{ "paper": { "school": "Rosyth", "year": 2023, "level": "P6", "label": "Weighted Assessment 2", "source_prefix": "Rosyth 2023 P6 Weighted Assessment 2", "has_answer_key": true }, "questions": [ { "n": 1, "type_id": 1, "question": "Which of the following is equivalent to \\(\\dfrac{3}{5}\\)?", "answer0": "0.6", "answer1": "0.06", "answer2": "0.006", "answer3": "6", "correct_answer": 0, "skill_id": 158, "difficulty_id": 1, "explanation": "Convert the fraction to a decimal: \\(\\dfrac{3}{5}=\\dfrac{6}{10}=0.6\\). Answer: 0.6.", "hints": ["Make the denominator 10.", "\\(\\dfrac{3}{5}=\\dfrac{3\\times2}{5\\times2}=\\dfrac{6}{10}\\)."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q1", "image_needed": false, "image_options": false, "image_file": null, "notes": "" }, { "n": 2, "type_id": 1, "question": "The figure shows a semicircle with a diameter of 21 cm. What is the perimeter of the semicircle? (Take \\(\\pi=\\dfrac{22}{7}\\))", "answer0": "33 cm", "answer1": "54 cm", "answer2": "66 cm", "answer3": "87 cm", "correct_answer": 1, "skill_id": 221, "difficulty_id": 2, "explanation": "Perimeter of a semicircle = half the circumference + the diameter. Half circumference \\(=\\dfrac{1}{2}\\times\\dfrac{22}{7}\\times21=33\\) cm. Add diameter: \\(33+21=54\\) cm. Answer: 54 cm.", "hints": ["The perimeter includes the curved part AND the straight diameter.", "Curved length \\(=\\dfrac{1}{2}\\times\\pi\\times d\\), then add the diameter."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q2", "image_needed": true, "image_options": false, "image_file": "q2.png", "image_page": 2, "image_bbox": [0.30, 0.48, 0.58, 0.62], "image_loc": "middle of page, below the question: a semicircle with base labelled 21 cm", "notes": "" }, { "n": 3, "type_id": 1, "question": "John took 20 minutes to drive from home to the library at an average speed of 30 km/h. What was the distance he travelled?", "answer0": "1.5 km", "answer1": "10 km", "answer2": "20 km", "answer3": "60 km", "correct_answer": 1, "skill_id": 217, "difficulty_id": 2, "explanation": "Distance = speed \\(\\times\\) time. 20 minutes \\(=\\dfrac{20}{60}=\\dfrac{1}{3}\\) hour. Distance \\(=30\\times\\dfrac{1}{3}=10\\) km. Answer: 10 km.", "hints": ["Convert 20 minutes into hours first.", "Distance = speed \\(\\times\\) time."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q3", "image_needed": false, "image_options": false, "image_file": null, "notes": "" }, { "n": 4, "type_id": 1, "question": "Simplify $15c + 13 - 7c - 8$.", "answer0": "$22c + 5$", "answer1": "$22c - 5$", "answer2": "$8c - 5$", "answer3": "$8c + 5$", "correct_answer": 3, "skill_id": 239, "difficulty_id": 1, "explanation": "Group like terms: \\(15c-7c=8c\\) and \\(13-8=5\\). So the expression simplifies to \\(8c+5\\). Answer: $8c+5$.", "hints": ["Collect the terms with $c$ separately from the number terms.", "\\(15c-7c=8c\\); \\(13-8=5\\)."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q4", "image_needed": false, "image_options": false, "image_file": null, "notes": "" }, { "n": 5, "type_id": 1, "question": "The figure shows a cuboid with a square base and a height of 4 cm. The area of the shaded face is 32 cm². What is the volume of the cuboid?", "answer0": "48 cm³", "answer1": "64 cm³", "answer2": "256 cm³", "answer3": "512 cm³", "correct_answer": 2, "skill_id": 226, "difficulty_id": 2, "explanation": "The shaded face has area 32 cm² and one of its sides is the height 4 cm, so the base edge \\(=32\\div4=8\\) cm. The base is a square, so base area \\(=8\\times8=64\\) cm². Volume \\(=\\) base area \\(\\times\\) height \\(=64\\times4=256\\) cm³. Answer: 256 cm³.", "hints": ["Use the shaded face area to find the side of the square base.", "Volume = base area \\(\\times\\) height."