 2 (36°, index 1)."
    },
    {
      "n": 15,
      "type_id": 1,
      "question": "The figure is made up of a square and two identical rectangles. The area of the square is 36 cm². Find the perimeter of the figure.",
      "answer0": "44 cm",
      "answer1": "48 cm",
      "answer2": "56 cm",
      "answer3": "66 cm",
      "correct_answer": 0,
      "skill_id": 138,
      "difficulty_id": 3,
      "explanation": "Square area 36 cm² → side = 6 cm. The full left side height is 10 cm, so each rectangle is 10 cm tall stacked? The big left block is 6 cm wide and 10 cm tall made of the 6 cm square plus a rectangle; the two identical rectangles each measure 6 cm by 4 cm and one extends to the right. Tracing the outline gives a total perimeter of 44 cm.",
      "hints": ["Find the side of the square from its area (\\(6\\times 6 = 36\\)).", "Add up every outer edge of the L-shaped figure once."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q15",
      "image_needed": true,
      "image_options": false,
      "image_file": "q15.png",
      "image_page": 8,
      "image_bbox": [0.30, 0.48, 0.72, 0.70],
      "image_loc": "centre; figure of a square with two rectangles, left height marked 10 cm",
      "notes": "Answer key: option 1 (44 cm, index 0)."
    },
    {
      "n": 16,
      "type_id": 1,
      "question": "Find the value of \\(23 \\div 9\\). Express your answer as a mixed number in the simplest form.",
      "answer0": "\\(2\\dfrac{5}{9}\\)",
      "answer1": "\\(2\\dfrac{4}{9}\\)",
      "answer2": "\\(1\\dfrac{5}{9}\\)",
      "answer3": "\\(\\dfrac{23}{9}\\)",
      "correct_answer": 0,
      "skill_id": 157,
      "difficulty_id": 1,
      "explanation": "\\(23 \\div 9 = \\dfrac{23}{9} = 2\\dfrac{5}{9}\\) (since 9 goes into 23 twice with remainder 5).",
      "hints": ["Divide 23 by 9: how many whole 9s and what remainder?", "The remainder becomes the numerator over 9."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q16",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer is a mixed number (2 5/9), so made MCQ per spec. Answer key: 23/9 = 2 5/9 (index 0)."
    },
    {
      "n": 17,
      "type_id": 2,
      "question": "How many minutes are there in \\(1\\dfrac{3}{5}\\) h? [?] min",
      "answer0": "96",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 163,
      "difficulty_id": 2,
      "explanation": "\\(1\\dfrac{3}{5}\\) h \\(= \\dfrac{8}{5}\\) h. \\(\\dfrac{8}{5}\\times 60 = \\dfrac{8\\times 60}{5} = \\dfrac{480}{5} = 96\\) min. (Or 1 h = 60 min and \\(\\dfrac{3}{5}\\times 60 = 36\\) min; 60 + 36 = 96 min.)",
      "hints": ["1 hour = 60 minutes.", "Multiply the mixed number by 60: \\(\\dfrac{3}{5}\\) of 60 is 36, plus 60."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q17",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "FIB, integer answer 96. Answer key shows 96 min."
    },
    {
      "n": 18,
      "type_id": 2,
      "question": "Measure and write down the size of \\(\\angle GFH\\). [?]°",
      "answer0": "53",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 140,
      "difficulty_id": 2,
      "explanation": "Measuring the angle at vertex F in triangle FGH with a protractor gives \\(\\angle GFH = 53\\degree\\).",
      "hints": ["Place the protractor centre on vertex F.", "Read the angle between ray FG and ray FH."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q18",
      "image_needed": true,
      "image_options": false,
      "image_file": "q18.png",
      "image_page": 10,
      "image_bbox": [0.20, 0.63, 0.78, 0.86],
      "image_loc": "centre; triangle with vertices G (top), F (lower left, angle marked), H (lower right)",
      "notes": "FIB, integer answer 53. Answer key: 53°. Measured-from-figure question; the printed key value is authoritative."
    },
    {
      "n": 19,
      "type_id": 0,
      "question": "Draw the minute hand after it makes a \\(\\dfrac{1}{4}\\)-turn clockwise.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 141,
      "difficulty_id": 2,
      "explanation": "A \\(\\dfrac{1}{4}\\)-turn clockwise is 90°. The minute hand starts pointing to the 3 (right). After a quarter turn clockwise it points to the 6 (straight down).",
      "hints": ["A quarter turn is 90°.", "Rotate the hand from the 3 position clockwise by 90°."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q19",
      "image_needed": true,
      "image_options": false,
      "image_file": "q19.png",
      "image_page": 11,
      "image_bbox": [0.33, 0.13, 0.58, 0.34],
      "image_loc": "centre-top; analogue clock with minute hand pointing to 3 and short hand to about 7-8",
      "notes": "Drawing task (no value answer) → type_id 0, skipped on insert. Answer: minute hand points to 6 (down) after the quarter turn clockwise."
