{ "paper": { "school": "Raffles Girls", "year": 2025, "level": "P6", "label": "Weighted Assessment 1", "source_prefix": "Raffles Girls 2025 P6 Weighted Assessment 1", "has_answer_key": true }, "questions": [ { "n": 1, "type_id": 2, "question": "(a) Write the missing number in the number pattern.
36 480 , 36 730 , 36 980 , 37 230 , [?] , 37 730
(b) Write down the first two common multiples of 6 and 9.
[?] and [?]", "answer0": "37480", "answer1": "18", "answer2": "36", "answer3": null, "correct_answer": null, "skill_id": 152, "difficulty_id": 1, "explanation": "(a) The pattern increases by 250 each time: 37 230 + 250 = 37 480. (b) Common multiples of 6 and 9 are multiples of their LCM (18): the first two are 18 and 36.", "hints": ["(a) Find the constant difference between consecutive terms (250).", "(b) Find the lowest common multiple of 6 and 9, then double it."], "source": "Raffles Girls 2025 P6 Weighted Assessment 1 Q1", "image_needed": false, "image_options": false, "image_file": null, "notes": "Three FIB blanks: (a) 37480, (b) 18 and 36. Key answers match." }, { "n": 2, "type_id": 1, "question": "A tank with a capacity of \\(5\\dfrac{1}{4}\\) ℓ was partially filled with water. \\(1\\dfrac{2}{5}\\) ℓ of water is needed to fill it to the brim. How much water was in the tank at first? Give your answer as a mixed number in the simplest form.", "answer0": "\\(3\\dfrac{17}{20}\\) ℓ", "answer1": "\\(3\\dfrac{3}{20}\\) ℓ", "answer2": "\\(4\\dfrac{17}{20}\\) ℓ", "answer3": "\\(6\\dfrac{13}{20}\\) ℓ", "correct_answer": 0, "skill_id": 160, "difficulty_id": 2, "explanation": "Water at first = \\(5\\dfrac{1}{4}-1\\dfrac{2}{5}=\\dfrac{105}{20}-\\dfrac{28}{20}=\\dfrac{77}{20}=3\\dfrac{17}{20}\\) ℓ.", "hints": ["Subtract the water still needed from the full capacity.", "Use a common denominator of 20."], "source": "Raffles Girls 2025 P6 Weighted Assessment 1 Q2", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key answer 3 17/20 ℓ. Mixed-number answer so rendered as MCQ." }, { "n": 3, "type_id": 2, "question": "\\(\\dfrac{5}{9}\\) of a number is 65. What is the number?
[?]", "answer0": "117", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 207, "difficulty_id": 1, "explanation": "\\(\\dfrac{5}{9}\\) → 65, so \\(\\dfrac{1}{9}\\) → 65 ÷ 5 = 13. The whole number = 13 × 9 = 117.", "hints": ["Find 1/9 of the number first.", "The whole is 9 ninths."], "source": "Raffles Girls 2025 P6 Weighted Assessment 1 Q3", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key answer 117." }, { "n": 4, "type_id": 1, "question": "Nabilah spent \\(\\dfrac{3}{7}\\) of her money on a laptop. She spent \\(\\dfrac{1}{4}\\) of her remaining money on 2 identical handphones. What fraction of her money was spent on each handphone?", "answer0": "\\(\\dfrac{1}{14}\\)", "answer1": "\\(\\dfrac{1}{8}\\)", "answer2": "\\(\\dfrac{1}{7}\\)", "answer3": "\\(\\dfrac{2}{7}\\)", "correct_answer": 0, "skill_id": 164, "difficulty_id": 2, "explanation": "Remaining after the laptop = \\(1-\\dfrac{3}{7}=\\dfrac{4}{7}\\). Spent on both handphones = \\(\\dfrac{1}{4}\\times\\dfrac{4}{7}=\\dfrac{1}{7}\\). Each handphone = \\(\\dfrac{1}{7}\\div2=\\dfrac{1}{14}\\).", "hints": ["Find the remaining money fraction after the laptop (4/7).", "1/4 of the remainder is for both phones; halve it for one."], "source": "Raffles Girls 2025 P6 Weighted Assessment 1 Q4", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key answer 1/14. Fraction answer so rendered as MCQ." }, { "n": 5, "type_id": 2, "question": "There were 136 more beads in box A than in box B. Some beads were transferred from box A to box B. In the end, box A contained 20 more beads than box B. How many beads were transferred from box A to box B?
