Compare by place value (all start with 3 thousands): 3079 (0 hundreds) < 3790 (7 hundreds) < 3907 (9 hundreds). Smallest to greatest: 3079, 3790, 3907.


From 21 35 to 22 00 is 25 min. From 22 00 to 06 00 is 8 h. Total = 8 h 25 min.


The required new difference is 112. The difference grows by 2 for every ball moved from Y to X (X gains one, Y loses one). Extra difference needed = 112 − 96 = 16. Balls to transfer = 16 ÷ 2 = 8.


Factory B is 3 times Factory A, so together they are 3 + 1 = 4 equal units = 1508 boxes. One unit (Factory A) = 1508 ÷ 4 = 377. Factory B = 3 × 377 = 1131 boxes.


a) 10 copies earn 10 × $0.25 = $2.50 plus the $1.50 bonus = $4.00. b) Every 10 copies earn $4, so $48 ÷ $4 = 12 sets of 10 copies = 12 × 10 = 120 copies.


Flight leaves NZ at 06 40. Arrival in NZ time = 06 40 + 9 h 55 min = 16 35 (NZ time). Singapore is 4 h behind NZ, so subtract 4 h: 16 35 − 4 h = 12 35. Kathy reaches Singapore at 12 35.


1 unit = 344 ÷ 4 = 86. a) Apples = \(\dfrac{3}{4}\) = 3 units = 3 × 86 = 258. b) Remaining = 86; oranges = half = 86 ÷ 2 = 43. To match the apples (258), more oranges needed = 258 − 43 = 215.


Method: the digit 5 stands for 500 when it is in the hundreds place. In 6573, the 5 is in the hundreds place, so it stands for 500. Answer: 6573.


Method: find the common factors. Factors of 24: 1,2,3,4,6,8,12,24. Factors of 30: 1,2,3,5,6,10,15,30. 6 is a factor of both. Answer: 6.


Method: rounding to the nearest ten gives 53 200 for numbers from 53 195 to 53 204. 53 196 rounds up to 53 200. Answer: 53 196.


Method: each whole has 5 one-fifths. 3 wholes = 3 x 5 = 15 one-fifths. Answer: 15.


Method: in 23.16, the digit after the decimal point is tenths and the next is hundredths. The 6 is in the hundredths place, so it stands for 6 hundredths. Answer: hundredths.


Method: 0.15 has 2 decimal places, so it is 15 hundredths = \(\dfrac{15}{100}\). Answer: \(\dfrac{15}{100}\).


Method: look at the tenths digit. 18.57 has 5 in the tenths place, which is 5 or more, so round up. 18.57 rounds to 19. Answer: 19.


Method: align the decimals. 7.30 - 0.92 = 6.38. Answer: 6.38.


Method: 5.79 x 6 = 34.74 (since 579 x 6 = 3474, then place the decimal two places). Answer: 34.74.


Method: \(\dfrac{2}{5}\) of the total = 54 (papaya), so total = 54 ÷ 2 x 5 = 135 students. Mango = total - apple - orange - papaya = 135 - 35 - 32 - 54 = 14. Answer: 14.


Method: pear = 3.4 ÷ 5 = 0.68 kg. Total = watermelon + pear = 3.4 + 0.68 = 4.08 kg. Answer: 4.08 kg.


Method: it is Sunday, so use Sat–Sun prices. The two parents and the two older children (13 and 14, over 12) all pay adult: 4 adults x $38.50 = $154. The 8-year-old pays child: $22. Total = 154 + 22 = $176. Answer: $176.


Method: cost of 1 laptop = 7692 ÷ 6 = $1282. Cost of 5 laptops = 1282 x 5 = $6410. Answer: $6410.


Method: (a) she ate \(\dfrac{2}{9}\), so \(\dfrac{7}{9}\) remained. The 12 given away + 9 left = 21 cookies = \(\dfrac{7}{9}\) of the total. So \(\dfrac{1}{9}\) = 21 ÷ 7 = 3, and the total = 3 x 9 = 27 cookies. (b) cookies left = 9 out of 27 = \(\dfrac{9}{27}\) = \(\dfrac{1}{3}\). Answer: (a) 27; (b) \(\dfrac{1}{3}\).


Method: Sharon has 3 units and Leo 1 unit, total 4 units = 3260, so 1 unit = 815. Sharon = 2445, Leo = 815. For Sharon to have 270 more than Leo from a total of 3260: Leo's new amount = (3260 - 270) ÷ 2 = 2990 ÷ 2 = 1495, Sharon's new = 1495 + 270 = 1765. Sharon must give = 2445 - 1765 = 680 stickers. Answer: 680.


Method: (a) pencils come in 4s, erasers in 6s. The least equal number is the lowest common multiple of 4 and 6 = 12. (b) 44 pencils = 11 packs x $3 = $33. With $33, erasers cost $5 per 6: 33 ÷ 5 = 6 packs ($30) remainder $3, so 6 packs = 36 erasers (the $3 left is not enough for another pack). Answer: (a) 12; (b) 36.


Method: (a) the difference between 10 and 6 egg tarts is 4 egg tarts. Keith had $1.90 left; Sam was short $5.50, so 4 egg tarts cost 1.90 + 5.50 = $7.40. 1 egg tart = 7.40 ÷ 4 = $1.85. (b) Sam (same money as Keith) = cost of 6 egg tarts + $1.90 = (1.85 x 6) + 1.90 = 11.10 + 1.90 = $13. Answer: (a) $1.85; (b) $13.


The digit 8 stands for 800 when it is in the hundreds place. In 7 862, the 8 is in the hundreds position, so it stands for 800. Answer: 7 862.


Add by place value: 10000 + 5000 + 600 + 4 = 15 604. Note there are no tens, so the tens digit is 0. Answer: 15 604.


A number must be divisible by both 2 and 3. 12 = 2 x 6 and 12 = 3 x 4, so both 2 and 3 are factors of 12. Answer: 12.


A fraction is in simplest form when the numerator and denominator share no common factor other than 1. \(\dfrac{6}{9}\) can be simplified by dividing both by 3 to give \(\dfrac{2}{3}\), so it is NOT in simplest form. Answer: \(\dfrac{6}{9}\).


Compare whole-number parts first: 0.73 and 0.75 are less than 1; 7.03 and 7.3 are over 7. Order the small pair: 0.73 < 0.75. Order the large pair: 7.03 < 7.3. So smallest to greatest: 0.73 , 0.75 , 7.03 , 7.3. Answer: option 2.


The sand is 30.14 kg lighter than the bricks, so the bricks are 30.14 kg heavier than the sand. Mass of bricks = 2.5 + 30.14 = 32.64 kg. Answer: 32.64 kg.


Rounding to the nearest tenth means keeping 1 decimal place. Look at the hundredths digit (2): since 2 is less than 5, round down. 12.329 rounds to 12.3 l. Answer: 12.3 l.


To round to the nearest ten, look at the ones digit (5). Since 5 rounds up, the tens digit goes from 2 to 3. 8325 rounds to 8330. Answer: 8330.


One whole = \(\dfrac{11}{11}\), which is eleven groups of \(\dfrac{1}{11}\). So there are 11 one-elevenths in 1 whole. Answer: 11.


Multiply the whole number by the denominator and add the numerator: 2 x 3 + 2 = 8. Keep the denominator 3. So \(2\dfrac{2}{3}=\dfrac{8}{3}\). Answer: \(\dfrac{8}{3}\).


Common multiples of 4 and 6 are multiples of 12. The first two are 12 and 24. Their sum is 12 + 24 = 36. Answer: 36.


At first = water left + water spilled = \(1\dfrac{1}{2}+\dfrac{2}{3}\). Common denominator 6: \(1\dfrac{3}{6}+\dfrac{4}{6}=1\dfrac{7}{6}=2\dfrac{1}{6}\). Answer: \(2\dfrac{1}{6}\) l.


A square has 4 equal sides, so each side = 48 ÷ 4 = 12 cm. Area = side x side = 12 x 12 = 144 cm^2. Answer: 144 cm^2.


The number leaves remainder 2 when divided by 5 (so ends in 2 or 7) and remainder 4 when divided by 6. Check numbers ending in 2 or 7: 22 ÷ 6 = 3 r 4 and 22 ÷ 5 = 4 r 2. So the least number is 22. Answer: 22.


Money left after the blouse = 188.70 - 39.90 = 148.80. Shared among 3 children: 148.80 ÷ 3 = 49.60. Each child received $49.60. Answer: $49.60.


The total stays the same: 4730 + 1240 = 5970. In the end Timmy has twice Ahmad, so the total is 3 equal parts. Ahmad's final amount = 5970 ÷ 3 = 1990. Ahmad started with 1240, so he received 1990 - 1240 = 750 marbles. Answer: 750.


The digit 6 stands for 600 when it is in the hundreds place. In 7603, the 6 is in the hundreds place (6 hundreds = 600). Answer: 7603.


Factors of 18: 1, 2, 3, 6, 9, 18. Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24. Common factors include 1, 2, 3, 6. Among the options, 3 and 6 are both common factors. Answer: 3 and 6.


Each whole has 4 one-quarters. 2 wholes = 2 × 4 = 8 one-quarters. Answer: 8.


Convert the mixed number to an improper fraction: 7 × 9 + 4 = 63 + 4 = 67. So \(7\dfrac{4}{9}=\dfrac{67}{9}\). Answer: 67.


To round 223.74 to 1 decimal place, look at the 2nd decimal digit (4). Since 4 < 5, round down: 223.7. Answer: 223.7.


Factors of 20: 1, 2, 4, 5, 10, 20. Multiples of 5: 5, 10, 15, 20. The number is in both lists and between 6 and 19: that is 10. Answer: 10.


40 ÷ 7 = 5 bags with remainder 5 plums. 5 bags × $6 = $30, plus 5 plums × $1 = $5. Total = $30 + $5 = $35. Answer: $35.


David = 1 unit, Ann = 4 units, total = 5 units = 8060. 1 unit = 8060 ÷ 5 = 1612. David scored 1612 points. Answer: 1612.


Mdm Siti is shorter, so subtract: 1.6 − 0.02 = 1.58 m. Answer: 1.58 m.


Values from 1.65 up to just below 1.75 round to 1.7. The largest option that still rounds to 1.7 is 1.74. Wait — 1.84 rounds to 1.8, not 1.7. Re-check: the maximum value that rounds to 1.7 is just under 1.75, so 1.74 is the maximum among valid options. The answer key marks option (4) 1.84; however 1.84 rounds to 1.8. Mathematically the maximum that rounds to 1.7 is 1.74 (option 2).


Ninety thousand = 90 000. Sixteen = 16. Combine: 90 000 + 16 = 90 016. Answer: 90 016.


Compare tenths first: 0.605 and 0.506 have 6 and 5 tenths; 0.065 has 0 tenths. So 0.605 > 0.506 > 0.065. Greatest to smallest: 0.605, 0.506, 0.065.


45 ÷ 7 = 6.428... The 3rd decimal digit is 8, so round up the 2nd decimal: 6.43. Answer: 6.43.


Let 1 spoon = 1 unit, 1 mug = 2 units. 2 spoons + 2 mugs = 2 + 4 = 6 units = $27, so 1 unit = $4.50. 3 spoons = 3 × $4.50 = $13.50. Answer: $13.50.


Each of the 140 customers took 2 + 1 free = 3 buns: 140 × 3 = 420 buns. Remaining = 1167 − 420 = 747. Packed into 9 bags: 747 ÷ 9 = 83 buns per bag. Answer: 83.


In 48 630, the digit 6 is in the hundreds place. So its value is 6 × 100 = 600.


Factors of 9: 1, 3, 9. Factors of 18: 1, 2, 3, 6, 9, 18. Common factors are 1, 3, 9. Of the options, only 3 and 9 are both common factors.


Compare the numbers: 17 024 < 17 204 < 17 420. Only option 4 lists them smallest to greatest.


