{
 "paper": {
  "school": "Maha Bodhi",
  "year": 2024,
  "level": "P4",
  "label": "Weighted Assessment 2",
  "source_prefix": "Maha Bodhi 2024 P4 Weighted Assessment 2",
  "has_answer_key": true
 },
 "questions": [
  {
   "n": 1,
   "type_id": 1,
   "question": "What is the size of ∠FEG?",
   "answer0": "45°",
   "answer1": "55°",
   "answer2": "135°",
   "answer3": "145°",
   "correct_answer": 1,
   "skill_id": 140,
   "difficulty_id": 2,
   "explanation": "Read the protractor along the ray EG. EF lies on the 0° line and ray EG passes through the 55° mark on the inner scale (measured from EF). So ∠FEG = 55°.",
   "hints": [
    "EF lies along the base (0°) of the protractor.",
    "Read the scale where ray EG crosses, starting from 0° at F."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q1",
   "image_needed": true,
   "image_options": false,
   "image_file": "q1.png",
   "image_page": 1,
   "image_bbox": [
    0.2,
    0.5,
    0.92,
    0.74
   ],
   "image_loc": "protractor diagram in the middle of the page with rays D-E-F and G",
   "notes": "Answer key Q1 = option 2 (55°)."
  },
  {
   "n": 2,
   "type_id": 1,
   "question": "How many eighths are there in $$3\\frac{7}{8}$$?",
   "answer0": "7",
   "answer1": "10",
   "answer2": "24",
   "answer3": "31",
   "correct_answer": 3,
   "skill_id": 119,
   "difficulty_id": 1,
   "explanation": "Convert the mixed number to an improper fraction with denominator 8: $$3\\frac{7}{8} = \\frac{3\\times8 + 7}{8} = \\frac{31}{8}$$. So there are 31 eighths.",
   "hints": [
    "3 wholes = $$\\frac{24}{8}$$ (3 × 8 eighths).",
    "Add the extra 7 eighths to 24 eighths."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q2",
   "image_needed": false,
   "image_options": false,
   "image_file": null,
   "notes": "Answer key Q2 = option 4 (31)."
  },
  {
   "n": 3,
   "type_id": 1,
   "question": "The diagram shows a rectangle ABEF and a square BCDE. Which of the following shows a correct pair of parallel lines?",
   "answer0": "AC // AF",
   "answer1": "BC // FD",
   "answer2": "FE // BE",
   "answer3": "CD // ED",
   "correct_answer": 1,
   "skill_id": 100,
   "difficulty_id": 2,
   "explanation": "ABEF is a rectangle and BCDE a square sitting side by side, so the top edge ABC and the bottom edge FED are two straight parallel lines. BC is part of the top edge and FD is part of the bottom edge, so BC // FD. The other pairs meet or lie on the same line, so they are not parallel.",
   "hints": [
    "The top line A-B-C is parallel to the bottom line F-E-D.",
    "Look for two segments lying on those two parallel edges."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q3",
   "image_needed": true,
   "image_options": false,
   "image_file": "q3.png",
   "image_bbox": [
    0.27,
    0.34,
    0.66,
    0.47
   ],
   "image_loc": "rectangle-and-square diagram with vertices A B C across top and F E D across bottom",
   "notes": "Answer key Q3 = option 2 (BC // FD)."
  },
  {
   "n": 4,
   "type_id": 1,
   "question": "Mrs Chua cut a cake into 12 equal slices. She gave $$\\frac{1}{2}$$ of the cake to her neighbour and 4 slices to her daughter. How many slices of cake was left?",
   "answer0": "10",
   "answer1": "2",
   "answer2": "6",
   "answer3": "8",
   "correct_answer": 1,
   "skill_id": 120,
   "difficulty_id": 2,
   "explanation": "$$\\frac{1}{2}$$ of 12 slices = 6 slices to the neighbour. Daughter got 4 slices. Slices given away = 6 + 4 = 10. Slices left = 12 − 10 = 2.",
   "hints": [
    "Half of 12 slices is 6 slices.",
    "Subtract the neighbour's 6 and the daughter's 4 from 12."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q4",
   "image_needed": false,
   "image_options": false,
   "image_file": null,
   "notes": "Answer key Q4 = option 2 (2 slices)."