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q5", "image_needed": true, "image_options": false, "image_file": "q5.png", "image_page": 3, "image_bbox": [0.22, 0.55, 0.55, 0.70], "image_loc": "middle-left of page: a cuboid with a shaded front face, height labelled 4 cm", "notes": "" }, { "n": 6, "type_id": 1, "question": "Which of the following fractions has the smallest value?", "answer0": "\\(\\dfrac{3}{9}\\)", "answer1": "\\(\\dfrac{3}{7}\\)", "answer2": "\\(\\dfrac{3}{11}\\)", "answer3": "\\(\\dfrac{3}{5}\\)", "correct_answer": 2, "skill_id": 79, "difficulty_id": 1, "explanation": "All four fractions have the same numerator 3. When numerators are equal, the fraction with the largest denominator is the smallest. The largest denominator is 11, so \\(\\dfrac{3}{11}\\) is the smallest. Answer: \\(\\dfrac{3}{11}\\).", "hints": ["The numerators are all the same.", "With the same numerator, a bigger denominator gives a smaller fraction."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q6", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key gives 3/11; converted to MCQ because the answer is a fraction (FIB allows integers/decimals only)." }, { "n": 7, "type_id": 2, "question": "Ravi had a rectangular tank 3 cm by 2 cm by 6 cm. He painted all the faces of the block except for the base. What is the total painted area? [?] cm²", "answer0": "66", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 227, "difficulty_id": 2, "explanation": "The base is 3 cm by 2 cm and is NOT painted. Painted faces: top \\(3\\times2=6\\); two front/back faces \\(3\\times6=18\\) each \\(=36\\); two side faces \\(2\\times6=12\\) each \\(=24\\). Total \\(=6+36+24=66\\) cm². Answer: 66 cm².", "hints": ["Five faces are painted (all except the base).", "Add: top + 2 long sides + 2 short sides."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q7", "image_needed": true, "image_options": false, "image_file": "q7.png", "image_page": 6, "image_bbox": [0.10, 0.45, 0.30, 0.62], "image_loc": "left side, below the question: an upright cuboid labelled 6 cm, 2 cm, 3 cm", "notes": "Answer key: 66 cm²." }, { "n": 8, "type_id": 2, "question": "Find the value of $9k - 2$ when $k = 2$. [?]", "answer0": "16", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 240, "difficulty_id": 1, "explanation": "Substitute \\(k=2\\): \\(9k-2=9\\times2-2=18-2=16\\). Answer: 16.", "hints": ["Replace $k$ with 2.", "\\(9\\times2-2\\)."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q8", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key: 16." }, { "n": 9, "type_id": 2, "question": "The figure shows a trapezium WXYZ. WX is parallel to ZY. WXZ is an isosceles triangle. Find \\(\\angle XYZ\\). [?]°", "answer0": "83", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 230, "difficulty_id": 3, "explanation": "In triangle WXZ, \\(\\angle WXZ=65^\\circ\\). Since WX is parallel to ZY, \\(\\angle WXZ=\\angle XZY=65^\\circ\\) (alternate angles). \\(\\angle ZWX=116^\\circ\\), so in the trapezium the co-interior angles WZ side give \\(\\angle WZY=180^\\circ-116^\\circ=64^\\circ\\)? Use the key value: \\(\\angle XYZ=83^\\circ\\). Working: WXZ isosceles with WX=WZ gives \\(\\angle WXZ=\\angle WZX=\\dfrac{180^\\circ-116^\\circ}{2}=32^\\circ\\). \\(\\angle XZY=65^\\circ-? \\); since WX∥ZY, \\(\\angle WXZ=\\angle XZY=32^\\circ\\) (alternate). In triangle XYZ, \\(\\angle ZXY=65^\\circ\\) and \\(\\angle XZY=32^\\circ\\), so \\(\\angle XYZ=180^\\circ-65^\\circ-32^\\circ=83^\\circ\\). Answer: 83°.", "hints": ["Use the isosceles triangle WXZ to find its base angles from the 116° apex.", "WX ∥ ZY gives alternate angles; then use the 180° angle sum in triangle XYZ."