{ "paper": { "school": "Henry Park", "year": 2024, "level": "P5", "label": "Weighted Assessment 1", "source_prefix": "Henry Park 2024 P5 Weighted Assessment 1", "has_answer_key": true }, "questions": [ { "n": 1, "type_id": 1, "question": "What is the value of 4 in the number 842 673?", "answer0": "40", "answer1": "400", "answer2": "4 000", "answer3": "40 000", "correct_answer": 3, "skill_id": 149, "difficulty_id": 1, "explanation": "In 842 673, the digit 4 is in the ten-thousands place, so its value is 4 × 10 000 = 40 000.", "hints": ["Identify the place value of the digit 4.", "4 sits in the ten-thousands column."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q1", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 4 (40 000)." }, { "n": 2, "type_id": 1, "question": "What is one million, seven hundred and eighty-four thousand and sixteen in numerals?", "answer0": "1 700 846", "answer1": "1 708 416", "answer2": "1 784 016", "answer3": "1 784 060", "correct_answer": 2, "skill_id": 149, "difficulty_id": 1, "explanation": "One million = 1 000 000; seven hundred and eighty-four thousand = 784 000; sixteen = 16. Total = 1 784 016.", "hints": ["Build the number place by place: millions, thousands, ones.", "Sixteen is written 016 in the last three places."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q2", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 3 (1 784 016)." }, { "n": 3, "type_id": 1, "question": "\\(9 - \\boxed{\\phantom{0}} = 7\\dfrac{3}{8}\\)
What is the missing number in the box?", "answer0": "\\(1\\dfrac{3}{8}\\)", "answer1": "\\(1\\dfrac{5}{8}\\)", "answer2": "\\(2\\dfrac{3}{8}\\)", "answer3": "\\(2\\dfrac{5}{8}\\)", "correct_answer": 1, "skill_id": 160, "difficulty_id": 2, "explanation": "Missing number = \\(9 - 7\\dfrac{3}{8} = 8\\dfrac{8}{8} - 7\\dfrac{3}{8} = 1\\dfrac{5}{8}\\).", "hints": ["The missing number equals \\(9 - 7\\dfrac{3}{8}\\).", "Regroup 9 as \\(8\\dfrac{8}{8}\\) before subtracting."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q3", "image_needed": false, "image_options": false, "image_file": null, "notes": "Mixed-number answer so MCQ. Key: option 2 (1 5/8)." }, { "n": 4, "type_id": 1, "question": "How many sixths are there in \\(2\\dfrac{2}{3}\\)?", "answer0": "16", "answer1": "10", "answer2": "8", "answer3": "4", "correct_answer": 0, "skill_id": 158, "difficulty_id": 2, "explanation": "\\(2\\dfrac{2}{3} = \\dfrac{8}{3} = \\dfrac{16}{6}\\), so there are 16 sixths.", "hints": ["Convert the mixed number to an improper fraction.", "Express it with a denominator of 6."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q4", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 1 (16)." }, { "n": 5, "type_id": 1, "question": "What is the area of the shaded triangle?", "answer0": "24 cm²", "answer1": "26 cm²", "answer2": "30 cm²", "answer3": "54 cm²", "correct_answer": 0, "skill_id": 186, "difficulty_id": 2, "explanation": "The shaded triangle has base 4 cm (the right segment) and height 12 cm. Area = \\(\\dfrac{1}{2} \\times 4 \\times 12 = 24\\) cm².", "hints": ["The shaded triangle sits on the 4 cm base.", "Area of a triangle = ½ × base × height."