  },
  {
   "n": 5,
   "type_id": 1,
   "question": "Packet A contains $$\\frac{3}{4}$$ kg of salt. It has $$\\frac{1}{3}$$ kg more salt than Packet B. What is the total mass of salt in Packet A and B?",
   "answer0": "$$1\\frac{1}{6}$$ kg",
   "answer1": "$$1\\frac{5}{6}$$ kg",
   "answer2": "$$1\\frac{1}{12}$$ kg",
   "answer3": "$$1\\frac{5}{12}$$ kg",
   "correct_answer": 0,
   "skill_id": 122,
   "difficulty_id": 3,
   "explanation": "Packet B = $$\\frac{3}{4} - \\frac{1}{3} = \\frac{9}{12} - \\frac{4}{12} = \\frac{5}{12}$$ kg. Total = $$\\frac{3}{4} + \\frac{5}{12} = \\frac{9}{12} + \\frac{5}{12} = \\frac{14}{12} = 1\\frac{2}{12} = 1\\frac{1}{6}$$ kg.",
   "hints": [
    "A has more salt, so B = A − $$\\frac{1}{3}$$.",
    "Use a common denominator of 12 to add and subtract."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q5",
   "image_needed": false,
   "image_options": false,
   "image_file": null,
   "notes": "Answer key Q5 = option 1 (1 1/6 kg)."
  },
  {
   "n": 6,
   "type_id": 2,
   "question": "Arrange the fractions in increasing order.<br>$$\\frac{7}{3}$$, $$\\frac{5}{6}$$, $$2\\frac{1}{4}$$<br>[?], [?], [?]",
   "answer0": "5/6",
   "answer1": "2 1/4",
   "answer2": "7/3",
   "answer3": null,
   "correct_answer": null,
   "skill_id": 79,
   "difficulty_id": 2,
   "explanation": "Compare values: $$\\frac{5}{6} \\approx 0.83$$, $$2\\frac{1}{4} = 2.25$$, $$\\frac{7}{3} \\approx 2.33$$. Increasing order: $$\\frac{5}{6}$$, $$2\\frac{1}{4}$$, $$\\frac{7}{3}$$.",
   "hints": [
    "Convert each to a decimal to compare easily.",
    "$$\\frac{7}{3} = 2\\frac{1}{3}$$, which is just larger than $$2\\frac{1}{4}$$."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q6",
   "image_needed": false,
   "image_options": false,
   "image_file": null,
   "notes": "Answer key Q6 lists 5/6, 2 1/4, 7/3 (the leading '6/5' on the key is a marker typo for 5/6)."
  },
  {
   "n": 7,
   "type_id": 2,
   "question": "Find the sum of $$\\frac{9}{10}$$ and $$\\frac{4}{5}$$. Express your answer as a mixed number in its simplest form.<br>[?]",
   "answer0": "1 7/10",
   "answer1": null,
   "answer2": null,
   "answer3": null,
   "correct_answer": null,
   "skill_id": 121,
   "difficulty_id": 2,
   "explanation": "$$\\frac{4}{5} = \\frac{8}{10}$$. Sum = $$\\frac{9}{10} + \\frac{8}{10} = \\frac{17}{10} = 1\\frac{7}{10}$$.",
   "hints": [
    "Change $$\\frac{4}{5}$$ to tenths.",
    "Add the numerators over 10, then write as a mixed number."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q7",
   "image_needed": false,
   "image_options": false,
   "image_file": null,
   "notes": "Answer key Q7 = 1 7/10."