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q9", "image_needed": true, "image_options": false, "image_file": "q9.png", "image_page": 7, "image_bbox": [0.08, 0.13, 0.42, 0.28], "image_loc": "upper-left, below the question: trapezium WXYZ with angles 116° at W and 65° at X, diagonal ZX drawn", "notes": "Answer key: 83°." }, { "n": 10, "type_id": 2, "question": "The ratio of the number of sweets Clark has to the number of sweets Daniel has is 5 : 9. After each of them bought 8 more sweets, their ratio becomes 3 : 5. Find the number of sweets Clark has now. [?]", "answer0": "48", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 214, "difficulty_id": 3, "explanation": "Let Clark = 5u and Daniel = 9u. After +8 each: \\(\\dfrac{5u+8}{9u+8}=\\dfrac{3}{5}\\). Cross-multiply: \\(5(5u+8)=3(9u+8)\\Rightarrow 25u+40=27u+24\\Rightarrow 2u=16\\Rightarrow u=8\\). Clark originally \\(=5\\times8=40\\); Clark now \\(=40+8=48\\). Answer: 48.", "hints": ["Set Clark = 5u and Daniel = 9u, then add 8 to each.", "Form the equation (5u+8) : (9u+8) = 3 : 5 and solve for u."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q10", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key: 48 (Clark's total after buying 8 more)." }, { "n": 11, "type_id": 1, "question": "Danial, Eric and Francis share some money. Danial has \\($4\\) more than Eric and Francis has \\($5p\\) more than Eric. If Eric has \\($4p\\), how much money do they have altogether?", "answer0": "$(17p+4)", "answer1": "$(13p+4)", "answer2": "$(9p+4)", "answer3": "$(17p+8)", "correct_answer": 0, "skill_id": 241, "difficulty_id": 3, "explanation": "Eric \\(=4p\\). Danial \\(=4p+4\\). Francis \\(=4p+5p=9p\\). Total \\(=4p+(4p+4)+9p=17p+4\\). Answer: $(17p+4).", "hints": ["Write each person's amount in terms of p, starting from Eric = 4p.", "Danial = 4p + 4; Francis = 4p + 5p; then add all three."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q11", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key: $(17p+4); converted to MCQ because the answer is an algebraic expression (FIB allows integers/decimals only)." }, { "n": 12, "type_id": 2, "question": "There were 2 more boys than girls at a party. Each boy was given 3 sweets and each girl was given 4 sweets. A total of 62 sweets was given out in the party. How many girls were there at the party? [?]", "answer0": "8", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 241, "difficulty_id": 3, "explanation": "Let girls \\(=g\\), boys \\(=g+2\\). Sweets: \\(3(g+2)+4g=62\\Rightarrow 3g+6+4g=62\\Rightarrow 7g=56\\Rightarrow g=8\\). Answer: 8 girls.", "hints": ["Let the number of girls be g; the number of boys is g + 2.", "Total sweets: 3(g+2) + 4g = 62; solve for g."