{
  "paper": {
    "school": "Catholic High",
    "year": 2025,
    "level": "P4",
    "label": "Weighted Assessment 3",
    "source_prefix": "Catholic High 2025 P4 Weighted Assessment 3",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "Which digit in $$17.48$$ is in the tenths place?",
      "answer0": "1",
      "answer1": "7",
      "answer2": "8",
      "answer3": "4",
      "correct_answer": 3,
      "skill_id": 123,
      "difficulty_id": 1,
      "explanation": "In $$17.48$$ the digit right after the decimal point is the tenths place. That digit is $$4$$. (The $$8$$ is in the hundredths place.) Answer: $$4$$.",
      "hints": ["The first digit after the decimal point is the tenths place.", "$$17.48$$: tens=1, ones=7, tenths=4, hundredths=8."],
      "source": "Catholic High 2025 P4 Weighted Assessment 3 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 4 (value 4)."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "Express $$6\\frac{7}{25}$$ as a decimal.",
      "answer0": "6.07",
      "answer1": "6.25",
      "answer2": "6.28",
      "answer3": "6.70",
      "correct_answer": 2,
      "skill_id": 127,
      "difficulty_id": 2,
      "explanation": "Convert $$\\frac{7}{25}$$ to hundredths: $$\\frac{7}{25}=\\frac{7\\times4}{25\\times4}=\\frac{28}{100}=0.28$$. So $$6\\frac{7}{25}=6.28$$. Answer: $$6.28$$.",
      "hints": ["Make the denominator 100: $$25\\times4=100$$.", "$$\\frac{28}{100}=0.28$$, then add the whole number 6."],
      "source": "Catholic High 2025 P4 Weighted Assessment 3 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 3 (value 6.28)."
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "ABCD is a rectangle. $$\\angle EDF$$ is $$34°$$ and $$\\angle FDC$$ is $$14°$$. Find $$\\angle ADE$$.",
      "answer0": "42°",
      "answer1": "48°",
      "answer2": "56°",
      "answer3": "76°",
      "correct_answer": 0,
      "skill_id": 143,
      "difficulty_id": 2,
      "explanation": "The corner of a rectangle is a right angle, so $$\\angle ADC=90°$$. This angle is split into $$\\angle ADE+\\angle EDF+\\angle FDC$$. So $$\\angle ADE=90°-34°-14°=42°$$. Answer: $$42°$$.",
      "hints": ["Each corner angle of a rectangle is $$90°$$.", "$$\\angle ADE=90°-\\angle EDF-\\angle FDC$$."],
      "source": "Catholic High 2025 P4 Weighted Assessment 3 Q3",
      "image_needed": true,
      "image_options": false,
      "image_file": "q3.png",
      "image_page": 2,
      "image_bbox": [0.30, 0.13, 0.60, 0.27],
      "image_loc": "top of page, below the question — rectangle ABCD with lines from D to E and F",
      "notes": "Key: option 1 (value 42°)."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "The number line is marked at equal intervals. What decimal is represented by the letter G on the number line?",
      "answer0": "8.007",
      "answer1": "8.017",
      "answer2": "8.07",
      "answer3": "8.17",
      "correct_answer": 1,
      "skill_id": 123,
      "difficulty_id": 2,
      "explanation": "From $$8.01$$ to $$8.02$$ is $$0.01$$, divided into 10 equal intervals, so each interval is $$0.001$$. G is 7 intervals from $$8.01$$: $$8.01+7\\times0.001=8.017$$. Answer: $$8.017$$.",
      "hints": ["Find the gap between $$8.01$$ and $$8.02$$ and divide by the number of intervals.", "Each small step is $$0.001$$; count steps from $$8.01$$ to G."],
      "source": "Catholic High 2025 P4 Weighted Assessment 3 Q4",
      "image_needed": true,
      "image_options": false,
      "image_file": "q4.png",
      "image_page": 2,
      "image_bbox": [0.30, 0.44, 0.78, 0.50],
      "image_loc": "middle of page, below the question — horizontal number line from 8.01 to 8.02 with G marked near the right",
      "notes": "Key: option 2 (value 8.017)."
