{
  "paper": {
    "school": "Rosyth",
    "year": 2025,
    "level": "P6",
    "label": "WA1",
    "source_prefix": "Rosyth 2025 P6 WA1",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "Which number when rounded to the nearest thousand is 9 760 000?",
      "answer0": "9 758 330",
      "answer1": "9 759 491",
      "answer2": "9 760 397",
      "answer3": "9 760 500",
      "correct_answer": 2,
      "skill_id": 150,
      "difficulty_id": 2,
      "explanation": "Round each option to the nearest thousand. 9 760 397 rounds to 9 760 000 (hundreds digit 3 < 5, round down). The others round to 9 758 000, 9 759 000 and 9 761 000 respectively. Answer: 9 760 397.",
      "hints": ["Look at the hundreds digit of each number to decide rounding to the nearest thousand.", "9 760 397 has 3 hundreds, so it rounds down to 9 760 000."],
      "source": "Rosyth 2025 P6 WA1 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q1 = option 3 (9 760 397)."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "6 children share 5 similar pizzas equally. What fraction of the pizza does each child get?",
      "answer0": "\\(\\dfrac{1}{5}\\)",
      "answer1": "\\(\\dfrac{1}{6}\\)",
      "answer2": "\\(\\dfrac{5}{6}\\)",
      "answer3": "\\(\\dfrac{6}{5}\\)",
      "correct_answer": 2,
      "skill_id": 157,
      "difficulty_id": 1,
      "explanation": "Sharing 5 pizzas equally among 6 children means each child gets \\(5 \\div 6 = \\dfrac{5}{6}\\) of a pizza. Answer: \\(\\dfrac{5}{6}\\).",
      "hints": ["A fraction can represent a division: total \\(\\div\\) number of people.", "\\(5 \\div 6 = \\dfrac{5}{6}\\)."],
      "source": "Rosyth 2025 P6 WA1 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q2 = option 3 (5/6). MCQ because answer is a fraction."
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "A machine can pack 55 boxes per minute. How many boxes can the machine pack in an hour?",
      "answer0": "330",
      "answer1": "550",
      "answer2": "3300",
      "answer3": "5500",
      "correct_answer": 2,
      "skill_id": 152,
      "difficulty_id": 1,
      "explanation": "There are 60 minutes in an hour. 55 x 60 = 3300 boxes. Answer: 3300.",
      "hints": ["1 hour = 60 minutes.", "55 x 60 = 3300."],
      "source": "Rosyth 2025 P6 WA1 Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q3 = option 3 (3300)."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "Arrange the following masses from the heaviest to the lightest.<br>8.02 kg, \\(8\\dfrac{1}{5}\\) kg, 8 kg 2 g",
      "answer0": "\\(8\\dfrac{1}{5}\\) kg, 8.02 kg, 8 kg 2 g",
      "answer1": "\\(8\\dfrac{1}{5}\\) kg, 8 kg 2 g, 8.02 kg",
      "answer2": "8.02 kg, \\(8\\dfrac{1}{5}\\) kg, 8 kg 2 g",
      "answer3": "8 kg 2 g, \\(8\\dfrac{1}{5}\\) kg, 8.02 kg",
      "correct_answer": 0,
      "skill_id": 184,
      "difficulty_id": 2,
      "explanation": "Convert all to kg: \\(8\\dfrac{1}{5}\\) kg = 8.20 kg; 8.02 kg = 8.02 kg; 8 kg 2 g = 8.002 kg. From heaviest to lightest: 8.20 kg, 8.02 kg, 8.002 kg, i.e. \\(8\\dfrac{1}{5}\\) kg, 8.02 kg, 8 kg 2 g. Answer: option 1.",
      "hints": ["Convert every mass to the same unit (kg) in decimal form before comparing.", "\\(8\\dfrac{1}{5}\\) = 8.2 kg; 8 kg 2 g = 8.002 kg."],
      "source": "Rosyth 2025 P6 WA1 Q4",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q4 = option 1. Options contain fractions, so MCQ."
    },
    {
      "n": 5,
      "type_id": 1,
      "question": "\\(12 : 32 = 9 : \\square\\). What is the answer in the box?",
      "answer0": "18",
      "answer1": "24",
      "answer2": "27",
      "answer3": "32",
      "correct_answer": 1,
      "skill_id": 181,
      "difficulty_id": 1,
      "explanation": "12 : 32 simplifies to 3 : 8. To get 9 in the first term, multiply by 3: 3 x 3 = 9 and 8 x 3 = 24. So the box is 24. Answer: 24.",
      "hints": ["Simplify 12 : 32 first.", "12 : 32 = 3 : 8, and 9 = 3 x 3, so the second term is 8 x 3 = 24."],
      "source": "Rosyth 2025 P6 WA1 Q5",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q5 = option 2 (24)."
    },
    {
      "n": 6,
      "type_id": 1,
      "question": "Alvin is 3 times as heavy as Ben. Ben is twice as heavy as Caleb. What is the ratio of Alvin's mass to Ben's mass to Caleb's mass?",
      "answer0": "3 : 1 : 2",
      "answer1": "3 : 2 : 1",
      "answer2": "6 : 1 : 2",
      "answer3": "6 : 2 : 1",
      "correct_answer": 3,
      "skill_id": 180,
      "difficulty_id": 2,
      "explanation": "Let Caleb = 1. Ben is twice Caleb = 2. Alvin is 3 times Ben = 6. So Alvin : Ben : Caleb = 6 : 2 : 1. Answer: 6 : 2 : 1.",
      "hints": ["Start with the smallest, Caleb, as 1 unit.", "Ben = 2 x Caleb = 2; Alvin = 3 x Ben = 6, giving 6 : 2 : 1."],
      "source": "Rosyth 2025 P6 WA1 Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q6 = option 4 (6 : 2 : 1)."
    },
    {
      "n": 7,
      "type_id": 1,
      "question": "Find the area of the triangle.",
      "answer0": "24 cm²",
      "answer1": "30 cm²",
      "answer2": "40 cm²",
      "answer3": "48 cm²",
      "correct_answer": 0,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "The triangle has a right angle between the two sides 8 cm and 6 cm, so these are the base and height. Area = \\(\\dfrac{1}{2} \\times 8 \\times 6 = 24\\) cm². (The 10 cm side is the hypotenuse, not used.) Answer: 24 cm².",
      "hints": ["The right angle is between the 8 cm and 6 cm sides; use those as base and height.", "Area = \\(\\dfrac{1}{2} \\times 8 \\times 6 = 24\\) cm²."],
      "source": "Rosyth 2025 P6 WA1 Q7",
      "image_needed": true,
      "image_options": false,
      "image_file": "q7.png",
      "image_page": 4,
      "image_bbox": [0.22, 0.13, 0.62, 0.31],
      "image_loc": "right-angled triangle with sides 8 cm, 6 cm and base 10 cm, top of page below the question",
      "notes": "Key: Q7 = option 1 (24 cm²)."
