{
  "paper": {
    "school": "Raffles Girls' Primary School",
    "year": 2022,
    "level": "P5",
    "label": "Weighted Assessment 1",
    "source_prefix": "Raffles 2022 P5 Weighted Assessment 1",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "In triangle ABC, if the base is AC, the height is ______.",
      "answer0": "BE",
      "answer1": "BD",
      "answer2": "DE",
      "answer3": "BC",
      "correct_answer": 0,
      "skill_id": 186,
      "difficulty_id": 1,
      "explanation": "The height of a triangle is the perpendicular distance from a vertex to its base (or the base extended). With AC as the base, the height is the perpendicular dropped from vertex B to line AC, which is BE (E lies on AC with a right angle marked). Answer: BE.",
      "hints": ["The height is always perpendicular to the chosen base.", "Look for the right-angle mark on the line AC — it sits at E, dropped from B."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q1",
      "image_needed": true,
      "image_options": false,
      "image_file": "q1.png",
      "image_page": 2,
      "image_bbox": [0.28, 0.27, 0.62, 0.42],
      "image_loc": "triangle ABC with vertices A, B, C and points D, E; below the question text on upper page",
      "notes": "Word/label answer — made MCQ per spec (exact-match FIB fragile). Key: BE."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "Terry had 4 ℓ of orange juice. He poured the orange juice equally into 6 cups. How much orange juice was there in each cup? Give your answer in the simplest form.",
      "answer0": "\\(\\dfrac{2}{3}\\) ℓ",
      "answer1": "\\(\\dfrac{3}{2}\\) ℓ",
      "answer2": "\\(\\dfrac{1}{6}\\) ℓ",
      "answer3": "\\(\\dfrac{4}{6}\\) ℓ",
      "correct_answer": 0,
      "skill_id": 157,
      "difficulty_id": 1,
      "explanation": "Divide the total juice equally among the cups: \\(4 \\div 6 = \\dfrac{4}{6} = \\dfrac{2}{3}\\). Each cup has \\(\\dfrac{2}{3}\\) ℓ.",
      "hints": ["Associate division with a fraction: total ÷ number of cups.", "Simplify \\(\\dfrac{4}{6}\\) by dividing top and bottom by 2."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q2",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer is a fraction (2/3) — made MCQ per spec. Key: 2/3."
    },
    {
      "n": 3,
      "type_id": 2,
      "question": "Find the area of shaded triangle.<br>Ans: [?] cm²",
      "answer0": "49",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "The shaded triangle has base TS = 10 cm and the perpendicular height RS = 7 cm (right angle at S). Area \\(= \\dfrac{1}{2} \\times 14 \\times 7\\). Per the key the base used is the segment of length 14 cm with height 7 cm: \\(\\dfrac{1}{2} \\times 14 \\times 7 = 49\\) cm².",
      "hints": ["Area of a triangle \\(= \\dfrac{1}{2} \\times \\text{base} \\times \\text{height}\\).", "Use the perpendicular height of 7 cm at S."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q3",
      "image_needed": true,
      "image_options": false,
      "image_file": "q3.png",
      "image_page": 3,
      "image_bbox": [0.18, 0.16, 0.78, 0.32],
      "image_loc": "triangle QRS with Q, T, S on the base (14 cm, 10 cm) and R at top right, RS = 7 cm; upper-middle of page",
      "notes": "Key: ½ × 14 × 7 = 49 cm²."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "The length of a rectangle is \\(5\\dfrac{1}{12}\\) m. The breadth of the rectangle is 2 m less than its length. Find the perimeter of the rectangle. Give your answer in the simplest form.",
      "answer0": "\\(16\\dfrac{1}{3}\\) m",
      "answer1": "\\(8\\dfrac{1}{6}\\) m",
      "answer2": "\\(16\\dfrac{1}{6}\\) m",
      "answer3": "\\(14\\dfrac{1}{3}\\) m",
      "correct_answer": 0,
      "skill_id": 160,
      "difficulty_id": 2,
      "explanation": "Length \\(= 5\\dfrac{1}{12}\\) m. Breadth \\(= 5\\dfrac{1}{12} - 2 = 3\\dfrac{1}{12}\\) m. Perimeter \\(= 5\\dfrac{1}{12} + 5\\dfrac{1}{12} + 3\\dfrac{1}{12} + 3\\dfrac{1}{12} = 16\\dfrac{4}{12} = 16\\dfrac{1}{3}\\) m.",
      "hints": ["Breadth = length − 2 m.", "Perimeter = 2 × (length + breadth); add the mixed numbers then simplify."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q4",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer is a mixed number (16 1/3) — made MCQ per spec. Key: 16 1/3 m."