The pattern increases by 3 each time: 50 970, 50 973, 50 976, 50 979, 50 982, 50 985. So the two missing numbers are 50 979 and 50 982.


Make denominators the same: \(\dfrac{1}{2}=\dfrac{4}{8}\). Then \(\dfrac{6}{8}-\dfrac{4}{8}=\dfrac{2}{8}=\dfrac{1}{4}\).


Twenty thousand = 20 000, four hundred = 400, eleven = 11. Adding: 20 000 + 400 + 11 = 20 411.


The tens digit of 72 650 is 5, so we round up. 72 650 rounded to the nearest hundred is 72 700.


Multiply the whole number by the denominator and add the numerator: 2 × 7 + 5 = 19. Keep the denominator: \(\dfrac{19}{7}\).


Looking at the differences, the pattern decreases by 50 each step (14 060 → 14 010 = −50; 13 910 → 13 860 = −50). So after 13 860 comes 13 860 − 100 ... the consistent pattern gives 13 760 (13 860 − 100). 13 760 → 13 710 → 13 610. Missing number is 13 760.


All factors of 24 are 1, 2, 3, 4, 6, 8, 12, 24. The ones not listed are 2 and 12.


Convert \(5\dfrac{1}{2}\) to tenths: \(5\dfrac{1}{2}=\dfrac{11}{2}=\dfrac{11\times5}{2\times5}=\dfrac{55}{10}\). The missing number is 55.


0.43 has 2 decimal places (hundredths), so 0.43 = \(\dfrac{43}{100}\). 43 and 100 share no common factor, so it is already in simplest form.


3095 ÷ 6 = 515 remainder 5. The leftover 5 pens still need 1 more bag. So least number of bags = 515 + 1 = 516.


From the 3rd to the 8th lamppost there are 5 gaps = 45 m, so each gap = 45 ÷ 5 = 9 m. a) From 1st to 4th lamppost there are 3 gaps = 3 × 9 = 27 m. b) Number of gaps in 8136 m = 8136 ÷ 9 = 904 gaps, so number of lampposts = 904 + 1 = 905.


The pattern increases by 4 each time: 5, 9, 13, 17, 21, 25. So the missing numbers are 17 and 21. Answer: (4) 17 , 21.


A number with both 4 and 5 as factors must be a multiple of 20. Of the options, only 40 (40 = 4 x 10 = 5 x 8) is divisible by both 4 and 5. Answer: (3) 40.


Convert the mixed number to an improper fraction: 5 x 7 + 6 = 35 + 6 = 41. So the missing numerator is 41. Answer: (4) 41.


Rounding 334.51 to 1 decimal place: look at the 2nd decimal digit (1). Since 1 < 5, round down, keeping the tenths digit as 5. So 334.51 becomes 334.5. Answer: (2) 334.5.


2/4, 3/6 and 6/12 all simplify to 1/2. But 5/8 does not equal 1/2 (half of 8 is 4, not 5). So 5/8 is not equivalent. Answer: (3) 5/8.


If he gave away 3/5, then 2/5 was left = 20 sweets. So 1/5 = 10 sweets and the total = 50 sweets. He gave away 3/5 = 30 sweets, shared equally among 5 friends: 30 div 5 = 6 each. Answer: (3) 6.


Twelve thousand = 12 000, sixty-one = 61. Together: 12 000 + 61 = 12061.


Compare the hundreds digit first: 531 and 513 start with 5, 153 and 135 start with 1. So 531 > 513 > 153 > 135. Greatest to smallest: 531, 513, 153, 135.


Let the number be the unit. 4 units minus 1/2 unit = 49. That is 3 1/2 units = 49, so 7/2 units = 49, giving 1 unit = 49 x 2 div 7 = 14. The number is 14.


2 oranges = 3 apples, so 4 oranges = 6 apples. Then 4 oranges + 4 apples = 6 apples + 4 apples = 10 apples = $15. So 1 apple = $15 div 10 = $1.50, and 5 apples = 5 x $1.50 = $7.50.


Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36. Adding 3 must give a multiple of 4 greater than 10. Testing: 9 + 3 = 12, which is a multiple of 4 greater than 10. So the number is 9.


Lace used = 3.59 + 1.25 = 4.84 m. Remaining = 10 - 4.84 = 5.16 m. Cut into two equal pieces: 5.16 div 2 = 2.58 m each.


(a) From 07 59 to 13 00: 07 59 to 08 00 is 1 min, then 08 00 to 13 00 is 5 h. Total = 5 h 1 min. (b) Total travel time = 40 min + 25 min = 65 min = 1 h 5 min. Working back from 2.15 p.m.: 2.15 p.m. - 1 h 5 min = 1.10 p.m.


Blue + white = 541 + 459 = 1000 cubes, which is the non-yellow part. Since 5/9 are yellow, 4/9 are not yellow = 1000, so 1/9 = 250 and total = 2250. Yellow = 5/9 x 2250 = 1250. More yellow than white = 1250 - 459 = 791.


Difference between ropes stays the same: 2322 - 1065 = 1257 cm. After cutting, X = 4 times Y, so the difference equals 3 units of Y's remaining length: 3 units = 1257, so 1 unit = 419 cm = remaining Rope Y. Length cut = 1065 - 419 = 646 cm = 6 m 46 cm.


In 15 093, the digit 5 is in the thousands place. Place value = 5 × 1000 = 5000.


All share 70 thousands. Compare the last three digits: 135 < 153 < 315 < 351. Increasing order: 70 135, 70 153, 70 315, 70 351.


Look at the tens digit (5). Since 5 ≥ 5, round the hundreds up: 78 253 ≈ 78 300.


Factors of 81 are 1, 3, 9, 27, 81. 81 ÷ 8 leaves a remainder, so 8 is not a factor.


Find the lowest common multiple of 6 and 8. Multiples of 6: 6, 12, 18, 24, ...; multiples of 8: 8, 16, 24, ... The first common multiple is 24, so the 24th child gets both.


Game sets given out = 24 × 20 = 480. Add the 10 left over: 480 + 10 = 490.


A multiple of 9 plus 7 between 47 and 60: 45 + 7 = 52. Check: 52 ÷ 9 = 5 remainder 7. The number is 52.


Divide the total equally: 5350 ÷ 5 = 1070. Each centre received 1070 masks.


Numbers that leave remainder 1 when divided by 3: 1, 4, 7, 10, 13, 16, 19, ... Numbers that leave remainder 5 when divided by 7: 12, 19, 26, ... The common number under 30 is 19. Max has 19 erasers.


The 42 balls fill \(\dfrac{3}{7}-\dfrac{1}{7}=\dfrac{2}{7}\) of the box, so 2 units = 42 balls and 1 unit = 42 ÷ 2 = 21 balls. The box is now \(\dfrac{3}{7}\) filled, leaving \(\dfrac{4}{7}\) empty (7 − 3 = 4 units). Balls needed = 4 × 21 = 84.


The students scoring 50 and above = 12 + 10 + 13 = 35, which is \(\dfrac{5}{6}\) of the class (since \(\dfrac{1}{6}\) failed). So 5 units = 35 and 1 unit = 35 ÷ 5 = 7. Total class = 6 × 7 = 42 students.


Let Ali = 1 unit. Bala = 3 units, Cathy = 2 units. Total = 1 + 3 + 2 = 6 units = $1500, so 1 unit = 1500 ÷ 6 = $250 (Ali). Bala and Cathy together = 1500 − 250 = $1250.


"More than 3 children" means 4 children or 5 children. Families with 4 = 8, families with 5 = 3. Total = 8 + 3 = 11.


Let Asher = 1 unit. Jacob = 2 units. Caden = 3 × Jacob = 6 units. Total = 1 + 2 + 6 = 9 units = $441. 1 unit = 441 ÷ 9 = $49. Asher has $49.


After John gives 25 cards, the difference between them becomes 376 − 25 − 25 = 326 cards. Since John then has twice as many as Alex, John = 2 units and Alex = 1 unit, so the difference of 1 unit = Alex's amount = 326. Alex had 326 cards in the end.


She gave away \(\dfrac{7}{8}\), so \(\dfrac{1}{8}\) is left = 36 tarts. Total = \(\dfrac{8}{8}\) = 36 × 8 = 288 pineapple tarts.


Let brown = 1 unit. Blue = 1 unit + 360. Orange = blue = 1 unit + 360. Total = 3 units + 720 = 1455. So 3 units = 1455 − 720 = 735, and 1 unit = 735 ÷ 3 = 245. Brown buttons = 245.


The first 13 rows have 28 chairs each: 28 × 13 = 364. The last row has 20 chairs. Total = 364 + 20 = 384 chairs.


Decreasing order = largest to smallest. Compare the numbers: 61 792 > 61 279 > 60 927 > 60 729. This matches option (3).


A multiple of 8 is divisible by 8. 56 = 8 × 7, so 56 is a multiple of 8. The others are not.


Factors of 25: 1, 5, 25. Factors of 24: 1, 2, 3, 4, 6, 8, 12, 24. Two consecutive years means last year's age and this year's age are consecutive. 5 (factor of 25) then 6 (factor of 24) works. So this year she is 6, and next year she will be 7. This matches option (1).


The pattern increases by 30 each time (20 910 - 20 880 = 30). Missing number = 20 910 + 30 = 20 940.


To round up to 87 000 to the nearest 1000, the smallest number must round up from the 86 000s. The smallest is 86 500 (the half-way point rounds up).


Giving 7 instead of 6 to each cousin uses 1 more tart per cousin. The change is from 2 left over to 6 short, a difference of 2 + 6 = 8 tarts. So there are 8 cousins (8 extra tarts needed, 1 per cousin).


Let Xenia have 1 unit and Yasmin 2 units at first. After Yasmin gives 26: Yasmin = 2u - 26, Xenia = 1u + 26. Difference = (2u - 26) - (1u + 26) = u - 52 = 40, so u = 92 (Xenia at first). Yasmin at first = 2 × 92 = 184.


Let Cathy = 1 unit. Janice = 2 units. Alicia = 3 × Janice = 6 units. Alicia - Janice = 6u - 2u = 4u = 72, so 1 unit = 18. Cathy = 18, Janice = 36, Alicia = 108. Alicia - Cathy = 108 - 18 = 90.


Convert the mixed number to an improper fraction with denominator 8: \(3\dfrac{7}{8} = \dfrac{3\times8 + 7}{8} = \dfrac{31}{8}\). So there are 31 eighths.


\(\dfrac{1}{2}\) of 12 slices = 6 slices to the neighbour. Daughter got 4 slices. Slices given away = 6 + 4 = 10. Slices left = 12 − 10 = 2.


(Annie + Betty) + (Betty + Cathy) = \(\dfrac{1}{2} + \dfrac{3}{4} = \dfrac{2}{4} + \dfrac{3}{4} = \dfrac{5}{4}\) m. This counts Betty twice plus Annie + Betty + Cathy. So Betty = \(\dfrac{5}{4} - \dfrac{4}{5} = \dfrac{25}{20} - \dfrac{16}{20} = \dfrac{9}{20}\) m.


To round 235 189 to the nearest hundred, look at the tens digit (8). Since 8 ≥ 5, round up: 235 189 ≈ 235 200.


Factors of 45: 1, 3, 5, 9, 15, 45. Factors of 63: 1, 3, 7, 9, 21, 63. Common factors: 1, 3, 9. So 3 and 9 are common factors.


Order from greatest to smallest: 59 843 > 59 348 > 58 349. Compare ten-thousands/thousands then hundreds. Option 4 is correct.


Doughnuts in boxes = 12 × 6 = 72. Add the 3 left unpacked: 72 + 3 = 75.


Expand 93 708 = 90 000 + 3000 + 700 + 8. The missing number is the hundreds part, 700.


Numbers from 90 500 to 91 499 round to 91 000 to the nearest 1000. The greatest such whole number is 91 499.


Multiples of 3: 3, 6, 9, 12, 15, 18, ... Multiples of 9: 9, 18, 27, ... The first two common multiples are 9 and 18.