    },
    {
      "n": 8,
      "type_id": 1,
      "question": "Express 30 m as a percentage of 5 km.",
      "answer0": "0.6%",
      "answer1": "6%",
      "answer2": "60%",
      "answer3": "600%",
      "correct_answer": 0,
      "skill_id": 171,
      "difficulty_id": 2,
      "explanation": "5 km = 5000 m. 30 m as a percentage of 5000 m = \\(\\dfrac{30}{5000} \\times 100\\% = 0.6\\%\\). Answer: 0.6%.",
      "hints": ["Convert km to m first: 5 km = 5000 m.", "\\(\\dfrac{30}{5000} \\times 100\\% = 0.6\\%\\)."],
      "source": "Rosyth 2025 P6 WA1 Q8",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q8 = option 1 (0.6%)."
    },
    {
      "n": 9,
      "type_id": 1,
      "question": "In the figure, AC and BD are straight lines. Find \\(\\angle y\\).",
      "answer0": "23°",
      "answer1": "43°",
      "answer2": "66°",
      "answer3": "67°",
      "correct_answer": 1,
      "skill_id": 194,
      "difficulty_id": 2,
      "explanation": "157° is the angle AOB measured above line BD. The angle from B round to the ray making \\(\\angle y\\) plus the 24° must total. On the straight line BD, angles below: \\(\\angle y + 24° + (180° - 157°) = 90°\\) using the right angle marked. \\(\\angle y = 90° - 24° - 23° = 43°\\). Answer: 43°.",
      "hints": ["Use angles on a straight line (BD) and the marked right angle.", "157° above the line leaves 23°; with the 24° and the right angle, y = 43°."],
      "source": "Rosyth 2025 P6 WA1 Q9",
      "image_needed": true,
      "image_options": false,
      "image_file": "q9.png",
      "image_page": 4,
      "image_bbox": [0.28, 0.62, 0.55, 0.76],
      "image_loc": "figure with straight lines AC and BD meeting at a point, angles 157°, 24° and y marked, lower-left of page",
      "notes": "Key: Q9 = option 2 (43°)."
    },
    {
      "n": 10,
      "type_id": 1,
      "question": "Which two lines in the figure are parallel to each other?",
      "answer0": "AB and CD",
      "answer1": "AB and FE",
      "answer2": "AF and DE",
      "answer3": "CD and FE",
      "correct_answer": 0,
      "skill_id": 194,
      "difficulty_id": 2,
      "explanation": "On the square grid, lines AB and CD have the same gradient (both slope down at the same rate), so they are parallel. Answer: AB and CD.",
      "hints": ["Parallel lines have the same gradient (rise over run) on the grid.", "Count grid steps: AB and CD share the same slope."],
      "source": "Rosyth 2025 P6 WA1 Q10",
      "image_needed": true,
      "image_options": false,
      "image_file": "q10.png",
      "image_page": 5,
      "image_bbox": [0.23, 0.10, 0.48, 0.30],
      "image_loc": "square grid with points A, B, C, D, E, F joined by lines, top-left of page",
      "notes": "Key: Q10 = option 1 (AB and CD)."
    },
    {
      "n": 11,
      "type_id": 1,
      "question": "The mass of a container with Ball A in it is 4170 g. The mass of the same container with Ball B in it is 4650 g. The total mass of the same container with both Ball A and Ball B in it is 6170 g. What is the mass of the empty container?",
      "answer0": "480 g",
      "answer1": "1520 g",
      "answer2": "2000 g",
      "answer3": "2650 g",
      "correct_answer": 3,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "Container + A = 4170 and Container + B = 4650, so (2 x Container) + A + B = 8820. Container + A + B = 6170, so Container = 8820 - 6170 = 2650 g. Answer: 2650 g.",
      "hints": ["Add the first two masses: 2 containers plus A plus B.", "8820 - 6170 = 2650 g (the extra container)."],
      "source": "Rosyth 2025 P6 WA1 Q11",
      "image_needed": true,
      "image_options": false,
      "image_file": "q11.png",
      "image_page": 5,
      "image_bbox": [0.28, 0.46, 0.65, 0.60],
      "image_loc": "three containers showing Ball A (4170 g), Ball B (4650 g) and both A and B (6170 g), middle of page",
      "notes": "Key: Q11 = option 4 (2650 g). 2-mark question."
    },
    {
      "n": 12,
      "type_id": 1,
      "question": "ABC and ADE are identical equilateral triangles. Find \\(\\angle CAD\\).",
      "answer0": "98°",
      "answer1": "104°",
      "answer2": "131°",
      "answer3": "150°",
      "correct_answer": 1,
      "skill_id": 197,
      "difficulty_id": 3,
      "explanation": "The reflex angle at C is 262°, so \\(\\angle BCD = 360° - 262° = 98°\\). Each equilateral triangle has 60° angles. Working through the figure, \\(\\angle CAD = 104°\\). Answer: 104°.",
      "hints": ["Reflex angle 262° means the inner angle at C is 360° - 262° = 98°.", "Use the 60° angles of the equilateral triangles to find \\(\\angle CAD = 104°\\)."],
      "source": "Rosyth 2025 P6 WA1 Q12",
      "image_needed": true,
      "image_options": false,
      "image_file": "q12.png",
      "image_page": 6,
      "image_bbox": [0.58, 0.13, 0.85, 0.34],
      "image_loc": "two overlapping equilateral triangles ABC and ADE with reflex angle 262° marked at C, right side of page",
      "notes": "Key: Q12 = option 2 (104°). 2-mark question."
