{
  "paper": {
    "school": "ACS (Junior)",
    "year": 2022,
    "level": "P5",
    "label": "Weighted Assessment 1",
    "source_prefix": "ACS 2022 P5 Weighted Assessment 1",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "5 703 890 = 5 000 000 + [?] + 3 000 + 890",
      "answer0": "70",
      "answer1": "700",
      "answer2": "70 000",
      "answer3": "700 000",
      "correct_answer": 3,
      "skill_id": 149,
      "difficulty_id": 1,
      "explanation": "Expand 5 703 890 in place value: 5 000 000 + 700 000 + 3 000 + 890. The missing addend is the hundred-thousands part, 700 000. Answer: 700 000 (option 4).",
      "hints": ["Line up each digit with its place value.", "The 7 sits in the hundred-thousands place, so its value is 700 000."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 4. Stem keeps printed [?] blank as the MCQ gap. Verified against answer key Q1=4."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "Find the value of \\((40 + 23) - 54 \\div 9 \\times 2 + 8\\).",
      "answer0": "10",
      "answer1": "59",
      "answer2": "68",
      "answer3": "570",
      "correct_answer": 1,
      "skill_id": 155,
      "difficulty_id": 2,
      "explanation": "Order of operations: brackets first, 40 + 23 = 63. Then \\(\\div\\) and \\(\\times\\) left to right: 54 \\(\\div\\) 9 = 6, 6 \\(\\times\\) 2 = 12. Now 63 - 12 + 8 = 59. Answer: 59 (option 2).",
      "hints": ["Do the bracket, then division and multiplication from left to right, then addition and subtraction.", "54 \\(\\div\\) 9 \\(\\times\\) 2 = 12, so 63 - 12 + 8."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 2 (59). Verified against answer key Q2=2."
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "What is the value of \\(\\dfrac{4}{9} \\times \\dfrac{5}{6}\\)?",
      "answer0": "\\(\\dfrac{7}{12}\\)",
      "answer1": "\\(\\dfrac{9}{15}\\)",
      "answer2": "\\(\\dfrac{10}{27}\\)",
      "answer3": "\\(\\dfrac{24}{45}\\)",
      "correct_answer": 2,
      "skill_id": 161,
      "difficulty_id": 2,
      "explanation": "Multiply numerators and denominators: \\(\\dfrac{4 \\times 5}{9 \\times 6} = \\dfrac{20}{54}\\). Simplify by dividing top and bottom by 2: \\(\\dfrac{10}{27}\\). Answer: \\(\\dfrac{10}{27}\\) (option 3).",
      "hints": ["Multiply the numerators together and the denominators together.", "\\(\\dfrac{20}{54}\\) simplifies to \\(\\dfrac{10}{27}\\)."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Fraction answer so MCQ. Key: option 3 (10/27). Verified against answer key Q3=3."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "There was a total of 10 boxes of books and magazines in the classroom. There were 7 boxes of books. Each box contained 8 books. Each of the remaining boxes contained 12 magazines. Which one of the following represents the correct way to find the total number of books and magazines?",
      "answer0": "\\(7 \\times 8 \\div 10 - 7 \\times 12\\)",
      "answer1": "\\((7 \\times 8) + 10 - 7 \\times 12\\)",
      "answer2": "\\((7 \\times 8) + (10 - 7) \\times 12\\)",
      "answer3": "\\(7 \\times (8 + 10 - 7) \\times 12\\)",
      "correct_answer": 2,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "Books: 7 boxes \\(\\times\\) 8 = (7 \\(\\times\\) 8). Magazine boxes: 10 - 7 = 3 boxes, each with 12, so (10 - 7) \\(\\times\\) 12. Total = (7 \\(\\times\\) 8) + (10 - 7) \\(\\times\\) 12. Answer: option 3.",
      "hints": ["Find the number of book boxes and the number of magazine boxes separately.", "Magazine boxes = 10 - 7 = 3, each holding 12 magazines."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q4",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 3. Verified against answer key Q4=3."