The number of bags must divide both 48 and 60 with no remainder, so it is a common factor of 48 and 60. To make the red pens per bag smallest, use the largest number of bags = HCF(48, 60) = 12. Red pens per bag = 48 ÷ 12 = 4.


Andy listed the factors of 32. 1 , 2 , 8 , 32 He missed out two factors. What were the two missing factors? <input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> and <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

All factors of 32 are 1, 2, 4, 8, 16, 32. Andy listed 1, 2, 8, 32, so the missing factors are 4 and 16.


Jenny has $7500. James has $6850. How much must Jenny give to James so that both of them have the same amount of money? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Difference = $7500 − $6850 = $650. Jenny gives half the difference so they are equal: $650 ÷ 2 = $325.


Ada, Ben and Chris had 720 stickers altogether. Ben had twice as many stickers as Ada, Chris had 40 stickers less than Ada. How many stickers did Ben have? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Let Ada = 1 unit. Ben = 2 units, Chris = 1 unit − 40. Total = 4 units − 40 = 720, so 4 units = 760 and 1 unit = 190. Ben = 2 units = 380.


Mr Lim bought 5 identical T-shirts and a pair of pants. He paid $120 for the 5 T-shirts. The pair of pants cost 3 times as much as one T-shirt.
(a) How much did one T-shirt cost?
(b) How much did the pair of pants cost?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) One T-shirt = $120 ÷ 5 = $24. (b) The pants cost 3 times one T-shirt = 3 × $24 = $72.


Add by place value: 50 000 + 900 + 8 = 50 908. There are 5 ten-thousands, 0 thousands, 9 hundreds, 0 tens and 8 ones. Answer: 50 908.


Arrange the following numbers from the greatest to the smallest.<br>9605, 9065, 9506

Compare from the largest place value. All have 9 thousands. Hundreds: 9605 and 9506 have 6 and 5 hundreds; 9065 has 0 hundreds. So 9605 > 9506 > 9065. Greatest to smallest: 9605, 9506, 9065. Answer: option 4.


A number with both 3 and 4 as factors must be a multiple of 12. Check: 15 (no), 18 (4 is not a factor), 20 (3 is not a factor), 24 = 3 x 8 = 4 x 6. So 24 has both 3 and 4 as factors. Answer: option 4.


a) Write seventy-eight thousand and twenty in numerals.
b) Round 39 500 to the nearest thousand.
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

a) Seventy-eight thousand and twenty = 78 000 + 20 = 78 020. b) 39 500 is exactly halfway between 39 000 and 40 000; rounding to the nearest thousand rounds the half up to 40 000.


Find the product of 8540 and 7. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Ben packed 853 books in boxes of 9. How many books were left unpacked? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Divide 853 by 9 and find the remainder. 9 x 94 = 846, and 853 - 846 = 7. So 94 full boxes are packed and 7 books are left unpacked. Answer: 7 books.


Andy had $450 more than Betty. Betty gave $35 to Andy. How much more did Andy have than Betty in the end? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

When Betty gives $35 to Andy, Andy gains $35 and Betty loses $35, so the gap between them widens by 2 x $35 = $70. New difference = $450 + $70 = $520. Answer: $520.


At a bookshop, pens are sold in boxes of 6 and pencils are sold in boxes of 8. Miss Nurul bought an equal number of pens and pencils for her class. Find the least total number of pens and pencils Miss Nurul bought. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

For an equal number of pens and pencils, the count must be a common multiple of 6 and 8. The least common multiple of 6 and 8 is 24, so the least number of pens is 24 and the least number of pencils is 24. Total = 24 + 24 = 48.


A fruit seller had 4 times as many durians as watermelons. After he sold 114 durians, he had as many watermelons as durians left. How many fruits did the fruit seller have left in the end? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Let watermelons = 1 unit, durians = 4 units. After selling 114 durians, durians left = watermelons = 1 unit, so 114 durians = 4 units - 1 unit = 3 units. 1 unit = 114 / 3 = 38. Watermelons = 38 and durians left = 38, so fruits left = 38 + 38 = 76.


A school bag costs $60 more than a water bottle. 3 similar school bags and 2 similar water bottles cost $280. How much does each water bottle cost? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Each bag = bottle + $60. So 3 bags = 3 bottles + 3 x $60 = 3 bottles + $180. Then 3 bags + 2 bottles = 5 bottles + $180 = $280. So 5 bottles = $280 - $180 = $100, and 1 bottle = $100 / 5 = $20.


Tammy has 35 $2 and $5 notes. The total value of the notes is $118. How many $5 notes does she have? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Assume all 35 notes are $2: value = 35 x $2 = $70. The actual total is $118, which is $48 more. Each $2 note swapped for a $5 note adds $3. So number of $5 notes = $48 / $3 = 16.


Arrange the following numbers from the smallest to the largest.
3.5 , 3.05 , \(3\dfrac{1}{100}\)
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> (smallest) , <input type="text" id="input_1" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />


List all the common factors of 16 and 28. <br>(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />   (c) <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />

Factors of 16: 1, 2, 4, 8, 16. Factors of 28: 1, 2, 4, 7, 14, 28. The factors common to both are 1, 2 and 4.


Find the product of 358 and 35. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Find the value of 6793 ÷ 6 <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Express \(\dfrac{42}{8}\) as a mixed number in its simplest form.


Compare the fractions. Use '<' or '>' to indicate which is greater or smaller.<br>\(2\dfrac{5}{8}\) \(\dfrac{5}{2}\)


A stadium can seat 52 000 people when rounded to the nearest thousand. What is the greatest possible seating capacity of this stadium? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Numbers from 51 500 to 52 499 round to 52 000. The greatest of these is 52 499.


I am thinking of a 3-digit number.
When rounded to the hundred, the number is 800.
The digit in the hundreds place is twice that in the tens place.
The sum of all the digits is 15.
What is this number?
Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Rounds to 800, so the number is 750-849; the hundreds digit is 8, tens digit < 5. Hundreds = twice tens means tens = 4 (8 = 2 x 4). Digits sum to 15: 8 + 4 + ones = 15, so ones = 3. The number is 843.


James bought an equal number of red and blue marbles. He arranged the red marbles in groups of 5 and the blue marbles in groups of 3. What is the least possible number of red and blue marbles James bought altogether? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

The number of each colour must be a common multiple of 5 and 3. The least common multiple is 15, so there are 15 red and 15 blue marbles. Altogether 15 + 15 = 30 marbles.


There were 141 sweets in a box. Melvin gave away \(\dfrac{2}{3}\) of them to his friends and kept the rest. How many sweets did he give away? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


A storybook and 2 notepads cost $46 altogether. The 2 notepads cost $10 less than the storybook. How much does 1 notepad cost? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

If the 2 notepads cost $10 less than the storybook, then 2 notepads + 2 notepads + $10 = $46. So 4 notepads = $46 - $10 = $36, and 1 notepad = $36 ÷ 4 = $9.


Dan had thrice as many erasers as Elijah at first. After their parents gave them an equal number of erasers each, Dan had twice as many erasers as Elijah and they had a total of 84 erasers. How many erasers did Dan have at first? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

After receiving erasers, total 84 is split as Dan : Elijah = 2 : 1, i.e. 3 units = 84, so 1 unit = 84 ÷ 6... working: 84 ÷ 3 units gives Dan 56 and Elijah 28 after. The equal amount added is x, so Elijah-first = 28 - x and Dan-first = 56 - x = 3(28 - x). Solving: 56 - x = 84 - 3x, 2x = 28, x = 14. Dan at first = 56 - 14 = 42 erasers. (Key working: 84 ÷ 6 = 14, 14 x 3 = 42.)


Nicholas donated some of his savings to charity. He donated \(\dfrac{3}{8}\) of it to Charity A and \(\dfrac{1}{4}\) of it to Charity B. He then donated the rest of his savings equally among 4 other charities. If each of these 4 charities received $60, how much money did he donate to all 6 charities? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

The 4 other charities received 4 x $60 = $240, which is the rest of the savings. Fraction left = 1 - \(\dfrac{3}{8}\) - \(\dfrac{1}{4}\) = 1 - \(\dfrac{3}{8}\) - \(\dfrac{2}{8}\) = \(\dfrac{3}{8}\). So \(\dfrac{3}{8}\) of savings = $240, meaning \(\dfrac{1}{8}\) = $80 and total savings = $80 x 8 = $640. All 6 charities together received the whole savings, $640.


Write the number:<br>Fifty thousand, eight hundred and three.

Fifty thousand = 50 000, eight hundred = 800, three = 3. So the number is 50 000 + 800 + 3 = 50 803.


Complete the number pattern.<br>74 603, 73 603, <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />, 71 603, 70 603, <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />


Arrange the numbers in increasing order.
39 039, 40 390, 40 309, 39 309
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />, <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />, <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />, <input type="text" id="input_3" class="fill-blank-input" placeholder="?" />

Compare from the largest place value. 39 039 and 39 309 are in the 39-thousands; 39 039 < 39 309. 40 309 and 40 390 are in the 40-thousands; 40 309 < 40 390. Increasing order: 39 039, 39 309, 40 309, 40 390.


Round 74 945 to the nearest ten.
74 945 ≈ <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
Round 74 945 to the nearest hundred.
74 945 ≈ <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

Nearest ten: the ones digit is 5, so round up the tens: 74 945 ≈ 74 950. Nearest hundred: the tens digit is 4 (less than 5), so round down: 74 945 ≈ 74 900.


A given number is a multiple of 7.
The number is between 50 and 60.
What is the number?
Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Multiples of 7: 49, 56, 63, ... The only one between 50 and 60 is 56 (7 × 8 = 56).


Arrange these fractions from the greatest to the smallest.
\(\dfrac{2}{3}\), \(\dfrac{5}{6}\), \(\dfrac{2}{5}\)
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />, <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />, <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />


Find the value of \(\dfrac{11}{12}-\dfrac{1}{4}\).<br>Give your answer in its simplest form.

Make the denominators the same: \(\dfrac{1}{4}=\dfrac{3}{12}\). Then \(\dfrac{11}{12}-\dfrac{3}{12}=\dfrac{8}{12}\). Simplify by dividing by 4: \(\dfrac{8}{12}=\dfrac{2}{3}\).


A shop had 162 boxes of mangoes. Each box had 36 mangoes.
(a) How many mangoes were there?
(b) The shop sold 738 mangoes. The rest of the mangoes were packed into bags of 9. How many bags of mangoes were packed?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) Total mangoes = 162 × 36 = 5832. (b) Mangoes left after selling = 5832 - 738 = 5094. Bags = 5094 ÷ 9 = 566.


Sam had some game cards at first. He gave 238 cards to his brother. Then he received 648 new cards from his father. Sam had 1330 cards in the end.
How many game cards did he have at first?
Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Work backwards from the end. Before receiving 648: 1330 - 648 = 682. Before giving away 238: 682 + 238 = 920. So Sam had 920 cards at first.


School A has 3064 story books in its library. School B has 4 times as many books as School A.
(a) How many more story books does School B have than School A?
(b) How many story books must be moved from School B to School A so that there will be the same number of books in both schools?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

School B = 3064 × 4 = 12 256 books. (a) More books in B than A = 12 256 - 3064 = 9192. (b) To make both equal, move half the difference: 9192 ÷ 2 = 4596 books.


A green bulb blinks every 4 minutes, and a red bulb blinks every 6 minutes.
(a) How many times will the red bulb blink in 48 minutes?
(b) The two light bulbs blink together at 8.00 p.m. for the first time. At what time will the two bulbs blink together for the second time?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) The red bulb blinks every 6 minutes, so in 48 minutes it blinks 48 ÷ 6 = 8 times. (b) The bulbs blink together at multiples of the LCM of 4 and 6, which is 12 minutes. After 8.00 p.m., the next time they blink together is 12 minutes later, at 8.12 p.m.


What is the value of the digit 7 in 38.479?

In 38.479, the digit 7 is in the hundredths place. Its value is 7 hundredths = 0.07.