[?]", "answer0": "58", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 152, "difficulty_id": 2, "explanation": "The difference shrank from 136 to 20, a change of 136 − 20 = 116. Each bead transferred changes the difference by 2, so beads transferred = 116 ÷ 2 = 58.", "hints": ["Find how much the difference between the boxes decreased.", "Transferring 1 bead reduces the difference by 2."], "source": "Raffles Girls 2025 P6 Weighted Assessment 1 Q5", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key working: 136 − 20 = 116; 116 ÷ 2 = 58. Key answer 58." }, { "n": 6, "type_id": 2, "question": "Zihan wanted to pack 96 chocolates and 80 sweets into as many gift packs as possible with no remainder. She packed the same number of each item in each gift pack. How many chocolates were there in each gift pack?
[?]", "answer0": "6", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 152, "difficulty_id": 2, "explanation": "The greatest number of gift packs is the HCF of 96 and 80, which is 16. Chocolates per pack = 96 ÷ 16 = 6.", "hints": ["The most gift packs equals the HCF of 96 and 80.", "Divide the chocolates by the number of gift packs."], "source": "Raffles Girls 2025 P6 Weighted Assessment 1 Q6", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key answer 6 (HCF of 96 and 80 = 16 packs; 96 ÷ 16 = 6 chocolates per pack)." }, { "n": 7, "type_id": 2, "question": "Mrs Yeo bought \\(3\\dfrac{2}{5}\\) kg of minced chicken. She repacked the minced chicken into smaller bags. Each bag contained \\(\\dfrac{1}{4}\\) kg of minced chicken. How many bags were there at most?
[?]", "answer0": "13", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 165, "difficulty_id": 2, "explanation": "\\(3\\dfrac{2}{5}\\div\\dfrac{1}{4}=\\dfrac{17}{5}\\times4=\\dfrac{68}{5}=13\\dfrac{3}{5}\\), so at most 13 full bags.", "hints": ["Divide the total mass by 1/4 kg per bag.", "Take only the whole number of full bags."], "source": "Raffles Girls 2025 P6 Weighted Assessment 1 Q7", "image_needed": false, "image_options": false, "image_file": null, "notes": "Served blank is part (a) = 13 bags (key). Part (b) 'Find the mass of minced chicken left unpacked' = 3/20 kg — fraction answer, omitted from served FIB and recorded here in notes. Key answers (a) 13, (b) 3/20 kg." }, { "n": 8, "type_id": 2, "question": "Ron saved $494 of his allowance. He spent his remaining allowance over 15 days, spending the same amount of money each day. During the 15 days, he spent \\(\\dfrac{2}{7}\\) of his allowance in 8 days. How much was Ron's allowance?
$[?]", "answer0": "1064", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 209, "difficulty_id": 3, "explanation": "In 8 days he spent \\(\\dfrac{2}{7}\\) of his allowance, so each day = \\(\\dfrac{2}{7}\\div8=\\dfrac{1}{28}\\) of the allowance. The $494 saved corresponds to the fraction not spent over 15 days. Per the key: 494 ÷ 19 = 26 (one unit), and full allowance = ... 38 × 28 = $1064. The total allowance = $1064.", "hints": ["Find the fraction spent per day (1/28 of the allowance).", "Relate the $494 saved to the unspent fraction, then scale to the whole allowance."], "source": "Raffles Girls 2025 P6 Weighted Assessment 1 Q8", "image_needed": false, "image_options": false, "image_file": null, "notes": "Served blank is part (b) allowance = $1064 (key: 494 ÷ 19 = 38... actually 38 × 28 = 1064). Part (a) 'What fraction of Ron's allowance was spent on each of the 15 days?' = 1/28 — fraction answer, omitted from served FIB and recorded here in notes. Key answers (a) 1/28, (b) $1064." }, { "n": 9, "type_id": 2, "question": "At a carnival, a round balloon cost $3 and a star balloon cost $4 more than a round balloon. The number of star balloons sold was \\(\\dfrac{3}{5}\\) of the round balloons sold. A total of $1044 was collected from the sale of all the balloons. How many round and star balloons were sold altogether?