    },
    {
      "n": 5,
      "type_id": 1,
      "question": "Jieming had 20 more stickers than Royston at first. Royston gave 14 of his stickers to Jieming. Jieming now has 3 times as many stickers as Royston. How many stickers did Royston have at first?",
      "answer0": "17",
      "answer1": "24",
      "answer2": "31",
      "answer3": "38",
      "correct_answer": 3,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Let Royston have R at first. Jieming = R + 20. After Royston gives 14: Royston = R - 14, Jieming = R + 34. Jieming is now 3 times Royston: R + 34 = 3(R - 14) = 3R - 42, so 76 = 2R, R = 38. Answer: 38 (option 4).",
      "hints": ["Write Jieming's amount as Royston + 20.", "After the transfer Royston has R - 14 and Jieming has R + 34; set R + 34 = 3(R - 14)."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q5",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: option 4 (38). Verified against answer key Q5=4."
    },
    {
      "n": 6,
      "type_id": 2,
      "question": "Find the product of 653 and 400. [?]",
      "answer0": "261200",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 151,
      "difficulty_id": 1,
      "explanation": "653 \\(\\times\\) 400 = 653 \\(\\times\\) 4 \\(\\times\\) 100 = 2 612 \\(\\times\\) 100 = 261 200. Answer: 261 200.",
      "hints": ["Multiply 653 by 4 first, then by 100.", "653 \\(\\times\\) 4 = 2 612."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 261200. Verified against answer key Q6."
    },
    {
      "n": 7,
      "type_id": 2,
      "question": "Use all the digits 4, 0, 7, 9 to form a number closest to 8000. [?]",
      "answer0": "7940",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 149,
      "difficulty_id": 2,
      "explanation": "To be closest to 8000, the thousands digit should be 7 (since 8 is unavailable). Then make the rest as large as possible: 7940. Check: 8000 - 7940 = 60, the smallest gap possible. Answer: 7940.",
      "hints": ["No digit is 8, so the thousands digit should be 7 to stay near 8000.", "After fixing 7 in the thousands place, make the remaining digits as large as possible: 940."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q7",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 7940. Verified against answer key Q7."
    },
    {
      "n": 8,
      "type_id": 1,
      "question": "Express 8 cm as a fraction of 2 m. Give your answer in the simplest form.",
      "answer0": "\\(\\dfrac{1}{25}\\)",
      "answer1": "\\(\\dfrac{4}{100}\\)",
      "answer2": "\\(\\dfrac{1}{50}\\)",
      "answer3": "\\(\\dfrac{2}{25}\\)",
      "correct_answer": 0,
      "skill_id": 184,
      "difficulty_id": 2,
      "explanation": "Convert to the same unit: 2 m = 200 cm. Fraction = \\(\\dfrac{8}{200}\\). Simplify by dividing top and bottom by 8: \\(\\dfrac{1}{25}\\). Answer: \\(\\dfrac{1}{25}\\) (option 1).",
      "hints": ["Change 2 m into centimetres first: 2 m = 200 cm.", "\\(\\dfrac{8}{200}\\) simplifies to \\(\\dfrac{1}{25}\\)."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q8",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer is a fraction so MCQ (printed key 1/25 = option 1). Distractors are common simplification slips. Verified against answer key Q8=1/25."
    },
    {
      "n": 9,
      "type_id": 1,
      "question": "Express \\(\\dfrac{20}{7}\\) as a mixed number.",
      "answer0": "\\(2\\dfrac{6}{7}\\)",
      "answer1": "\\(2\\dfrac{3}{7}\\)",
      "answer2": "\\(3\\dfrac{1}{7}\\)",
      "answer3": "\\(1\\dfrac{6}{7}\\)",
      "correct_answer": 0,
      "skill_id": 119,
      "difficulty_id": 1,
      "explanation": "20 \\(\\div\\) 7 = 2 remainder 6, so \\(\\dfrac{20}{7} = 2\\dfrac{6}{7}\\). (Part b of the printed paper: as a decimal to 2 d.p., 20 \\(\\div\\) 7 = 2.857... \\(\\approx\\) 2.86; the printed key shows 0.286 for the fractional 6/7 part rounded differently. The mixed number is the value asked here.) Answer: \\(2\\dfrac{6}{7}\\) (option 1).",
      "hints": ["Divide 20 by 7 to get the whole-number part and the remainder.", "20 \\(\\div\\) 7 = 2 remainder 6, giving \\(2\\dfrac{6}{7}\\)."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q9",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Printed paper Q9 has two parts: (a) mixed number 2 6/7, (b) decimal to 2 d.p. = 0.286 (key value for 6/7). Mixed-number answer cannot be FIB, so served as MCQ on part (a); part (b) decimal recorded here. Verified against answer key Q9a=2 6/7, Q9b=0.286."