    },
    {
      "n": 13,
      "type_id": 1,
      "question": "The bar graph shows the number of cups of juices sold at a stall. What percentage of the cups of juice sold were orange and watermelon juice?",
      "answer0": "40%",
      "answer1": "45%",
      "answer2": "50%",
      "answer3": "90%",
      "correct_answer": 1,
      "skill_id": 171,
      "difficulty_id": 2,
      "explanation": "Reading the bar graph (units of 1 small division): Watermelon = 4, Orange = 5, Apple = 9, Carrot = 2, total = 20. Orange + Watermelon = 9 out of 20 = \\(\\dfrac{9}{20} \\times 100\\% = 45\\%\\). Answer: 45%.",
      "hints": ["Read each bar's value from the graph and add to get the total.", "(Watermelon + Orange) ÷ total x 100% = 45%."],
      "source": "Rosyth 2025 P6 WA1 Q13",
      "image_needed": true,
      "image_options": false,
      "image_file": "q13.png",
      "image_page": 6,
      "image_bbox": [0.24, 0.40, 0.72, 0.63],
      "image_loc": "bar graph of cups of juices sold for Watermelon, Orange, Apple, Carrot, middle of page",
      "notes": "Key: Q13 = option 2 (45%). 2-mark question."
    },
    {
      "n": 14,
      "type_id": 1,
      "question": "The figure is made up of a square ABCD and a rhombus ABEF. \\(\\angle BEF = 124°\\). Find \\(\\angle BCE\\).",
      "answer0": "34°",
      "answer1": "56°",
      "answer2": "62°",
      "answer3": "73°",
      "correct_answer": 3,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "In rhombus ABEF, \\(\\angle BEF = 124°\\) so \\(\\angle ABE = 180° - 124° = 56°\\) and \\(\\angle EAB = 124°\\). BE = AB = BC (sides of rhombus and square), so triangle BCE is isosceles. Working through the angles gives \\(\\angle BCE = 73°\\). Answer: 73°.",
      "hints": ["A rhombus has equal sides and opposite angles equal; adjacent angles sum to 180°.", "BE = BC makes triangle BCE isosceles; \\(\\angle BCE = 73°\\)."],
      "source": "Rosyth 2025 P6 WA1 Q14",
      "image_needed": true,
      "image_options": false,
      "image_file": "q14.png",
      "image_page": 7,
      "image_bbox": [0.24, 0.12, 0.58, 0.36],
      "image_loc": "square ABCD joined to rhombus ABEF with angle 124° marked at E, top of page",
      "notes": "Key: Q14 = option 4 (73°). 2-mark question."
    },
    {
      "n": 15,
      "type_id": 1,
      "question": "Mr Sim had 3 empty containers X, Y and Z. He poured an equal amount of water into each of them. After that, \\(\\dfrac{1}{3}\\) of X was filled with water, \\(\\dfrac{1}{4}\\) of Y was filled with water and \\(\\dfrac{2}{5}\\) of Z was filled with water. What was the ratio of the capacity of container X to container Y to container Z?",
      "answer0": "1 : 1 : 2",
      "answer1": "3 : 4 : 5",
      "answer2": "4 : 6 : 3",
      "answer3": "6 : 8 : 5",
      "correct_answer": 3,
      "skill_id": 183,
      "difficulty_id": 3,
      "explanation": "Equal volume V fills \\(\\dfrac{1}{3}\\) of X, \\(\\dfrac{1}{4}\\) of Y, \\(\\dfrac{2}{5}\\) of Z. So capacities are X = 3V, Y = 4V, Z = \\(\\dfrac{5}{2}V\\). Ratio X : Y : Z = 3 : 4 : \\(\\dfrac{5}{2}\\) = 6 : 8 : 5. Answer: 6 : 8 : 5.",
      "hints": ["Same volume V; capacity = V ÷ (fraction filled).", "X = 3V, Y = 4V, Z = 2.5V, giving 6 : 8 : 5 when doubled."],
      "source": "Rosyth 2025 P6 WA1 Q15",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q15 = option 4 (6 : 8 : 5). 2-mark question."
    },
    {
      "n": 16,
      "type_id": 2,
      "question": "Find the value of \\(7 + (20 - 18 \\div 2) \\times 4\\).<br>[?]",
      "answer0": "51",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 155,
      "difficulty_id": 2,
      "explanation": "Order of operations: 18 ÷ 2 = 9; 20 - 9 = 11; 11 x 4 = 44; 7 + 44 = 51. Answer: 51.",
      "hints": ["Do division inside the brackets first.", "7 + 11 x 4 = 7 + 44 = 51."],
      "source": "Rosyth 2025 P6 WA1 Q16",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q16 = 51."
    },
    {
      "n": 17,
      "type_id": 2,
      "question": "Find the value of \\(144 \\div 6000\\).<br>[?]",
      "answer0": "0.024",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 166,
      "difficulty_id": 2,
      "explanation": "144 ÷ 6000 = 144 ÷ 6 ÷ 1000 = 24 ÷ 1000 = 0.024. Answer: 0.024.",
      "hints": ["Split 6000 into 6 x 1000.", "144 ÷ 6 = 24; 24 ÷ 1000 = 0.024."],
      "source": "Rosyth 2025 P6 WA1 Q17",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q17 = 0.024."
    },
    {
      "n": 18,
      "type_id": 2,
      "question": "What is the percentage discount for the shirt shown?<br>Usual Price: $60<br>Sale Price: $48<br>[?]%",
      "answer0": "20",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 176,
      "difficulty_id": 2,
      "explanation": "Discount = $60 - $48 = $12. Percentage discount = \\(\\dfrac{12}{60} \\times 100\\% = 20\\%\\). Answer: 20%.",
      "hints": ["Discount amount = usual price - sale price.", "\\(\\dfrac{12}{60} \\times 100\\% = 20\\%\\)."],
      "source": "Rosyth 2025 P6 WA1 Q18",
      "image_needed": true,
      "image_options": false,
      "image_file": "q18.png",
      "image_page": 9,
      "image_bbox": [0.26, 0.52, 0.64, 0.69],
      "image_loc": "sale tag showing Usual Price $60, Sale Price $48 beside a shirt, middle of page",
      "notes": "Key: Q18 = 20%. Answer unit is %."
    },
    {
      "n": 19,
      "type_id": 0,
      "question": "Measure and write down the size of \\(\\angle ABC\\).",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 197,
      "difficulty_id": 1,
      "explanation": "This requires physically measuring the drawn angle ABC with a protractor; the key gives 98° for the printed figure (∠ABC = 98°).",
      "hints": [],
      "source": "Rosyth 2025 P6 WA1 Q19",
      "image_needed": true,
      "image_options": false,
      "image_file": "q19.png",
      "image_page": 10,
      "image_bbox": [0.20, 0.11, 0.52, 0.33],
      "image_loc": "triangle ABC drawn for protractor measurement, top of page",
      "notes": "type_id 0 (measure with protractor) - skipped on insert. Key: ∠ABC = 98°."
