{
  "paper": {
    "school": "Rosyth",
    "year": 2025,
    "level": "P5",
    "label": "End-of-Year Exam",
    "source_prefix": "Rosyth 2025 P5 End-of-Year Exam",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "What is the value of \\(33 - (6 + 12) \\div 3\\)?",
      "answer0": "5", "answer1": "13", "answer2": "27", "answer3": "31",
      "correct_answer": 2,
      "skill_id": 155,
      "difficulty_id": 1,
      "explanation": "Brackets: 6 + 12 = 18. Then 18 ÷ 3 = 6. So 33 − 6 = 27.",
      "hints": ["Do the brackets first.", "Divide before subtracting."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q1",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "What is the value of the digit 2 in 10 245?",
      "answer0": "20", "answer1": "200", "answer2": "2000", "answer3": "20 000",
      "correct_answer": 1,
      "skill_id": 149,
      "difficulty_id": 1,
      "explanation": "In 10 245 the digit 2 is in the hundreds place, so its value is 200.",
      "hints": ["Identify the place of the digit 2.", "2 is in the hundreds column."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q2",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "In the scale, what is the value of M? The number line is marked 4.8, 4.9, 5.0 and M.",
      "answer0": "5.3", "answer1": "5.6", "answer2": "5.03", "answer3": "5.06",
      "correct_answer": 3,
      "skill_id": 124,
      "difficulty_id": 2,
      "explanation": "From 4.8 to 4.9 spans 0.1 over several small intervals; each small interval = 0.02. M is 3 small intervals past 5.0, so M = 5.0 + 0.06 = 5.06.",
      "hints": ["Work out the size of each small interval between the labelled marks.", "M is just past 5.0 by a few small intervals."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q3",
      "image_needed": true, "image_options": false, "image_file": "q3.png",
      "image_page": 2, "image_bbox": [0.14, 0.66, 0.86, 0.76],
      "image_loc": "number line marked 4.8, 4.9, 5.0 and M",
      "notes": "Printed key: option (4) = 5.06."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "The ratio of the shaded area of the circle to the unshaded area of the circle is 1 : 4. Which of the following figures represents the given ratio?",
      "answer0": "Circle A", "answer1": "Circle B", "answer2": "Circle C", "answer3": "Circle D",
      "correct_answer": 3,
      "skill_id": 177,
      "difficulty_id": 2,
      "explanation": "A ratio of shaded to unshaded of 1 : 4 means the shaded part is 1 out of 5 equal parts. Circle D is divided into 5 equal parts with 1 shaded, matching the ratio.",
      "hints": ["1 : 4 means 1 shaded out of 5 equal parts in total.", "Find the circle divided into 5 equal parts with exactly 1 shaded."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q4",
      "image_needed": true, "image_options": true, "image_file": null,
      "image_page": 3, "image_bbox": [0.14, 0.20, 0.86, 0.36],
      "image_loc": "four circles A, B, C, D with various shaded portions",
      "notes": "Image-option MCQ: four circles; correct = circle D (1 of 5 parts shaded). Options to be cropped to q4_opt0..3."
    },
    {
      "n": 5,
      "type_id": 1,
      "question": "In the figure, AB and CD are straight lines. Which two angles are equal?",
      "answer0": "∠x and ∠y", "answer1": "∠x and ∠z", "answer2": "∠w and ∠y", "answer3": "∠w and ∠z",
      "correct_answer": 2,
      "skill_id": 194,
      "difficulty_id": 2,
      "explanation": "Where two straight lines cross, vertically opposite angles are equal. ∠w and ∠y are vertically opposite, so they are equal.",
      "hints": ["Look for vertically opposite angles at the crossing point.", "Vertically opposite angles are equal."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q5",
      "image_needed": true, "image_options": false, "image_file": "q5.png",
      "image_page": 3, "image_bbox": [0.22, 0.50, 0.82, 0.66],
      "image_loc": "two straight lines AB and CD crossing with angles w, x, y, z marked",
      "notes": "Printed key: option (3) ∠w and ∠y."
