{
"paper": {
"school": "Red Swastika",
"year": 2024,
"level": "P6",
"label": "Class Test 2",
"source_prefix": "Red Swastika 2024 P6 Class Test 2",
"has_answer_key": true
},
"questions": [
{
"n": 1,
"type_id": 1,
"question": "There are 40 students in a class and 25 of them are girls. What is the ratio of the number of boys to number of girls?",
"answer0": "3 : 5",
"answer1": "3 : 8",
"answer2": "5 : 3",
"answer3": "5 : 8",
"correct_answer": 0,
"skill_id": 180,
"difficulty_id": 1,
"explanation": "Number of boys = 40 − 25 = 15. Ratio of boys to girls = 15 : 25 = 3 : 5 (dividing both by 5). Answer: 3 : 5.",
"hints": ["Find the number of boys first: total minus girls.", "Write boys : girls and simplify by dividing both terms by their common factor."],
"source": "Red Swastika 2024 P6 Class Test 2 Q1",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": ""
},
{
"n": 2,
"type_id": 1,
"question": "The circle has centre O. AOE and COF are straight lines. Which line is the diameter of the circle?",
"answer0": "AF",
"answer1": "BD",
"answer2": "EO",
"answer3": "FC",
"correct_answer": 3,
"skill_id": 220,
"difficulty_id": 2,
"explanation": "A diameter is a chord that passes through the centre O. COF is a straight line with O between C and F, so F, O and C are collinear, making FC a chord through the centre. Therefore FC is the diameter. Answer: FC.",
"hints": ["A diameter passes through the centre O of the circle.", "Look for the straight line that has O lying on it between two points on the circle."],
"source": "Red Swastika 2024 P6 Class Test 2 Q2",
"image_needed": true,
"image_options": false,
"image_file": "q2.png",
"image_page": 1,
"image_bbox": [0.38, 0.60, 0.62, 0.74],
"image_loc": "circle diagram below the question with points A,B,C,D,E,F,O"
},
{
"n": 3,
"type_id": 1,
"question": "The diameter of the semicircle is 14 cm. Find the perimeter of the semicircle. (Take \\(\\pi = \\dfrac{22}{7}\\))",
"answer0": "22 cm",
"answer1": "36 cm",
"answer2": "58 cm",
"answer3": "77 cm",
"correct_answer": 1,
"skill_id": 221,
"difficulty_id": 2,
"explanation": "Perimeter of a semicircle = half the circumference + diameter. Arc length = \\(\\dfrac{1}{2} \\times \\dfrac{22}{7} \\times 14 = 22\\) cm. Perimeter = 22 + 14 = 36 cm. Answer: 36 cm.",
"hints": ["The perimeter of a semicircle includes the curved arc AND the straight diameter.", "Arc = \\(\\dfrac{1}{2}\\times\\pi\\times d\\); then add the diameter of 14 cm."],
"source": "Red Swastika 2024 P6 Class Test 2 Q3",
"image_needed": true,
"image_options": false,
"image_file": "q3.png",
"image_page": 2,
"image_bbox": [0.34, 0.09, 0.60, 0.18],
"image_loc": "semicircle with 14 cm base, top of page above the options"
},
{
"n": 4,
"type_id": 1,
"question": "The perimeter of a square X is 36 cm. The length of square Y is 2 times the length of square X. Find the perimeter of square Y.",
"answer0": "48 cm",
"answer1": "72 cm",
"answer2": "81 cm",
"answer3": "144 cm",
"correct_answer": 1,
"skill_id": 222,
"difficulty_id": 2,
"explanation": "Length of square X = 36 ÷ 4 = 9 cm. Length of square Y = 2 × 9 = 18 cm. Perimeter of square Y = 4 × 18 = 72 cm. Answer: 72 cm.",
"hints": ["Find the side of square X from its perimeter (perimeter ÷ 4).", "Double that side to get square Y's side, then multiply by 4 for its perimeter."],
"source": "Red Swastika 2024 P6 Class Test 2 Q4",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Two squares shown for illustration only; computation does not depend on the figure."