    },
    {
      "n": 20,
      "type_id": 2,
      "question": "The graph shows the points scored by 5 classes during Sports Day. How many points did Class 4B score? [?]",
      "answer0": "56",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 147,
      "difficulty_id": 1,
      "explanation": "Reading the bar for Class 4B on the graph, the top of the bar lines up with 56 on the 'Number of points' axis. So Class 4B scored 56 points.",
      "hints": ["Find the 4B bar and read across to the vertical axis.", "The bar's top is between 50 and 60, just over halfway."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q20",
      "image_needed": true,
      "image_options": false,
      "image_file": "q20.png",
      "image_page": 11,
      "image_bbox": [0.20, 0.42, 0.85, 0.74],
      "image_loc": "centre; bar graph of points for classes 4A-4E",
      "notes": "FIB, integer answer 56. Answer key: 56."
    },
    {
      "n": 21,
      "type_id": 0,
      "question": "Draw the following cuboid on the isometric grid provided. PQ has been drawn for you.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 187,
      "difficulty_id": 2,
      "explanation": "On the isometric grid, draw a cuboid measuring 4 units (length) by 2 units (width) by 2 units (height), with edge PQ (a 2-unit vertical edge) already given. The completed drawing matches the answer-key sketch of the cuboid.",
      "hints": ["PQ is one vertical edge (2 units high).", "Build the 4 × 2 × 2 box along the isometric grid lines from PQ."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q21",
      "image_needed": true,
      "image_options": false,
      "image_file": "q21.png",
      "image_page": 12,
      "image_bbox": [0.10, 0.25, 0.40, 0.48],
      "image_loc": "left; pictorial cuboid labelled 4 units, 2 units, 2 units with P and Q marked (the right box is the blank isometric dot grid)",
      "notes": "Drawing task (no value answer) → type_id 0, skipped on insert. Answer: 4x2x2 cuboid drawn on the isometric grid (see key sketch)."
    },
    {
      "n": 22,
      "type_id": 2,
      "question": "6000 ml of paint was poured into 5 containers equally. How many litres of paint were there in one container? Express your answer as a decimal. [?] ℓ",
      "answer0": "1.2",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 192,
      "difficulty_id": 2,
      "explanation": "6000 ml ÷ 5 = 1200 ml per container. 1200 ml = 1.2 ℓ.",
      "hints": ["Divide 6000 ml equally among 5 containers.", "1000 ml = 1 ℓ, so convert your ml answer to litres."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q22",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "FIB, decimal answer 1.2 (litres). Answer key: 1200 ml = 1.2 L."
    },
    {
      "n": 23,
      "type_id": 1,
      "question": "Find the ratio of the length of String A to the length of String B. Give your answer in the simplest form.",
      "answer0": "1 : 4",
      "answer1": "2 : 8",
      "answer2": "1 : 3",
      "answer3": "2 : 6",
      "correct_answer": 0,
      "skill_id": 179,
      "difficulty_id": 2,
      "explanation": "From the ruler, String A measures 2 cm and String B measures 8 cm. A : B = 2 : 8 = 1 : 4 in simplest form.",
      "hints": ["Read each string's length off the ruler scale.", "Divide both parts of the ratio by their common factor."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q23",
      "image_needed": true,
      "image_options": false,
      "image_file": "q23.png",
      "image_page": 13,
      "image_bbox": [0.20, 0.13, 0.66, 0.25],
      "image_loc": "centre-top; two strings A and B drawn above a ruler scaled 0-10",
      "notes": "Answer is a ratio (1:4), so made MCQ per spec. Answer key: A:B = 2:8 = 1:4 (index 0)."
    },
    {
      "n": 24,
      "type_id": 1,
      "question": "The table shows the time taken by 5 swimmers to complete a race. Who was first in the race?",
      "answer0": "Swimmer A",
      "answer1": "Swimmer B",
      "answer2": "Swimmer C",
      "answer3": "Swimmer D",
      "correct_answer": 3,
      "skill_id": 124,
      "difficulty_id": 1,
      "explanation": "First place is the swimmer with the shortest time. Times: A 14.2, B 15.0, C 13.9, D 13.7, E 14.3. The smallest is 13.7 s, which is Swimmer D.",
      "hints": ["First place = least time taken.", "Compare the decimals and pick the smallest."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q24",
      "image_needed": true,
      "image_options": false,
      "image_file": "q24.png",
      "image_page": 13,
      "image_bbox": [0.40, 0.41, 0.62, 0.52],
      "image_loc": "centre; table of swimmers A-E and their times in seconds",
      "notes": "Answer is a name (letter D) → MCQ per spec. Answer key: D (index 3). Table values can also be transcribed into the stem if served without the image."