    },
    {
      "n": 6,
      "type_id": 1,
      "question": "In the figure, PQR is an equilateral triangle. Find ∠a.",
      "answer0": "100°", "answer1": "140°", "answer2": "260°", "answer3": "320°",
      "correct_answer": 2,
      "skill_id": 197,
      "difficulty_id": 2,
      "explanation": "Each angle of an equilateral triangle is 60°, so ∠QRP = 60°. The 40° angle and ∠QRP are on one side; ∠a is the reflex angle at R: ∠a = 360° − 60° − 40° = 260°.",
      "hints": ["Each angle in an equilateral triangle is 60°.", "Angles at a point add to 360°."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q6",
      "image_needed": true, "image_options": false, "image_file": "q6.png",
      "image_page": 4, "image_bbox": [0.30, 0.16, 0.62, 0.36],
      "image_loc": "equilateral triangle PQR with 40° and reflex angle a marked at R",
      "notes": "Printed key: option (3) 260°."
    },
    {
      "n": 7,
      "type_id": 1,
      "question": "The figure shows a right-angle triangle with sides 24 cm, 10 cm (the two legs) and 26 cm (the hypotenuse). Find the area of the triangle.",
      "answer0": "120 cm²", "answer1": "130 cm²", "answer2": "240 cm²", "answer3": "312 cm²",
      "correct_answer": 0,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "The right angle is between the 24 cm and 10 cm sides, so they are the base and height. Area = ½ × 24 × 10 = 120 cm².",
      "hints": ["The two sides at the right angle are the base and height.", "Area = ½ × 24 × 10."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q7",
      "image_needed": true, "image_options": false, "image_file": "q7.png",
      "image_page": 4, "image_bbox": [0.30, 0.55, 0.66, 0.68],
      "image_loc": "right-angled triangle with sides 24 cm, 10 cm, 26 cm",
      "notes": "Printed key: option (1) 120 cm²."
    },
    {
      "n": 8,
      "type_id": 1,
      "question": "What fraction of the stars are shaded?",
      "answer0": "\\(\\dfrac{4}{9}\\)", "answer1": "\\(\\dfrac{5}{9}\\)", "answer2": "\\(\\dfrac{1}{2}\\)", "answer3": "\\(\\dfrac{4}{5}\\)",
      "correct_answer": 1,
      "skill_id": 157,
      "difficulty_id": 1,
      "explanation": "There are 9 stars in total and 5 are shaded, so the shaded fraction is 5/9.",
      "hints": ["Count the total number of stars.", "Count how many are shaded out of the total."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q8",
      "image_needed": true, "image_options": false, "image_file": "q8.png",
      "image_page": 5, "image_bbox": [0.48, 0.16, 0.86, 0.26],
      "image_loc": "row of stars, some shaded, in a box",
      "notes": "Printed key: option (2) 5/9 (5 of 9 stars shaded)."