},
{
"n": 5,
"type_id": 1,
"question": "Shaun had $100. He spent $60 on a bag and 10% of his remaining money on a shirt. What percentage of his money did Shaun spend in total?",
"answer0": "30%",
"answer1": "36%",
"answer2": "64%",
"answer3": "70%",
"correct_answer": 2,
"skill_id": 209,
"difficulty_id": 2,
"explanation": "Remaining after bag = 100 − 60 = $40. Spent on shirt = 10% of 40 = $4. Total spent = 60 + 4 = $64. As a percentage = \\(\\dfrac{64}{100}\\times100\\% = 64\\%\\). Answer: 64%.",
"hints": ["Find the money left after buying the bag, then take 10% of that for the shirt.", "Add both amounts spent, then express the total out of $100 as a percentage."],
"source": "Red Swastika 2024 P6 Class Test 2 Q5",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": ""
},
{
"n": 6,
"type_id": 2,
"question": "(a) Express 0.5 as a percentage. [?]%
(b) 200% of a number is 14. What is the number? [?]",
"answer0": "50",
"answer1": "7",
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 173,
"difficulty_id": 1,
"explanation": "(a) 0.5 = \\(\\dfrac{5}{10}\\) = \\(\\dfrac{50}{100}\\) = 50%. (b) 200% of a number is 14, so 100% = 14 ÷ 2 = 7. The number is 7.",
"hints": ["To turn a decimal into a percentage, multiply by 100.", "200% means 2 times the number, so divide 14 by 2 to find 100%."],
"source": "Red Swastika 2024 P6 Class Test 2 Q6",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Two-part numeric FIB; both answers are whole numbers."
},
{
"n": 7,
"type_id": 1,
"question": "The figure is made up of 12 identical rectangles.
(a) What is the ratio of the number of shaded rectangles to the number of unshaded rectangles to the total number of rectangles? Leave your answer in its simplest form.",
"answer0": "1 : 5 : 6",
"answer1": "2 : 10 : 12",
"answer2": "1 : 6 : 5",
"answer3": "5 : 1 : 6",
"correct_answer": 0,
"skill_id": 180,
"difficulty_id": 2,
"explanation": "Shaded = 2, unshaded = 10, total = 12. Ratio = 2 : 10 : 12 = 1 : 5 : 6 (dividing all terms by 2). Answer: 1 : 5 : 6.",
"hints": ["Count the shaded rectangles and the unshaded rectangles; the total is 12.", "Write shaded : unshaded : total and divide every term by their common factor."],
"source": "Red Swastika 2024 P6 Class Test 2 Q7",
"image_needed": true,
"image_options": false,
"image_file": "q7.png",
"image_page": 3,
"image_bbox": [0.18, 0.49, 0.88, 0.59],
"image_loc": "horizontal strip of 12 rectangles, 2 shaded, below the Q7 stem",
"notes": "Part (a) made MCQ because answer is a 3-term ratio (not a single numeric value). Part (b) split out as Q7b below."
},
{
"n": "7b",
"type_id": 2,
"question": "The figure is made up of 12 identical rectangles, of which 2 are shaded. How many more rectangles must be shaded so that 75% of the figure is shaded? [?]",
"answer0": "7",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 174,
"difficulty_id": 2,
"explanation": "75% of 12 = \\(\\dfrac{75}{100}\\times12 = 9\\) rectangles must be shaded. Already 2 shaded, so additional = 9 − 2 = 7. Answer: 7.",
"hints": ["Find 75% of the 12 rectangles to get how many should be shaded in total.", "Subtract the 2 already shaded from that total."],
"source": "Red Swastika 2024 P6 Class Test 2 Q7b",
"image_needed": true,
"image_options": false,
"image_file": "q7.png",
"image_page": 3,
"image_bbox": [0.18, 0.49, 0.88, 0.59],
"image_loc": "same strip of 12 rectangles as Q7a",
"notes": "Part (b) of Q7, separated to give it its own numeric FIB answer (7)."