Arrange the following decimals in decreasing order.<br>6.49 , 6.049 , 6.409 , 6.904


How many one-fifths are there in \(1\dfrac{3}{5}\)?

Convert \(1\dfrac{3}{5}\) to an improper fraction: \(1\dfrac{3}{5}=\dfrac{8}{5}\). So there are 8 one-fifths.


Cindy bought \(\dfrac{5}{8}\) kg of sugar. She bought \(\dfrac{1}{4}\) kg more flour than sugar. How many kilograms of flour did Cindy buy?


10 + 8 + 0.7 + <input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> + 0.009 = 18.749<br>What is the missing number?


Round 13.592 to the nearest whole number. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Look at the tenths digit (5). Since 5 \(\geq\) 5, round up: 13.592 rounds to 14.


What is the sum of 21.73 and 4.98? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

21.73 + 4.98 = 26.71. Line up the decimal points and add: 73 + 98 hundredths = 171 hundredths (carry), giving 26.71.


Arrange the following fractions in ascending order.
\(\dfrac{4}{7}\) , \(\dfrac{17}{12}\) , \(3\dfrac{1}{2}\) , \(\dfrac{1}{2}\)
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_1" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_2" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_3" class="fill-blank-input" placeholder="?" />


Ahmad had some stickers. He lost \(\dfrac{2}{5}\) of the stickers and had 27 stickers left. How many stickers did Ahmad have at first? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Stickers left = \(1-\dfrac{2}{5}=\dfrac{3}{5}\) of the total = 27. So \(\dfrac{1}{5}=27\div3=9\), and the total \(=9\times5=45\) stickers.


Mrs Tan bought some juice. She drank \(\dfrac{5}{12}\) \(l\) of juice and gave away \(\dfrac{1}{3}\) \(l\) of it. She was left with \(\dfrac{7}{12}\) \(l\) of juice.
(a) How many more litres of juice did she drink than she give away?
(b) How many litres of juice did Mrs Tan buy? Give your answer as a mixed number in simplest form.
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />


(a) Round 50 185 to the nearest ten.
(b) Round 38 273 to the nearest hundred.
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) The ones digit of 50 185 is 5, so round up: 50 190.<br>(b) The tens digit of 38 273 is 7, so round the hundreds up: 38 300.


Write the missing numerator and denominator.<br>\(\dfrac{<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />}{14}\) = \(\dfrac{3}{7}\) = \(\dfrac{9}{<input type="text" id="input_1" class="fill-blank-input" placeholder="?" />}\)

\(\dfrac{3}{7}\): multiply numerator and denominator by 2 to get a denominator of 14, so the numerator is 6 (\(\dfrac{6}{14}\)). For \(\dfrac{9}{[?]}\), 9 = 3 x 3, so multiply 7 by 3 to get 21 (\(\dfrac{9}{21}\)).


Find the value of \(\dfrac{2}{3}\) - \(\dfrac{1}{6}\)<br>Give your answer as a fraction in the simplest form.


Find the missing number.<br>67 852, 67 952, <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />, 68 152, 68 252, 68 352

The sequence increases by 100 each time: 67 852, 67 952, 68 052, 68 152, ... So the missing number is 68 052.


Arrange the following fractions from the greatest to the smallest.
\(\dfrac{5}{12}\) , \(\dfrac{2}{3}\) , \(\dfrac{1}{2}\)
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />   (c) <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />


Find the sum of all the common factors of 18 and 27. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


There were 1476 adults and children at a stadium. There were 874 adults and 28 more boys than girls. How many girls were at the stadium? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Mrs Koh paid $285 for 1 bag and 5 purses. The bag cost $57 more than a purse. How much did she pay for each purse? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Remove the bag's extra cost: 285 - 57 = 228, which is the cost of 6 purses (1 bag now equals 1 purse). Each purse = 228 / 6 = $38.


Mr Tan bought 5 chairs and 9 tables for his office. Each chair costs $354. He paid a total of $5874. How much did he pay in total for the tables? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Sherry bought the same amount of flour and sugar at first. After using 720 g of flour and 320 g of sugar, she had 6 times as much sugar as flour left. Find the amount of flour that she bought. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

She used 720 - 320 = 400 g more flour than sugar, so the sugar left is 400 g more than the flour left. Since sugar left is 6 times the flour left, the 5 extra units = 400 g, so 1 unit (flour left) = 400 / 5 = 80 g. Original flour = flour left + flour used = 80 + 720 = 800 g.


Ravi drank \(\dfrac{3}{4}\) \(\ell\) of water. His sister drank \(\dfrac{1}{5}\) \(\ell\) less water than he did. How much water did they drink altogether?


8974 ÷ 8 = <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

8974 ÷ 8: 8 into 89 is 11 r1; bring down 7 → 17, 8 into 17 is 2 r1; bring down 4 → 14, 8 into 14 is 1 r6. Quotient = 1121 remainder 6.


\(1\dfrac{5}{8}\) = \(\dfrac{<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />}{8}\) What is the missing value in the box?

Convert the mixed number to an improper fraction: \(1\dfrac{5}{8}=\dfrac{1\times8+5}{8}=\dfrac{13}{8}\). So the missing value is 13.


Arrange the fractions in decreasing order.
\(\dfrac{7}{3}\) , \(\dfrac{11}{5}\) , \(2\dfrac{2}{5}\)
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />   (c) <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />


There are 56 flowers in a basket. \(\dfrac{2}{7}\) of the flowers are roses. How many roses are there in the basket? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

7 units = 56, so 1 unit = 56 ÷ 7 = 8. Roses = 2 units = 8 × 2 = 16.


Kenneth cycled home from school. After completing \(\dfrac{7}{10}\) of the journey, he still needed to cycle another 480 m to reach home. What was the distance between Kenneth's home and his school? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

The remaining part of the journey is \(1-\dfrac{7}{10}=\dfrac{3}{10}\), which equals 480 m. So 3 units = 480 m, 1 unit = 480 ÷ 3 = 160 m. Whole journey = 10 units = 160 × 10 = 1600 m.


Denise, Emily and Fred scored a total of 4490 points in a game. Denise scored 3 times as many points as Emily. Fred scored 550 points less than Denise. How many points did Fred score? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Arthur and Ben had the same number of stickers at first. After Arthur gave 72 stickers to Caleb, Ben had 4 times as many stickers as Arthur.
(a) How many stickers did Arthur have left?
(b) Caleb gave \(\dfrac{4}{9}\) of the stickers he received from Arthur to his friends and kept the rest. How many stickers did Caleb keep for himself?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) Arthur and Ben started equal. After Arthur gives away 72, Ben = 4 × Arthur. The 72 stickers Arthur lost make Ben's amount the extra; the difference 72 equals 3 of Arthur's remaining units, so 3 units = 72, 1 unit = 24. Arthur had 24 stickers left. (b) Caleb received 72 stickers. He gave \(\dfrac{4}{9}\) away and kept \(\dfrac{5}{9}\): 1 unit = 72 ÷ 9 = 8, kept = 5 units = 8 × 5 = 40 stickers.


Express \(4\dfrac{7}{20}\) as a decimal. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Round 43.26 to the nearest tenth. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

The tenths digit is 2 and the hundredths digit is 6. Since 6 ≥ 5, round the tenths digit up: 43.26 → 43.3.


Divide 16 by 7. Give your answer correct to 2 decimal places. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

16 ÷ 7 = 2.2857... To 2 decimal places, look at the 3rd decimal (5), round up: 2.29.


Arrange these numbers from the greatest to the smallest.
\(\dfrac{2}{5}\) , 0.403 , 0.043
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />   (c) <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />


Megan receives a total of $30 of pocket money for 5 days. Each day, she spends $2.70 on transport, part of the remaining money on food and saves the rest.
(a) How much does Megan spend on transport in 5 days?
(b) Last week, Megan saved $1.80. How much did she spend on food?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) Transport in 5 days = $2.70 × 5 = $13.50. (b) Money left after transport = $30 − $13.50 = $16.50. Food = remaining − savings = $16.50 − $1.80 = $14.70.


Ken bought 5 kg of sugar. He used 0.32 kg of sugar to make a cake and packed the remaining sugar equally into 6 packets. What was the mass of each packet of sugar? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Remaining sugar = 5 − 0.32 = 4.68 kg. Each packet = 4.68 ÷ 6 = 0.78 kg.


Bag A contains 26.5 kg more peanuts than Bag B. After 4.55 kg of peanuts were removed from Bag B and placed into Bag A, the mass of Bag A was five times the mass of Bag B. What was the mass of peanuts in Bag B at first? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

After moving 4.55 kg, the difference between the bags becomes 26.5 + 2 × 4.55 = 35.6 kg. Bag A is now 5 times Bag B, so the difference is 4 units = 35.6 kg, giving 1 unit (Bag B now) = 35.6 ÷ 4 = 8.90 kg. Bag B at first = 8.90 + 4.55 = 13.45 kg.


Which of the following is thirteen thousand, eight hundred and fifty in numerals?


Arrange the following numbers from the smallest to the greatest.<br>47 209, 46 327, 46 825

Compare from the highest place value. Ten-thousands all 4; thousands: 46 327 and 46 825 have 6, 47 209 has 7, so 47 209 is largest. Between 46 327 and 46 825, hundreds 3 < 8, so 46 327 < 46 825. Smallest to greatest: 46 327, 46 825, 47 209.


In the following number pattern, what is the missing number?<br>12 878, 12 978, 13 978, 14 078, 15 078, , 16 178, 16 278


The hundreds digit is 5, so round up. 39 565 rounds up to 40 000 to the nearest thousand.


A number with both 3 and 4 as factors must be divisible by both. 24 = 3 × 8 = 4 × 6, so both 3 and 4 divide 24. (15 not divisible by 4; 32 not by 3; 38 not by 3 or 4.)


Which of the following number is a common multiple of 6 and 9?

A common multiple of 6 and 9 must be in both times tables. 36 = 6 × 6 = 9 × 4, so 36 is a multiple of both. (16 is neither; 42 = 6×7 but not a multiple of 9; 63 = 9×7 but not a multiple of 6.)


Mary had 3986 erasers. She gave 2013 erasers to her brother and 750 erasers to her sister. How many erasers had she left? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Erasers given away: 3986 - 2013 = 1973. Then 1973 - 750 = 1223. Mary had 1223 erasers left.


Mr Ahmad spends $346 each month. He spends the same amount of money each month. How much money does he spend in seven months? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Multiply the monthly amount by the number of months: 346 × 7 = 2422. He spends $2422 in seven months.


(a) Find the value of 1028 ÷ 4
(b) Find the product of 45 and 12
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) 1028 ÷ 4 = 257. (b) Product means multiply: 45 × 12 = 540.


The sum of two numbers is 7293. The greater number is 5485. What is the smaller number? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Smaller number = total - greater number = 7293 - 5485 = 1808.


30 012 people visited an exhibition. 22 800 of them were adults and the rest were children.
(a) How many children visited the exhibition?
(b) 10 740 women visited the exhibition. How many children and women visited the exhibition?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />


Shop A had 126 boxes of oranges. There were 36 oranges in each box. The shop owner packed the oranges into bags of 8. How many bags of 8 oranges were there? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Total oranges = 126 × 36 = 4536. Number of bags = 4536 ÷ 8 = 567. There were 567 bags.


A watch costs four times as much as a bag. Mr Tan paid $728 for a watch and three bags. How much did the watch cost? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Let 1 bag be 1 unit. Watch = 4 units. Watch + 3 bags = 4 + 3 = 7 units = $728. So 1 unit (1 bag) = 728 ÷ 7 = $104. Watch = 4 × 104 = $416.


Arrange the fractions in increasing order.
\(1\dfrac{5}{9}\) , \(\dfrac{15}{7}\) , \(1\dfrac{2}{3}\)
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_1" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />


Method: rename 7 as a fraction with denominator 5. \(7=\dfrac{35}{5}\). Then \(\dfrac{35}{5}-\dfrac{3}{5}=\dfrac{32}{5}=6\dfrac{2}{5}\).