    },
    {
      "n": 20,
      "type_id": 0,
      "question": "Complete the symmetric figure with XY as the line of symmetry.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 26,
      "difficulty_id": 2,
      "explanation": "This is a draw/complete task: reflect the given lines across the diagonal line of symmetry XY on the grid. Key: see figure.",
      "hints": [],
      "source": "Rosyth 2025 P6 WA1 Q20",
      "image_needed": true,
      "image_options": false,
      "image_file": "q20.png",
      "image_page": 10,
      "image_bbox": [0.22, 0.42, 0.62, 0.70],
      "image_loc": "square grid with partial figure and diagonal line of symmetry XY, middle of page",
      "notes": "type_id 0 (complete/draw symmetric figure) - skipped on insert. Key: see figure."
    },
    {
      "n": 21,
      "type_id": 2,
      "question": "Wendy had 21 kg of sugar. She packed them into bags of \\(\\dfrac{3}{7}\\) kg each. How many bags of sugar did she pack?<br>[?]",
      "answer0": "49",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 206,
      "difficulty_id": 2,
      "explanation": "Number of bags = \\(21 \\div \\dfrac{3}{7} = 21 \\times \\dfrac{7}{3} = 7 \\times 7 = 49\\) bags. Answer: 49.",
      "hints": ["Dividing by a fraction = multiplying by its reciprocal.", "\\(21 \\times \\dfrac{7}{3} = 49\\)."],
      "source": "Rosyth 2025 P6 WA1 Q21",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q21 = 49 bags. 2-mark question."
    },
    {
      "n": 22,
      "type_id": 2,
      "question": "A piece of rope 25.35 m long was cut into two pieces in the ratio 2 : 3. What was the length of the longer piece?<br>[?] m",
      "answer0": "15.21",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 183,
      "difficulty_id": 2,
      "explanation": "Total units = 2 + 3 = 5. Longer piece = 3 units = \\(\\dfrac{3}{5} \\times 25.35 = 25.35 \\div 5 \\times 3 = 5.07 \\times 3 = 15.21\\) m. Answer: 15.21 m.",
      "hints": ["Total ratio units = 2 + 3 = 5; find one unit first.", "25.35 ÷ 5 = 5.07; longer piece = 5.07 x 3 = 15.21 m."],
      "source": "Rosyth 2025 P6 WA1 Q22",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q22 = 15.21 m. 2-mark question."
    },
    {
      "n": 23,
      "type_id": 2,
      "question": "Find the perimeter of a three-quarter circle with radius of 14 cm. (Take \\(\\pi = \\dfrac{22}{7}\\))<br>[?] cm",
      "answer0": "94",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 221,
      "difficulty_id": 3,
      "explanation": "Arc of three-quarter circle = \\(\\dfrac{3}{4} \\times 2 \\times \\dfrac{22}{7} \\times 14 = 66\\) cm. The two straight radii add 14 + 14 = 28 cm. Perimeter = 66 + 28 = 94 cm. Answer: 94 cm.",
      "hints": ["A three-quarter circle's perimeter = ¾ of the circumference plus two radii.", "\\(\\dfrac{3}{4} \\times 2\\pi r = 66\\); 66 + 14 + 14 = 94 cm."],
      "source": "Rosyth 2025 P6 WA1 Q23",
      "image_needed": true,
      "image_options": false,
      "image_file": "q23.png",
      "image_page": 12,
      "image_bbox": [0.20, 0.17, 0.48, 0.34],
      "image_loc": "three-quarter circle with radius 14 cm marked, upper-left of page",
      "notes": "Key: Q23 = 94 cm. 2-mark question."
    },
    {
      "n": 24,
      "type_id": 0,
      "question": "In the figure, XYZ is a right-angled triangle where XZ is longer than YZ and PQR is an equilateral triangle. Each statement is either true, false or not possible to tell from the information given. (a) The sum of \\(\\angle b\\) and \\(\\angle c\\) is 105°. (b) The sum of \\(\\angle a\\), \\(\\angle b\\), \\(\\angle c\\) and \\(\\angle d\\) is 210°. (c) \\(\\angle a\\) is greater than \\(\\angle d\\).",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 197,
      "difficulty_id": 3,
      "explanation": "(a) Since YZ < XZ, \\(\\angle c < \\angle d\\) so \\(\\angle c < 45°\\); \\(\\angle b = 60°\\). Thus \\(\\angle c + \\angle b < 105°\\), so the statement is False. (b) \\(\\angle a + \\angle b + \\angle c + \\angle d = (180° - 60°) + (180° - 90°) = 120° + 90° = 210°\\), True. (c) \\(\\angle a = 60°\\) and \\(\\angle d > 45°\\), so it is Not possible to tell whether \\(\\angle a > \\angle d\\).",
      "hints": [],
      "source": "Rosyth 2025 P6 WA1 Q24",
      "image_needed": true,
      "image_options": false,
      "image_file": "q24.png",
      "image_page": 13,
      "image_bbox": [0.30, 0.16, 0.62, 0.36],
      "image_loc": "right-angled triangle XYZ overlapping equilateral triangle PQR with angles a, b, c, d marked, top of page",
      "notes": "type_id 0 (true/false/not-possible-to-tell tick table) - skipped on insert. Key: (a) False, (b) True, (c) Not possible to tell. 2-mark question."
    },
    {
      "n": 25,
      "type_id": 2,
      "question": "Siti used \\(\\dfrac{2}{7}\\) of her money to buy 3 notebooks and 10 pens. Each notebook cost as much as 4 pens. How many pens could she buy with the remaining amount of money?<br>[?]",
      "answer0": "55",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "3 notebooks + 10 pens = (3 x 4 + 10) pens = 22 pens, which cost \\(\\dfrac{2}{7}\\) of her money. So \\(\\dfrac{1}{7}\\) buys 22 ÷ 2 = 11 pens. Remaining money = \\(1 - \\dfrac{2}{7} = \\dfrac{5}{7}\\), which buys 5 x 11 = 55 pens. Answer: 55 pens.",
      "hints": ["Convert notebooks to pens: 1 notebook = 4 pens.", "\\(\\dfrac{2}{7}\\) buys 22 pens, so \\(\\dfrac{5}{7}\\) buys 55 pens."],
      "source": "Rosyth 2025 P6 WA1 Q25",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q25 = 55 pens. 2-mark question."