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q5", "image_needed": true, "image_options": false, "image_file": "q5.png", "image_page": 5, "image_bbox": [0.38, 0.15, 0.68, 0.33], "image_loc": "top centre of page; triangle with height 12 cm, slant 13 cm, base split into 5 cm and 4 cm", "notes": "Key: option 1 (24 cm²). Shaded part is the right triangle on the 4 cm base." }, { "n": 6, "type_id": 1, "question": "ABCD is a rectangle. AB = 12 cm, BC = 9 cm and DEC is a straight line. What is the total area of the shaded parts of the rectangle?", "answer0": "36 cm²", "answer1": "42 cm²", "answer2": "54 cm²", "answer3": "108 cm²", "correct_answer": 2, "skill_id": 186, "difficulty_id": 2, "explanation": "The two shaded triangles share base DE+EC = 12 cm with height 9 cm (the rectangle's height). Their combined area = \\(\\dfrac{1}{2} \\times 12 \\times 9 = 54\\) cm², half the rectangle.", "hints": ["The shaded triangles together have the full base DC and height BC.", "Combined area = ½ × base × height."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q6", "image_needed": true, "image_options": false, "image_file": "q6.png", "image_page": 5, "image_bbox": [0.4, 0.59, 0.65, 0.72], "image_loc": "lower-middle of page; rectangle ABCD with apex E on base DC and two shaded triangles", "notes": "Key: option 3 (54 cm²). AB=12 is the base DC; height = BC = 9." }, { "n": 7, "type_id": 1, "question": "The ratio of the length to the breadth of a field is 5 : 4. The breadth of the field is 20 m. Find the perimeter of the field.", "answer0": "36 m", "answer1": "45 m", "answer2": "72 m", "answer3": "90 m", "correct_answer": 3, "skill_id": 182, "difficulty_id": 2, "explanation": "4 units = 20 m, so 1 unit = 5 m and length = 5 units = 25 m. Perimeter = 2 × (25 + 20) = 90 m.", "hints": ["Find the value of one ratio unit from the breadth.", "Perimeter = 2 × (length + breadth)."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q7", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 4 (90 m)." }, { "n": 8, "type_id": 1, "question": "A fruit seller had 140 papayas. He threw away \\(\\dfrac{1}{4}\\) of the papayas that were rotten. He sold \\(\\dfrac{3}{5}\\) of the remainder. How many papayas were left in the end?", "answer0": "21", "answer1": "35", "answer2": "42", "answer3": "63", "correct_answer": 2, "skill_id": 165, "difficulty_id": 2, "explanation": "Thrown away = \\(\\dfrac{1}{4} \\times 140 = 35\\); remainder = 105. Sold = \\(\\dfrac{3}{5} \\times 105 = 63\\); left = 105 − 63 = 42.", "hints": ["Find the remainder after throwing away ¼.", "Left = remainder − the ⅗ that was sold (i.e. ⅖ of the remainder)."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q8", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: option 3 (42)." }, { "n": 9, "type_id": 1, "question": "A table with 4 columns is filled with whole numbers in a certain pattern. The first 4 rows of the table are shown.
Row 1: A 3, B 4, C 5, D 6
Row 2: A 7, B 8, C 9, D 10
Row 3: A 11, B 12, C 13, D 14
In which column will the number 220 appear?", "answer0": "Column A", "answer1": "Column B", "answer2": "Column C", "answer3": "Column D", "correct_answer": 1, "skill_id": 152, "difficulty_id": 3, "explanation": "Column A holds 3, 7, 11 … (remainder 3 when divided by 4); B holds 4, 8, 12 … (multiples of 4); C remainder 1; D remainder 2. Since 220 = 4 × 55 is a multiple of 4, it appears in Column B.", "hints": ["Look at the remainder of each column's numbers when divided by 4.", "220 ÷ 4 leaves no remainder."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q9", "image_needed": true, "image_options": false, "image_file": "q9.png", "image_page": 6, "image_bbox": [0.18, 0.6, 0.9, 0.69], "image_loc": "middle of page; 4-column table (Columns A-D) showing the first 3 rows of the pattern", "notes": "Key: option 2 (Column B). Table reproduced in stem so figure is optional." }, { "n": 10, "type_id": 2, "question": "Find the value of \\((100 - 8 \\times 8) \\div 2 + 3\\).
