{
"paper": {
"school": "Henry Park",
"year": 2023,
"level": "P5",
"label": "Weighted Assessment 1",
"source_prefix": "Henry Park 2023 P5 Weighted Assessment 1",
"has_answer_key": true
},
"questions": [
{
"n": 1,
"type_id": 1,
"question": "What is the value of the digit 8 in the number 282 405?",
"answer0": "80",
"answer1": "800",
"answer2": "8000",
"answer3": "80 000",
"correct_answer": 3,
"skill_id": 149,
"difficulty_id": 1,
"explanation": "In 282 405, the digit 8 is in the ten-thousands place, so its value is 8 × 10 000 = 80 000.",
"hints": ["Identify which place the digit 8 sits in.", "The digit 8 is in the ten-thousands column."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q1",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": ""
},
{
"n": 2,
"type_id": 1,
"question": "Which of the following is not a factor of 36?",
"answer0": "6",
"answer1": "9",
"answer2": "16",
"answer3": "18",
"correct_answer": 2,
"skill_id": 111,
"difficulty_id": 1,
"explanation": "Factors of 36 are 1, 2, 3, 4, 6, 9, 12, 18, 36. 16 does not divide 36 exactly (36 ÷ 16 = 2 r 4), so 16 is not a factor.",
"hints": ["Check which numbers divide 36 with no remainder.", "36 ÷ 16 leaves a remainder."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q2",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": ""
},
{
"n": 3,
"type_id": 1,
"question": "Which of the following has the same value as \\(4\\dfrac{3}{8}\\)?",
"answer0": "\\(\\dfrac{28}{8}\\)",
"answer1": "\\(\\dfrac{35}{8}\\)",
"answer2": "\\(\\dfrac{43}{8}\\)",
"answer3": "\\(\\dfrac{56}{8}\\)",
"correct_answer": 1,
"skill_id": 119,
"difficulty_id": 1,
"explanation": "Convert the mixed number to an improper fraction: \\(4\\dfrac{3}{8} = \\dfrac{4 \\times 8 + 3}{8} = \\dfrac{35}{8}\\).",
"hints": ["Multiply the whole number by the denominator, then add the numerator.", "4 × 8 + 3 = 35."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q3",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": ""
},
{
"n": 4,
"type_id": 1,
"question": "Which of the following fractions is the smallest?",
"answer0": "\\(\\dfrac{5}{11}\\)",
"answer1": "\\(\\dfrac{5}{9}\\)",
"answer2": "\\(\\dfrac{5}{8}\\)",
"answer3": "\\(\\dfrac{5}{6}\\)",
"correct_answer": 0,
"skill_id": 79,
"difficulty_id": 1,
"explanation": "All four fractions have the same numerator 5. With equal numerators, the fraction with the largest denominator is the smallest, so \\(\\dfrac{5}{11}\\) is the smallest.",
"hints": ["The numerators are all 5.", "With the same numerator, a bigger denominator means a smaller fraction."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q4",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": ""
},
{
"n": 5,
"type_id": 1,
"question": "The figure is made up of 3 triangles, ABC, ACD and ADE. BCD is a straight line. Given that the base of triangle ACD is CD, name the height of triangle ACD.",
"answer0": "AB",
"answer1": "AC",
"answer2": "EA",
"answer3": "ED",
"correct_answer": 3,
"skill_id": 186,
"difficulty_id": 2,
"explanation": "The height must be perpendicular to the base CD. ED is perpendicular to CD (right angle at D), so ED is the height of triangle ACD.",
"hints": ["The height is perpendicular to the chosen base.", "Look for the side that meets CD at a right angle."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q5",
"image_needed": true,
"image_options": false,
"image_file": "q5.png",
"image_page": 4,
"image_bbox": [0.18, 0.14, 0.72, 0.27],
"image_loc": "top of page, below the question: triangles ABC/ACD/ADE with A top-left, E top-right, B bottom-left, C and D bottom-right",
"notes": ""
},
{
"n": 6,
"type_id": 1,
"question": "Find the area of the shaded triangle.",
"answer0": "110 cm²",
"answer1": "120 cm²",
"answer2": "130 cm²",
"answer3": "220 cm²",
"correct_answer": 0,
"skill_id": 186,
"difficulty_id": 2,
"explanation": "Base of the shaded triangle = 22 cm, perpendicular height = 10 cm. Area = ½ × base × height = ½ × 22 × 10 = 110 cm².",
"hints": ["Area of a triangle = ½ × base × height.", "Use the 22 cm side as base and the 10 cm dashed line as the height."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q6",
"image_needed": true,
"image_options": false,
"image_file": "q6.png",
"image_page": 4,
"image_bbox": [0.18, 0.46, 0.56, 0.66],
"image_loc": "middle of page, below the question: shaded triangle labelled 26 cm, 22 cm, 10 cm and 2 cm",
"notes": "Answer key gives option (1) 110 cm²; base 22 cm with height 10 cm."