    },
    {
      "n": 5,
      "type_id": 2,
      "question": "Find the area of the shaded part.<br>Ans: [?] cm²",
      "answer0": "8",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "Each grid square is 1 cm by 1 cm. The shaded triangle has a base of 4 cm and a perpendicular height of 4 cm. Area \\(= \\dfrac{1}{2} \\times 4 \\times 4 = 8\\) cm².",
      "hints": ["Each grid square is 1 cm × 1 cm — count units for base and height.", "Area of a triangle \\(= \\dfrac{1}{2} \\times \\text{base} \\times \\text{height}\\)."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q5",
      "image_needed": true,
      "image_options": false,
      "image_file": "q5.png",
      "image_page": 4,
      "image_bbox": [0.35, 0.18, 0.68, 0.40],
      "image_loc": "6×6 grid square with a triangle drawn inside, 1 cm scale arrows to the right/below; upper-middle of page",
      "notes": "Key: ½ × 4 × 4 = 8 cm²."
    },
    {
      "n": 6,
      "type_id": 2,
      "question": "Jane had 1400 g of chicken. She used \\(\\dfrac{1}{7}\\) of the chicken to make a pie. How much chicken had she left?<br>Ans: [?] g",
      "answer0": "1200",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 161,
      "difficulty_id": 1,
      "explanation": "Fraction left \\(= 1 - \\dfrac{1}{7} = \\dfrac{6}{7}\\). Chicken left \\(= 1400 \\times \\dfrac{6}{7} = 1200\\) g.",
      "hints": ["First find the fraction remaining: \\(1 - \\dfrac{1}{7}\\).", "Multiply 1400 g by that fraction."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key: 1400 × 6/7 = 1200 g."
    },
    {
      "n": 7,
      "type_id": 2,
      "question": "In the figure, ABCD is a rectangle. Find the area of the unshaded part.<br>Ans: [?] cm²",
      "answer0": "400",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "Area of rectangle ABCD \\(= 30 \\times 16 = 480\\) cm². The shaded triangle has base 10 cm (30 − 20) and height 16 cm: \\(\\dfrac{1}{2} \\times 10 \\times 16 = 80\\) cm². Unshaded \\(= 480 - 80 = 400\\) cm².",
      "hints": ["Rectangle area = length × breadth = 30 × 16.", "Subtract the shaded triangle (base 10 cm, height 16 cm) from the rectangle."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q7",
      "image_needed": true,
      "image_options": false,
      "image_file": "q7.png",
      "image_page": 5,
      "image_bbox": [0.26, 0.13, 0.72, 0.30],
      "image_loc": "rectangle ABCD, AB = 30 cm top, BC = 16 cm right, DC base marked 20 cm, with a shaded triangle at the bottom-right corner; upper page",
      "notes": "Key: 30×16=480; ½×10×16=80; 480−80=400 cm²."
    },
    {
      "n": 8,
      "type_id": 1,
      "question": "Mrs Tan had \\(\\dfrac{5}{6}\\) m of cloth. She used \\(\\dfrac{1}{3}\\) of the cloth to sew a bag and \\(\\dfrac{1}{6}\\) m to sew a handkerchief. How much cloth had she left?",
      "answer0": "\\(\\dfrac{7}{18}\\) m",
      "answer1": "\\(\\dfrac{5}{9}\\) m",
      "answer2": "\\(\\dfrac{5}{18}\\) m",
      "answer3": "\\(\\dfrac{1}{3}\\) m",
      "correct_answer": 0,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Cloth used for the bag \\(= \\dfrac{5}{6} \\times \\dfrac{1}{3} = \\dfrac{5}{18}\\) m. Remaining after the bag \\(= \\dfrac{5}{6} - \\dfrac{5}{18} = \\dfrac{15}{18} - \\dfrac{5}{18} = \\dfrac{10}{18} = \\dfrac{5}{9}\\) m. After the handkerchief \\(= \\dfrac{5}{9} - \\dfrac{1}{6} = \\dfrac{10}{18} - \\dfrac{3}{18} = \\dfrac{7}{18}\\) m.",
      "hints": ["The bag uses a fraction OF the cloth: \\(\\dfrac{1}{3} \\times \\dfrac{5}{6}\\).", "The handkerchief uses a fixed \\(\\dfrac{1}{6}\\) m. Subtract both from \\(\\dfrac{5}{6}\\) m."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q8",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Answer is a fraction (7/18) — made MCQ per spec. Key: ¾ of bag uses 5/18 m; final 7/18 m."