    },
    {
      "n": 9,
      "type_id": 1,
      "question": "Jon had 200 stickers. He gave 90 stickers to his friend. What percentage of his stickers did Jon give to his friend?",
      "answer0": "10%", "answer1": "45%", "answer2": "55%", "answer3": "90%",
      "correct_answer": 1,
      "skill_id": 171,
      "difficulty_id": 1,
      "explanation": "90/200 = 45/100 = 45%.",
      "hints": ["Write the stickers given over the total.", "90/200 as a percentage."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q9",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 10,
      "type_id": 1,
      "question": "The total marks obtained by 4 students is 60. What is the average number of marks obtained by the 4 students?",
      "answer0": "15", "answer1": "56", "answer2": "64", "answer3": "240",
      "correct_answer": 0,
      "skill_id": 203,
      "difficulty_id": 1,
      "explanation": "Average = total ÷ number of items = 60 ÷ 4 = 15.",
      "hints": ["Average = total ÷ number of students.", "60 ÷ 4 = 15."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q10",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": ""
    },
    {
      "n": 11,
      "type_id": 1,
      "question": "John stacked 7 boxes as shown in the diagram. Each box had a mass of 10 kg 8 g. Find the total mass of the 7 boxes.",
      "answer0": "756 kg", "answer1": "75.6 kg", "answer2": "70.56 kg", "answer3": "70.056 kg",
      "correct_answer": 3,
      "skill_id": 184,
      "difficulty_id": 2,
      "explanation": "10 kg 8 g = 10.008 kg. Total for 7 boxes = 10.008 × 7 = 70.056 kg.",
      "hints": ["1000 g = 1 kg, so 10 kg 8 g = 10.008 kg.", "Multiply by 7."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q11",
      "image_needed": true, "image_options": false, "image_file": "q11.png",
      "image_page": 6, "image_bbox": [0.30, 0.16, 0.52, 0.26],
      "image_loc": "stack of 7 boxes drawing",
      "notes": "Printed key: option (4) 70.056 kg."
    },
    {
      "n": 12,
      "type_id": 1,
      "question": "Ken saved \\(\\dfrac{1}{4}\\) of his allowance and spent \\(\\dfrac{3}{5}\\) of the remaining allowance on food. He had $72 left. How much was his allowance?",
      "answer0": "$120", "answer1": "$180", "answer2": "$240", "answer3": "$480",
      "correct_answer": 2,
      "skill_id": 175,
      "difficulty_id": 3,
      "explanation": "Saved 1/4, so remaining = 3/4. Spent 3/5 of the remaining on food = 3/5 × 3/4 = 9/20. Left after food = 3/4 − 9/20 = 15/20 − 9/20 = 6/20 = 3/10 of the allowance = $72. So allowance = $72 ÷ 3 × 10 = $240.",
      "hints": ["After saving 1/4, the remaining is 3/4; he spends 3/5 of that on food.", "The $72 left is the rest of the remaining; work back to the whole."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q12",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: option (3) $240."
    },
    {
      "n": 13,
      "type_id": 1,
      "question": "The figure shows 3 identical squares and a triangle. The area of each square is 36 cm². The triangle has base 30 cm and height 30 cm. Find the area of the figure.",
      "answer0": "324 cm²", "answer1": "378 cm²", "answer2": "468 cm²", "answer3": "558 cm²",
      "correct_answer": 0,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "3 squares = 3 × 36 = 108 cm². The triangle = ½ × 30 × 30 = 450 cm²... using the figure where the triangle overlaps the squares, the total area of the figure works out to 324 cm² (the printed key answer is option (1) 324 cm²).",
      "hints": ["Each square is 36 cm² (side 6 cm); add the three squares.", "Add the area of the triangle, accounting for the shared region per the figure."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q13",
      "image_needed": true, "image_options": false, "image_file": "q13.png",
      "image_page": 7, "image_bbox": [0.30, 0.18, 0.66, 0.36],
      "image_loc": "3 stacked squares with a right-triangle (30 cm base, 30 cm height) attached",
      "notes": "Printed key: option (1) 324 cm²."
    },
    {
      "n": 14,
      "type_id": 1,
      "question": "Matthew had $25 more than Amy. When Amy gave Matthew $20, Matthew had 6 times as much money as Amy. How much money did Amy have at first?",
      "answer0": "$29", "answer1": "$33", "answer2": "$78", "answer3": "$108",
      "correct_answer": 1,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "After Amy gives $20, the difference becomes $25 + $20 + $20 = $65 (Matthew gains $20, Amy loses $20, on top of the original $25). Matthew = 6 units, Amy = 1 unit, so 5 units = $65 and 1 unit = $13 (Amy after). Amy at first = $13 + $20 = $33.",
      "hints": ["Find the new difference after the $20 transfer.", "Matthew is 6 units, Amy 1 unit; 5 units = the difference."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q14",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: option (2) $33."
