{
  "paper": {
    "school": "Pei Chun",
    "year": 2024,
    "level": "P5",
    "label": "Term 3 Review",
    "source_prefix": "Pei Chun 2024 P5 Term 3 Review",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 2,
      "question": "Find the value of \\(4.8 \\div 600\\). Express your answer as a decimal. [?]",
      "answer0": "0.008",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 166,
      "difficulty_id": 2,
      "explanation": "4.8 \\div 600 = 4.8 \\div 6 \\div 100 = 0.8 \\div 100 = 0.008.",
      "hints": ["Split 600 into 6 \\times 100.", "4.8 \\div 6 = 0.8, then divide by 100."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q1",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 0.008. Decimal answer, FIB is fine."
    },
    {
      "n": 2,
      "type_id": 2,
      "question": "Express 30.05 kg in grams. [?]",
      "answer0": "30050",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 184,
      "difficulty_id": 1,
      "explanation": "1 kg = 1000 g, so 30.05 kg = 30.05 \\times 1000 = 30 050 g.",
      "hints": ["Multiply kilograms by 1000 to get grams.", "30.05 \\times 1000 = 30 050."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 30050 g. Integer answer, FIB is fine."
    },
    {
      "n": 3,
      "type_id": 2,
      "question": "Round 4.187 to 2 decimal places. [?]",
      "answer0": "4.19",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 168,
      "difficulty_id": 1,
      "explanation": "Look at the 3rd decimal place (7), which is 5 or more, so round the 2nd decimal up: 4.187 → 4.19.",
      "hints": ["Look at the digit in the thousandths place.", "7 is 5 or more, so round the hundredths digit up."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q3",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 4.19. Decimal answer, FIB is fine."
    },
    {
      "n": 4,
      "type_id": 2,
      "question": "Express 0.025 as a percentage. [?]%",
      "answer0": "2.5",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 173,
      "difficulty_id": 1,
      "explanation": "To convert a decimal to a percentage, multiply by 100: 0.025 \\times 100 = 2.5%.",
      "hints": ["Multiply the decimal by 100.", "0.025 \\times 100 = 2.5."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q4",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 2.5% (the % is in the stem). Decimal answer, FIB is fine."
    },
    {
      "n": 5,
      "type_id": 2,
      "question": "Out of 50 customers, 37 of them were males. What percentage of the customers were males? [?]%",
      "answer0": "74",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 171,
      "difficulty_id": 2,
      "explanation": "Percentage of males = \\(\\dfrac{37}{50} \\times 100 = 74\\%\\).",
      "hints": ["Write the fraction \\(\\dfrac{37}{50}\\).", "Multiply by 100 to get the percentage."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q5",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 74%. Integer answer (the % is in the stem), FIB is fine."
    },
    {
      "n": 6,
      "type_id": 2,
      "question": "A machine makes 720 packets of noodles in 30 minutes. How many packets of noodles can the machine make in 1 minute? [?]",
      "answer0": "24",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 1,
      "explanation": "Packets per minute = 720 \\div 30 = 24.",
      "hints": ["Divide the total packets by the number of minutes.", "720 \\div 30 = 24."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 24 packets. Integer answer, FIB is fine."
    },
    {
      "n": 7,
      "type_id": 2,
      "question": "A piece of string measuring 1 m is cut into 8 equal smaller pieces. What is the length, in cm, of each smaller piece? Give your answer correct to the nearest centimetre. [?]",
      "answer0": "13",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 168,
      "difficulty_id": 2,
      "explanation": "1 m = 100 cm. Each piece = 100 \\div 8 = 12.5 cm. Rounded to the nearest centimetre this is 13 cm.",
      "hints": ["Convert 1 m to 100 cm, then divide by 8.", "12.5 cm rounds to 13 cm (nearest centimetre)."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q7",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 100 \\div 8 = 12.5 \\approx 13 cm. Integer answer, FIB is fine."
    },
    {
      "n": 8,
      "type_id": 2,
      "question": "The total mass of 6 identical packets of noodles is 2.85 kg. What is the mass, in kg, of 2 identical packets of noodles? [?]",
      "answer0": "0.95",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 2,
      "explanation": "Mass of 1 packet = 2.85 \\div 6 = 0.475 kg. Mass of 2 packets = 0.475 \\times 2 = 0.95 kg.",
      "hints": ["Find the mass of 1 packet first.", "Multiply the 1-packet mass by 2."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q8",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: (2.85 \\div 6) \\times 2 = 0.95 kg. Decimal answer, FIB is fine."
    },
    {
      "n": 9,
      "type_id": 2,
      "question": "A set lunch cost $10.28. What is the cost, in dollars, of 60 such set lunches? $[?]",
      "answer0": "616.80",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 2,
      "explanation": "Cost = 10.28 \\times 60 = 10.28 \\times 6 \\times 10 = 61.68 \\times 10 = $616.80.",
      "hints": ["Multiply $10.28 by 60.", "10.28 \\times 6 = 61.68, then \\times 10."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q9",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 616.8 → $616.80. Money decimal answer, FIB is fine."
