{
  "paper": {
    "school": "Maha Bodhi",
    "year": 2025,
    "level": "P5",
    "label": "Weighted Assessment 2",
    "source_prefix": "Maha Bodhi 2025 P5 Weighted Assessment 2",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 2,
      "question": "In 1 hour, 360 litres of water flows from a tap. What is the rate of water flow, in litres per minute? [?]",
      "answer0": "6",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 1,
      "explanation": "1 hour = 60 minutes. Rate = 360 ÷ 60 = 6 litres per minute.",
      "hints": ["There are 60 minutes in an hour.", "Divide 360 by 60."],
      "source": "Maha Bodhi 2025 P5 Weighted Assessment 2 Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: 6 ℓ per min."
    },
    {
      "n": 2,
      "type_id": 2,
      "question": "(a) Find the value of $25.79 + 2.31$. [?]<br>(b) Round 173.896 to the nearest tenth. [?]",
      "answer0": "28.1",
      "answer1": "173.9",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 168,
      "difficulty_id": 1,
      "explanation": "(a) 25.79 + 2.31 = 28.10 = 28.1. (b) The hundredths digit of 173.896 is 9 (≥ 5), so round the tenths up: 173.896 → 173.9.",
      "hints": ["For (a) line up the decimal points and add.", "For (b) look at the hundredths digit to round the tenths place."],
      "source": "Maha Bodhi 2025 P5 Weighted Assessment 2 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: (a) 28.1, (b) 173.9."
    },
    {
      "n": 3,
      "type_id": 2,
      "question": "The table shows the cost of sending a parcel to Town A: First 300 g costs $2; every additional 50 g or part thereof costs $0.35. How much does it cost to send a parcel that has a mass of 480 g? [?]",
      "answer0": "3.40",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 2,
      "explanation": "First 300 g = $2. Extra mass = 480 − 300 = 180 g, charged in 50 g blocks (part thereof rounds up): 180 ÷ 50 = 3 remainder 30, so 4 blocks. Cost = $2 + 4 × $0.35 = $2 + $1.40 = $3.40.",
      "hints": ["Charge the first 300 g at $2, then count the 50 g blocks for the rest.", "Round any part of a 50 g block up to a full block."],
      "source": "Maha Bodhi 2025 P5 Weighted Assessment 2 Q3",
      "image_needed": true,
      "image_options": false,
      "image_file": "q3.png",
      "image_page": 2,
      "image_bbox": [0.28, 0.14, 0.82, 0.21],
      "image_loc": "two-row charge table ('First 300 g $2' and 'Every additional 50 g or part thereof $0.35'), top of the page",
      "notes": "Answer key: $3.40 (key shows 180 ÷ 50 = 3 R 30 → 4 blocks). Answer in dollars."
    },
    {
      "n": 4,
      "type_id": 2,
      "question": "The figure is made up of squares ABCD and EFGC. The length of AB is twice the length of EF. What is the area of triangle AGD? [?]",
      "answer0": "972",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "AB = 36 cm, so EF = 36 ÷ 2 = 18 cm. The base DG = DC + CG = 36 + 18 = 54 cm and the height (AD) = 36 cm. Area of triangle AGD = ½ × 54 × 36 = 972 cm².",
      "hints": ["Find EF first: it is half of AB.", "The base DG runs across both squares; use ½ × base × height with height 36 cm."],
      "source": "Maha Bodhi 2025 P5 Weighted Assessment 2 Q4",
      "image_needed": true,
      "image_options": false,
      "image_file": "q4.png",
      "image_page": 3,
      "image_bbox": [0.34, 0.25, 0.64, 0.4],
      "image_loc": "two squares ABCD and EFGC forming a shaded triangle AGD, AB = 36 cm marked, upper-middle of the page",
      "notes": "Answer key: 972 cm². Answer in cm²."
    },
    {
      "n": 5,
      "type_id": 2,
      "question": "The figure is made up of rectangle PQST and triangle QRS. What is the area of the shaded part of the figure? [?]",
      "answer0": "6650",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Rectangle PQST area = 70 × 100 = 7000 m². Triangle QRS area = ½ × 40 × 70 = 1400 m², giving whole figure = 7000 + 1400 = 8400 m². The unshaded triangle = ½ × 100 × 35 = 1750 m². Shaded = 8400 − 1750 = 6650 m².",
      "hints": ["Find the rectangle and triangle areas to get the whole figure.", "Subtract the unshaded triangle (½ × 100 × 35)."],
      "source": "Maha Bodhi 2025 P5 Weighted Assessment 2 Q5",
      "image_needed": true,
      "image_options": false,
      "image_file": "q5.png",
      "image_page": 4,
      "image_bbox": [0.4, 0.16, 0.78, 0.3],
      "image_loc": "rectangle PQST joined to triangle QRS with shaded region, dimensions 70 m, 100 m, 40 m, 35 m, upper-middle of the page",
      "notes": "Answer key: 6650 m². Answer in m²."