},
{
"n": 8,
"type_id": 2,
"question": "Caleb drew Figure Q in a 1-cm square grid. A rectangle is drawn with the same area as Q on the square grid. What is the perimeter of the rectangle drawn? [?] cm",
"answer0": "26",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 138,
"difficulty_id": 3,
"explanation": "Figure Q has an area of 12 cm². A rectangle of the same area can be 6 cm by 2 cm, giving perimeter = 6 + 2 + 6 + 2 = 16 cm; or 12 cm by 1 cm, giving perimeter 12 + 1 + 12 + 1 = 26 cm. The marked answer is 26 cm (a 12×1 rectangle). Answer: 26 cm.",
"hints": ["Count the unit squares to find the area of Figure Q.", "Choose whole-number side lengths whose product equals that area, then add up all four sides."],
"source": "Red Swastika 2024 P6 Class Test 2 Q8",
"image_needed": true,
"image_options": false,
"image_file": "q8.png",
"image_page": 4,
"image_bbox": [0.36, 0.12, 0.60, 0.28],
"image_loc": "Figure Q drawn on the 1-cm grid at top of page",
"notes": "Answer key gives 'Ans: 26 or 14'. The student's drawn rectangle and shown working (12+1+12+1=26) give 26 for a 12x1 rectangle; a 6x2 rectangle would give 16, not 14 (key '14' appears to be a typo for 16). Using the keyed/shown value 26."
},
{
"n": 9,
"type_id": 2,
"question": "Katie grew 14 cm taller from Primary 4 to Primary 5. This was a 10% increase in her height.
(a) How tall was Katie when she was in Primary 5? [?] cm
(b) Katie was 161 cm in Primary 6. What was the percentage increase in her height from Primary 4 to Primary 6? [?] %",
"answer0": "154",
"answer1": "15",
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 208,
"difficulty_id": 3,
"explanation": "(a) 10% of P4 height = 14 cm, so P4 height (100%) = 14 × 10 = 140 cm. P5 height = 140 + 14 = 154 cm. (b) Increase from P4 to P6 = 161 − 140 = 21 cm. Percentage increase = \\(\\dfrac{21}{140}\\times100\\% = 15\\%\\). Answers: 154 cm; 15%.",
"hints": ["A 10% increase equal to 14 cm means 100% (the P4 height) is ten times 14 cm.", "For (b) find the total height gained from P4 to P6, then express it as a percentage of the P4 height."],
"source": "Red Swastika 2024 P6 Class Test 2 Q9",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Two-part numeric FIB; both answers are whole numbers (cm and %)."
},
{
"n": 10,
"type_id": 2,
"question": "Mrs Tan used a recipe for 5 cookies needing 200 g flour, 150 g butter and 60 g sugar. Mrs Tan had 700 g of flour, 300 g of butter and 200 g of sugar. She used the ingredients to make the most number of cookies. What percentage of the sugar did she use? [?] %",
"answer0": "60",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 209,
"difficulty_id": 3,
"explanation": "Per 5 cookies the recipe needs 200 g flour, 150 g butter, 60 g sugar. With 700 g flour she could make up to 17 (in groups of 5: 600 g → 15 cookies); with 300 g butter up to 10 cookies (300 g ÷ 150 g = 2 batches → 10 cookies); with 200 g sugar up to 15 cookies (180 g → 3 batches). Butter limits her to 10 cookies (2 batches). Sugar used = 2 × 60 = 120 g. Percentage of sugar used = \\(\\dfrac{120}{200}\\times100\\% = 60\\%\\). Answer: 60%.",
"hints": ["Work out how many batches of 5 cookies each ingredient allows; the smallest number limits the total.", "Find the sugar used for that many batches, then express it as a percentage of 200 g."],
"source": "Red Swastika 2024 P6 Class Test 2 Q10",
"image_needed": true,
"image_options": false,
"image_file": "q10.png",
"image_page": 5,
"image_bbox": [0.31, 0.10, 0.62, 0.21],
"image_loc": "boxed 'Recipe for 5 cookies' table at top of page",
"notes": "Recipe is in a small box; included as figure. Limiting ingredient is butter (2 batches = 10 cookies); sugar used 120 g of 200 g = 60%."