  },
  {
   "n": 8,
   "type_id": 1,
   "question": "Name an angle that is smaller than a right angle.",
   "answer0": "∠BCD",
   "answer1": "∠AED",
   "answer2": "∠EAB",
   "answer3": "∠ABC",
   "correct_answer": 0,
   "skill_id": 139,
   "difficulty_id": 2,
   "explanation": "The figure is a pentagon ABCDE shaped like an arrow/house pointing right at C. The angle at C, ∠BCD, is the pointed vertex which is acute (smaller than 90°). The angles at A and E are right angles and those at B and D are obtuse (reflex of the point).",
   "hints": [
    "An angle smaller than a right angle is acute (less than 90°).",
    "Look at the sharp pointed corner of the figure."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q8",
   "image_needed": true,
   "image_options": false,
   "image_file": "q8.png",
   "image_bbox": [
    0.3,
    0.67,
    0.66,
    0.79
   ],
   "image_loc": "arrow/house-shaped pentagon with vertices A and B on top, E and D on bottom, point C on the right",
   "notes": "Converted from open fill-in to MCQ (word/letter answers must be MCQ). Answer key Q8 = ∠BCD; distractors are the other named angles in the figure."
  },
  {
   "n": 9,
   "type_id": 2,
   "question": "Lynn had some sugar at first. She used $$\\frac{1}{8}$$ of the sugar and she had 560 g of sugar left. How much sugar did she have at first?<br>[?] g",
   "answer0": "640",
   "answer1": null,
   "answer2": null,
   "answer3": null,
   "correct_answer": null,
   "skill_id": 122,
   "difficulty_id": 2,
   "explanation": "She used $$\\frac{1}{8}$$, so $$\\frac{7}{8}$$ of the sugar = 560 g. 1 unit ($$\\frac{1}{8}$$) = 560 ÷ 7 = 80 g. Total (8 units) = 80 × 8 = 640 g.",
   "hints": [
    "The 560 g left is $$\\frac{7}{8}$$ of the total.",
    "Find $$\\frac{1}{8}$$ first, then multiply by 8."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q9",
   "image_needed": false,
   "image_options": false,
   "image_file": null,
   "notes": "Answer key Q9 = 560 ÷ 7 = 80, 80 × 8 = 640 g."
  },
  {
   "n": 10,
   "type_id": 2,
   "question": "Figure A shows a rectangular piece of paper. It is folded along the dotted line as shown in Figure B. Find ∠a.<br>[?]°",
   "answer0": "33",
   "answer1": null,
   "answer2": null,
   "answer3": null,
   "correct_answer": null,
   "skill_id": 197,
   "difficulty_id": 3,
   "explanation": "In Figure A the diagonal makes 24° with the base, so the angle between the diagonal and the right edge of the rectangle is 90° − 24° = 66°. Folding along the dotted line reflects the flap, splitting this 66° equally into two parts. So ∠a = 66° ÷ 2 = 33°.",
   "hints": [
    "The corner of the rectangle is 90°; subtract the 24° to get the angle at that corner above the diagonal.",
    "Folding makes two equal angles, so halve the result."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q10",
   "image_needed": true,
   "image_options": false,
   "image_file": "q10.png",
   "image_bbox": [
    0.18,
    0.48,
    0.88,
    0.64
   ],
   "image_loc": "Figure A (rectangle with 24° and fold arrow) and Figure B (folded shape with angle a) side by side",
   "notes": "Answer key Q10 = 90 − 24 = 66, 66 ÷ 2 = 33°."