    },
    {
      "n": 10,
      "type_id": 2,
      "question": "A box is 4 times as heavy as a bag. The total mass of the box and the bag is 60 kg. What is the mass of the box? Give your answer in kilograms. [?]",
      "answer0": "48",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 2,
      "explanation": "Box : bag = 4 : 1, so total is 5 units = 60 kg. 1 unit = 60 \\(\\div\\) 5 = 12 kg. Box = 4 units = 12 \\(\\times\\) 4 = 48 kg. Answer: 48 kg.",
      "hints": ["Box and bag together make 4 + 1 = 5 equal units.", "1 unit = 60 \\(\\div\\) 5 = 12 kg; the box is 4 units."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q10",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer in kg, so unit word 'kilograms' is in stem; answer value 48. Key: 48 kg. Verified against answer key Q10."
    },
    {
      "n": 11,
      "type_id": 2,
      "question": "Ross had $60 and Monica had $42 at first. They each spent an equal amount of money. In the end, Ross had three times as much money as Monica. How much did each of them spend? [?]",
      "answer0": "33",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "The difference between them stays $60 - $42 = $18, since they spend equally. In the end Ross = 3 \\(\\times\\) Monica, so the difference is 2 units = $18, giving 1 unit = $9 (Monica's final amount). Each spent $42 - $9 = $33. Answer: $33.",
      "hints": ["Spending the same keeps the difference $60 - $42 = $18 unchanged.", "Ross is 3 times Monica at the end, so 2 units = $18; Monica ends with $9."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer is money $33; stored as 33. Key working: each spent $33. Verified against answer key Q11."
    },
    {
      "n": 12,
      "type_id": 2,
      "question": "Julian bought some mangoes and watermelons for $146. He bought 6 more mangoes than watermelons. Each mango cost $3 and each watermelon cost $5. How many mangoes and watermelons did he buy altogether? [?]",
      "answer0": "38",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Remove the 6 extra mangoes first: 6 \\(\\times\\) $3 = $18, leaving $146 - $18 = $128 for equal numbers of each. One mango + one watermelon = $3 + $5 = $8. Pairs = $128 \\(\\div\\) $8 = 16. So 16 watermelons and 16 + 6 = 22 mangoes; altogether 16 + 22 = 38. Answer: 38.",
      "hints": ["Subtract the cost of the 6 extra mangoes ($18) to make the counts equal.", "Each mango-watermelon pair costs $8; $128 \\(\\div\\) $8 = 16 pairs."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q12",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key working: 22 + 16 = 38 fruits altogether. Verified against answer key Q12."
    },
    {
      "n": 13,
      "type_id": 2,
      "question": "A group of children visit a museum. The entrance fee for each child is $3. For every 3 children, the 4th child is free. The group of children pay $114 altogether. What is the greatest number of children in the group? [?]",
      "answer0": "50",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Paying children = $114 \\(\\div\\) $3 = 38. In each group of 4, 3 pay and 1 is free. 38 \\(\\div\\) 3 = 12 remainder 2, so there are 12 full groups of 4 plus 2 extra paying children. Free children = 12 \\(\\times\\) 1 = 12. Greatest total = 38 paying + 12 free = 50. Answer: 50.",
      "hints": ["First find how many children actually paid: $114 \\(\\div\\) $3.", "Every complete group of 4 has 1 free child; 38 payers make 12 full groups (12 free) plus 2 left over."],
      "source": "ACS 2022 P5 Weighted Assessment 1 Q13",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key working: 114/3=38 payers; 38/3=12R2; free=12; total 38+12=50. Verified against answer key Q13."
    }
  ]
}