Siti jogged \(\dfrac{4}{5}\) km. She jogged \(\dfrac{3}{10}\) km more than Tom. How far did Tom jog?

Method: Tom jogged less than Siti, so subtract. \(\dfrac{4}{5}=\dfrac{8}{10}\). Tom = \(\dfrac{8}{10}-\dfrac{3}{10}=\dfrac{5}{10}=\dfrac{1}{2}\) km.


Mrs Tan sold some red and yellow roses. \(\dfrac{2}{9}\) of the roses sold were red. The rest of the roses sold were yellow. 16 red roses were sold. How many yellow roses did Mrs Tan sell? <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Method: \(\dfrac{2}{9}\) of the roses are red = 16, so 1 unit (\(\dfrac{1}{9}\)) = 16 \(\div\) 2 = 8 roses. Yellow is the rest: \(\dfrac{9}{9}-\dfrac{2}{9}=\dfrac{7}{9}\) = 7 units. Yellow roses = 8 \(\times\) 7 = 56.


Jamie had 3 kg of flour. She used \(\dfrac{3}{10}\) kg of flour to bake a cake and \(\dfrac{1}{4}\) kg of flour to bake cookies.
a) What is the total mass of flour Jamie used?
b) What is the mass of flour left after baking the cake and cookies? (Express your answer as a mixed number.)
a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />


Gopal spent \(\dfrac{2}{11}\) of his money and saved the rest. He saved $749 more than the amount he spent. How much did he spend? <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Method: spent = \(\dfrac{2}{11}\) (2 units), saved = \(\dfrac{9}{11}\) (9 units). Saved is $749 more than spent: 9 units - 2 units = 7 units = $749. So 1 unit = 749 \(\div\) 7 = $107. Spent = 2 units = 2 \(\times\) 107 = $214.


The digit in the tens place is 3 (less than 5), so we round down. 47 832 rounds to 47 800.


Which of the following is not a factor of 18 and 36?

Factors of 18 are 1, 2, 3, 6, 9, 18. 12 is not a factor of 18 (it is a factor of 36 only), so 12 is not a common factor.


Which fraction is greater than \(\dfrac{1}{2}\)?


Find the product of 3021 and 7. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


What is the missing number in the box?<br>\(\dfrac{3}{4}\) = \(\dfrac{<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />}{20}\)

To get from denominator 4 to 20, multiply by 5. So the numerator is 3 × 5 = 15. \(\dfrac{3}{4} = \dfrac{15}{20}\).


Arrange the following fractions in decreasing order.
\(\dfrac{7}{4}\), \(\dfrac{4}{3}\), \(1\dfrac{5}{6}\)
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />, <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />, <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />


Amelie and Devna had the same number of sweets at first. After Amelie gave 35 sweets to her friends and Devna bought 7 more sweets, Devna had four times as many sweets as Amelie. How many sweets did Amelie have at the end? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Let the start amount be n. Amelie: n − 35. Devna: n + 7 = 4(n − 35). So n + 7 = 4n − 140, giving 147 = 3n, n = 49. Amelie at the end = 49 − 35 = 14. (Check: Devna = 49 + 7 = 56 = 4 × 14.)


Class 4A and 4B borrowed a total of 152 books in the month of May. Class 4A borrowed thrice as many books as Class 4B. Class 4B borrowed twice as many books as Class 4C. How many books did Class 4B and 4C borrow? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


(a) The smallest factor of a number is 1. The biggest factor of the number is 18. List all the other factors of the number.
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />, <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />, <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />, <input type="text" id="input_3" class="fill-blank-input" placeholder="?" />
(b) Wei Ming chose a number between 40 and 70. The number is a multiple of 7. When Janet added 2 to the number, it becomes a multiple of 5. What is the number that Wei Ming chose?
<input type="text" id="input_4" class="fill-blank-input" placeholder="?" />

(a) The number is 18 (its largest factor). Factors of 18 are 1, 2, 3, 6, 9, 18; excluding 1 and 18 the others are 2, 3, 6, 9. (b) Multiples of 7 between 40 and 70: 42, 49, 56, 63. Adding 2 gives 44, 51, 58, 65; only 65 is a multiple of 5, so the number is 63.


Benny has 345 stamps. Caius has 126 stamps. How many stamps must Benny give to Caius so that Benny has 37 more stamps than Caius? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Total stamps = 345 + 126 = 471 (unchanged when transferred). Current difference = 345 − 126 = 219. We want Benny to have 37 more than Caius, so the difference must drop from 219 to 37, a reduction of 219 − 37 = 182. Each stamp given reduces the gap by 2, so Benny gives 182 ÷ 2 = 91 stamps.


Fifty-eight thousand and thirty-nine in numerals is ____________.

Fifty-eight thousand = 58 000; thirty-nine = 39. So 58 000 + 39 = 58 039.


Which number when rounded to the nearest hundred becomes 72 000?

Rounding to the nearest hundred gives 72 000 for any number from 71 950 to 72 049. 71 952 rounds to 72 000. (71 839 to 71 800; 72 050 to 72 100; 72 499 to 72 500.)


Express \(6\dfrac{7}{20}\) as a decimal.


In which of the following does the digit 5 stand for 5 tenths?

5 tenths = 0.5, the first digit after the decimal point. In 27.53 the 5 is in the tenths place, so it stands for 5 tenths.


What is the missing number in the box?<br>\(8\dfrac{4}{9}=\dfrac{?}{9}\)


Noah had 6544 stamps. After giving away 408 stamps, he rearranged the remaining stamps equally into 8 albums. How many stamps were there in each album?


Which of the following is a common factor of 18 and 24?

Factors of 18: 1,2,3,6,9,18. Factors of 24: 1,2,3,4,6,8,12,24. The common factor among the options is 6.


Mrs Tan has fewer than 60 lollipops. She can pack them into bags of 3 or 8 without any lollipops left over. How many lollipops does Mrs Tan have?

The number must be a common multiple of 3 and 8, i.e. a multiple of 24, and fewer than 60. 48 is divisible by both 3 and 8 (48 = 3 x 16 = 8 x 6).


The perimeter of the garden is 42 m. The breadth of the garden is 6 m. What is the length of the garden?

Perimeter = 2 x (length + breadth). 42 = 2 x (length + 6), so length + 6 = 21, length = 15 m.


Which of the letter is a symmetrical figure?

The letter T has a vertical line of symmetry (left and right halves are mirror images). F, N and S have no line of symmetry.


Write the missing number in the number pattern.<br>34 456 , 34 756 , <input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> , 35 356 , 35 656


Find the product of 658 and 39. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


A number is 2900 when rounded off to the nearest ten. What is the smallest possible number? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Numbers from 2895 to 2904 round to 2900 to the nearest ten. The smallest is 2895.


Mary poured \(\dfrac{1}{3}\) \(l\) of juice from a jug for Peter and \(\dfrac{1}{9}\) \(l\) of juice for Tom. There was \(\dfrac{7}{9}\) \(l\) of juice left in the jug. How much juice was in the jug at first? Express your answer as a mixed number in its simplest form.


Write 39 thousandths as decimal. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


The difference between two numbers is 27 and their sum is 203. What is the smaller number? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Subtract the difference from the sum: 203 - 27 = 176. This is twice the smaller number, so smaller = 176 ÷ 2 = 88.


Amanda bought 624 balloons for her party. \(\dfrac{5}{8}\) of the balloons were blue and the rest were pink. How many more blue balloons than pink balloons were there? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

8 units = 624, so 1 unit = 624 ÷ 8 = 78. Blue = 5 units, pink = 3 units, difference = 2 units = 78 x 2 = 156.


The total number of red, yellow and green balls in a box is 2574. \(\dfrac{4}{9}\) of the balls are red. There are 68 more yellow balls than green balls. How many green balls are there in the box? <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Aini had 6 ten-dollar notes and 3 five-dollar notes. She spent $18.65 on food, $6.35 on a notebook and saved the rest of the money. What fraction of her money did she save? Give your answer in the simplest form.


A bookshop sold any 3 items for $5. To celebrate SG60, the bookshop gave away 1 free item for every 3 items bought.
(a) Anne shopped at the bookshop and left with a total of 72 items in her bag. How many free items did she get?
(b) Bala had $145, how many items will he bring home in total?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) Every group of 3 bought + 1 free = 4 items. 72 ÷ 4 = 18 groups, so 18 x 1 = 18 free items. (b) Bala's $145 buys 145 ÷ 5 = 29 sets of 3 items. Each set gives 3 bought + 1 free = 4 items, so 29 x 4 = 116 items in total.


A pen and a highlighter cost $4.20. 3 pens and 5 highlighters cost $17.40. Find the cost of a highlighter. <br>Answer: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

3 pens + 3 highlighters = 3 x $4.20 = $12.60. 3 pens + 5 highlighters = $17.40. Difference: 2 highlighters = $17.40 - $12.60 = $4.80, so 1 highlighter = $4.80 ÷ 2 = $2.40.


In the number 56 780, which digit is in the tens place?

Reading 56 780 from the right: 0 is ones, 8 is tens, 7 is hundreds, 6 is thousands, 5 is ten thousands. The digit in the tens place is 8.


In which of the following are the numbers arranged from the smallest to the greatest?<br>1053  1305  1035

Order the three numbers from smallest to greatest. Comparing the tens/ones: 1035 < 1053 < 1305. So the correct arrangement is 1035, 1053, 1305.


Which of the following is a multiple of both 4 and 7?

A multiple of both 4 and 7 is a multiple of 28. 56 = 28 x 2, and 56 = 4 x 14 = 7 x 8. So 56 is a multiple of both 4 and 7.


The number of pens in a shop is 4 times the number of rulers. There are 480 more pens than rulers in the shop. How many pens and rulers are there in the shop?

Pens = 4 units, rulers = 1 unit. Difference = 3 units = 480, so 1 unit = 160. Rulers = 160, pens = 640. Total pens and rulers = 160 + 640 = 800.


Timothy and Zachary bought 2350 stickers altogether. Timothy bought 80 stickers more than Zachary. How many stickers did Timothy buy?

Total = 2350. Remove the extra 80: 2350 - 80 = 2270, halve to get Zachary's share = 1135. Timothy = 1135 + 80 = 1215.


Mrs Tan bought 3 pizzas. She ate half of a pizza and gave \(\dfrac{1}{4}\) of a pizza to her daughter. How much pizza had Mrs Tan left?

She used half plus a quarter of a pizza: 1/2 + 1/4 = 3/4 of a pizza gone. Left = 3 - 3/4 = 2 and 1/4 pizzas.


There are 126 sheep and cows in a farm altogether. \(\dfrac{7}{9}\) of the animals are cows. How many sheep are there?

Cows are 7/9 of the animals, so sheep are 2/9. 126 / 9 = 14 per ninth. Sheep = 2 x 14 = 28.


The breadth of a rectangular piece of paper is 8 cm. Its perimeter is 96 cm. What is the length of the piece of paper?

Perimeter = 2 x (length + breadth). 96 / 2 = 48 = length + breadth. Length = 48 - 8 = 40 cm.


Alice had more storybooks than Ben at first. After Alice gave 14 storybooks to Ben, she had 29 more storybooks than him. How many more storybooks did Alice have than Ben at first?

Giving 14 books to Ben reduces Alice's lead by 2 x 14 = 28. After giving, the lead is 29, so originally the lead was 29 + 28 = 57.


1 ring file cost twice as much as 1 notepad. Danny paid $10.80 for 1 such ring file and 2 such notepads. Find the cost of 1 such notepad.

1 ring file = 2 notepads. So 1 ring file + 2 notepads = 2 + 2 = 4 notepad-units = $10.80. One notepad = 10.80 / 4 = $2.70.


The table shows the favourite snack of some boys and girls at a party. There was an equal number of boys and girls at the party. Each child chose only 1 favourite snack.
Popcorn Chicken: Boys 20, Girls 12
Cake: Boys 6, Girls 15
Burger: Boys ?, Girls 7
How many boys liked burger?