},
{
"n": 11,
"type_id": 1,
"question": "The figure shows two circles. The ratio of the diameter of the small shaded circle to the diameter of the big circle is 2 : 3. Find the ratio of the area of shaded part to the area of the unshaded part.",
"answer0": "4 : 5",
"answer1": "2 : 3",
"answer2": "4 : 9",
"answer3": "5 : 4",
"correct_answer": 0,
"skill_id": 222,
"difficulty_id": 3,
"explanation": "Area ratio = (radius)² ratio = small : big = 2² : 3² = 4 : 9. Shaded part = 4 units; unshaded part = 9 − 4 = 5 units. Ratio of shaded to unshaded = 4 : 5. Answer: 4 : 5.",
"hints": ["Areas of circles are in the ratio of the squares of their diameters (or radii).", "The unshaded part is the big circle's area minus the small shaded circle's area."],
"source": "Red Swastika 2024 P6 Class Test 2 Q11",
"image_needed": true,
"image_options": false,
"image_file": "q11.png",
"image_page": 5,
"image_bbox": [0.70, 0.60, 0.90, 0.74],
"image_loc": "small shaded circle inside a larger circle, right side of page",
"notes": "Answer made MCQ because it is a ratio. Area ratio 4:9 → shaded:unshaded = 4:5."
},
{
"n": 12,
"type_id": 2,
"question": "Joe cut out three identical right-angled triangles. He joined them to form the figure. AB = 26 cm and CD = 5 cm. The perimeter of the figure is 64 cm. Find the area of one triangle. [?] cm²",
"answer0": "30",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 186,
"difficulty_id": 3,
"explanation": "Let the longest side of each right-angled triangle (along the base) be x. The perimeter is made of 3x plus the segments 5 + 5 + 13: 3x + 5 + 5 + 13 = 64, so 3x = 64 − 23 = 36, giving x = 12 cm. AD = 26 ÷ 2 = 13 cm. Each triangle has base 12 cm and height 5 cm, so area = \\(\\dfrac{1}{2}\\times12\\times5 = 30\\) cm². Answer: 30 cm².",
"hints": ["Use the perimeter equation: the three equal long sides plus the known short segments total 64 cm.", "Once you find the base (12 cm) and height (5 cm) of a triangle, area = ½ × base × height."],
"source": "Red Swastika 2024 P6 Class Test 2 Q12",
"image_needed": true,
"image_options": false,
"image_file": "q12.png",
"image_page": 6,
"image_bbox": [0.22, 0.12, 0.82, 0.30],
"image_loc": "figure of three joined right-angled triangles with A,B,C,D labelled and 5 cm marks",
"notes": "Base x=12, height 5; area = 30 cm² per printed key."
},
{
"n": 13,
"type_id": 1,
"question": "There are some beads in boxes X, Y and Z. 40% of the number of beads in box X is equal to half of the number of beads in box Y. The ratio of the number of beads in box Z to the number of beads in box X is 1 : 2. Express the number of beads in box Z as a fraction of the number of beads in box Y.",
"answer0": "\\(\\dfrac{5}{8}\\)",
"answer1": "\\(\\dfrac{8}{5}\\)",
"answer2": "\\(\\dfrac{4}{5}\\)",
"answer3": "\\(\\dfrac{1}{2}\\)",
"correct_answer": 0,
"skill_id": 210,
"difficulty_id": 3,
"explanation": "40% of X = ½ of Y → \\(\\dfrac{40}{100}X = \\dfrac{1}{2}Y\\), so \\(\\dfrac{2}{5}X = \\dfrac{1}{2}Y\\), giving Y = \\(\\dfrac{4}{5}X\\). Let X = 40 units; then Y = 32 units (e.g. X = 40, Y = 32). Z : X = 1 : 2, so Z = 20 units. Z as a fraction of Y = \\(\\dfrac{20}{32} = \\dfrac{5}{8}\\). Answer: \\(\\dfrac{5}{8}\\).",
"hints": ["Turn '40% of X equals half of Y' into an equation to relate X and Y.", "Use Z : X = 1 : 2 to express Z in the same units, then write Z over Y and simplify."],
"source": "Red Swastika 2024 P6 Class Test 2 Q13",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Made MCQ because answer is a fraction (5/8). Printed key: 5/8 (or any equivalent)."