    },
    {
      "n": 25,
      "type_id": 2,
      "question": "Dora folds 12 paper cranes in 10 minutes. At this rate, how many paper cranes can Dora fold in 15 minutes? [?]",
      "answer0": "18",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "In 15 minutes she folds \\(12\\times \\dfrac{15}{10} = \\dfrac{180}{10} = 18\\) cranes. (Or 12 cranes per 10 min = 1.2 cranes/min; 1.2 × 15 = 18.)",
      "hints": ["Find the rate per minute or scale up by \\(\\dfrac{15}{10}\\).", "12 cranes in 10 min, so multiply 12 by 1.5."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q25",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "FIB, integer answer 18. Answer key: 12 x 15/10 = 18."
    },
    {
      "n": 26,
      "type_id": 2,
      "question": "In the number line, what is the value represented by X? Round your answer to 1 decimal place. [?]",
      "answer0": "6.3",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 128,
      "difficulty_id": 2,
      "explanation": "The interval from 6 to 7 is divided into 8 equal parts (each \\(\\dfrac{1}{8} = 0.125\\)). X is at the 2nd mark past 6: \\(6 + 2\\times 0.125 = 6.25\\). Rounded to 1 decimal place, 6.25 ≈ 6.3.",
      "hints": ["Count how many equal parts 6 to 7 is split into and find X's position.", "Round the value to 1 decimal place at the end."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q26",
      "image_needed": true,
      "image_options": false,
      "image_file": "q26.png",
      "image_page": 14,
      "image_bbox": [0.20, 0.16, 0.52, 0.27],
      "image_loc": "left-centre; number line marked 6 and 7 with arrow X above a tick between them",
      "notes": "FIB, decimal answer 6.3. Answer key: 6 1/4 = 6.25 ≈ 6.3."
    },
    {
      "n": 27,
      "type_id": 2,
      "question": "There are 140 students in the hall. 75% of the students are boys. How many girls are there? [?]",
      "answer0": "35",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 174,
      "difficulty_id": 2,
      "explanation": "If 75% are boys, then 25% are girls. Girls \\(= 25\\%\\times 140 = \\dfrac{25}{100}\\times 140 = 35\\). (Or 140 ÷ 4 = 35.)",
      "hints": ["Girls make up 100% − 75% = 25%.", "25% is one quarter, so divide 140 by 4."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q27",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "FIB, integer answer 35. Answer key: 140 ÷ 4 = 35."
    },
    {
      "n": 28,
      "type_id": 1,
      "question": "Jane had some water in her bottle. After she drank half the amount, she added in another \\(\\dfrac{4}{5}\\) ℓ. There were \\(1\\dfrac{1}{3}\\) ℓ of water left in the bottle. How many litres of water were there in the bottle at first? Express your answer as a mixed number in the simplest form.",
      "answer0": "\\(1\\dfrac{1}{15}\\)",
      "answer1": "\\(\\dfrac{8}{15}\\)",
      "answer2": "\\(1\\dfrac{2}{15}\\)",
      "answer3": "\\(2\\dfrac{2}{15}\\)",
      "correct_answer": 0,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Half the original amount remained after drinking, then \\(\\dfrac{4}{5}\\) ℓ was added to give \\(1\\dfrac{1}{3}\\) ℓ. So half the original \\(= 1\\dfrac{1}{3} - \\dfrac{4}{5} = \\dfrac{20}{15} - \\dfrac{12}{15} = \\dfrac{8}{15}\\) ℓ. The original amount \\(= \\dfrac{8}{15}\\times 2 = \\dfrac{16}{15} = 1\\dfrac{1}{15}\\) ℓ.",
      "hints": ["The water left = (half the original) + \\(\\dfrac{4}{5}\\) ℓ.", "Find half the original first, then double it."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q28",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer is a mixed number (1 1/15) → MCQ per spec. Answer key working: 1 unit = 1 1/3 - 4/5 = 8/15; 8/15 x 2 = 16/15 = 1 1/15 L (index 0)."
    },
    {
      "n": 29,
      "type_id": 2,
      "question": "There were 30 lampposts along a road. The lampposts were at the same distance apart. The distance between the first and third lamppost was 90 m. What was the distance between the first and the last lamppost? [?] m",
      "answer0": "1305",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "First to third lamppost spans 2 gaps = 90 m, so 1 gap = 45 m. From the 1st to the 30th lamppost there are 30 − 1 = 29 gaps. Distance = 45 × 29 = 1305 m.",
      "hints": ["First to third lamppost = 2 equal gaps; find one gap.", "From 1st to last (30th) lamppost there are 29 gaps, not 30."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q29",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "FIB, integer answer 1305 (m). Answer key: 90 ÷ 2 = 45; 30 - 1 = 29; 45 x 29 = 1305 m."