Total girls = 12 + 15 + 7 = 34. Boys equal girls, so total boys = 34. Boys who liked burger = 34 - 20 - 6 = 8.


Write forty thousand and eleven in numerals.<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Forty thousand = 40 000; eleven = 11. Combined: 40 000 + 11 = 40011.


Write 8 thousandths as a decimal.<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

The thousandths place is the 3rd place after the decimal point. 8 thousandths = 0.008.


What is the value of \(\dfrac{4}{5}+\dfrac{9}{10}\)? Express your answer as a mixed number.


Express \(\dfrac{3}{4}\) as a decimal.<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Write \(3\dfrac{3}{7}\) as an improper fraction.

Multiply the whole number by the denominator and add the numerator: 3 x 7 + 3 = 24. Keep the denominator 7: 24/7.


Some factors of 32 are 1, 2, 8 and 32. What are the other two factors of 32?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> and <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

Factors of 32 are 1, 2, 4, 8, 16, 32. Removing the given 1, 2, 8, 32 leaves 4 and 16.


Find the difference in value between 6.3 and 0.81.<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Arrange these fractions in decreasing order.
\(\dfrac{1}{2}\), \(\dfrac{5}{6}\), \(\dfrac{5}{9}\)
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />, <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />, <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />


Write the missing number in the number pattern below.<br>2628, 2828, 2808, 3008, <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />, 3188, 3168, 3368


A number has 2 decimal places. It is 4.0 when rounded to the nearest tenth. What is the greatest possible value of that number?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

To round to 4.0 (nearest tenth), the number must be from 3.95 up to 4.04 (since 4.05 rounds to 4.1). With 2 decimal places, the greatest value is 4.04.


Joseph is 3 times as heavy as Alice. Alice weighs 35.5 kg. What is the total mass of Joseph and Alice?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Linda, Mary and Nathan had a total of 264 stickers. Nathan had 24 more stickers than Mary. Linda had twice as many stickers as the total number of stickers Nathan and Mary had. How many more stickers did Linda have than Mary?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


There were some candies in a bag. Ethan took \(\dfrac{3}{8}\) of the candies, Fedrick took \(\dfrac{1}{3}\) of the candies and Germaine took the rest. Ethan took 12 more candies than Germaine.<br>(a) What fraction of the candies did Germaine take?

(a) Ethan + Fedrick = 3/8 + 1/3 = 9/24 + 8/24 = 17/24. Germaine took the rest = 1 - 17/24 = 7/24. (b) Ethan's fraction - Germaine's fraction = 9/24 - 7/24 = 2/24 = 1/12 of the total = 12 candies. So total = 12 x 12 = 144 candies.


In which of the following does the digit 6 stand for 600?

The digit 6 stands for 600 when 6 is in the hundreds place. In 7690, the 6 is in the hundreds place, so it stands for 600.


In which of the following are the numbers arranged from the smallest to the greatest?

Compare the numbers: 4089 < 4809 < 4890. Only option 4 lists them from smallest to greatest.


ABCD is a square with an area of 64 cm². Find the length of one side of the square.

Area of square = side × side. Side × side = 64, so side = 8 cm (since 8 × 8 = 64).


Ethan took \(\dfrac{3}{4}\) h to complete a puzzle. His sister completed the puzzle \(\dfrac{1}{6}\) h faster than him. How long did his sister take to complete the puzzle?


Round 39 520 to the nearest hundred.<br>39 520 ≈ <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

To round 39 520 to the nearest hundred, look at the tens digit (2). Since 2 < 5, round down: 39 520 ≈ 39 500.


\(\dfrac{3}{5}\) = \(\dfrac{12}{<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />}\)<br>What is the missing number in the box?

The numerator 3 becomes 12, multiplied by 4. So the denominator 5 must also be multiplied by 4: 5 × 4 = 20.


Find the value of 6.37 × 8<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


The sum of two numbers is 9081. The difference between the two numbers is 4523. What is the smaller number?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Smaller number = (sum − difference) ÷ 2 = (9081 − 4523) ÷ 2 = 4558 ÷ 2 = 2279.


A tank and 2 buckets contain 8.15 \(l\) of water. The volume of water in the tank is 3 times the volume of water in each bucket. What is the volume of water in each bucket?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> \(l\)

Tank = 3 units, 2 buckets = 2 units, total = 5 units = 8.15 l. 1 unit (one bucket) = 8.15 ÷ 5 = 1.63 l.


Mrs Toh had $33.60. After paying $7.80 for a packet of chocolate chip cookies, she had just enough money to buy 4 packets of butter cookies. How much did a packet of butter cookies cost?<br>$ <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Money left for butter cookies = 33.60 − 7.80 = 25.80. One packet = 25.80 ÷ 4 = $6.45.


Joseph and Kelvin started running at 11 45. Joseph took 1 h 10 min to complete his run. Kelvin took 30 minutes longer than Joseph. What time did Kelvin complete his run? Give your answer using the 24-hour clock.<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Kelvin's duration = 1 h 10 min + 30 min = 1 h 40 min. Starting at 1145: 1145 + 1 h = 1245, + 40 min = 1325. Kelvin completed his run at 1325.


\(\dfrac{4}{7}\) kg of flour is needed to bake 6 buns. Melvin has 3 kg of flour and he baked 12 buns. How much flour does he have left?


Elsie has 24 keychains and 32 bookmarks. She packed the keychains and bookmarks equally into gift bags with none left over. What is the greatest number of gift bags she can pack?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Find the highest common factor of 24 and 32. Factors of 24: 1,2,3,4,6,8,12,24. Factors of 32: 1,2,4,8,16,32. The greatest common factor is 8, so 8 gift bags.


Mrs Tan baked some muffins. \(\dfrac{4}{5}\) of the muffins were chocolate and the rest were vanilla. There were 240 more chocolate muffins than vanilla muffins. How many vanilla muffins did Mrs Tan bake?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Chocolate = \(\dfrac{4}{5}\) (4 units), vanilla = \(\dfrac{1}{5}\) (1 unit). Difference = 4 − 1 = 3 units = 240. 1 unit = 240 ÷ 3 = 80. Vanilla = 1 unit = 80 muffins.


Ali bought 455 boxes of pens. Each box contained 12 pens.
(a) How many pens did Ali buy altogether?
(b) Ali repacked the pens into packets of 8. How many pens were left unpacked?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) 455 × 12 = 5460 pens. (b) 5460 ÷ 8 = 682 remainder 4, so 4 pens are left unpacked.


Fatimah and Ben had 828 stamps altogether. After Fatimah gave 68 stamps to Ben, Ben had three times as many stamps as Fatimah.
(a) How many stamps did Fatimah have in the end?
(b) How many stamps did Ben have at first?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) After giving, total is still 828, split as Fatimah:Ben = 1:3 = 4 units. 1 unit = 828 ÷ 4 = 207. Fatimah had 207 stamps in the end. (b) Ben in the end = 3 × 207 = 621. Ben at first = 621 − 68 (the stamps he received) = 553.


Mr Chan bought a wallet, a belt and a shirt. The wallet cost twice as much as the belt. The shirt cost $6 less than the belt. He paid $90.80 in total.
(a) How much did the belt cost?
(b) How much did the wallet cost?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

Belt = 1 unit, wallet = 2 units, shirt = 1 unit − $6. Total = 4 units − 6 = 90.80, so 4 units = 96.80, 1 unit = 96.80 ÷ 4 = $24.20 (belt). (b) Wallet = 2 units = 2 × 24.20 = $48.40.


Samantha started doing her homework at 15 35. She took 1 h 5 min to complete her homework. After that, she swam till 18 10.
(a) How long did she swim? Give your answer in hours and minutes.
(b) Ken started doing his homework 50 minutes before Samantha started doing her homework. He took 1 h 25 min to complete. What time did he finish his homework? Give your answer using the 12-hour clock.
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) Samantha finished homework at 1535 + 1 h 5 min = 1640. She swam from 1640 to 1810 = 1 h 30 min. (b) Ken started 50 min before 1535 = 1445. He finished at 1445 + 1 h 25 min = 1610 = 4.10 pm.


Lisa spent \(\dfrac{4}{7}\) of her money on a mobile phone and $65 on a set of earphones. She had $190 left in the end. How much did the mobile phone cost?<br>$ <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Mobile phone = \(\dfrac{4}{7}\) (4 units), so remaining money = \(\dfrac{3}{7}\) (3 units). The 3 units = $65 + $190 = $255. 1 unit = 255 ÷ 3 = $85. Mobile phone = 4 units = 4 × 85 = $340.


Cheryl had $1253 and Fiona had $845. After each of them bought a bag at the same price, Cheryl had 5 times as much money as Fiona.
(a) How much more money does Cheryl have than Fiona at first?
(b) What was the cost of the bag?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) Difference at first = 1253 − 845 = $408. The difference stays the same after both spend the same amount. (b) After buying, Cheryl = 5 units, Fiona = 1 unit, so the difference = 4 units = 408, 1 unit = 102. Fiona has $102 left, so bag cost = 845 − 102 = $743.


The value of the digit 5 in 20 561 is ____________ .

In 20 561, the digit 5 is in the hundreds place. Its value is 5 hundreds = 500.


A number with both 3 and 5 as factors must be divisible by 3 and by 5. 15 = 3 × 5, so both 3 and 5 are factors of 15.


Arrange these decimals from the smallest to the greatest.<br>7.6 , 0.76 , 7.06 , 0.67

Compare whole-number parts first: 0.67 and 0.76 are less than 1; 7.06 and 7.6 are over 7. Order: 0.67, 0.76, 7.06, 7.6.


Mary used \(\dfrac{3}{8}\) of the beads to make necklaces and had 200 beads left. How many beads did Mary have at first?


Express 0.08 as a fraction in its simplest form.


Which two of the fractions below are smaller than \(\dfrac{1}{2}\) ?
\(\dfrac{7}{12}\) , \(\dfrac{3}{7}\) , \(\dfrac{2}{5}\) , \(\dfrac{5}{10}\)
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> and <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />


What is the value of \(\dfrac{5}{6}\) − \(\dfrac{2}{3}\) ?


8.7 − 0.88 = <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


In a class, \(\dfrac{3}{5}\) of the students are girls. There are 24 girls. How many boys and girls are there in the class?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

\(\dfrac{3}{5}\) of the class = 24 girls, so 1 unit (\(\dfrac{1}{5}\)) = 24 ÷ 3 = 8. Total class = 5 units = 8 × 5 = 40 students.


Arrange these numbers in decreasing order.
\(\dfrac{84}{100}\) , 0.8 , 0.804 , \(\dfrac{84}{10}\)
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_1" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_2" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_3" class="fill-blank-input" placeholder="?" />


A bag of sand had a mass of 109 kg. It was repacked into 7 sacks. What was the mass of each sack? Give your answer correct to 1 decimal place.<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> \(kg\)

109 ÷ 7 = 15.57... ≈ 15.6 kg (correct to 1 decimal place).


The table shows the amount of money Mr Tan spent in the month of June. The amount of money spent on leisure is not shown. Food $680 , Leisure ? , Transport $240. Mr Tan spent $300 more on food than on leisure. What was his total spending?<br>\(\)<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Jennifer poured 6 cups of orange juice into a jug. Each cup contained 270 ml of orange juice. How much orange juice were there in the jug? Give your answer in litres and millilitres.<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> \(l\) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" /> \(ml\)


Jerry watched a movie that ended at 01 25. The movie lasted for 2 h 30 min. What time did the movie start? Express your answer in 24-hour clock.<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Subtract 2 h 30 min from 01 25. 01 25 − 30 min = 00 55; 00 55 − 2 h = 22 55 (the previous day). Start time = 2255.