    },
    {
      "n": 26,
      "type_id": 2,
      "question": "The table shows the parking charges at a car park. Shuling parked her car from 4.15 p.m. to 8 p.m. on a day. How much did she have to pay?<br>Parking Charges: For the first hour or part thereof $2.50; For every additional \\(\\dfrac{1}{2}\\) hour or part thereof $1.20; After 6 p.m. $3 per entry.<br>$[?]",
      "answer0": "7.90",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "From 4.15 p.m. to 6 p.m. is 1 hour 45 minutes. First hour = $2.50. Remaining 45 minutes = 2 half-hour blocks (part thereof) = 2 x $1.20 = $2.40. After 6 p.m. = $3 flat. Total = $2.50 + $2.40 + $3.00 = $7.90. Answer: $7.90.",
      "hints": ["Charge up to 6 p.m. by the hourly/half-hourly rates, then add the flat after-6 p.m. fee.", "$2.50 + 2 x $1.20 + $3 = $7.90."],
      "source": "Rosyth 2025 P6 WA1 Q26",
      "image_needed": true,
      "image_options": false,
      "image_file": "q26.png",
      "image_page": 14,
      "image_bbox": [0.26, 0.43, 0.72, 0.57],
      "image_loc": "parking charges table, middle of page",
      "notes": "Key: Q26 = $7.90. 2-mark question. Charges table reproduced in stem."
    },
    {
      "n": 27,
      "type_id": 1,
      "question": "The square is made up of 2 triangles, A and B, and 2 trapeziums, C and D. The ratio of the area of A to the area of B is 13 : 1. The ratio of the area of C to the area of D is 3 : 1. Find the ratio of the area of C to the area of the square in its simplest form.",
      "answer0": "9 : 26",
      "answer1": "3 : 13",
      "answer2": "9 : 13",
      "answer3": "3 : 26",
      "correct_answer": 0,
      "skill_id": 223,
      "difficulty_id": 3,
      "explanation": "The diagonal splits the square into two equal halves: one half is A + (part), but here area of A = area of B + area of C + area of D (the diagonal divides the square so triangle A equals the rest). With C : D = 3 : 1 = 9 : 3 and A : B = 13 : 1, take A : B : C : D = 13 : 1 : 9 : 3. The whole square = 2 x 13 = 26 units. Area of C : square = 9 : 26. Answer: 9 : 26.",
      "hints": ["The diagonal makes triangle A equal to B + C + D combined.", "Scale so A : B : C : D = 13 : 1 : 9 : 3; square = 26 units, C = 9, giving 9 : 26."],
      "source": "Rosyth 2025 P6 WA1 Q27",
      "image_needed": true,
      "image_options": false,
      "image_file": "q27.png",
      "image_page": 15,
      "image_bbox": [0.24, 0.18, 0.45, 0.34],
      "image_loc": "square divided by a diagonal into triangles A, B and trapeziums C, D with C shaded, upper-left of page",
      "notes": "Key: Q27 = 9 : 26. Answer is a ratio, so MCQ. Distractor options added (paper is open-ended). 2-mark question."
    },
    {
      "n": 28,
      "type_id": 2,
      "question": "A rectangular piece of paper was folded as shown. Find \\(\\angle y\\).<br>[?]°",
      "answer0": "88",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 230,
      "difficulty_id": 3,
      "explanation": "The fold makes two right-angled corners. \\(\\angle a = 180° - 90° - 65° = 25°\\) and \\(\\angle b = 180° - 90° - 69° = 21°\\). Each fold reflects an equal angle, so \\(\\angle y = 180° - 25° - 25° - 21° - 21° = 88°\\). Answer: 88°.",
      "hints": ["Folded corners keep right angles; find the base angles 25° and 21°.", "Each folded angle appears twice: y = 180° - 2(25°) - 2(21°) = 88°."],
      "source": "Rosyth 2025 P6 WA1 Q28",
      "image_needed": true,
      "image_options": false,
      "image_file": "q28.png",
      "image_page": 15,
      "image_bbox": [0.20, 0.50, 0.74, 0.66],
      "image_loc": "folded rectangle showing angles 65°, 69° and y, lower part of page",
      "notes": "Key: Q28 = 88°. 2-mark question."
    },
    {
      "n": 29,
      "type_id": 2,
      "question": "Ishan had $700. He spent 30% of his money on an oven and spent 60% of the remaining money on a printer. How much money did he have left?<br>$[?]",
      "answer0": "196",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 175,
      "difficulty_id": 2,
      "explanation": "After the oven, 100% - 30% = 70% remains. After the printer, 100% - 60% = 40% of that remains. Money left = 40% x 70% x $700 = 0.40 x 0.70 x 700 = $196. Answer: $196.",
      "hints": ["Find the percentage remaining at each step.", "0.70 x 0.40 x $700 = $196."],
      "source": "Rosyth 2025 P6 WA1 Q29",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q29 = $196. 2-mark question."
    },
    {
      "n": 30,
      "type_id": 2,
      "question": "Shawn counted the number of coins in his piggy bank. 30% of the coins are $1 coins. 16% are 50¢ coins while the rest are 10¢ coins. The total value of the 50¢ coins is $72. Find the total value of the 10¢ coins.<br>$[?]",
      "answer0": "48.60",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 175,
      "difficulty_id": 3,
      "explanation": "Number of 50¢ coins = $72 ÷ $0.50 = 144 coins, which is 16% of the total. Total coins = 144 ÷ 16% = 900. 10¢ coins = (100% - 30% - 16%) = 54% of 900 = 486 coins. Value = 486 x $0.10 = $48.60. Answer: $48.60.",
      "hints": ["Find the number of 50¢ coins first from their total value.", "144 is 16% of total, so total = 900; 54% are 10¢ coins = 486 x $0.10 = $48.60."],
      "source": "Rosyth 2025 P6 WA1 Q30",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: Q30 = $48.60. 2-mark question. End of Paper 1."
    },
    {
      "n": 31,
      "type_id": 2,
      "question": "The total mass of three watermelons was 5 kg. The total mass of another two watermelons was 4.5 kg. Find the average mass of the five watermelons.<br>[?] kg",
      "answer0": "1.9",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 203,
      "difficulty_id": 1,
      "explanation": "Total mass = 5 + 4.5 = 9.5 kg over 3 + 2 = 5 watermelons. Average = 9.5 ÷ 5 = 1.9 kg. Answer: 1.9 kg.",
      "hints": ["Average = total mass ÷ number of items.", "9.5 ÷ 5 = 1.9 kg."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q1. Key: 1.9 kg."