},
{
"n": 7,
"type_id": 1,
"question": "In a class of 42 students, 18 are girls. Express the ratio of the number of girls to the number of boys in the class.",
"answer0": "9 : 21",
"answer1": "3 : 4",
"answer2": "4 : 7",
"answer3": "4 : 3",
"correct_answer": 1,
"skill_id": 179,
"difficulty_id": 2,
"explanation": "Boys = 42 − 18 = 24. Girls : boys = 18 : 24. Divide both by 6: 18 ÷ 6 = 3, 24 ÷ 6 = 4, giving 3 : 4.",
"hints": ["First find the number of boys.", "Simplify 18 : 24 by dividing both parts by 6."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q7",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": ""
},
{
"n": 8,
"type_id": 1,
"question": "Janet spent \\(\\dfrac{2}{5}\\) of her money on a cake and \\(\\dfrac{1}{3}\\) of the remainder on a cookie. What fraction of her money had she left?",
"answer0": "\\(\\dfrac{1}{5}\\)",
"answer1": "\\(\\dfrac{2}{5}\\)",
"answer2": "\\(\\dfrac{2}{15}\\)",
"answer3": "\\(\\dfrac{4}{15}\\)",
"correct_answer": 1,
"skill_id": 165,
"difficulty_id": 2,
"explanation": "After the cake, remainder = 1 − \\(\\dfrac{2}{5}\\) = \\(\\dfrac{3}{5}\\). Cookie = \\(\\dfrac{1}{3}\\) of \\(\\dfrac{3}{5}\\) = \\(\\dfrac{1}{5}\\). Left = \\(\\dfrac{3}{5}\\) − \\(\\dfrac{1}{5}\\) = \\(\\dfrac{2}{5}\\).",
"hints": ["Find the remainder after the cake first.", "Cookie uses one-third of that remainder, so two-thirds of the remainder is left."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q8",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": ""
},
{
"n": 9,
"type_id": 1,
"question": "A repeated pattern is formed using the numbers 3 and 0. The first 15 numbers are 0, 3, 0, 3, 3, 0, 3, 0, 3, 3, 0, 3, 0, 3, 3. What is the sum of the first 103 numbers?",
"answer0": "120",
"answer1": "180",
"answer2": "183",
"answer3": "228",
"correct_answer": 2,
"skill_id": 152,
"difficulty_id": 3,
"explanation": "The pattern repeats every 5 numbers (0, 3, 0, 3, 3) with a sum of 9 per block. 103 ÷ 5 = 20 blocks remainder 3. 20 × 9 = 180. The first 3 of the next block are 0, 3, 0 = 3. Total = 180 + 3 = 183.",
"hints": ["Find the repeating block of 5 numbers and its sum.", "103 = 20 full blocks of 5 with 3 extra numbers."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q9",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Pattern block of 5 (0,3,0,3,3) reconstructed from the printed strip; key answer (3) 183."
},
{
"n": 10,
"type_id": 2,
"question": "Find the value of \\(4 + (101 + 19) \\div 2\\). [?]",
"answer0": "64",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 155,
"difficulty_id": 1,
"explanation": "Brackets first: 101 + 19 = 120. Then divide: 120 ÷ 2 = 60. Then add: 4 + 60 = 64.",
"hints": ["Work out the brackets first, then division, then addition.", "120 ÷ 2 = 60."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q10",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Scan shows '+ 2' but the key answer 64 only works with ÷2, so the operation is ÷2: 4 + (101 + 19) ÷ 2 = 64."
},
{
"n": 11,
"type_id": 1,
"question": "Find the value of \\(\\dfrac{7}{15} - \\dfrac{1}{3}\\).",
"answer0": "\\(\\dfrac{2}{15}\\)",
"answer1": "\\(\\dfrac{6}{12}\\)",
"answer2": "\\(\\dfrac{2}{5}\\)",
"answer3": "\\(\\dfrac{1}{5}\\)",
"correct_answer": 0,
"skill_id": 159,
"difficulty_id": 1,
"explanation": "Make denominators the same: \\(\\dfrac{1}{3} = \\dfrac{5}{15}\\). Then \\(\\dfrac{7}{15} - \\dfrac{5}{15} = \\dfrac{2}{15}\\).",
"hints": ["Convert \\(\\dfrac{1}{3}\\) to fifteenths.", "\\(\\dfrac{1}{3} = \\dfrac{5}{15}\\)."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q11",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Printed as a fill-in but the answer 2/15 is a fraction, so converted to MCQ per spec (FIB answers must be integers/decimals only)."