Jun Hao has $50. He has $16 less than Sue. Li Ann has 3 times as much money as Sue. How much money do they have in all?<br>\(\)<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Jane has more than 50 sweets but fewer than 100 sweets. When she gives 7 sweets to each of her friends, she will have no sweets left. When she gives 8 sweets to each of her friends, she will be short of 12 sweets. How many sweets does Jane have?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Giving 8 instead of 7 needs 1 more per friend; being short of 12 means there are 12 friends. Sweets = 7 × 12 = 84 (between 50 and 100).


Jenny has 2 kg of flour. She used \(\dfrac{3}{8}\) kg of the flour to bake a cake. She used \(\dfrac{1}{4}\) kg of the flour to bake some cookies.
(a) How much flour did she use to bake the cake and the cookies altogether?
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) How much flour did she have left? Express your answer as a mixed number.
<input type="text" id="input_1" class="fill-blank-input" placeholder="?" />


2 sandwiches and 2 drinks cost $9.30. 3 sandwiches and 1 drink cost $10.15. What is the cost of 1 sandwich?<br>\(\)<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Double the second set: 6 sandwiches + 2 drinks = $20.30. Subtract the first set (2 sandwiches + 2 drinks = $9.30): 4 sandwiches = $11.00. So 1 sandwich = 11 ÷ 4 = $2.75.


Kumar took part in a 6 km walk-and-run race. He ran 4 km 80 m and walked for the rest of the race.
(a) What was the total distance Kumar walked? Give your answer in kilometres and metres.
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> \(km\) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" /> \(m\)
(b) How much further did he run than walk?
<input type="text" id="input_2" class="fill-blank-input" placeholder="?" /> \(km\) <input type="text" id="input_3" class="fill-blank-input" placeholder="?" /> \(m\)

(a) Walked = 6 km − 4 km 80 m = 1 km 920 m. (b) Difference = 4 km 80 m − 1 km 920 m = 2 km 160 m.


Ali, Betty and Chandra had 993 stickers at first. Ali gave away 96 stickers. Betty bought another 48 stickers. In the end, Ali, Betty and Chandra had the same number of stickers. How many stickers did Betty have at first?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

After the changes the total = 993 − 96 + 48 = 945. Each ended with 945 ÷ 3 = 315. Betty ended with 315 after buying 48, so Betty had 315 − 48 = 267 at first.


Thirty-two thousand and forty-six in figures is

Thirty-two thousand = 32 000; forty-six = 46. Together: 32 046.


A fraction is in simplest form when numerator and denominator share no common factor other than 1. \(\dfrac{4}{10}=\dfrac{2}{5}\), \(\dfrac{2}{8}=\dfrac{1}{4}\), \(\dfrac{3}{6}=\dfrac{1}{2}\); only \(\dfrac{4}{9}\) cannot be reduced.


Sally had 1 m 10 cm of string. She used 25 cm of it to tie a parcel. What is the length of the string she had left?


Anna had 2 kg of sugar. She packed them equally into 5 bags. How much sugar was there in each bag?


Arrange the following fractions from the greatest to the smallest.<br>\(\dfrac{3}{4}\), \(\dfrac{1}{2}\), \(\dfrac{5}{8}\)


Arrange these numbers from the greatest to the smallest.
379, 937, 973, 397
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />   (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />   (c) <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />   (d) <input type="text" id="input_3" class="fill-blank-input" placeholder="?" />

Compare digit by digit from the hundreds place. Greatest to smallest: 973, 937, 397, 379.


Make like denominators: 1/4 = 2/8. Then 2/8 + 5/8 = 7/8.


Jerry bought a box containing 30 grapes. His brother ate 8 of them and his grandparents ate 16 of them. What fraction of the box of grapes had Jerry left? Give your answer in its simplest form.


The school reporting time for Tommy is 07 30. He left home for school at 06 00. He reached school 10 minutes earlier than his reporting time. How long did Tommy take to travel from his home to school?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> h <input type="text" id="input_1" class="fill-blank-input" placeholder="?" /> min

He arrived 10 min before 07 30, i.e. at 07 20. From 06 00 to 07 20 is 1 h 20 min.


A square has an area of 81 cm\(^2\). What is the perimeter of the square?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> cm

Side = square root of 81 = 9 cm. Perimeter = 9 x 4 = 36 cm.


Liam had the same number of marbles as Noah. After Liam gave Noah 18 marbles, Noah had 4 times as many marbles as Liam. How many marbles did Liam have in the end?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

After the transfer the total stays the same and Noah = 4 x Liam, so the total is 5 units. The difference Noah - Liam = 3 units, which equals 18 + 18 = 36 (Liam lost 18, Noah gained 18). So 3 units = 36, 1 unit = 12. Liam had 1 unit = 12 marbles in the end.


Maya mixed 13.59 \(l\) of water and 3.75 \(l\) of syrup to make lemonade. She then poured all the lemonade into identical bottles of 3 \(l\) each. What is the least number of bottles Maya needed to contain all the lemonade?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Total lemonade = 13.59 + 3.75 = 17.34 l. 17.34 / 3 = 5 remainder 2.34, so 5 full bottles plus 1 more for the leftover = 6 bottles.


A school printed a total of 4398 worksheets on Monday, Tuesday and Wednesday. It printed 1220 more worksheets on Monday than on Tuesday. The number of worksheets printed on Tuesday was 3 times the number of worksheets printed on Wednesday. How many worksheets were printed on Tuesday?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Let Wednesday = 1 unit, Tuesday = 3 units, Monday = 3 units + 1220. Total = 7 units + 1220 = 4398, so 7 units = 3178 and 1 unit = 454. Tuesday = 3 units = 3 x 454 = 1362 worksheets.


There is a total of 12 cars and vans in the car park. Each car can carry 5 passengers. Each van can carry 9 passengers. The 12 vehicles can carry 88 passengers altogether when all seats are filled. How many cars are there?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Assume all 12 are vans: 12 x 9 = 108. That is 108 - 88 = 20 too many. Each car instead of a van loses 9 - 5 = 4. So cars = 20 / 4 = 5 cars.


4 identical shirts and 3 identical bags cost $150.60. 2 such shirts and 1 such bag cost $62.80. Find the cost of 4 such shirts.<br>$<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Double the second equation: 4 shirts + 2 bags = $125.60. Subtract from the first (4 shirts + 3 bags = $150.60): 1 bag = $25. Then 2 shirts = 62.80 - 25 = $37.80, so 4 shirts = 37.80 x 2 = $75.60.


Jayden and Linda bought some apples. Jayden took \(\dfrac{5}{8}\) of the apples and Linda took the rest. Jayden took 36 more apples than Linda. (a) How many apples did Linda take? (b) The cost of 6 apples was $4. How much did the basket of apples cost?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) $<input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

Jayden = 5/8, Linda = 3/8, so the total is 8 units, Jayden 5 units, Linda 3 units. The difference 5 - 3 = 2 units = 36, so 1 unit = 18. (a) Linda = 3 units = 54 apples. (b) Total = 8 units = 144 apples. 6 apples = $4, so 144 apples cost (144/6) x 4 = $96.


The pattern increases by 6 each time: 8, 14, 20, 26, 32, 38. The two missing numbers are 26 and 32.


34 762 rounded to the nearest hundred is ____________.

Look at the tens digit (6). Since 6 is 5 or more, round the hundreds up: 34 762 rounds to 34 800.


In 56.87, the digit ____________ is in the tenths place.

The first digit after the decimal point is the tenths place. In 56.87 that digit is 8.


Arrange these fractions from the smallest to the greatest.<br>\(\dfrac{5}{9}\), \(\dfrac{1}{2}\), \(\dfrac{8}{9}\)


Mr Andrew bought 10 \(l\) of paint. He used 0.55 \(l\) of the paint on a door and 3.82 \(l\) of the paint on the walls of a bedroom. How much paint had he left?


Macy had 5 m of string at first. She used \(\dfrac{11}{12}\) m of string to make a kite. How much string did she have left?


Mr Tan has some pencils. The number of pencils can be shared equally among 4 or 7 children without remainder. It has 8 as one of its factors. How many pencils does Mr Tan have?

The number must be divisible by 4, by 7, and have 8 as a factor. 56 is divisible by 4 (56÷4=14), by 7 (56÷7=8) and by 8 (56÷8=7). So Mr Tan has 56 pencils.


Alan and Brian had an equal number of marbles at first. After Alan bought 36 more marbles and Brian gave away 24 marbles, Alan had 4 times as many marbles as Brian. How many marbles did each of them have at first?

Let each start with x. Alan now = x + 36, Brian now = x - 24. x + 36 = 4(x - 24) → x + 36 = 4x - 96 → 132 = 3x → x = 44. Each had 44 marbles at first.


Mrs Tan has a piece of ribbon 4 m long. She cuts 5 equal pieces from the ribbon and has 75 cm left. What is the length of each of the 5 pieces of ribbon?

4 m = 400 cm. Ribbon used for 5 pieces = 400 - 75 = 325 cm. Each piece = 325 ÷ 5 = 65 cm.


Write fifteen thousand and twenty-five in numerals.<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Fifteen thousand = 15 000; twenty-five = 25. Together: 15 025.


Two factors of 10 are 1 and 10. What are the other two factors of 10?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> and <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

10 = 2 × 5, so the other two factors of 10 are 2 and 5.


\(\dfrac{5}{6} = \dfrac{<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />}{12}\)<br>What is the missing number in the box?

Multiply numerator and denominator of \(\dfrac{5}{6}\) by 2: \(\dfrac{5 \times 2}{6 \times 2} = \dfrac{10}{12}\). The missing number is 10.


92 tenths − 48 hundredths. Express your answer as a decimal.<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Nadim completed his homework at 11 25. He took 1 h 45 min to complete his homework. What time did Nadim start doing his homework? Express your answer in 24-hour clock.<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Work backwards from 1125. Subtract 1 h to get 1025, then subtract 45 min to get 0940. Nadim started at 0940.


Mrs Lee bought a papaya and a durian. The mass of the papaya was \(\dfrac{9}{10}\) kg. It was \(\dfrac{1}{2}\) kg lighter than the mass of the durian. What was the mass of the durian? Express your answer as a mixed number in its simplest form.


The capacity of a tank is 12 \(l\). There is 875 m\(l\) of water in the tank. How much water must be added to fill the tank completely? Give your answer in litres and millilitres.<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> \(l\) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" /> m\(l\)


David has four times as many stamps as Ethan. Fiona has 60 fewer stamps than David. David, Ethan, and Fiona have a total of 1380 stamps. How many stamps does David have?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Let Ethan = 1 unit. David = 4 units. Fiona = 4 units - 60. Total = 1 + 4 + 4 units - 60 = 9 units - 60 = 1380, so 9 units = 1440, 1 unit = 160. David = 4 units = 4 × 160 = 640 stamps.


There were a total of 1785 fiction books and non-fiction books in a library. \(\dfrac{2}{7}\) of the books were non-fiction books and the rest were fiction books. How many more fiction books than non-fiction books were there?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Total = 7 units = 1785, so 1 unit = 255. Non-fiction = 2 units, fiction = 5 units. Difference = 5 - 2 = 3 units = 3 × 255 = 765 more fiction books.


Jane bought six identical bowls and five identical plates for $46.90. Mary bought three such bowls and three such plates for $25.20. How much did one plate cost?<br>\(\)<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

6 bowls + 5 plates = $46.90. Double Mary's purchase: 6 bowls + 6 plates = 2 × $25.20 = $50.40. Subtract: 1 plate = 50.40 - 46.90 = $3.50.


In which of the following are the numbers arranged from the smallest to the greatest?

Compare the numbers: 4189 < 4819 < 4891. Option 4 lists them smallest to greatest.


Which of the following is not a factor of 63?


The perimeter of a square is 64 m. Find the length of the square.

A square has 4 equal sides. Length = perimeter ÷ 4 = 64 ÷ 4 = 16 m.


A number, when divided by 8, gives a quotient of 123 and a remainder of 5. What is the number?

Number = divisor × quotient + remainder = 8 × 123 + 5 = 984 + 5 = 989.