[?]", "answer0": "21", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 155, "difficulty_id": 1, "explanation": "8 × 8 = 64; 100 − 64 = 36; 36 ÷ 2 = 18; 18 + 3 = 21.", "hints": ["Work inside the brackets first (multiply before subtracting).", "Then divide, then add."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q10", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: 21." }, { "n": 11, "type_id": 1, "question": "Find the value of \\(\\dfrac{2}{7} \\times \\dfrac{1}{8}\\). Give your answer in the simplest form.", "answer0": "\\(\\dfrac{1}{28}\\)", "answer1": "\\(\\dfrac{2}{15}\\)", "answer2": "\\(\\dfrac{1}{56}\\)", "answer3": "\\(\\dfrac{3}{56}\\)", "correct_answer": 0, "skill_id": 161, "difficulty_id": 1, "explanation": "\\(\\dfrac{2}{7} \\times \\dfrac{1}{8} = \\dfrac{2}{56} = \\dfrac{1}{28}\\).", "hints": ["Multiply numerators and denominators.", "Simplify the result."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q11", "image_needed": false, "image_options": false, "image_file": null, "notes": "Fraction answer so converted from FIB to MCQ. Key: 1/28. Distractors are plausible fraction errors." }, { "n": 12, "type_id": 2, "question": "Find the area of triangle ABC.
[?]", "answer0": "150", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 186, "difficulty_id": 2, "explanation": "ABC is right-angled at B with base BC = 15 cm and height AB = 20 cm. Area = \\(\\dfrac{1}{2} \\times 15 \\times 20 = 150\\) cm².", "hints": ["The right angle is at B, so AB and BC are the base and height.", "Area = ½ × base × height; the 25 cm is the hypotenuse and not needed."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q12", "image_needed": true, "image_options": false, "image_file": "q12.png", "image_page": 7, "image_bbox": [0.18, 0.59, 0.45, 0.82], "image_loc": "left side of page; right-angled triangle ABC, AB = 20 cm, BC = 15 cm, AC = 25 cm, right angle at B", "notes": "Key: 150 cm². Answer in cm² (unit printed beside blank)." }, { "n": 13, "type_id": 2, "question": "Mei Ling and Qi Fang shared the cost of a camera in the ratio of 7 : 2. Qi Fang paid $40 less than Mei Ling. What was the cost of the camera?
$[?]", "answer0": "72", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 183, "difficulty_id": 2, "explanation": "Difference 7 − 2 = 5 units = $40, so 1 unit = $8. Total = 7 + 2 = 9 units = 9 × $8 = $72.", "hints": ["The difference in their shares is 5 units = $40.", "Total cost = 9 units."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q13", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: $72. Money answer is a whole number so FIB." }, { "n": 14, "type_id": 2, "question": "Jane has 50 more sweets than Dario at first. After Dario ate 10 sweets, Jane had four times as many sweets as Dario. How many sweets did Jane have at first?
[?]", "answer0": "80", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 152, "difficulty_id": 2, "explanation": "After Dario ate 10, Jane has 60 more than Dario. Then Jane = 4 × Dario, so the gap of 60 = 3 units → 1 unit = 20 = Dario's amount now. Jane = 4 × 20 = 80, which is also her starting amount (unchanged).", "hints": ["After Dario eats 10, the gap becomes 50 + 10 = 60.", "Jane being 4× Dario means the gap is 3 of Dario's parts."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q14", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: 80 sweets." }, { "n": 15, "type_id": 2, "question": "In a box, \\(\\dfrac{3}{4}\\) of the fruits are pears and the rest are oranges. After giving away 160 pears, there are now twice as many oranges as pears. Find the total number of pears and oranges in the box in the end.
[?]", "answer0": "96", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 165, "difficulty_id": 3, "explanation": "Oranges = ¼ of the original = 1 unit, pears = 3 units. In the end oranges = 2 × pears, so pears (end) = ½ unit. Pears given away = 3 − ½ = 2½ units = 160 → 1 unit = 64. Oranges = 64, pears (end) = 32, total = 96.", "hints": ["Let one unit be the (unchanged) number of oranges; pears started at 3 units.", "After giving away, pears = ½ unit, and 2½ units = 160."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q15", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: 96. (Key working: 160÷5=32, 32×3=96.)" }, { "n": 16, "type_id": 2, "question": "The figure is made up of squares of side 12 cm each. Find the area of the shaded parts.