},
{
"n": 12,
"type_id": 2,
"question": "What is the missing number in the following?
3 : 7 = 27 : [?]",
"answer0": "63",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 181,
"difficulty_id": 1,
"explanation": "3 × 9 = 27, so multiply the other term by 9 too: 7 × 9 = 63. The missing number is 63.",
"hints": ["Find what 3 was multiplied by to get 27.", "3 × 9 = 27, so 7 × 9 = 63."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q12",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": ""
},
{
"n": 13,
"type_id": 2,
"question": "Form the smallest even number using all the digits given. Each digit can only be used once.
2, 7, 0, 6, 9, 4 [?]",
"answer0": "204796",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 149,
"difficulty_id": 2,
"explanation": "For the smallest number arrange digits in ascending order, but the leading digit cannot be 0, so start with 2: 2 0 4 6 7 9. To be even it must end in an even digit; the smallest arrangement ending in an even digit is 204796. Answer: 204 796.",
"hints": ["Smallest number puts small digits first, but it cannot start with 0.", "It must end in an even digit to be an even number."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q13",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Digit set is 2, 7, 0, 6, 9, 4 (the smudged digit reads 6). Key answer 204796."
},
{
"n": 14,
"type_id": 2,
"question": "Find the area of the shaded triangle. [?]",
"answer0": "99",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 186,
"difficulty_id": 2,
"explanation": "Base = 18 cm, perpendicular height = 11 cm. Area = ½ × 18 × 11 = 99 cm².",
"hints": ["Area of a triangle = ½ × base × height.", "Use 18 cm as the base and 11 cm as the height."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q14",
"image_needed": true,
"image_options": false,
"image_file": "q14.png",
"image_page": 7,
"image_bbox": [0.24, 0.13, 0.54, 0.27],
"image_loc": "top-left of page, below the question: shaded triangle with 8 cm (top dashed), 11 cm (left dashed height), 13 cm (right slant), 18 cm (base)",
"notes": "Answer in cm²."
},
{
"n": 15,
"type_id": 2,
"question": "Gwen spent \\(\\dfrac{5}{8}\\) of her money and had $48 left. How much money did she have at first? $[?]",
"answer0": "128",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 165,
"difficulty_id": 2,
"explanation": "She spent \\(\\dfrac{5}{8}\\), so \\(\\dfrac{3}{8}\\) is left = $48. Then \\(\\dfrac{1}{8}\\) = 48 ÷ 3 = $16. Total = 8 × 16 = $128.",
"hints": ["The fraction left is 1 − \\(\\dfrac{5}{8}\\) = \\(\\dfrac{3}{8}\\), which equals $48.", "Find 1 unit (one-eighth) first, then multiply by 8."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q15",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Answer in dollars."
},
{
"n": 16,
"type_id": 2,
"question": "The diagram shows rectangle ABCD with a shaded triangle EBF in it. Given that AE = EB, find the total area of the unshaded parts of rectangle ABCD. [?]",
"answer0": "315",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 186,
"difficulty_id": 3,
"explanation": "Since AE = EB, EB = 28 ÷ 2 = 14 cm. Area of shaded triangle EBF = ½ × 14 × 15 = 105 cm². Area of rectangle = 28 × 15 = 420 cm². Unshaded area = 420 − 105 = 315 cm².",
"hints": ["AE = EB means EB is half of AB.", "Unshaded area = rectangle area − triangle area."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q16",
"image_needed": true,
"image_options": false,
"image_file": "q16.png",
"image_page": 8,
"image_bbox": [0.22, 0.16, 0.62, 0.33],
"image_loc": "top of page, below the question: rectangle ABCD (28 cm wide, 15 cm tall) with E on top side and shaded triangle EBF",
"notes": "Answer in cm²."