    },
    {
      "n": 30,
      "type_id": 2,
      "question": "The line graph shows the temperature of water in a tank from 20 00 to 21 00. For how many minutes was the temperature of the water 40°C and above? [?] min",
      "answer0": "40",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 147,
      "difficulty_id": 2,
      "explanation": "From the graph the temperature reaches 40°C at 20 20 and stays at or above 40°C until 21 00. Duration = 21 00 − 20 20 = 40 min.",
      "hints": ["Find the time when the line first reaches 40°C.", "Count the minutes from then until 21 00."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q30",
      "image_needed": true,
      "image_options": false,
      "image_file": "q30.png",
      "image_page": 15,
      "image_bbox": [0.24, 0.40, 0.80, 0.68],
      "image_loc": "centre; line graph of water temperature (°C) vs time 20 00 to 21 00",
      "notes": "FIB, integer answer 40 (min). Answer key: 40 min."
    },
    {
      "n": 31,
      "type_id": 2,
      "question": "Emerlyn had 3.45 m of string. She used 102 cm of it to tie a parcel and cut another 4 pieces of string, each 33 cm long, to wrap some presents. How much string did she have left? [?] m",
      "answer0": "1.11",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "102 cm = 1.02 m. String used = 1.02 + 4 × 0.33 = 1.02 + 1.32 = 2.34 m. Left = 3.45 − 2.34 = 1.11 m. (Key: 3.45 − 1.02 = 2.43; 2.43 − 0.33 × 4 = 1.11 m.)",
      "hints": ["Convert all lengths to metres first (102 cm = 1.02 m, 33 cm = 0.33 m).", "Subtract the parcel string and the 4 pieces from 3.45 m."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q31",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q1. FIB, decimal answer 1.11 (m). Answer key: 3.45 - 1.02 = 2.43; 2.43 - 0.33 x 4 = 1.11 m."
    },
    {
      "n": 32,
      "type_id": 2,
      "question": "A pastry chef takes 27 minutes to decorate a cake. At this rate, how much time is needed to decorate 8 cakes? [?] h [?] min",
      "answer0": "3",
      "answer1": "36",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "8 cakes × 27 min = 216 min. 216 ÷ 60 = 3 remainder 36, so 216 min = 3 h 36 min.",
      "hints": ["Multiply 27 min by 8 cakes.", "Convert the total minutes to hours and minutes (÷ 60)."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q32",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q2. Two-blank FIB: hours then minutes (3 h, 36 min). Answer key: 27 x 8 = 216 min = 3h 36min."
    },
    {
      "n": 33,
      "type_id": 2,
      "question": "The figure is made up of 4 identical squares. Find the sum of \\(\\angle k\\), \\(\\angle m\\) and \\(\\angle n\\). [?]°",
      "answer0": "135",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 194,
      "difficulty_id": 3,
      "explanation": "Each square's diagonal makes a 45° angle. \\(\\angle m = 90° ÷ 2 = 45°\\) (diagonal of a square). \\(\\angle n + \\angle k = 180° − 90° = 90°\\) (angles forming the complement along the lines). Total \\(= 90° + 45° = 135°\\).",
      "hints": ["A diagonal of a square splits its right angle into two 45° angles.", "Combine the angle relationships to add k, m and n."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q33",
      "image_needed": true,
      "image_options": false,
      "image_file": "q33.png",
      "image_page": 17,
      "image_bbox": [0.18, 0.68, 0.46, 0.88],
      "image_loc": "left; 2x2 grid of identical squares with diagonal lines, angles k, m, n marked",
      "notes": "Paper 2 Q3. FIB, integer answer 135 (degrees). Answer key: m = 45; n + k = 90; total = 135."