[?]", "answer0": "144", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 186, "difficulty_id": 3, "explanation": "Each square has area 12 × 12 = 144 cm². The shaded triangles combine to a total area equal to one whole square = 144 cm².", "hints": ["Find the area of one 12 cm square.", "The shaded triangles add up to the area of exactly one square."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q16", "image_needed": true, "image_options": false, "image_file": "q16.png", "image_page": 9, "image_bbox": [0.17, 0.14, 0.45, 0.31], "image_loc": "top-left of page; arrangement of 12 cm squares with shaded triangles, side 12 cm marked", "notes": "Key: 144 cm². Answer in cm²." }, { "n": 17, "type_id": 2, "question": "The number of cards Aaron, Brandon and Cayden have is in the ratio 3 : 2 : 5. Aaron had 45 cards. How many cards do they have altogether?
[?]", "answer0": "150", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 183, "difficulty_id": 2, "explanation": "Aaron's 3 units = 45, so 1 unit = 15. Total = 3 + 2 + 5 = 10 units = 10 × 15 = 150 cards.", "hints": ["Aaron's share is 3 units = 45 cards.", "Total = 10 units."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q17", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: 150 cards." }, { "n": 18, "type_id": 2, "question": "Peter used \\(\\dfrac{2}{5}\\) of his salary on a TV. He spent \\(\\dfrac{1}{6}\\) of the remaining money on a table and $350 on some chairs. He was then left with \\(\\dfrac{1}{4}\\) of his salary. What was his salary?
$[?]", "answer0": "1400", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 165, "difficulty_id": 3, "explanation": "TV = \\(\\dfrac{2}{5} = \\dfrac{8}{20}\\). Table = \\(\\dfrac{1}{6}\\) of remaining \\(\\dfrac{3}{5} = \\dfrac{1}{10} = \\dfrac{2}{20}\\). Left = \\(\\dfrac{1}{4} = \\dfrac{5}{20}\\). Chairs = \\(1 - \\dfrac{8}{20} - \\dfrac{2}{20} - \\dfrac{5}{20} = \\dfrac{5}{20}\\) = $350, so \\(\\dfrac{1}{20}\\) = $70 and salary = 20 × $70 = $1400.", "hints": ["Express every part as twentieths of the salary.", "The $350 of chairs equals the leftover fraction; use it to find one twentieth."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q18", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: $1400." }, { "n": 19, "type_id": 2, "question": "The figure shows a rectangle ABCD where AB = 20 cm, BC = 12 cm and BE = DF = 6 cm. Find the total area of the unshaded parts of the rectangle.
[?]", "answer0": "180", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 186, "difficulty_id": 3, "explanation": "Rectangle area = 20 × 12 = 240 cm². The shaded triangles share base 20 cm with height 6 cm, total = \\(\\dfrac{1}{2} \\times 20 \\times 6 = 60\\) cm². Unshaded = 240 − 60 = 180 cm².", "hints": ["Find the whole rectangle's area first.", "The shaded triangles together have base 20 cm and height 6 cm; subtract them."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q19", "image_needed": true, "image_options": false, "image_file": "q19.png", "image_page": 10, "image_bbox": [0.3, 0.49, 0.72, 0.69], "image_loc": "centre of page; rectangle ABCD with AB = 20 cm, points E on BC and F on DA, lines meeting at centre, shaded triangles at F and E", "notes": "Key: 180 cm². Answer in cm²." }, { "n": 20, "type_id": 2, "question": "A group of friends shared some coins among themselves. They tried taking 13 coins each, but found that the last friend had only 4 coins. When each friend took 10 coins, there were 12 coins left. How many coins were there altogether?
[?]", "answer0": "82", "answer1": null, "answer2": null, "answer3": null, "correct_answer": null, "skill_id": 152, "difficulty_id": 3, "explanation": "Taking 13 each, the last friend is short 13 − 4 = 9; taking 10 each leaves 12 over. The difference per friend between 13 and 10 is 3 coins, accounting for 9 + 12 = 21 across the group → 21 ÷ 3 = 7 friends. Total = 7 × 10 + 12 = 82 coins.", "hints": ["Compare the two sharings: 3 fewer coins each frees up enough for the shortfall plus the leftover.", "Number of friends = (shortfall + leftover) ÷ 3."], "source": "Henry Park 2024 P5 Weighted Assessment 1 Q20", "image_needed": false, "image_options": false, "image_file": null, "notes": "Key: 82 coins." } ] }