},
{
"n": 17,
"type_id": 2,
"question": "The ratio of the area of triangle PQS to the area of triangle PSR is 2 : 5. The area of triangle PQR is 84 cm². What is the area of triangle PSR? [?]",
"answer0": "60",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 183,
"difficulty_id": 2,
"explanation": "Triangle PQR is made up of PQS and PSR, so total units = 2 + 5 = 7 units = 84 cm². 1 unit = 84 ÷ 7 = 12 cm². Triangle PSR = 5 units = 12 × 5 = 60 cm².",
"hints": ["PQR = PQS + PSR, so the total is 2 + 5 = 7 units.", "Find the value of 1 unit, then multiply by 5."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q17",
"image_needed": true,
"image_options": false,
"image_file": "q17.png",
"image_page": 8,
"image_bbox": [0.22, 0.55, 0.48, 0.71],
"image_loc": "middle-left of page, below the question: triangle PQR with apex P, base QR and point S on QR, line PS drawn",
"notes": "Answer in cm²."
},
{
"n": 18,
"type_id": 2,
"question": "In a shop, oranges are sold at 5 oranges for $7. Susan bought 30 oranges with all her money. To buy 20 papayas with the same amount of money, she will be short of $18. Given that the cost of each papaya is the same, how much does each papaya cost? $[?]",
"answer0": "3",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 152,
"difficulty_id": 3,
"explanation": "30 oranges = 6 groups of 5, so cost = 6 × $7 = $42 (all her money). For 20 papayas she needs $42 + $18 = $60. Each papaya = $60 ÷ 20 = $3.",
"hints": ["Work out how much Susan has from the 30 oranges first.", "She needs $18 more than $42 for the 20 papayas."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q18",
"image_needed": true,
"image_options": false,
"image_file": "q18.png",
"image_page": 9,
"image_bbox": [0.40, 0.12, 0.58, 0.23],
"image_loc": "top-centre of page, below the question: drawing of a bag of oranges labelled '5 oranges for $7'",
"notes": "Answer in dollars. The '5 oranges for $7' price is in the figure."
},
{
"n": 19,
"type_id": 2,
"question": "Chef Lim had some eggs at first. He used \\(\\dfrac{1}{10}\\) of the total number of eggs and an additional 38 eggs on Monday. He continued using \\(\\dfrac{4}{7}\\) of the remaining eggs on Tuesday. He used up the remaining 30 eggs on Wednesday. How many eggs did Chef Lim have at first? [?]",
"answer0": "120",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 165,
"difficulty_id": 3,
"explanation": "Work backwards. After Tuesday 30 eggs are \\(\\dfrac{3}{7}\\) of Tuesday's start, so 1 unit = 30 ÷ 3 = 10 and Tuesday's start = 7 × 10 = 70 eggs. These 70 eggs are what remained after Monday, i.e. 70 + 38 = 108 is \\(\\dfrac{9}{10}\\) of the total. So \\(\\dfrac{1}{10}\\) = 108 ÷ 9 = 12 and the total = 12 × 10 = 120 eggs.",
"hints": ["Work backwards from the 30 eggs left on Wednesday.", "After using \\(\\dfrac{4}{7}\\), three-sevenths (30 eggs) remained."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q19",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": ""
},
{
"n": 20,
"type_id": 2,
"question": "Figure ABCDE has an area of 34 cm². ADC and BDE are straight lines. Find the area of the shaded triangle ABD. [?]",
"answer0": "8",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 186,
"difficulty_id": 3,
"explanation": "Area of triangle ABC = ½ × AB × BC = ½ × 6 × 10 = 30 cm². Area of triangle ABE = ½ × AB × height(4) = ½ × 6 × 4 = 12 cm²... whole figure ABCDE = 34 cm². Triangle ABD = whole figure − triangle BCD − triangle ADE. Triangle BCD = ½ × 10 × 6 = 30 cm²; 34 − 30 = 4 cm² = triangle ADE which has base AE-related height 4, so AD base gives ½ × 6 × 4 = ... Using the key: 34 − (½ × 10 × 6) = 4, then shaded ABD = ½ × 6 × 4 = 8 cm².",
"hints": ["Use the total area 34 cm² and subtract the large triangle (½ × 10 × 6).", "The leftover (4 cm²) helps you find the height for triangle ABD: ½ × 6 × 4 = 8."],
"source": "Henry Park 2023 P5 Weighted Assessment 1 Q20",
"image_needed": true,
"image_options": false,
"image_file": "q20.png",
"image_page": 11,
"image_bbox": [0.27, 0.13, 0.66, 0.36],
"image_loc": "top-centre of page, below the question: figure ABCDE with C top-right (10 cm), E left (4 cm height), A and B at bottom (AB = 6 cm), shaded triangle ABD",
"notes": "Answer in cm². Key working: 34 − ½×10×6 = 4; ½×6×4 = 8 cm²."
}
]
}