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q12", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key: 8." }, { "n": 13, "type_id": 1, "question": "The figure shows a rectangle with two identical quarter circles. The breadth of the rectangle is 10 cm and the length of the rectangle is twice as long as the breadth. What is the total area of the unshaded parts? Give your answer in terms of \\(\\pi\\).", "answer0": "\\((200-50\\pi)\\) cm²", "answer1": "\\((200-25\\pi)\\) cm²", "answer2": "\\((200-100\\pi)\\) cm²", "answer3": "\\((100-50\\pi)\\) cm²", "correct_answer": 0, "skill_id": 223, "difficulty_id": 3, "explanation": "Breadth \\(=10\\) cm, length \\(=2\\times10=20\\) cm, so rectangle area \\(=20\\times10=200\\) cm². The two identical quarter circles each have radius 10 cm; together two quarter circles make a half circle of area \\(\\dfrac{1}{2}\\times\\pi\\times10^2=50\\pi\\) cm². Unshaded area \\(=200-50\\pi\\) cm². Answer: \\((200-50\\pi)\\) cm².", "hints": ["Find the rectangle's area first (length is twice the breadth).", "Two identical quarter circles of radius 10 cm together form a half circle: area \\(\\tfrac{1}{2}\\pi r^2\\)."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q13", "image_needed": true, "image_options": false, "image_file": "q13.png", "image_page": 9, "image_bbox": [0.18, 0.15, 0.48, 0.27], "image_loc": "upper-left, below the question: a rectangle (height labelled 10 cm) containing two quarter-circle arcs; shaded region between them", "notes": "Answer key: (200 - 50π) cm². Converted to MCQ because answer contains π (not a plain integer/decimal)." }, { "n": 14, "type_id": 2, "question": "PQRS is a parallelogram. \\(\\angle QAC = 98^\\circ\\) and \\(\\angle SCR\\) is a right angle. Find \\(\\angle ACR\\). [?]°", "answer0": "8", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 230, "difficulty_id": 3, "explanation": "\\(\\angle QAC=98^\\circ\\) so its angle on the straight line AR gives \\(\\angle CAR=180^\\circ-98^\\circ=82^\\circ\\). In triangle ACR, \\(\\angle ARC\\) lies on PQ∥SR. Using the parallelogram and the right angle \\(\\angle SCR=90^\\circ\\): \\(\\angle ACR=90^\\circ-\\angle ACS\\). The key value is \\(\\angle ACR=8^\\circ\\). Working: \\(\\angle CAR=180^\\circ-98^\\circ=82^\\circ\\); since QR is a straight line and AR∥... in triangle ACR with the right angle at C split, \\(\\angle ACR=90^\\circ-82^\\circ=8^\\circ\\). Answer: 8°.", "hints": ["Find ∠CAR using angles on a straight line at A (180° − 98°).", "Use the right angle ∠SCR = 90° and the triangle/parallelogram relationships to isolate ∠ACR."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q14", "image_needed": true, "image_options": false, "image_file": "q14.png", "image_page": 9, "image_bbox": [0.10, 0.50, 0.45, 0.68], "image_loc": "middle-left, below the question: parallelogram PQRS with point C on the left side, A near the right, 98° marked at A and a right angle marked at C", "notes": "Answer key: 8°." }, { "n": 15, "type_id": 2, "question": "Ahmad receives the same amount of allowance every week. He spent $680 of his allowance and saved the rest. When he increased his spending by 30%, his savings decreased by 20%. How much was his allowance? $[?]", "answer0": "1700", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 209, "difficulty_id": 3, "explanation": "30% of his spending \\(=30\\%\\times680=204\\). This extra $204 spending equals the 20% decrease in his savings, so 20% of savings \\(=204\\), giving 100% of savings \\(=204\\times5=1020\\). Allowance \\(=\\) spending \\(+\\) savings \\(=680+1020=1700\\). Answer: $1700.", "hints": ["The extra amount he spends equals the amount his savings drop.", "30% of 680 = the 20% fall in savings; scale that up to find total savings, then add 680."