},
{
"n": "14a",
"type_id": 1,
"question": "Mrs Kumar prepared some cherries and blueberries to decorate some cupcakes. The ratio of the number of cherries prepared to the number of blueberries prepared was 3 : 10. Each cupcake was decorated with 1 cherry and 3 blueberries. There were 2 blueberries left when all the cherries were used. What is the ratio of the number of blueberries used to the number of blueberries left?",
"answer0": "9 : 1",
"answer1": "10 : 3",
"answer2": "3 : 1",
"answer3": "1 : 9",
"correct_answer": 0,
"skill_id": 214,
"difficulty_id": 3,
"explanation": "Cherries : blueberries prepared = 3 : 10. Each cupcake uses 1 cherry and 3 blueberries, so cherries used : blueberries used = 3 : 9 (for every 3 cherries, 9 blueberries are used). Of 10 units of blueberries, 9 are used and 1 is left (the 2 leftover = 1 unit). Ratio of blueberries used to blueberries left = 9 : 1. Answer: 9 : 1.",
"hints": ["Each cupcake uses 1 cherry and 3 blueberries, so blueberries used are 3 times the cherries.", "Compare blueberries used against blueberries prepared to find how many are left, using the 3 : 10 ratio."],
"source": "Red Swastika 2024 P6 Class Test 2 Q14a",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Part (a) made MCQ because answer is a ratio. Printed key: 9 : 1."
},
{
"n": "14b",
"type_id": 2,
"question": "Mrs Kumar prepared cherries and blueberries in the ratio 3 : 10. Each cupcake was decorated with 1 cherry and 3 blueberries. There were 2 blueberries left when all the cherries were used. How many cupcakes were there? [?]",
"answer0": "6",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 214,
"difficulty_id": 3,
"explanation": "Cherries : blueberries prepared = 3 : 10. Blueberries used = 10 − 1 = 9 units (the leftover 2 blueberries = 1 unit, so 1 unit = 2). Cherries = 3 units = 6 cherries. Each cupcake uses 1 cherry, so number of cupcakes = number of cherries = 3 × 2 = 6. Answer: 6.",
"hints": ["The 2 leftover blueberries make up 1 part of the ratio, so each part equals 2.", "All cherries are used, one per cupcake, so the number of cupcakes equals the number of cherries."],
"source": "Red Swastika 2024 P6 Class Test 2 Q14b",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Part (b) numeric FIB; answer 6 cupcakes per printed key."
},
{
"n": "15a",
"type_id": 2,
"question": "Aisha bought a pen and a notebook during a sale from a shop. She paid a total of $6 for both items after discount. The usual price of the notebook is $5. There is a 20% discount on all items. Find the price of the pen after the discount. [?]",
"answer0": "$2",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 176,
"difficulty_id": 3,
"explanation": "Notebook after 20% discount = \\(\\dfrac{80}{100}\\times5 = $4\\). Total paid = $6, so pen after discount = 6 − 4 = $2. Answer: $2.",
"hints": ["Apply the 20% discount to the notebook's usual price of $5 first.", "Subtract the discounted notebook price from the $6 total to get the pen's price."],
"source": "Red Swastika 2024 P6 Class Test 2 Q15a",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Answer is money $2; numeric FIB. Pen/notebook/SALES pictures are decorative only."
},
{
"n": "15b",
"type_id": 0,
"question": "After the sales, the number of pens in the shop decreased by 60% and the number of notebooks decreased by 20%. As a result, the total number of pens and notebooks in the shop decreased by 8. Each statement is either true, false or not possible to tell. (i) There were equal number of pens and notebooks in the shop at first. (ii) There were equal number of pens and notebooks sold during the sales.",
"answer0": null,
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 209,
"difficulty_id": 3,
"explanation": "Let pens at first = p, notebooks = n. Pens sold = 0.6p, notebooks sold = 0.2n, and 0.6p + 0.2n = 8 → 6p + 2n = 80 → 3p + n = 40. Statement (i): this single equation does not fix whether p = n (e.g. p=10,n=10 gives 40 ✓, but p=12,n=4 also works), so it is NOT POSSIBLE TO TELL. Statement (ii): pens sold = 0.6p, notebooks sold = 0.2n; with 3p + n = 40 these are not forced to be equal (e.g. p=10,n=10 → 6 vs 2, not equal), so the claim of equal sold is FALSE. Answers: (i) Not possible to tell; (ii) False.",
"hints": ["Set up an equation for the decrease: 60% of pens plus 20% of notebooks equals 8.", "Test whether the equation alone forces the two statements, or whether different valid values break them."],
"source": "Red Swastika 2024 P6 Class Test 2 Q15b",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "type_id 0 (interactive true/false/not-possible tick-table, no app question type). Printed key: (i) Not possible to tell; (ii) False."