    },
    {
      "n": 34,
      "type_id": 1,
      "question": "The figure is made up of 2 rectangles, A and B, overlapping each other. Given that \\(\\dfrac{1}{6}\\) of rectangle A is shaded while \\(\\dfrac{1}{4}\\) of rectangle B is shaded, what fraction of the figure is unshaded?",
      "answer0": "\\(\\dfrac{8}{9}\\)",
      "answer1": "\\(\\dfrac{1}{9}\\)",
      "answer2": "\\(\\dfrac{5}{6}\\)",
      "answer3": "\\(\\dfrac{7}{9}\\)",
      "correct_answer": 0,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "The shaded part is the overlap, equal to \\(\\dfrac{1}{6}\\) of A and \\(\\dfrac{1}{4}\\) of B. Let the overlap be 1 unit: then A = 6 units, B = 4 units, and the whole figure = 6 + 4 − 1 (overlap counted once) = 9 units. Unshaded ÷ total: the key gives \\(\\dfrac{3+5}{6+3} = \\dfrac{8}{9}\\).",
      "hints": ["The shaded overlap is both \\(\\dfrac{1}{6}\\) of A and \\(\\dfrac{1}{4}\\) of B — set it as 1 equal unit.", "Total figure = A + B − overlap; unshaded = total − overlap."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q34",
      "image_needed": true,
      "image_options": false,
      "image_file": "q34.png",
      "image_page": 18,
      "image_bbox": [0.17, 0.20, 0.46, 0.40],
      "image_loc": "left; two overlapping rectangles A (upper-left) and B (lower-right) with the overlap shaded black",
      "notes": "Answer is a fraction (8/9) → MCQ per spec. Answer key: unshaded/total = (3+5)/(6+3) = 8/9 (index 0)."
    },
    {
      "n": 35,
      "type_id": 2,
      "question": "Jolie decorated the room with green and blue lights. The green light blinked every 6 minutes and the blue light blinked every 8 minutes. Both lights were turned on at the same time. After how many minutes did all the lights blink together for the 7th time? [?] min",
      "answer0": "168",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Both lights blink together every LCM(6, 8) = 24 minutes. The 7th time together is at 24 × 7 = 168 minutes.",
      "hints": ["Find the lowest common multiple of 6 and 8.", "Multiply that interval by 7 for the 7th time together."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q35",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q5. FIB, integer answer 168 (min). Answer key: 24 min x 7 = 168 min."
    },
    {
      "n": 36,
      "type_id": 2,
      "question": "\\(\\dfrac{3}{5}\\) of the tank was filled with water. Another 7 ℓ of water was poured into the tank and some water overflowed. What was the volume of water that overflowed in litres? [?] ℓ",
      "answer0": "0.04",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 193,
      "difficulty_id": 3,
      "explanation": "Tank capacity = 29 × 24 × 25 = 17 400 cm³ = 17.4 ℓ. Water at first = \\(\\dfrac{3}{5}\\times 17 400 = 10 440\\) cm³ = 10.44 ℓ. After adding 7 ℓ: 10.44 + 7 = 17.44 ℓ. Overflow = 17.44 − 17.4 = 0.04 ℓ.",
      "hints": ["Find the full tank volume (length × width × height) and convert cm³ to litres.", "Add 7 ℓ to the starting water, then subtract the tank capacity."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q36",
      "image_needed": true,
      "image_options": false,
      "image_file": "q36.png",
      "image_page": 19,
      "image_bbox": [0.18, 0.24, 0.50, 0.43],
      "image_loc": "left; rectangular tank partly filled, dimensions 29 cm, 24 cm, 25 cm",
      "notes": "Paper 2 Q6. FIB, decimal answer 0.04 (L). Answer key: capacity 17.4L; water 10.44L; 10.44+7=17.44L; overflow 17.44-17.4 = 0.04L."
    },
    {
      "n": 37,
      "type_id": 2,
      "question": "Mr Low took a taxi from home to his office. His taxi fare was based on the charges shown: First 1 km costs $4.40; every additional 500 m or less costs $0.35. Mr Low travelled 3.4 km. How much was his taxi fare? [?]",
      "answer0": "6.15",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "First 1 km: $4.40. Remaining distance = 3.4 − 1 = 2.4 km = 2400 m. At $0.35 per 500 m or less, 2400 m needs 5 blocks (2000 m is 4 blocks, the extra 400 m needs a 5th block). 5 × $0.35 = $1.75. Total = $4.40 + $1.75 = $6.15.",
      "hints": ["Charge $4.40 for the first 1 km, then count 500 m blocks for the rest.", "Round each part-block of 500 m up to a full $0.35 charge."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q37",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q7. FIB, money answer 6.15 (dollars). Answer key: 1.75 + 4.40 = 6.15. Charge table transcribed into stem."
    },
    {
      "n": 38,
      "type_id": 2,
      "question": "Mdm Su paid $26.40 for 15 pairs of scissors and 9 pencils. The total cost of a pair of scissors and a pencil was $2.40. Find the cost of a pair of scissors. [?]",
      "answer0": "0.80",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "9 (scissors + pencil) sets cost 9 × $2.40 = $21.60. The remaining 15 − 9 = 6 pairs of scissors cost $26.40 − $21.60 = $4.80. So one pair of scissors = $4.80 ÷ 6 = $0.80.",
      "hints": ["Pair up 9 scissors with the 9 pencils at $2.40 each.", "The leftover scissors account for the rest of the $26.40."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q38",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q8. FIB, money answer 0.80 (dollars). Answer key: $2.40 x 9 = $21.60; a pair of scissors cost $0.80."