    },
    {
      "n": 32,
      "type_id": 2,
      "question": "ACDF is a parallelogram and BDE is an equilateral triangle. \\(\\angle DFA = 72°\\). (a) Find \\(\\angle BAF\\). (b) Find \\(\\angle BDC\\).<br>(a) [?]° (b) [?]°",
      "answer0": "108",
      "answer1": "48",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 2,
      "explanation": "(a) In parallelogram ACDF, co-interior angles \\(\\angle BAF + \\angle DFA = 180°\\), so \\(\\angle BAF = 180° - 72° = 108°\\). (b) \\(\\angle BDC = 180° - \\angle DFA - \\angle EDB = 180° - 72° - 60° = 48°\\) (BDE is equilateral so \\(\\angle EDB = 60°\\)). Answers: (a) 108°, (b) 48°.",
      "hints": ["Co-interior angles of a parallelogram add to 180°.", "Use the 60° angle of the equilateral triangle for part (b)."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q2",
      "image_needed": true,
      "image_options": false,
      "image_file": "q32.png",
      "image_page": 18,
      "image_bbox": [0.24, 0.47, 0.70, 0.62],
      "image_loc": "parallelogram ACDF with equilateral triangle BDE and angle 72° marked at F, middle of page",
      "notes": "Paper 2 Q2. Two parts. Key: (a) 108°, (b) 48°. The 72° is ∠DFA at vertex F."
    },
    {
      "n": 33,
      "type_id": 0,
      "question": "The square grid is made up of 1-cm squares. (a) Find the area of triangle ABC. (b) Line AB forms one side of a triangle ABD such that triangle ABD has the same area as triangle ABC. Complete the drawing of triangle ABD in the square grid.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "(a) Triangle ABC has base AC = 3 cm (vertical) and perpendicular height 3 cm, so area = \\(\\dfrac{1}{2} \\times 3 \\times 3 = 4.5\\) cm². (b) Draw triangle ABD on the grid with the same base and equal height so its area is also 4.5 cm².",
      "hints": [],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q3",
      "image_needed": true,
      "image_options": false,
      "image_file": "q33.png",
      "image_page": 19,
      "image_bbox": [0.28, 0.18, 0.72, 0.46],
      "image_loc": "1-cm square grid with triangle ABC drawn, middle of page",
      "notes": "type_id 0 (part b is complete-the-drawing) - skipped on insert. Key: (a) 4.5 cm², (b) see figure. Paper 2 Q3."
    },
    {
      "n": 34,
      "type_id": 2,
      "question": "Ali has 15 kg 10 g of rice. He sold 7.503 kg of rice in May and 1.26 kg of rice in June. How much rice was left? Give your answer in kilograms and grams.<br>[?] kg [?] g",
      "answer0": "6",
      "answer1": "247",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 2,
      "explanation": "15 kg 10 g = 15.010 kg. Rice left = 15.010 - 7.503 - 1.260 = 6.247 kg = 6 kg 247 g. Answers: 6 kg, 247 g.",
      "hints": ["Convert 15 kg 10 g to 15.010 kg before subtracting.", "15.010 - 7.503 - 1.260 = 6.247 kg = 6 kg 247 g."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q4",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q4. Two blanks (kg and g). Key: 6 kg 247 g."
    },
    {
      "n": 35,
      "type_id": 2,
      "question": "Rectangle WXYZ has a perimeter of 80 cm. WX is 28 cm. The area of triangle WXS is 60 cm². Find the area of the shaded triangle XTS.<br>[?] cm²",
      "answer0": "108",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Width WZ = 80 ÷ 2 - 28 = 40 - 28 = 12 cm. Area of triangle WXT (base WX = 28, height = width 12) = \\(\\dfrac{1}{2} \\times 12 \\times 28 = 168\\) cm². Shaded triangle XTS = 168 - 60 = 108 cm². Answer: 108 cm².",
      "hints": ["Find the width of the rectangle from the perimeter and WX.", "Area XTS = area WXT - area WXS = 168 - 60 = 108 cm²."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q5",
      "image_needed": true,
      "image_options": false,
      "image_file": "q35.png",
      "image_page": 20,
      "image_bbox": [0.30, 0.55, 0.68, 0.74],
      "image_loc": "rectangle WXYZ with shaded triangle XTS and point S inside, lower-middle of page",
      "notes": "Paper 2 Q5. Key: 108 cm²."
    },
    {
      "n": 36,
      "type_id": 2,
      "question": "Xin Hui bought 15 similar pens and 8 similar files. Each file cost twice as much as each pen. The total cost of a pen and a file is $4.20. How much did Xin Hui pay altogether?<br>$[?]",
      "answer0": "43.40",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "A pen + a file = $4.20, and a file = 2 pens, so 1 pen + 2 pens = 3 pens = $4.20, giving 1 pen = $1.40. A file = $2.80. Total = 15 x $1.40 + 8 x $2.80 = $21 + $22.40 = $43.40. Answer: $43.40.",
      "hints": ["A pen plus a file equals 3 pens in value.", "Pen = $1.40, file = $2.80; 15 x $1.40 + 8 x $2.80 = $43.40."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q6. Key: $43.40. [3 marks]"
    },
    {
      "n": 37,
      "type_id": 2,
      "question": "Ed filled a tank using 2 taps. He turned on tap A first. After 6 minutes, he turned on tap B. At the 8th minute, he turned off both taps. The graph shows the amount of water in the tank over 8 minutes. (a) In one minute, how many litres of water flowed from Tap A? (b) In one minute, how many litres of water flowed from Tap B?<br>(a) [?] (b) [?]",
      "answer0": "2",
      "answer1": "8",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "(a) In the first 6 minutes only Tap A flows, reaching 12 l, so Tap A = 12 ÷ 6 = 2 l/min. (b) From minute 6 to 8, both taps add 32 - 12 = 20 l in 2 minutes = 10 l/min combined. Tap B = 10 - 2 = 8 l/min. Answers: (a) 2 l, (b) 8 l.",
      "hints": ["Tap A alone fills the first part of the graph (0-6 min).", "Combined rate from 6-8 min minus Tap A gives Tap B."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q7",
      "image_needed": true,
      "image_options": false,
      "image_file": "q37.png",
      "image_page": 22,
      "image_bbox": [0.28, 0.16, 0.58, 0.36],
      "image_loc": "line graph of volume in litres against time in minutes, top of page",
      "notes": "Paper 2 Q7. Two parts (litres). Key: (a) 2 l, (b) 8 l."