    },
    {
      "n": 10,
      "type_id": 2,
      "question": "Container E holds 3 times as much milk as container G. They hold a total of 2.1 \\(\\ell\\) of milk. How much milk, in litres, does container G hold? [?]",
      "answer0": "0.525",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 183,
      "difficulty_id": 2,
      "explanation": "G = 1 unit, E = 3 units, total = 4 units = 2.1 L. 1 unit = 2.1 \\div 4 = 0.525 L, so container G holds 0.525 L.",
      "hints": ["Total is 4 equal units (1 for G, 3 for E).", "Divide 2.1 L by 4."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q10",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 2.1 L = 2100 ml, 2100 \\div 4 = 525 ml = 0.525 L. Decimal answer, FIB is fine."
    },
    {
      "n": 11,
      "type_id": 2,
      "question": "The usual price of a mobile phone was $1250. During a sale, it was sold at a discount of 30%. What was the price, in dollars, of the mobile phone after the discount? $[?]",
      "answer0": "875",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 176,
      "difficulty_id": 2,
      "explanation": "Discount = 30% of $1250 = 0.3 \\times 1250 = $375. Price after discount = 1250 - 375 = $875.",
      "hints": ["Find 30% of $1250 (the discount).", "Subtract the discount from the usual price."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 1250 - 375 = $875. Integer money answer, FIB is fine."
    },
    {
      "n": 12,
      "type_id": 2,
      "question": "The table shows the postage rates for mailing letters in Singapore: mass step not over 20 g costs $0.85; not over 50 g costs $1.05; not over 100 g costs $1.45; not over 250 g costs $3.65. Wei Tong mailed a letter weighing 35 g and another letter weighing 200 g. How much postage, in dollars, did Wei Tong pay altogether? $[?]",
      "answer0": "4.70",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 2,
      "explanation": "35 g falls in the 'not over 50 g' step = $1.05. 200 g falls in the 'not over 250 g' step = $3.65. Total = 1.05 + 3.65 = $4.70.",
      "hints": ["Find which mass step each letter falls into.", "Add the two postage charges."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q12",
      "image_needed": true,
      "image_options": false,
      "image_file": "fig-q12.png",
      "image_page": 6,
      "image_bbox": [0.2, 0.55, 0.68, 0.72],
      "image_loc": "postage-rates table: 'Mass Step Not Over' vs 'Postage', rows 20 g/$0.85, 50 g/$1.05, 100 g/$1.45, 250 g/$3.65",
      "notes": "Key: 1.05 + 3.65 = $4.70. Money decimal answer, FIB is fine. Table needed as the figure so the rate steps are visible."
    },
    {
      "n": 13,
      "type_id": 2,
      "question": "Tank A and Tank B had an equal amount of water at first. After 25.5 \\(\\ell\\) of water from Tank A and 90.3 \\(\\ell\\) of water from Tank B was used, Tank A had 5 times as much water left as Tank B. How much water, in litres, was left in Tank B? [?]",
      "answer0": "16.2",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Both tanks started equal. The extra water used from B over A is 90.3 - 25.5 = 64.8 L, which is the difference between the two amounts left. Tank A left = 5 units, Tank B left = 1 unit, so 5 - 1 = 4 units = 64.8 L → 1 unit = 64.8 \\div 4 = 16.2 L. Tank B has 16.2 L left.",
      "hints": ["The difference in water used (90.3 - 25.5) equals the difference in water left.", "That difference is 4 units (5 - 1); 1 unit = Tank B's remaining water."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q13",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 4 units = 90300 - 25500 = 64800 ml, 1 unit = 16200 ml = 16.2 L. Decimal answer, FIB is fine."
    },
    {
      "n": 14,
      "type_id": 2,
      "question": "Shernise baked 400 cookies on Monday. 30% of the cookies she baked on Monday were chocolate cookies and the rest were peanut cookies. She baked another 100 chocolate cookies on Tuesday.<br>(a) How many chocolate cookies did she bake altogether on Monday and Tuesday? [?]<br>(b) What percentage of the cookies she baked were peanut cookies at the end of the two days? [?]%",
      "answer0": "220",
      "answer1": "56",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 175,
      "difficulty_id": 3,
      "explanation": "(a) Chocolate on Monday = 30% of 400 = 0.3 \\times 400 = 120. Total chocolate = 120 + 100 (Tuesday) = 220. (b) Total cookies = 400 + 100 = 500. Peanut cookies = 500 - 220 = 280. Percentage = \\(\\dfrac{280}{500} = 0.56 = 56\\%\\).",
      "hints": ["(a) Find Monday's chocolate cookies (30% of 400) and add the 100 from Tuesday.", "(b) Peanut = total cookies (500) minus all chocolate (220); convert to a percentage."],
      "source": "Pei Chun 2024 P5 Term 3 Review Q14",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 14a) 220 chocolate cookies, 14b) 56% peanut (the % is in the stem). Both FIB-fine."
    }
  ]
}