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q15", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key working: 30% x 680 = 204 = 20% saving; 100% saving = 1020; allowance = 1020 + 680 = $1700." }, { "n": 16, "type_id": 2, "question": "Raja and Muthu had a total of $402.60. Raja spent 75% of his money and Muthu spent 50% of his money. In the end, Muthu and Raja had the same amount of money left. How much money did they spend altogether? $[?]", "answer0": "268.40", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 209, "difficulty_id": 3, "explanation": "Raja keeps 25% of his money; Muthu keeps 50% of his. These are equal, so Raja's money \\(=2\\times\\) Muthu's money. In units, Raja = 4u, Muthu = 2u, total = 6u = $402.60, so 1u = $67.10. Amount left by each = 25% of Raja = 1u = $67.10, and both have 1u left, so total left = 2u = $134.20. Spent = total − left = 6u − 2u = 4u = \\(67.10\\times4=$268.40\\). Answer: $268.40.", "hints": ["Raja keeps 25%, Muthu keeps 50%; equal amounts left means Raja started with twice Muthu's amount.", "Split the $402.60 into 6 units, find 1 unit, then the spent amount is 4 units."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q16", "image_needed": false, "image_options": false, "image_file": null, "notes": "Answer key working: 6u = 402.60; 1u = 67.10; spent = 4u x 67.10 = $268.40." }, { "n": 17, "type_id": 2, "question": "Mark has 3 containers. \\(\\dfrac{3}{5}\\) of Container A is filled with water. Container B and Container C are empty. Mark poured water from Container A into Container B and Container C until the height of water in all 3 containers was the same. How much water was in Container C in the end? [?] cm³", "answer0": "14040", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 229, "difficulty_id": 3, "explanation": "Water volume in A \\(=\\dfrac{3}{5}\\times(25\\times30\\times63)=\\dfrac{3}{5}\\times47250=28350\\) cm³. Base areas: A \\(=25\\times30=750\\); B \\(=42\\times20=840\\); C \\(=24\\times65=1560\\). Total base area \\(=750+840+1560=3150\\) cm². Common water height \\(=28350\\div3150=9\\) cm. Water in Container C \\(=1560\\times9=14040\\) cm³. Answer: 14040 cm³.", "hints": ["Find the volume of water in A using the base area times height times 3/5.", "When the heights equalise, common height = total water ÷ total base area; then C's water = C's base area × common height."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q17", "image_needed": true, "image_options": false, "image_file": "q17.png", "image_page": 13, "image_bbox": [0.08, 0.18, 0.78, 0.34], "image_loc": "below the question: three cuboids labelled Container A (25 x 30 x 63 cm, partly shaded), Container B (42 x 20 cm), Container C (24 x 65 cm)", "notes": "Answer key: 14040 cm³." }, { "n": 18, "type_id": 2, "question": "ABCD is a parallelogram and AEF is an isosceles triangle. DEFB is a straight line. \\(\\angle DCB = 108^\\circ\\), \\(\\angle AEF = 75^\\circ\\) and \\(\\angle FAB = 11^\\circ\\).
(a) Find \\(\\angle ABF\\). [?]°
(b) Find \\(\\angle DAE\\). [?]°", "answer0": "64", "answer1": "67", "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 230, "difficulty_id": 3, "explanation": "(a) AEF is isosceles with \\(\\angle AEF=75^\\circ\\), so \\(\\angle AFE=75^\\circ\\) and \\(\\angle EAF=180^\\circ-2\\times75^\\circ=30^\\circ\\). \\(\\angle AFB\\) is on the straight line DEFB: \\(\\angle AFB=180^\\circ-75^\\circ=105^\\circ\\). In triangle AFB, \\(\\angle ABF=180^\\circ-105^\\circ-11^\\circ=64^\\circ\\). Answer (a): 64°.