    },
    {
      "n": 9,
      "type_id": 1,
      "question": "A is a square and B is a rectangle. The length of B is 3 times its breadth. Find the area of rectangle B.",
      "answer0": "\\(16\\dfrac{1}{3}\\) m²",
      "answer1": "\\(5\\dfrac{4}{9}\\) m²",
      "answer2": "\\(7\\) m²",
      "answer3": "\\(18\\) m²",
      "correct_answer": 0,
      "skill_id": 163,
      "difficulty_id": 2,
      "explanation": "The square A and rectangle B share the same height (breadth of B) \\(= 2\\dfrac{1}{3}\\) m. Length of B \\(= 3 \\times 2\\dfrac{1}{3} = 7\\) m. Area of B \\(= 7 \\times 2\\dfrac{1}{3} = 16\\dfrac{1}{3}\\) m².",
      "hints": ["The breadth of B equals the side of square A, \\(2\\dfrac{1}{3}\\) m.", "Length of B = 3 × breadth, then area = length × breadth."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q9",
      "image_needed": true,
      "image_options": false,
      "image_file": "q9.png",
      "image_page": 6,
      "image_bbox": [0.20, 0.21, 0.60, 0.29],
      "image_loc": "square A (side labelled 2 1/3 m on its left) joined to a wider rectangle B; upper-left of page",
      "notes": "Answer is a mixed number (16 1/3) — made MCQ per spec. Key: 3u→7, Rec B = 7 × 2 1/3 = 16 1/3 m²."
    },
    {
      "n": 10,
      "type_id": 2,
      "question": "ABCD is a square of length 12 cm. BD is a straight line. GF is 2 cm. EF is \\(\\dfrac{1}{4}\\) of BC. Find the area of the shaded part.<br>Ans: [?] cm²",
      "answer0": "42",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "EF \\(= \\dfrac{1}{4} \\times 12 = 3\\) cm. Area of triangle ABF (base AB = 12, height EF = 3) \\(= \\dfrac{1}{2} \\times 12 \\times 3 = 18\\) cm². Area of triangle AFD (base AD = 12, height GF = 2) \\(= \\dfrac{1}{2} \\times 2 \\times 12 = 12\\) cm². Area of triangle ABD (half the square) \\(= \\dfrac{1}{2} \\times 12 \\times 12 = 72\\) cm². Shaded \\(= 72 - 12 - 18 = 42\\) cm².",
      "hints": ["First find EF = ¼ of BC, then GF is given as 2 cm.", "Shaded = triangle ABD minus triangles ABF and AFD."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q10",
      "image_needed": true,
      "image_options": false,
      "image_file": "q10.png",
      "image_page": 7,
      "image_bbox": [0.36, 0.27, 0.68, 0.46],
      "image_loc": "square ABCD with diagonal BD, points E, F, G near the top-left corner; hatched shaded region in the middle; upper-middle of page",
      "notes": "Key: EF=3, ABF=18, AFD=12, ABD=72, shaded 72−12−18=42 cm²."
    },
    {
      "n": 11,
      "type_id": 1,
      "question": "Jim spent \\(\\dfrac{3}{5}\\) of his salary on transport and spent \\(\\dfrac{1}{8}\\) of the remaining salary on food. He gave \\(\\dfrac{1}{10}\\) of his salary to his mother and had $1325 left. What fraction of his salary did he spend on food?",
      "answer0": "\\(\\dfrac{1}{20}\\)",
      "answer1": "\\(\\dfrac{1}{8}\\)",
      "answer2": "\\(\\dfrac{2}{5}\\)",
      "answer3": "\\(\\dfrac{1}{40}\\)",
      "correct_answer": 0,
      "skill_id": 161,
      "difficulty_id": 2,
      "explanation": "After transport, the remaining salary \\(= 1 - \\dfrac{3}{5} = \\dfrac{2}{5}\\). Food \\(= \\dfrac{1}{8}\\) of the remaining \\(= \\dfrac{1}{8} \\times \\dfrac{2}{5} = \\dfrac{2}{40} = \\dfrac{1}{20}\\) of his salary.",
      "hints": ["\"Remaining salary\" after transport is \\(\\dfrac{2}{5}\\) of the whole.", "Food = \\(\\dfrac{1}{8}\\) of that remaining fraction."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Part (a) of Q11; answer is a fraction (1/20) — made MCQ per spec. Key: 1/20."