  },
  {
   "n": 11,
   "type_id": 0,
   "question": "Line WX is part of square WXYZ. (a) Draw square WXYZ in the grid and label your drawing. (b) Name a pair of perpendicular lines.",
   "answer0": null,
   "answer1": null,
   "answer2": null,
   "answer3": null,
   "correct_answer": null,
   "skill_id": 101,
   "difficulty_id": 2,
   "explanation": "(a) WX is a diagonal-direction segment on the grid; complete the square WXYZ so all four sides are equal and meet at right angles. (b) Adjacent sides of a square are perpendicular, e.g. WX and XY, or ZY and WX as completed.",
   "hints": [
    "A square has four equal sides and four right angles.",
    "Adjacent sides of a square meet at 90° (perpendicular)."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q11",
   "image_needed": true,
   "image_options": false,
   "image_file": "q11.png",
   "image_bbox": [
    0.22,
    0.33,
    0.7,
    0.68
   ],
   "image_loc": "square grid with segment WX drawn diagonally near upper-left, W lower and X upper",
   "notes": "type_id 0: interactive draw-on-grid task (cannot be a single value/sequence answer). Answer key Q11(b): ZY and WX are a pair of perpendicular lines."
  },
  {
   "n": 12,
   "type_id": 2,
   "question": "Annie and Betty had $$\\frac{1}{2}$$ m of cloth. Betty and Cathy had $$\\frac{3}{4}$$ m of cloth. Annie, Betty and Cathy had $$\\frac{4}{5}$$ m of cloth altogether. How much cloth did Betty have? Express your answer in its simplest form.<br>[?] m",
   "answer0": "9/20",
   "answer1": null,
   "answer2": null,
   "answer3": null,
   "correct_answer": null,
   "skill_id": 122,
   "difficulty_id": 3,
   "explanation": "(Annie + Betty) + (Betty + Cathy) = $$\\frac{1}{2} + \\frac{3}{4} = \\frac{2}{4} + \\frac{3}{4} = \\frac{5}{4}$$ m. This counts Betty twice plus Annie + Betty + Cathy. So Betty = $$\\frac{5}{4} - \\frac{4}{5} = \\frac{25}{20} - \\frac{16}{20} = \\frac{9}{20}$$ m.",
   "hints": [
    "Add the two pair-totals: this includes Betty twice.",
    "Subtract the all-three total $$\\frac{4}{5}$$ to leave just Betty."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q12",
   "image_needed": false,
   "image_options": false,
   "image_file": null,
   "notes": "Answer key Q12 final = 9/20 m (3/10 etc. in the key are intermediate working)."
  },
  {
   "n": 13,
   "type_id": 2,
   "question": "There was 4 $$\\ell$$ of water in a container. Raju used $$\\frac{1}{6}$$ $$\\ell$$ of water in the morning. Raju used another $$\\frac{1}{4}$$ $$\\ell$$ of water in the afternoon.<br>(a) What was the total amount of water used by Raju? Express your answer as a fraction in the simplest form.<br>[?] $$\\ell$$<br>(b) How much water was left in the container? Express your answer as a mixed number in the simplest form.<br>[?] $$\\ell$$",
   "answer0": "5/12",
   "answer1": "3 7/12",
   "answer2": null,
   "answer3": null,
   "correct_answer": null,
   "skill_id": 122,
   "difficulty_id": 2,
   "explanation": "(a) Total used = $$\\frac{1}{6} + \\frac{1}{4} = \\frac{2}{12} + \\frac{3}{12} = \\frac{5}{12}$$ ℓ. (b) Water left = $$4 - \\frac{5}{12} = 3\\frac{12}{12} - \\frac{5}{12} = 3\\frac{7}{12}$$ ℓ.",
   "hints": [
    "Use a common denominator of 12 to add $$\\frac{1}{6}$$ and $$\\frac{1}{4}$$.",
    "Subtract the total used from 4 ℓ; borrow 1 whole as $$\\frac{12}{12}$$."
   ],
   "source": "Maha Bodhi 2024 P4 Weighted Assessment 2 Q13",
   "image_needed": false,
   "image_options": false,
   "image_file": null,
   "notes": "Two-part question. Answer key Q13(a) = 5/12 ℓ, (b) = 3 7/12 ℓ."
  }
 ]
}