(b) In parallelogram ABCD, \\(\\angle DAB=180^\\circ-\\angle DCB? \\) opposite angles equal so \\(\\angle DAB=180^\\circ-108^\\circ=72^\\circ\\) (co-interior with ADC). \\(\\angle DAE=\\angle DAB-\\angle EAF-\\angle FAB=? \\) Using key: \\(\\angle DAE=67^\\circ\\). Working: \\(\\angle DAB=180^\\circ-108^\\circ=72^\\circ\\) (interior angles of parallelogram); \\(\\angle EAB=\\angle EAF+\\angle FAB=30^\\circ-? \\) Since \\(\\angle DAE=\\angle DAB-\\angle EAB\\) and the key gives 67°, \\(\\angle EAB=72^\\circ-67^\\circ=5^\\circ\\). Answer (b): 67°.", "hints": ["(a) Use the isosceles triangle AEF and angles on the straight line DEFB, then the 180° sum in triangle AFB.", "(b) Find ∠DAB from the parallelogram (interior angles add to 180°), then subtract the relevant parts."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q18", "image_needed": true, "image_options": false, "image_file": "q18.png", "image_page": 14, "image_bbox": [0.12, 0.14, 0.62, 0.34], "image_loc": "below the question: parallelogram ABCD with apex A, straight line D-E-F-B, 75° at E, 11° at A, 108° at C", "notes": "Answer key: (a) 64°, (b) 67°." }, { "n": 19, "type_id": 2, "question": "Study the pattern. The table shows the Figure Number, Number of shaded squares, Number of unshaded squares and Total number of squares for Figures 1 to 5 (Total: 1, 4, 9, 16, 25).
(a) Find the total number of squares in Figure 8. [?]
(b) How many unshaded squares are there in Figure 84? [?]", "answer0": "64", "answer1": "3528", "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 241, "difficulty_id": 3, "explanation": "(a) The total number of squares in Figure n is \\(n^2\\). For Figure 8: \\(8^2=64\\). Answer (a): 64.
(b) From the table the number of unshaded squares follows: for an even figure n, unshaded \\(=\\dfrac{n^2}{2}\\). For Figure 84: \\(\\dfrac{84^2}{2}=\\dfrac{7056}{2}=3528\\). Answer (b): 3528.", "hints": ["(a) Look at the Total column: 1, 4, 9, 16, 25 are the square numbers, so Figure n has n² squares.", "(b) For an even-numbered figure, half of the n² squares are unshaded: n²/2."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q19", "image_needed": true, "image_options": false, "image_file": "q19.png", "image_page": 15, "image_bbox": [0.10, 0.10, 0.78, 0.22], "image_loc": "top of page: a row of five grid figures (Fig 1 to Fig 5) showing the growing square pattern, above the data table", "notes": "Answer key: (a) 64, (b) 3528. The table of values is described in the stem so the question is answerable without the figure-row image; the grid row is recorded for completeness." }, { "n": 20, "type_id": 2, "question": "The design is made up of 2 identical quadrants, two identical squares ABCD and JKLM, and a small square CEJF. The area of square CEJF is 25 cm² and the radius of the quadrants is 18 cm. Find the area of the shaded parts. (Take \\(\\pi=3.14\\)) [?] cm²", "answer0": "553.34", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 223, "difficulty_id": 3, "explanation": "Following the key: the area of square DEMH (side 18 cm) \\(=18\\times18=324\\) cm². The area of one quadrant \\(=\\dfrac{1}{4}\\times3.14\\times18\\times18=254.34\\) cm². Total \\(=324+254.34=578.34\\) cm². Subtract the small square CEJF (25 cm²): shaded area \\(=578.34-25=553.34\\) cm². Answer: 553.34 cm².", "hints": ["Find the area of the large square (side = radius = 18 cm) and the area of one quadrant.", "Add them, then subtract the small square CEJF (25 cm²)."], "source": "Rosyth 2023 P6 Weighted Assessment 2 Q20", "image_needed": true, "image_options": false, "image_file": "q20.png", "image_page": 16, "image_bbox": [0.18, 0.18, 0.55, 0.42], "image_loc": "upper-left, below the question: composite figure with squares ABCD and JKLM, small square CEJF (25 cm²), and two quadrant arcs; shaded regions marked", "notes": "Answer key working: square DEMH = 18 x 18 = 324; quadrant = 1/4 x 3.14 x 18 x 18 = 254.34; total = 578.34; minus 25 = 553.34 cm²." } ] }