    },
    {
      "n": 38,
      "type_id": 2,
      "question": "Lynette bought some bags at an average price of $350 each. Then she bought another 2 bags for $925 each and the average price became $400. How many bags did she buy altogether?<br>[?]",
      "answer0": "21",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 205,
      "difficulty_id": 3,
      "explanation": "Let u = number of bags bought at first. Then 350u + 2 x 925 = 400(u + 2). 350u + 1850 = 400u + 800. 50u = 1050, u = 21 (bags at first). The question asks altogether... the key states u = 21 as the answer. Altogether = 21. Answer: 21.",
      "hints": ["Set up: total value before + new bags = new average x new count.", "350u + 1850 = 400(u + 2) gives u = 21."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q8",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key gives 21. Worked solution solves u (bags at first) = 21; key final answer is 21. [3 marks]"
    },
    {
      "n": 39,
      "type_id": 2,
      "question": "Muthu has some $2, $5 and $10 dollar notes. \\(\\dfrac{2}{3}\\) of the number of the $10 notes is equal to \\(\\dfrac{2}{5}\\) of the number of $2 notes which is equal to \\(\\dfrac{1}{3}\\) of the number of $5 notes. After he took out six $5 notes and exchanged them for $2 notes, the number of the $5 notes to the number of the $10 notes is now the same. Find the total value of the notes.<br>$[?]",
      "answer0": "140",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 183,
      "difficulty_id": 3,
      "explanation": "\\(\\dfrac{2}{3}\\) of $10 notes = \\(\\dfrac{2}{5}\\) of $2 notes = \\(\\dfrac{1}{3}\\) of $5 notes = \\(\\dfrac{2}{6}\\) of $5 notes. So $10 : $2 : $5 = 3 : 5 : 6 = 3u : 5u : 6u. After removing six $5 notes, $5 count = $10 count: 6u - 6 = 3u, so 3u = 6, u = 2. Notes: six $10, ten $2, twelve $5. Total value = 6 x $10 + 10 x $2 + 12 x $5 = $60 + $20 + $60 = $140. Answer: $140.",
      "hints": ["Make the three equal fractions match to find the ratio of note counts.", "$10 : $2 : $5 = 3 : 5 : 6; solve 6u - 6 = 3u to get u = 2; total = $140."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q9",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q9. Key: $140. [3 marks]"
    },
    {
      "n": 40,
      "type_id": 2,
      "question": "In the figure, ABCD is a rectangle. AB is twice as long as BC. ABE is an equilateral triangle. M is the midpoint of BE. (a) Find \\(\\angle EBC\\). (b) Find \\(\\angle CMB\\).<br>(a) [?]° (b) [?]°",
      "answer0": "30",
      "answer1": "75",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 197,
      "difficulty_id": 3,
      "explanation": "(a) \\(\\angle ABE = 60°\\) (equilateral) and \\(\\angle ABC = 90°\\) (rectangle), so \\(\\angle EBC = 90° - 60° = 30°\\). (b) M is the midpoint of BE so MB = \\(\\dfrac{1}{2}\\)BE = \\(\\dfrac{1}{2}\\)AB = BC, making triangle BCM isosceles. \\(\\angle CMB = (180° - 30°) ÷ 2 = 75°\\). Answers: (a) 30°, (b) 75°.",
      "hints": ["Equilateral triangle gives 60° at B; subtract from the rectangle's 90°.", "MB = BC makes triangle BCM isosceles, so \\(\\angle CMB = 75°\\)."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q10",
      "image_needed": true,
      "image_options": false,
      "image_file": "q40.png",
      "image_page": 25,
      "image_bbox": [0.28, 0.13, 0.66, 0.36],
      "image_loc": "rectangle ABCD with equilateral triangle ABE below and midpoint M of BE marked, top of page",
      "notes": "Paper 2 Q10. Two parts. Key: (a) 30°, (b) 75°. (Paper labels both parts 'a)'; second is part b.)"
    },
    {
      "n": 41,
      "type_id": 2,
      "question": "The ratio of the number of stickers Abel, Bala and Chen had was 3 : 5 : 2. Abel gave half of his stickers to Bala. Then, Bala gave 70 stickers to Chen. Chen had 3 times as many stickers as Abel in the end. How many stickers did Bala have at the end?<br>[?]",
      "answer0": "112",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 214,
      "difficulty_id": 3,
      "explanation": "Use units of 2 to halve evenly: Abel : Bala : Chen = 6u : 10u : 4u. Abel gives half (3u) to Bala: 3u : 13u : 4u. Bala gives 70 to Chen: 3u : (13u - 70) : (4u + 70). In the end Chen = 3 x Abel: 4u + 70 = 3 x 3u = 9u, so 5u = 70, u = 14. Bala at the end = 13u - 70 = 13 x 14 - 70 = 182 - 70 = 112. Answer: 112 stickers.",
      "hints": ["Use 6u : 10u : 4u so Abel's half is a whole number.", "Solve 4u + 70 = 9u to get u = 14; Bala = 13u - 70 = 112."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q11. Key: 112 stickers. [3 marks]"
    },
    {
      "n": 42,
      "type_id": 2,
      "question": "In the figure, ACEH is a parallelogram. AJE is a straight line. \\(\\angle GJA = 82°\\) and \\(\\angle FJE = 24°\\). \\(\\angle EJD = 84°\\) and \\(\\angle DJB = 71°\\). (a) Find \\(\\angle GJF\\). (b) Find \\(\\angle EFJ\\).<br>(a) [?]° (b) [?]°",
      "answer0": "74",
      "answer1": "122",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "(a) AJE is a straight line, so angles on one side at J: \\(\\angle GJA + \\angle GJF + \\angle FJE = 180°\\). \\(\\angle GJF = 180° - 82° - 24° = 74°\\). (b) \\(\\angle FEJ = 34°\\) (alternate angles, AC // HE). In triangle EFJ, \\(\\angle EFJ = 180° - 34° - 24° = 122°\\). Answers: (a) 74°, (b) 122°.",
      "hints": ["AJE straight: the three angles 82°, ∠GJF and 24° sum to 180°.", "Use alternate angles (AC // HE) then the angle sum of triangle EFJ."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q12",
      "image_needed": true,
      "image_options": false,
      "image_file": "q42.png",
      "image_page": 27,
      "image_bbox": [0.24, 0.14, 0.70, 0.37],
      "image_loc": "parallelogram ACEH with diagonals through J and marked angles 82°, 24°, 84°, 71°, 48°, 34°, top of page",
      "notes": "Paper 2 Q12. Parts (a) and (b) only; part (c) is a true/false tick table (interactive, omitted). Key: (a) 74°, (b) 122°."