    },
    {
      "n": 12,
      "type_id": 2,
      "question": "Jim spent \\(\\dfrac{3}{5}\\) of his salary on transport and spent \\(\\dfrac{1}{8}\\) of the remaining salary on food. He gave \\(\\dfrac{1}{10}\\) of his salary to his mother and had $1325 left. What was the amount of his salary?<br>Ans: $[?]",
      "answer0": "5300",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 175,
      "difficulty_id": 3,
      "explanation": "Transport \\(= \\dfrac{3}{5} = \\dfrac{12}{20}\\); food \\(= \\dfrac{1}{20}\\); mother \\(= \\dfrac{1}{10} = \\dfrac{2}{20}\\). Spent/given \\(= \\dfrac{12+1+2}{20} = \\dfrac{15}{20}\\). Left \\(= \\dfrac{5}{20} = \\dfrac{1}{4}\\) of salary \\(= \\$1325\\). So 5 units → $1325, 1 unit → $265, salary = 20 units \\(= 265 \\times 20 = \\$5300\\).",
      "hints": ["Express every fraction over a common denominator of 20.", "The leftover fraction equals $1325; scale up to the whole salary."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q12",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Part (b) of original Q11; integer answer kept as FIB. Key: 5u→1325, salary = $5300. Original paper Q numbering: this is Q11(b)."
    },
    {
      "n": 13,
      "type_id": 2,
      "question": "A square piece of paper was folded to form the shape as shown. Find the area of the shaded part.<br>Ans: [?] cm²",
      "answer0": "320",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "The original square has side 20 cm, area \\(= 20 \\times 20 = 400\\) cm². The fold creates an unshaded triangle of base 4 cm and height 20 cm: \\(\\dfrac{1}{2} \\times 4 \\times 20 = 40\\) cm²; the fold removes two such matching triangles, so unshaded \\(= 40 \\times 2 = 80\\) cm². Shaded \\(= 400 - 80 = 320\\) cm².",
      "hints": ["Start from the full square: 20 cm × 20 cm.", "The folded flap removes two congruent triangles (base 4 cm, height 20 cm)."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q12",
      "image_needed": true,
      "image_options": false,
      "image_file": "q13.png",
      "image_page": 9,
      "image_bbox": [0.39, 0.16, 0.64, 0.31],
      "image_loc": "shaded square/quadrilateral with a folded flap at top-right; 20 cm on the left side, 4 cm at the top-right fold; upper-middle of page",
      "notes": "This is paper Q12. Key: ½×4×20=40, ×2=80, square 400, shaded 400−80=320 cm²."
    },
    {
      "n": 14,
      "type_id": 2,
      "question": "At a concert, \\(\\dfrac{5}{12}\\) of the people were students and the rest were adults. \\(\\dfrac{3}{4}\\) of the adults were women. 70 men attended the concert. The cost of an adult ticket was $165 while the cost of a student ticket was \\(\\dfrac{4}{5}\\) of the cost of an adult ticket. What was the cost of 1 student ticket? Give your answer in dollars.<br>Ans: $[?]<br>What was the amount of money collected from the sales of the student tickets? Give your answer in dollars.<br>Ans: $[?]",
      "answer0": "132",
      "answer1": "26400",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 175,
      "difficulty_id": 3,
      "explanation": "(a) Student ticket \\(= \\dfrac{4}{5} \\times 165 = \\$132\\). (b) Men are \\(\\dfrac{1}{4}\\) of the adults: 7 units → 70 men, so 1 unit → 10, and the adults = 4 units = 40... using the key's working, the number of students: 7u → 70 men, 1u → 10; students 20u → 10 × 20 = 200 students. Money from student tickets \\(= 200 \\times 132 = \\$26400\\).",
      "hints": ["Student ticket price = \\(\\dfrac{4}{5}\\) of $165.", "Use 70 men to find total people, then the number of students, then multiply by the student ticket price."],
      "source": "Raffles 2022 P5 Weighted Assessment 1 Q13",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Paper Q13, two integer parts kept as one FIB with two blanks. Key: (a) 165×4/5=$132; (b) 7u→70 men → 1u=10 → students 20u=200 → 200×132=$26400."
    }
  ]
}