    },
    {
      "n": 39,
      "type_id": 2,
      "question": "Mrs Lim bought some beads for Ahmad and Bala. For every 8 beads Ahmad took, Bala took 5 beads. In the end, Ahmad had 216 more beads than Bala. How many beads did Mrs Lim buy? [?]",
      "answer0": "936",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 183,
      "difficulty_id": 3,
      "explanation": "Ahmad : Bala = 8 : 5, so Ahmad has 8 − 5 = 3 units more than Bala. 3 units = 216, so 1 unit = 72. Total units = 8 + 5 = 13, so total beads = 13 × 72 = 936. (Key: Ahmad 576, Bala 360, total 936.)",
      "hints": ["The difference in the ratio is 8 − 5 = 3 units = 216.", "Find 1 unit, then multiply by the total number of units (13)."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q39",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q9. FIB, integer answer 936. Answer key: 1 unit = 216 ÷ 3 = 72; total = 576 + 360 = 936."
    },
    {
      "n": 40,
      "type_id": 2,
      "question": "The figure is made up of identical rectangles. How many more rectangles should be shaded so that the ratio of the number of shaded rectangles to the number of unshaded rectangles is 3 : 5? [?]",
      "answer0": "3",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 181,
      "difficulty_id": 3,
      "explanation": "There are 24 rectangles in total (3 rows × 8). For a shaded : unshaded ratio of 3 : 5, the parts total 3 + 5 = 8, so shaded = \\(\\dfrac{3}{8}\\times 24 = 9\\). Currently 6 are shaded, so 9 − 6 = 3 more must be shaded.",
      "hints": ["Count the total rectangles and the number already shaded.", "Ratio 3 : 5 means 3 out of every 8 are shaded; find that count for the whole figure."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q40",
      "image_needed": true,
      "image_options": false,
      "image_file": "q40.png",
      "image_page": 21,
      "image_bbox": [0.22, 0.18, 0.62, 0.28],
      "image_loc": "centre-top; 3 rows by 8 columns grid of rectangles with some shaded black",
      "notes": "Paper 2 Q10. FIB, integer answer 3. Answer key: 3 x 8 = 24 total; 9 shaded needed; 9 - 6 = 3 more."
    },
    {
      "n": 41,
      "type_id": 2,
      "question": "ABC and XYZ are identical right-angled triangles. The total area of the shaded parts is 130 cm². Find the area of the unshaded part. [?] cm²",
      "answer0": "37",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Each triangle has area \\(\\dfrac{1}{2}\\times 12\\times 17 = 102\\) cm². Two triangles = 204 cm². The unshaded part = (total area of both triangles − total shaded) ÷ 2 = (204 − 130) ÷ 2 = 74 ÷ 2 = 37 cm².",
      "hints": ["Find the area of one triangle (\\(\\dfrac{1}{2}\\times 12\\times 17\\)) and double it.", "Subtract the shaded area, then halve, as the key shows."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q41",
      "image_needed": true,
      "image_options": false,
      "image_file": "q41.png",
      "image_page": 21,
      "image_bbox": [0.52, 0.55, 0.90, 0.76],
      "image_loc": "right; two identical right-angled triangles meeting at point X, shaded regions inside, 12 cm and 17 cm marked",
      "notes": "Paper 2 Q11. FIB, integer answer 37 (cm²). Answer key: 1 triangle = 102; 2 triangles = 204; (204-130)÷2 = 37 cm²."
    },
    {
      "n": 42,
      "type_id": 2,
      "question": "EFGC is a trapezium with EF parallel to CG, ABCD is a square and CE = BE. \\(\\angle CEF = 90\\degree\\). Reflex \\(\\angle BCG = 230\\degree\\) and \\(\\angle GFE = 110\\degree\\).<br>(a) Find \\(\\angle FGC\\). [?]°<br>(b) Find \\(\\angle CBE\\). [?]°",
      "answer0": "70",
      "answer1": "50",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "(a) \\(\\angle DCG = 360° - 230° = 130°\\) (angles at a point). In trapezium EFGC, EF ∥ CG so \\(\\angle FGC + \\angle GFE = 180°\\)... using the key: \\(\\angle BCG = 130° - 90° = 40°\\); \\(\\angle ECB = 130° - 40° - 40° = 50°\\); \\(180° - 110° = 70°\\), so \\(\\angle FGC = 70°\\). (b) \\(\\angle CBE = 130° - 40° - 40° = 50°\\).",
      "hints": ["Use angles at a point (360°) at C and the square's 90° angles.", "Triangle CEB is isosceles since CE = BE."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q42",
      "image_needed": true,
      "image_options": false,
      "image_file": "q42.png",
      "image_page": 22,
      "image_bbox": [0.18, 0.16, 0.62, 0.40],
      "image_loc": "centre; square ABCD with trapezium EFGC attached, angle 110 at F and reflex 230 at C marked",
      "notes": "Paper 2 Q12, two parts. Two-blank FIB: (a) angle FGC = 70, (b) angle CBE = 50. Answer key: (a) 70°, (b) 50°."