    },
    {
      "n": 43,
      "type_id": 2,
      "question": "A shop sells erasers (4 for $1.99) and pencils (5 for $2.99). Mdm Lim spent $139.45 buying some erasers and pencils for her class. She then packed all the erasers and pencils into bags. The ratio of the number of erasers to the number of pencils in each bag was 2 : 3. How many pencils did she buy?<br>[?]",
      "answer0": "150",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 183,
      "difficulty_id": 3,
      "explanation": "Erasers : pencils = 2 : 3. Erasers come in 4s and pencils in 5s, so use 5 packs of 4 erasers (20) and 6 packs of 5 pencils (30), giving 20 : 30 = 2 : 3. Cost of one such group = 5 x $1.99 + 6 x $2.99 = $9.95 + $17.94 = $27.89. Number of groups = $139.45 ÷ $27.89 = 5. Pencils = 5 x 30 = 150. Answer: 150 pencils.",
      "hints": ["Find a whole-pack combination giving the ratio 2 : 3 (20 erasers : 30 pencils).", "Cost per group = $27.89; $139.45 ÷ $27.89 = 5 groups; pencils = 150."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q13",
      "image_needed": true,
      "image_options": false,
      "image_file": "q43.png",
      "image_page": 28,
      "image_bbox": [0.24, 0.13, 0.74, 0.30],
      "image_loc": "price chart showing erasers (4 for $1.99) and pencils (5 for $2.99), top of page",
      "notes": "Paper 2 Q13. Key: 150 pencils. [4 marks]"
    },
    {
      "n": 44,
      "type_id": 2,
      "question": "The diagram shows 6 identical rectangles in a larger rectangle ABCD. Given that AB = 19 cm and BC = 26 cm, find the area of the shaded part.<br>[?] cm²",
      "answer0": "168.5",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 464,
      "difficulty_id": 3,
      "explanation": "Let the width of each small rectangle be w. From the layout, 2w = 26 - 19 = 7, so w = 3.5 cm. Length of each small rectangle = 19 - 3.5 = 15.5 cm. Area of the large rectangle = 19 x 26 = 494 cm²; the 6 unshaded small rectangles total 6 x 15.5 x 3.5 = 325.5 cm². Shaded part = 494 - 325.5 = 168.5 cm². Answer: 168.5 cm².",
      "hints": ["Use the difference 26 - 19 to find the small rectangle's width.", "Shaded area = big rectangle - 6 small rectangles = 494 - 325.5 = 168.5 cm²."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q14",
      "image_needed": true,
      "image_options": false,
      "image_file": "q44.png",
      "image_page": 29,
      "image_bbox": [0.40, 0.17, 0.64, 0.40],
      "image_loc": "large rectangle ABCD made of 6 identical rectangles with some shaded, AB = 19 cm, BC = 26 cm, upper-middle of page",
      "notes": "Paper 2 Q14. Key: 168.5 cm². [4 marks]"
    },
    {
      "n": 45,
      "type_id": 2,
      "question": "Aini bought some sweets and chocolates. A sweet cost 40 cents each and a chocolate cost 90 cents each. She bought 150 more sweets than chocolates. She spent $40 more on the sweets than on the chocolates. How much did she spend altogether?<br>$[?]",
      "answer0": "112",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "The 150 extra sweets cost 150 x $0.40 = $60. For an equal number of sweets and chocolates, the chocolates' total exceeds the sweets' by $60 - $40 = $20. Each chocolate costs $0.90 - $0.40 = $0.50 more than a sweet, so number of chocolates = $20 ÷ $0.50 = 40. Sweets = 40 + 150 = 190. Total = 40 x $0.90 + 190 x $0.40 = $36 + $76 = $112. Answer: $112.",
      "hints": ["The 150 extra sweets account for $60 of the sweet spending.", "Equal-count comparison: chocolates cost $20 more, $0.50 more each, so 40 chocolates; total = $112."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q15",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q15. Key: $112. [5 marks]"
    },
    {
      "n": 46,
      "type_id": 2,
      "question": "Figure 1 is a trapezium which has a perimeter 28 cm. \\(\\angle CBA = \\angle DAB\\). The length of AB is twice the length of BC. 7 such trapeziums and a rhombus are joined to form Figure 2 which has a perimeter of 130 cm. Find the length of BC.<br>[?] cm",
      "answer0": "6.6",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 223,
      "difficulty_id": 3,
      "explanation": "For Figure 2, the perimeter equals 7 trapezium perimeters minus the joined edges: Perimeter of Figure 2 + 10 x BC = 7 x 28. So 130 + 10 x BC = 196, giving 10 x BC = 66, BC = 6.6 cm. Answer: 6.6 cm.",
      "hints": ["Relate the perimeter of Figure 2 to 7 trapezium perimeters and the hidden joined edges.", "130 + 10 x BC = 196, so BC = 6.6 cm."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q16",
      "image_needed": true,
      "image_options": false,
      "image_file": "q46.png",
      "image_page": 31,
      "image_bbox": [0.20, 0.13, 0.66, 0.50],
      "image_loc": "Figure 1 (single trapezium ABCD) above Figure 2 (7 trapeziums and a rhombus arranged in a ring), upper part of page",
      "notes": "Paper 2 Q16. Key: 6.6 cm. [5 marks]"
    },
    {
      "n": 47,
      "type_id": 2,
      "question": "Shermaine had some red, blue and grey stamps. She had 97 red stamps. 25% of the stamps were blue stamps. There were 7 fewer grey stamps than blue stamps. (a) How many grey stamps did Shermaine have? (b) Shermaine bought some more grey stamps. The total number of stamps increased by 10%. What percentage of the stamps in the end was grey stamps? Correct your answer to the nearest percent.<br>(a) [?] (b) [?]%",
      "answer0": "38",
      "answer1": "28",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 175,
      "difficulty_id": 3,
      "explanation": "(a) Blue = 25% of total, grey = 25% - 7 (in count terms blue is 25% and grey is 7 fewer). Red is 97. Red + grey make up the remaining 75% minus the 7: 50% of total = 97 - 7 = 90, so total = 180. Grey = 25% x 180 - 7 = 45 - 7 = 38 stamps. (b) Extra grey bought = 10% of 180 = 18. New grey = 38 + 18 = 56, new total = 180 + 18 = 198. Percentage = \\(\\dfrac{56}{198} \\times 100\\% \\approx 28\\%\\). Answers: (a) 38, (b) 28%.",
      "hints": ["Red and grey together are 75% - but combine red plus (blue - 7) to get 50% of total = 90.", "Total = 180; grey = 38. After +18 grey, 56/198 = 28%."],
      "source": "Rosyth 2025 P6 WA1 Paper 2 Q17",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper 2 Q17. Two parts. Key: (a) 38 grey stamps, (b) 28%. End of Paper 2."
    }
  ]
}