    },
    {
      "n": 6,
      "type_id": 2,
      "question": "Container A has a square base with sides 15 cm and a height of 74 cm. Container A has 5850 cm³ of water in it. The capacity of Container B is 5 times the capacity of Container A.<br>(a) What is the capacity of Container B? [?]<br>(b) All the water in Container A is poured into Container B. How much more water is needed to fill Container B completely? [?]",
      "answer0": "83250",
      "answer1": "77400",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 193,
      "difficulty_id": 3,
      "explanation": "(a) Capacity of A = 15 × 15 × 74 = 16 650 cm³. Capacity of B = 5 × 16 650 = 83 250 cm³. (b) Container B holds 83 250 cm³; pouring in the 5850 cm³ of water leaves 83 250 − 5850 = 77 400 cm³ still needed.",
      "hints": ["For (a) find Container A's volume first, then multiply by 5.", "For (b) subtract the 5850 cm³ of water from Container B's capacity."],
      "source": "Maha Bodhi 2025 P5 Weighted Assessment 2 Q6",
      "image_needed": true,
      "image_options": false,
      "image_file": "q6.png",
      "image_page": 5,
      "image_bbox": [0.28, 0.18, 0.74, 0.36],
      "image_loc": "tall Container A (square base 15 cm, height 74 cm) beside the wider Container B cuboid, upper-middle of the page",
      "notes": "Answer key: (a) 83 250 cm³, (b) 77 400 cm³. Both answers in cm³."
    },
    {
      "n": 7,
      "type_id": 2,
      "question": "Matthew had $256.50 in the form of 10-cent, 20-cent and 50-cent coins. There are 4 times as many 50-cent coins as 20-cent coins. There are twice as many 20-cent coins as 10-cent coins. What is the value of 50-cent coins Matthew had? [?]",
      "answer0": "228",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "Let 10-cent coins = 1 unit. Then 20-cent coins = 2 units and 50-cent coins = 4 × 2 = 8 units. Value of one set: 8 × $0.50 + 2 × $0.20 + 1 × $0.10 = $4.00 + $0.40 + $0.10 = $4.50. Number of sets = $256.50 ÷ $4.50 = 57. Value of 50-cent coins = 57 × 8 × $0.50 = $228.",
      "hints": ["Set the 10-cent coins as 1 unit and express the others in units.", "Find the value of one whole 'unit-set', divide the total by it, then value the 50-cent coins."],
      "source": "Maha Bodhi 2025 P5 Weighted Assessment 2 Q7",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: $228. Answer in dollars."
    },
    {
      "n": 8,
      "type_id": 2,
      "question": "Jamie used unit cubes to form solids in a pattern (1st, 2nd, 3rd, ...).<br>(a) How many unit cubes are there in the 7th solid in this pattern? [?]<br>(b) To form a cube, what is the least number of unit cubes to be added to the 7th solid? [?]",
      "answer0": "63",
      "answer1": "280",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 193,
      "difficulty_id": 3,
      "explanation": "(a) Each n-th solid has 9 × n unit cubes (the cubes increase by 9 each step), so the 7th solid has 9 × 7 = 63 cubes. (b) The smallest cube that can contain it has edge 7, holding 7 × 7 × 7 = 343 cubes, so 343 − 63 = 280 more cubes are needed.",
      "hints": ["For (a) find how many cubes are added at each step in the pattern.", "For (b) the next perfect cube number (7³) minus the 7th solid's cubes."],
      "source": "Maha Bodhi 2025 P5 Weighted Assessment 2 Q8",
      "image_needed": true,
      "image_options": false,
      "image_file": "q8.png",
      "image_page": 7,
      "image_bbox": [0.22, 0.14, 0.82, 0.27],
      "image_loc": "three unit-cube solids labelled 1st, 2nd, 3rd showing the growing pattern, upper part of the page",
      "notes": "Answer key: (a) 63 cubes, (b) 280 cubes (7³ = 343, 343 − 63 = 280)."
    },
    {
      "n": 9,
      "type_id": 2,
      "question": "Linda bought 12 melons and 4 pears from a fruit stall. Brenda bought 4 melons and 12 pears from the same stall. Brenda paid $28.80 less than Linda. Each pear cost $1.80. How much did a melon cost? [?]",
      "answer0": "5.40",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "Linda has 8 more melons but 8 fewer pears than Brenda. The 8 fewer pears save Brenda 12 × $1.80 − 4 × $1.80 = 8 × $1.80 = $14.40. Since Brenda paid $28.80 less overall, the 8 extra melons Linda has cost $28.80 + $14.40 = $43.20. One melon = $43.20 ÷ 8 = $5.40.",
      "hints": ["Compare the two purchases: Linda has 8 more melons and 8 fewer pears.", "Account for the pear difference in price, then divide by 8 melons."],
      "source": "Maha Bodhi 2025 P5 Weighted Assessment 2 Q9",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer key: $5.40 (12 × 1.80 = 21.60; 21.60 − 7.20 = 14.40; 28.80 + 14.40 = 43.20; 43.20 ÷ 8 = $5.40). Answer in dollars."
    },
    {
      "n": 10,
      "type_id": 2,
      "question": "The figure is made up of square ABCD and triangle EBF. The area of Square ABCD is 196 cm² and AE = EB. Find the difference between area X and area Y. [?]",
      "answer0": "147",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Side of square = √196 = 14 cm. AE = EB = 14 ÷ 2 = 7 cm. The overlapping triangle (between X and Y) has area ½ × 14 × 7 = 49 cm². Difference X − Y = area of square − that triangle = 196 − 49 = 147 cm².",
      "hints": ["Find the square's side from its area, then AE = EB.", "Difference between X and Y equals the square's area minus the shared triangle (½ × 14 × 7)."],
      "source": "Maha Bodhi 2025 P5 Weighted Assessment 2 Q10",
      "image_needed": true,
      "image_options": false,
      "image_file": "q10.png",
      "image_page": 9,
      "image_bbox": [0.3, 0.18, 0.66, 0.35],
      "image_loc": "square ABCD with triangle EBF, shaded regions X and Y marked, upper-middle of the page",
      "notes": "Answer key: 147 cm² (196 ÷ 14 = 14; 14 ÷ 2 = 7; ½ × 14 × 7 = 49; 196 − 49 = 147). Answer in cm²."
    }
  ]
}