    },
    {
      "n": 43,
      "type_id": 0,
      "question": "The interest rates Rise Bank and Shine Bank pay on amounts deposited are shown. Rise Bank: up to $50 000 → 1% per year, above $50 000 → 2.5% per year. Shine Bank: up to $100 000 → 1.5% per year, above $100 000 → 2% per year. Mr Ali wants to deposit $90 000 into a bank. Which bank, Rise Bank or Shine Bank, should he deposit his money so that he will earn more interest at the end of one year? What is the difference in the amount of interest earned between the two banks?",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 176,
      "difficulty_id": 3,
      "explanation": "Rise Bank: 1% of first $50 000 = $500, plus 2.5% of the remaining $40 000 = $1000, total $1500. Shine Bank: 1.5% of $90 000 = $1350. Rise Bank pays more. Difference = $1500 − $1350 = $150. (Answer: Rise Bank, $150.)",
      "hints": ["For Rise Bank apply 1% to the first $50 000 and 2.5% to the rest.", "For Shine Bank the whole $90 000 is in the 1.5% band; compare totals."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q43",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q13. Two-part answer (bank name + money difference) cannot be a single value/sequence FIB → type_id 0, skipped on insert. Answer: Rise Bank; difference $150. (Printed key arithmetic mislabels figures but concludes Rise Bank, $900 written as the line-by-line diff; correct difference is $150: Rise $1500 vs Shine $1350. Flagged: key's intermediate '92250 - 91350 = 900' appears to be an error; mathematically correct difference is $150.)"
    },
    {
      "n": 44,
      "type_id": 0,
      "question": "The table shows the ferry schedule to Bintan Island (Indonesia) from Trust Marine Ferry Terminal (Singapore). BR Ferry: departs 12 10 / 13 10, duration 1h 10min, sails Mon, Wed, Fri. Sinde Ferry: departs 12 20 / 17 05, duration 2h, sails Mon, Thu, Fri. Majestic Ferry: departs 11 30 / 13 10, duration 1h 40min, sails Tue, Wed. Fast Ferry: departs 08 10 / 10 15, duration 1h 20min, sails Wed, Thu, Fri. Bintan (Indonesia) Time is one hour behind Singapore Time. Mrs Lim is planning a ferry ride to Bintan on a Wednesday. A local tour guide will pick her up at 13 30 (Bintan Time).<br>(a)(i) Which operator should she choose to arrive nearest to 1330 (Bintan time)?<br>(a)(ii) What will be the departure (Singapore Time) and arrival (Bintan Time) times of the ride?<br>(b) The local tour guide will have to wait at least 20 minutes if Mrs Lim chooses this operator. Which operator is it?",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 135,
      "difficulty_id": 3,
      "explanation": "(a)(i) BR Ferry. The 13 10 (SG) departure on Wednesday arrives 13 10 + 1h 10min = 14 20 SG = 13 20 Bintan, nearest to 13 30. (a)(ii) Departure 13 10 (Singapore Time); arrival 13 20 (Bintan Time). (b) Majestic Ferry — its arrival is earliest before 13 30, leaving the guide waiting 20+ minutes.",
      "hints": ["Add each Wednesday sailing's duration to its departure, then subtract 1 h for Bintan time.", "Compare each arrival time to 13 30 Bintan; for (b) find the one that arrives well before."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q44",
      "image_needed": true,
      "image_options": false,
      "image_file": "q44.png",
      "image_page": 24,
      "image_bbox": [0.18, 0.16, 0.78, 0.28],
      "image_loc": "centre-top; ferry schedule table (operator, departure times, duration, sailing days)",
      "notes": "Paper 2 Q14. Multi-part with operator-name + time answers → type_id 0, skipped on insert. Answers: (a)(i) BR Ferry; (a)(ii) Departure 13 10 (SG), Arrival 13 20 (Bintan); (b) Majestic Ferry. Per answer key."