    },
    {
      "n": 5,
      "type_id": 2,
      "question": "Round $$39.95$$ to 1 decimal place.",
      "answer0": "40.0",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 128,
      "difficulty_id": 2,
      "explanation": "To round to 1 decimal place, look at the hundredths digit. $$39.95$$ has hundredths digit $$5$$, so round the tenths up: $$39.9\\to40.0$$. Answer: $$40.0$$.",
      "hints": ["Look at the 2nd decimal place (hundredths) to decide.", "Hundredths digit is $$5$$, so round up; $$39.95\\to40.0$$."],
      "source": "Catholic High 2025 P4 Weighted Assessment 3 Q5",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 40.0."
    },
    {
      "n": 6,
      "type_id": 2,
      "question": "Complete the number pattern.<br>$$7.38, 7.48, 7.47, 7.57, 7.56, 7.66,$$ [?] $$, 7.75, 7.74, 7.84$$",
      "answer0": "7.65",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 108,
      "difficulty_id": 3,
      "explanation": "The pattern alternates: +0.10 then -0.01. $$7.38(+0.10)7.48(-0.01)7.47(+0.10)7.57(-0.01)7.56(+0.10)7.66(-0.01)\\mathbf{7.65}(+0.10)7.75(-0.01)7.74(+0.10)7.84$$. The missing term is $$7.66-0.01=7.65$$. Answer: $$7.65$$.",
      "hints": ["Look at the change between each pair of terms — it alternates.", "After $$7.66$$ the next step subtracts $$0.01$$: $$7.66-0.01=7.65$$."],
      "source": "Catholic High 2025 P4 Weighted Assessment 3 Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 7.65."
    },
    {
      "n": 7,
      "type_id": 2,
      "question": "In a class of 40, the pupils participated in different Co-Curricular Activities. Each pupil only participated in 1 Co-Curricular Activity. The pie chart shows their participation. What fraction of the pupils in the class participated in Choir?",
      "answer0": "1/8",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 236,
      "difficulty_id": 2,
      "explanation": "Art is $$\\frac{3}{8}$$. Basketball, Choir and Scouts make up the rest. The right angle at the centre marks Basketball = $$\\frac{2}{8}$$ (quarter) and Scouts = $$\\frac{2}{8}$$. So Art+Basketball+Scouts $$=\\frac{3}{8}+\\frac{2}{8}+\\frac{2}{8}=\\frac{7}{8}$$. Choir $$=1-\\frac{7}{8}=\\frac{1}{8}$$. Answer: $$\\frac{1}{8}$$.",
      "hints": ["The whole pie is $$1$$ (or $$\\frac{8}{8}$$).", "Add the known parts, then subtract from $$1$$: $$1-\\frac{7}{8}=\\frac{1}{8}$$."],
      "source": "Catholic High 2025 P4 Weighted Assessment 3 Q7",
      "image_needed": true,
      "image_options": false,
      "image_file": "q7.png",
      "image_page": 4,
      "image_bbox": [0.36, 0.16, 0.66, 0.36],
      "image_loc": "top-centre of page — pie chart with Art (3/8), Basketball, Choir and Scouts sectors and a right-angle mark at the centre",
      "notes": "Key: 1/8. FIB fraction answer kept plain a/b."
    },
    {
      "n": 8,
      "type_id": 2,
      "question": "In a class of 40, the pupils participated in different Co-Curricular Activities. Each pupil only participated in 1 Co-Curricular Activity. The pie chart shows their participation. How many pupils in the class participated in Basketball?",
      "answer0": "10",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 236,
      "difficulty_id": 2,
      "explanation": "Basketball is the right-angle (quarter) sector, so it is $$\\frac{2}{8}=\\frac{1}{4}$$ of the class. $$\\frac{1}{4}$$ of 40 $$=40\\div4=10$$ pupils. (Key working: $$40\\div8=5$$, $$5\\times2=10$$.) Answer: $$10$$.",
      "hints": ["The right-angle sector is a quarter of the circle.", "$$\\frac{1}{4}$$ of $$40=40\\div4=10$$."],
      "source": "Catholic High 2025 P4 Weighted Assessment 3 Q8",
      "image_needed": true,
      "image_options": false,
      "image_file": "q8.png",
      "image_page": 4,
      "image_bbox": [0.36, 0.16, 0.66, 0.36],
      "image_loc": "top-centre of page — same pie chart as Q7 (Art 3/8, Basketball, Choir, Scouts; right-angle at centre)",
      "notes": "Key: 10. Shares the Q7 pie chart figure."