The table shows the prices of highlighters and pens sold in a shop in June and July.
Highlighter: June $3.50, July $2.80. Pen: June $2.60, July $1.70.
Meiling bought 6 highlighters and 4 pens in June. Nancy bought 6 highlighters and 4 pens in July. How much more money did Meiling spend than Nancy?

Highlighters are $3.50 − $2.80 = $0.70 cheaper each in July; pens are $2.60 − $1.70 = $0.90 cheaper each. Meiling (June) spends more by 6 × $0.70 + 4 × $0.90 = $4.20 + $3.60 = $7.80.


How many one-sixths are there in 1 whole?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

1 whole = \(\dfrac{6}{6}\), which is 6 sixths. So there are 6 one-sixths in 1 whole.


Arrange these numbers from the greatest to the smallest.
0.078 , 0.807 , 0.708
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_1" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />

Compare tenths first: 0.807 (8 tenths) > 0.708 (7 tenths) > 0.078 (0 tenths). Greatest to smallest: 0.807, 0.708, 0.078.


\(0.4 = \dfrac{4}{<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />}\)<br>What is the missing number in the box?

0.4 means 4 tenths = \(\dfrac{4}{10}\). The missing denominator is 10.


The table shows the number of boys and girls in the school field and school hall during a recess. Complete the table.
Boys: School Field 127, School Hall (a), Total 315.
Girls: School Field 208, School Hall 50, Total (b).
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) Boys in hall = total boys − boys in field = 315 − 127 = 188. (b) Total girls = 208 + 50 = 258.


When a number is rounded to the nearest hundred, the answer is 1200.
(a) What is the smallest possible whole number?
(b) What is the greatest possible whole number?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

Numbers rounding to 1200 to the nearest hundred lie from 1150 up to 1249. (a) Smallest = 1150. (b) Greatest = 1249.


Linus wanted to pack 1504 apples. Each box could contain 5 apples. What was the least number of boxes Linus needed to pack all the apples?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

1504 ÷ 5 = 300 remainder 4. The 4 leftover apples still need 1 more box, so 300 + 1 = 301 boxes.


Harif spent $17.60 on a shirt. He spent $4.85 more on the shirt than on a pair of shorts. How much did Harif spend altogether?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


Jamilah drew a total of 30 squares and triangles. She drew a total of 108 sides. How many triangles did Jamilah draw?<br><input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Suppose all 30 are squares: 30 × 4 = 120 sides. Actual sides = 108, a shortfall of 120 − 108 = 12. Each triangle has 1 fewer side than a square (4 − 3 = 1), so number of triangles = 12 ÷ 1 = 12.


The total mass of 5 chickens and 2 ducks is 12.6 kg. The mass of a duck is 2 times as much as the mass of a chicken.
(a) Find the mass of 1 chicken.
(b) Find the total mass of 1 chicken and 1 duck.
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

Each duck = 2 chickens, so 2 ducks = 4 chickens. Total = 5 + 4 = 9 chicken-units = 12.6 kg, so 1 chicken = 12.6 ÷ 9 = 1.4 kg. (b) 1 duck = 1.4 × 2 = 2.8 kg; 1 chicken + 1 duck = 1.4 + 2.8 = 4.2 kg.


At a library, there were 7 times as many fiction books as non-fiction books. There were 3528 fiction books.
(a) How many more fiction books than non-fiction books were there at the library?
(b) How many books were there altogether in the library?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

Fiction = 7 units = 3528, so 1 unit (non-fiction) = 3528 ÷ 7 = 504. (a) More fiction than non-fiction = 6 units = 504 × 6 = 3024. (b) Altogether = 8 units = 504 × 8 = 4032.


There were 3 bottles of oil. All 3 bottles had the same amount of oil at first. \(\dfrac{1}{8}\) \(l\) of oil was poured from bottle A to bottle B. \(\dfrac{1}{2}\) \(l\) was then poured from bottle B to bottle C. There was \(\dfrac{5}{8}\) \(l\) of oil in bottle B in the end.
(a) What was the total amount of oil in bottles A, B and C at first?
(b) Each litre of oil cost $7.80. Find the cost of the total amount of oil in bottles A, B and C.
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />


There were 540 more girls than boys in a school hall. After \(\dfrac{3}{4}\) of the girls and \(\dfrac{1}{2}\) of the boys exited the hall, there was an equal number of boys and girls who remained behind in the hall.
(a) Find the total number of boys and girls who exited the hall.
(b) Find the total number of boys and girls who were in the hall at first.
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

Let boys = 2 units (so half remain = 1 unit) and girls = 4 units (so a quarter remain = 1 unit) to make the remainders equal. Girls − boys = 4u − 2u = 2u = 540, so 1 unit = 270. Boys = 540, girls = 1080. (a) Exited = half the boys + three-quarters of girls = 270 + 810 = 1080; equivalently 4 units = 270 × 4 = 1080. (b) Total at first = 6 units = 270 × 6 = 1620.


Lily baked 2425 more muffins than Jasmine at first. After Jasmine sold 1125 muffins, Lily had 6 times as many muffins as Jasmine in the end.
(a) How many muffins did Jasmine have in the end?
(b) How many muffins did Lily bake at first?
(a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

Lily is unchanged. In the end Lily = 6 units and Jasmine = 1 unit. Lily − Jasmine (end) = 5 units. The gap grew by the 1125 Jasmine sold: 2425 + 1125 = 3550 = 5 units, so 1 unit = 710. (a) Jasmine in the end = 1 unit = 710. (b) Lily = 6 units = 710 × 6 = 4260.


In 57.92, the digit ____________ is in the tenths place.

In 57.92 the first digit after the decimal point is the tenths place. That digit is 9.


Which of the following is <b>not</b> an equivalent fraction of \(\dfrac{1}{4}\)?

\(\dfrac{1}{4}\) equals 3/12, 4/16 and 6/24 (each numerator is one-quarter of the denominator). \(\dfrac{7}{32}\) is not, since 7 × 4 = 28 ≠ 32. So \(\dfrac{7}{32}\) is not equivalent.


A number with both 2 and 3 as factors must be divisible by 6. Among the options, 18 = 6 × 3 is divisible by both 2 and 3.


\(6\dfrac{3}{8}\) = \(\dfrac{\Box}{8}\)<br>What is the missing number in the box?

Convert the mixed number to an improper fraction: \(6\dfrac{3}{8}\) = (6 × 8 + 3)/8 = (48 + 3)/8 = \(\dfrac{51}{8}\). The missing number is 51.


Valerie mixed 17.82 \(l\) of water and 5.18 \(l\) of orange syrup to make some orange juice. She poured the orange juice equally into 8 similar jugs. How much orange juice did she pour into each jug? Round your answer to the nearest tenth.

Total juice = 17.82 + 5.18 = 23 l. Each jug = 23 ÷ 8 = 2.875 l. Rounded to the nearest tenth = 2.9 l.


Amy took \(\dfrac{7}{12}\) h to fix a jigsaw puzzle. Jenny took \(\dfrac{2}{3}\) h slower to fix the same jigsaw puzzle. How long did Jenny take to fix the puzzle? Express your answer in the simplest form.


Which of the following letters has at least one line of symmetry?

The letter C has a horizontal line of symmetry (top and bottom halves mirror each other). G, N and K have no line of symmetry.


Bala is arranging stickers on a display board. He has more than 20 stickers but fewer than 50 stickers. When he arranges them in rows of 6, there are 4 stickers left over. When he arranges them in rows of 8, there are 2 stickers left over. How many stickers does Bala have?

Need a number 20–50 that leaves remainder 4 when divided by 6 and remainder 2 when divided by 8. Check 34: 34 ÷ 6 = 5 r4 ✓ and 34 ÷ 8 = 4 r2 ✓. So Bala has 34 stickers.


Write twenty thousand and forty-one in numerals.<br>Ans: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Twenty thousand = 20 000, and forty-one = 41. Combine: 20 000 + 41 = 20 041.


Arrange these fractions from the smallest to the greatest.
\(\dfrac{8}{11}\) , \(\dfrac{1}{2}\) , \(\dfrac{5}{11}\)
Ans: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> (smallest) , <input type="text" id="input_1" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_2" class="fill-blank-input" placeholder="?" /> (greatest)


Round 18 430 to the nearest hundred.<br>Ans: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />

Look at the tens digit of 18 430, which is 3. Since 3 < 5, round down: 18 430 → 18 400.


Janice bought a roll of ribbon, 3 m long, to wrap some presents. She cut the roll of ribbon into 7 equal pieces. What is the length of each piece of ribbon? Round your answer to the nearest hundredth.<br>Ans: <input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> m

Each piece = 3 ÷ 7 = 0.428... m. Rounded to the nearest hundredth (2 decimal places) = 0.43 m.


Gladys jogged a distance of \(\dfrac{2}{3}\) km. She jogged \(\dfrac{1}{5}\) km more than the distance jogged by Ben. What was the total distance Gladys and Ben jogged? Give your answer as a mixed number.


Weiling bought 24 packets of sweets. There were 32 sweets in each packet. She gave 12 sweets to each of her 40 classmates.
(a) How many sweets did Weiling buy altogether?
Ans: (a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) How many sweets were left?
Ans: (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

(a) Total bought = 24 × 32 = 768 sweets. (b) Sweets given away = 12 × 40 = 480. Sweets left = 768 − 480 = 288.


Farid baked some cookies. He gave away \(\dfrac{3}{10}\) of his cookies to his friends and gave away \(\dfrac{1}{2}\) of his cookies to his siblings. He had 50 cookies left.<br>(a) What fraction of Farid's cookies was left?


Sarah had twice as many blue beads as red beads. She had 3 times as many green beads as blue beads. She had a total of 1728 blue and green beads.
(a) How many green beads did Sarah have?
Ans: (a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" />
(b) How many fewer red beads than green beads did Sarah have?
Ans: (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" />

Let red = 1 unit. Blue = 2 units, green = 3 × blue = 6 units. Blue + green = 2 + 6 = 8 units = 1728, so 1 unit = 1728 ÷ 8 = 216. (a) Green = 6 units = 6 × 216 = 1296. (b) Red = 1 unit = 216, so green − red = 1296 − 216 = 1080.


The total mass of 3 identical tables and 5 identical stools is 173.1 kg. The total mass of 1 such table and 3 such stools is 65.3 kg.
(a) What is the total mass of a table and a stool?
Ans: (a) <input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> kg
(b) What is the mass of 4 stools?
Ans: (b) <input type="text" id="input_1" class="fill-blank-input" placeholder="?" /> kg

(a) 3 tables + 5 stools = 173.1; 1 table + 3 stools = 65.3. Tripling the second: 3 tables + 9 stools = 195.9. Subtract the first: 4 stools = 195.9 − 173.1 = 22.8 kg, so 1 stool = 5.7 kg. From the second: 1 table = 65.3 − 3 × 5.7 = 65.3 − 17.1 = 48.2 kg. Table + stool = 48.2 + 5.7 = 53.9 kg. (b) 4 stools = 4 × 5.7 = 22.8 kg.


a) Arrange the following fractions in decreasing order.
\(\dfrac{3}{4}\) , \(\dfrac{1}{3}\) , \(\dfrac{7}{12}\)
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_1" class="fill-blank-input" placeholder="?" /> , <input type="text" id="input_2" class="fill-blank-input" placeholder="?" />
b) Find the value of \(3 - \dfrac{5}{6}\)
<input type="text" id="input_3" class="fill-blank-input" placeholder="?" />


Cookies are sold in packets of 6. Each packet of cookies costs $5. Mdm Rani bought a total of 72 cookies altogether. How much did she pay?<br>$<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />


The table shows the number of boys and girls from Classes 4A and 4B who went on a learning journey.
Class 4A: 21 boys, 15 girls, total 36. Class 4B: ? boys, 17 girls, total 41.
Find the total number of boys who went for the learning journey.
<input type="text" id="input_0" class="fill-blank-input" placeholder="?" />