    },
    {
      "n": 45,
      "type_id": 2,
      "question": "The average mass of some boxes was 66 kg. When Jane recorded the mass of these boxes, she wrongly indicated one box's mass as 95 kg when it should have been 59 kg. As a result, the average mass was wrongly calculated as 69 kg. How many boxes were there? [?]",
      "answer0": "12",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 205,
      "difficulty_id": 3,
      "explanation": "The wrong average is too high by 69 − 66 = 3 kg per box. The error in the one box's mass is 95 − 59 = 36 kg, which raised the total wrongly by 36 kg. Number of boxes = 36 ÷ 3 = 12.",
      "hints": ["The extra total mass from the wrong record is 95 − 59 = 36 kg.", "That 36 kg is shared as the 3 kg-per-box rise in the average; divide."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q45",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q15. FIB, integer answer 12. Answer key: avg diff = 3; box diff = 36; boxes = 36 ÷ 3 = 12."
    },
    {
      "n": 46,
      "type_id": 1,
      "question": "At a marathon, \\(\\dfrac{4}{7}\\) of the runners were male. \\(\\dfrac{3}{4}\\) of the male runners and 30 female runners completed the race. \\(\\dfrac{2}{5}\\) of the runners did not complete the race. What fraction of the runners who completed the race were females?",
      "answer0": "\\(\\dfrac{6}{21}\\)",
      "answer1": "\\(\\dfrac{6}{35}\\)",
      "answer2": "\\(\\dfrac{15}{21}\\)",
      "answer3": "\\(\\dfrac{2}{7}\\)",
      "correct_answer": 0,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Take total runners as 35 units (7 × 5). Male = \\(\\dfrac{4}{7}\\times 35 = 20\\) units; female = 15 units. Males who completed = \\(\\dfrac{3}{4}\\times 20 = 15\\) units. Total who completed = \\(\\dfrac{3}{5}\\times 35 = 21\\) units. Females who completed = 21 − 15 = 6 units. Fraction of finishers who were female = \\(\\dfrac{6}{21}\\).",
      "hints": ["Let total runners be 35 units so the fractions divide evenly.", "Finishers = \\(\\dfrac{3}{5}\\) of all; subtract the male finishers to get female finishers."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q46",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q16(a). Answer is a fraction (6/21) → MCQ per spec. Answer key: male completed 15 units, total completed 21 units, female completed 6 units → 6/21 (index 0)."
    },
    {
      "n": 47,
      "type_id": 2,
      "question": "At a marathon, \\(\\dfrac{4}{7}\\) of the runners were male. \\(\\dfrac{3}{4}\\) of the male runners and 30 female runners completed the race. \\(\\dfrac{2}{5}\\) of the runners did not complete the race. How many fewer female runners than male runners were there in the marathon? [?]",
      "answer0": "25",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Females who completed = 6 units (from part a) = 30 runners, so 1 unit = 5 runners. Male = 20 units, female = 15 units; the difference is 20 − 15 = 5 units = 5 × 5 = 25 runners.",
      "hints": ["The 6 units of female finishers equal 30 runners — find 1 unit.", "Male − female = 20 units − 15 units = 5 units; convert to runners."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q47",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q16(b). FIB, integer answer 25. Answer key: male - female = 5 units; 1 unit = 5; 5 x 5 = 25."
    },
    {
      "n": 48,
      "type_id": 2,
      "question": "The numbers represent the seat numbers at a theatre. Row 1 has 1 seat (seat 1); Row 2 has 2 seats (3, 5); Row 3 has 3 seats (7, 9, 11); Row 4 has 4 seats (13, 15, 17, 19); Row 5 has 5 seats (21, 23, 25, 27, 29).<br>(a) Find the greatest seat number in Row 9. [?]<br>(b) Maya's seat number is 53. Which Row is she seated at? [?]",
      "answer0": "89",
      "answer1": "7",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Seat numbers are the odd numbers in order. The greatest seat number in Row n is the (total seats up to row n)-th odd number = n(n+1)/2 × ... directly: total seats up to Row 9 = 1+2+...+9 = 45, and the 45th odd number is 2×45 − 1 = 89. (a) 89. (b) Total seats up to Row 6 = 21, up to Row 7 = 28; seat 53 is the 27th odd number (53 = 2×27 − 1), and 27 falls between 22 and 28, so it is in Row 7.",
      "hints": ["Seat numbers are consecutive odd numbers; the greatest in a row is the (cumulative seat count)-th odd number.", "Cumulative seats up to Row n = 1+2+...+n; find which row's range contains seat 53."],
      "source": "Tao Nan 2024 P5 End-of-Year Exam Q48",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q17(a)&(b). Two-blank FIB: (a) 89, (b) 7 (row number). Answer key: a) 89, b) 7. Part (c) tick-table (True/False) omitted as it is an interactive matching task with no value answer."
    }
  ]
}