    },
    {
      "n": 9,
      "type_id": 0,
      "question": "In the square grid, line AB and line BC form half of a rectangle. Draw 2 lines to complete the rectangle ABCD. Label rectangle ABCD.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 143,
      "difficulty_id": 2,
      "explanation": "AB and BC are two adjacent sides of a (tilted) rectangle. To complete it, draw CD parallel and equal to BA, and DA parallel and equal to BC, meeting at vertex D. The key diagram places D above A so that ABCD is a rectangle with the right angle preserved at each vertex.",
      "hints": ["Opposite sides of a rectangle are equal and parallel.", "From A draw a line equal/parallel to BC, and from C a line equal/parallel to BA; they meet at D."],
      "source": "Catholic High 2025 P4 Weighted Assessment 3 Q9",
      "image_needed": true,
      "image_options": false,
      "image_file": "q9.png",
      "image_page": 5,
      "image_bbox": [0.34, 0.14, 0.62, 0.36],
      "image_loc": "top-centre of page — square grid with points A, B, C marked and lines AB, BC drawn",
      "notes": "Interactive draw-and-label task — no value answer, so type_id 0 (skipped on insert). Key shows the completed tilted rectangle ABCD with D placed up-left of C."
    },
    {
      "n": 10,
      "type_id": 2,
      "question": "A water bottle contained $$1.2$$ $$l$$ of water. It contained $$2.5$$ $$l$$ less water than a kettle. How much water was there in 4 such kettles?",
      "answer0": "14.8",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 131,
      "difficulty_id": 2,
      "explanation": "One kettle holds $$1.2+2.5=3.7$$ $$l$$ (the bottle has 2.5 l less than a kettle). For 4 kettles: $$3.7\\times4=14.8$$ $$l$$. Answer: $$14.8$$ $$l$$.",
      "hints": ["A kettle has more than the bottle, so add: $$1.2+2.5$$.", "Multiply one kettle's amount by 4."],
      "source": "Catholic High 2025 P4 Weighted Assessment 3 Q10",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 14.8 (litres). Answer in litres."
    },
    {
      "n": 11,
      "type_id": 2,
      "question": "Mrs Tan had $$7.86$$ $$kg$$ of flour less than Mrs Siva. After Mrs Siva used $$10$$ $$kg$$ of flour, Mrs Tan had 3 times as much flour as Mrs Siva had left.<br>(a) How many more kilograms of flour did Mrs Tan have than Mrs Siva in the end? [?]<br>(b) How many kilograms of flour did Mrs Siva have left? [?]",
      "answer0": "2.14",
      "answer1": "1.07",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 129,
      "difficulty_id": 3,
      "explanation": "(a) Mrs Tan's amount is unchanged. At the start Mrs Siva had $$7.86$$ kg more than Mrs Tan; after using $$10$$ kg, Mrs Siva is now $$10-7.86=2.14$$ kg less than Mrs Tan. So Mrs Tan has $$2.14$$ kg more than Mrs Siva in the end. (b) In the end Tan = 3 × Siva, so the difference (Tan − Siva) = 2 units = $$2.14$$ kg, giving 1 unit = Siva = $$2.14\\div2=1.07$$ kg. Answers: (a) $$2.14$$ kg, (b) $$1.07$$ kg.",
      "hints": ["Mrs Tan's flour never changes; only Mrs Siva uses 10 kg.", "End difference = $$10-7.86=2.14$$ kg. Since Tan = 3×Siva, that 2.14 kg = 2 equal units, so Siva's left = $$2.14\\div2$$."],
      "source": "Catholic High 2025 P4 Weighted Assessment 3 Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: (a) 2.14 kg, (b) 1.07 kg. Two answer blanks (answer0=part a, answer1=part b)."
    }
  ]
}