},
{
"n": "16a",
"type_id": 2,
"question": "Ali cut out four identical semicircles from an isosceles triangular piece of paper as shown in Figure 1. The diameter of the semicircle is 20 cm. He then arranged the semicircles as shown in Figure 2. (Take \\(\\pi = 3.14\\)) Find the total area of the four semicircles. [?] cm²",
"answer0": "628",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 220,
"difficulty_id": 3,
"explanation": "Diameter = 20 cm, so radius = 10 cm. Four semicircles = 2 full circles. Total area = 2 × \\(\\pi\\) × r² = 2 × 3.14 × 10 × 10 = 628 cm². Answer: 628 cm².",
"hints": ["Four semicircles together make two whole circles.", "Use area = \\(\\pi r^2\\) with r = 10 cm, then multiply by 2."],
"source": "Red Swastika 2024 P6 Class Test 2 Q16a",
"image_needed": true,
"image_options": false,
"image_file": "q16.png",
"image_page": 9,
"image_bbox": [0.18, 0.13, 0.88, 0.33],
"image_loc": "Figure 1 (triangle with semicircles, 20 cm) and Figure 2 (arranged semicircles, 16 cm) side by side",
"notes": "Four semicircles = 2 circles; r=10. Area 628 cm² per printed key."
},
{
"n": "16b",
"type_id": 2,
"question": "Four identical semicircles (diameter 20 cm) were cut from an isosceles triangular piece of paper, the right-angled triangle having two equal sides of 40 cm. (Take \\(\\pi = 3.14\\)) Find the area of the remaining piece of paper. [?] cm²",
"answer0": "172",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 222,
"difficulty_id": 3,
"explanation": "The triangle has base 40 cm and height 40 cm, so area = \\(\\dfrac{1}{2}\\times40\\times40 = 800\\) cm². Subtract the four semicircles (628 cm² from part a). Remaining = 800 − 628 = 172 cm². Answer: 172 cm².",
"hints": ["Find the area of the right-angled triangular paper (½ × base × height = ½ × 40 × 40).", "Subtract the total area of the four semicircles found in part (a)."],
"source": "Red Swastika 2024 P6 Class Test 2 Q16b",
"image_needed": true,
"image_options": false,
"image_file": "q16.png",
"image_page": 9,
"image_bbox": [0.18, 0.13, 0.88, 0.33],
"image_loc": "same Figure 1 / Figure 2 diagram as Q16a",
"notes": "Triangle area 800 (base=height=40 cm from working) minus 628 = 172 cm² per printed key."
},
{
"n": "16c",
"type_id": 2,
"question": "Four identical semicircles of diameter 20 cm were arranged as shown in Figure 2, with a flat segment of 16 cm. (Take \\(\\pi = 3.14\\)) Find the perimeter of Figure 2. [?] cm",
"answer0": "157.6",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 221,
"difficulty_id": 3,
"explanation": "Length of the four semicircular arcs = 4 × (½ × \\(\\pi\\) × 20) = 2 × 3.14 × 20 = 125.6 cm. Add the straight edges: 16 + 16 = 32... using the printed working, perimeter = 125.6 + 16 + 16 = 157.6 cm. Answer: 157.6 cm.",
"hints": ["Each semicircle contributes a curved arc of ½ × \\(\\pi\\) × diameter; there are four of them.", "Add the straight 16 cm edges shown on Figure 2 to the total arc length."],
"source": "Red Swastika 2024 P6 Class Test 2 Q16c",
"image_needed": true,
"image_options": false,
"image_file": "q16.png",
"image_page": 9,
"image_bbox": [0.18, 0.13, 0.88, 0.33],
"image_loc": "same Figure 1 / Figure 2 diagram as Q16a",
"notes": "Printed working: 4 arcs = 125.6; + 16 + 16 = 157.6 cm. Answer 157.6 cm per printed key."
}
]
}