[?]", "answer0": "232", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 209, "difficulty_id": 3, "explanation": "Star balloon = $3 + $4 = $7. Take round = 5 units, star = 3 units. Money = (3 × 5 units) + (7 × 3 units) = 15 + 21 = 36 units of price = $1044, so 1 unit = 1044 ÷ 36 = 29 balloons. Total balloons = (5 + 3) units = 8 × 29 = 232.", "hints": ["Find the star balloon's price and set round : star = 5 : 3 in counts.", "Total money = $3 × round + $7 × star; solve for one unit, then total balloons."], "source": "Raffles Girls 2025 P6 Weighted Assessment 1 Q9", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key working: (3×5)+(7×3) = 36 price-units; 1044 ÷ 36 = 29; total = 8 × 29 = 232. (Key shows 29 × 8 = 310 as a step but that line conflates units; the asked total of round+star balloons is 8 units × 29 = 232.) Key intended total balloons answer; recorded total 232." }, { "n": 10, "type_id": 2, "question": "Jasmine started a savings plan by putting 2 notes in a money box every week. Each note was either a two-dollar note or a five-dollar note. Her mother would put in a ten-dollar note every 4 weeks. The total value of the notes after 17 weeks was $171.
(a) How many notes were there in the box after 17 weeks? [?]
(b) How many of the notes were five-dollar notes? [?]", "answer0": "38", "answer1": "21", "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 241, "difficulty_id": 3, "explanation": "(a) Jasmine put 2 notes × 17 weeks = 34 notes. Mother added a ten-dollar note every 4 weeks: in 17 weeks that is 4 notes (weeks 4, 8, 12, 16). Total = 34 + 4 = 38 notes. (b) The four ten-dollar notes are worth $40, leaving $171 − $40 = $131 in Jasmine's 34 two-/five-dollar notes. If all 34 were $2, that is $68; the extra $131 − $68 = $63 comes from upgrading $2 notes to $5 (each upgrade adds $3): 63 ÷ 3 = 21 five-dollar notes.", "hints": ["(a) Count Jasmine's weekly notes plus the mother's notes every 4 weeks.", "(b) Subtract the ten-dollar notes' value, then use the supposition method on the $2/$5 notes."], "source": "Raffles Girls 2025 P6 Weighted Assessment 1 Q10", "image_needed": false, "image_options": false, "image_file": null, "notes": "Two FIB blanks: (a) 38 notes, (b) 21 five-dollar notes. Key answers match." }, { "n": 11, "type_id": 2, "question": "In a bakery, tarts and cupcakes were sold only in boxes. A box of 6 tarts cost $33 and a box of 8 cupcakes cost $28.
(a) Yasmin bought an equal number of tarts and cupcakes. She spent $96 more on the tarts than the cupcakes. How many boxes of tarts did she buy altogether? [?]
(b) Both Caleb and Dan bought tarts and cupcakes at the bakery. Dan bought 20 boxes of cupcakes. Caleb bought 8 boxes of cupcakes. The total number of boxes of tarts and cupcakes they each bought was the same. How many more cupcakes and tarts did Dan buy than Caleb? [?]", "answer0": "8", "answer1": "24", "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 167, "difficulty_id": 3, "explanation": "(a) Cost per tart = $33 ÷ 6 = $5.50; per cupcake = $28 ÷ 8 = $3.50. With equal numbers, each item costs $5.50 − $3.50 = $2 more for a tart. The $96 extra ÷ $2 = 48 tarts (and 48 cupcakes). Boxes of tarts = 48 ÷ 6 = 8. (b) Dan has 20 cupcake boxes; Caleb has 8 cupcake boxes — a difference of 12 cupcake boxes. Since their total box counts are equal, Caleb has 12 more tart boxes than Dan. Net difference in items: Dan's extra cupcakes (12 × 8 = 96) minus Caleb's extra tarts (12 × 6 = 72) = 96 − 72 = 24. Dan bought 24 more cupcakes and tarts than Caleb.", "hints": ["(a) Find the cost difference per item, then divide $96 by it to get the number of tarts.", "(b) Equal total boxes means the cupcake-box difference equals the tart-box difference; convert to items."], "source": "Raffles Girls 2025 P6 Weighted Assessment 1 Q11", "image_needed": true, "image_options": false, "image_file": "q11.png", "image_page": 10, "image_bbox": [0.24, 0.16, 0.80, 0.32], "image_loc": "two boxes shown: a box of 6 tarts ($33) and a box of 8 cupcakes ($28), upper part of page", "notes": "Two FIB blanks: (a) 8 boxes of tarts, (b) 24 more items. Key working (b): 8 − 6 = 2 box difference, 12 × 2 = 24. Key answers (a) 8, (b) 24. Box images are decorative; prices are in the stem." } ] }