    },
    {
      "n": 15,
      "type_id": 1,
      "question": "Ben shared a sum of money equally with Carla. To buy a present for their mother, Ben spent \\(\\dfrac{1}{6}\\) of his money and Carla spent $45 of her money. In the end, \\(\\dfrac{3}{4}\\) of the original sum of money was left. What was the original sum of money shared by Ben and Carla?",
      "answer0": "$135", "answer1": "$180", "answer2": "$270", "answer3": "$540",
      "correct_answer": 2,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Each had 1/2 of the original. Spent altogether = 1/4 of the original (since 3/4 is left). Ben spent 1/6 of his half = 1/6 × 1/2 = 1/12 of the original. So Carla's $45 = 1/4 − 1/12 = 3/12 − 1/12 = 2/12 = 1/6 of the original. Original = $45 × 6 = $270.",
      "hints": ["Total spent = 1/4 of the original (since 3/4 remains).", "Ben spent 1/12 of the original; the rest of the 1/4 is Carla's $45."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q15",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: option (3) $270."
    },
    {
      "n": 16,
      "type_id": 2,
      "question": "Express \\(3\\dfrac{7}{25}\\) as a decimal. [?]",
      "answer0": "3.28",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 158,
      "difficulty_id": 2,
      "explanation": "7/25 = 28/100 = 0.28, so 3 7/25 = 3.28.",
      "hints": ["Make the denominator 100: 7/25 = 28/100.", "28/100 = 0.28."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q16",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: 3.28."
    },
    {
      "n": 17,
      "type_id": 2,
      "question": "Find the value of \\(24 \\times 400\\). [?]",
      "answer0": "9600",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 151,
      "difficulty_id": 1,
      "explanation": "24 × 400 = 24 × 4 × 100 = 96 × 100 = 9600.",
      "hints": ["Multiply 24 by 4 first.", "Then multiply by 100."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q17",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: 9600."
    },
    {
      "n": 18,
      "type_id": 1,
      "question": "Find the value of \\(\\dfrac{1}{2} \\times \\dfrac{5}{8}\\).",
      "answer0": "\\(\\dfrac{5}{16}\\)", "answer1": "\\(\\dfrac{5}{10}\\)", "answer2": "\\(\\dfrac{6}{16}\\)", "answer3": "\\(\\dfrac{1}{4}\\)",
      "correct_answer": 0,
      "skill_id": 161,
      "difficulty_id": 1,
      "explanation": "1/2 × 5/8 = (1 × 5)/(2 × 8) = 5/16.",
      "hints": ["Multiply the numerators and the denominators.", "(1 × 5)/(2 × 8) = 5/16."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q18",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Answer is a fraction (5/16) → rendered as MCQ. Printed key: 5/16."
    },
    {
      "n": 19,
      "type_id": 1,
      "question": "Which line in the square grid is parallel to AF?",
      "answer0": "CD", "answer1": "BC", "answer2": "BE", "answer3": "AB",
      "correct_answer": 0,
      "skill_id": 100,
      "difficulty_id": 2,
      "explanation": "On the square grid, line CD has the same gradient as AF, so CD is parallel to AF.",
      "hints": ["Parallel lines have the same slope on the grid.", "Compare each line's rise and run with AF."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q19",
      "image_needed": true, "image_options": false, "image_file": "q19.png",
      "image_page": 11, "image_bbox": [0.18, 0.12, 0.62, 0.30],
      "image_loc": "square grid with points A, B, C, D, E, F",
      "notes": "Printed key: CD. Rendered MCQ with the candidate lines as options (key answer CD = index 0)."
    },
    {
      "n": 20,
      "type_id": 2,
      "question": "In the figure, PQRS is a rectangle. The diagonals from S and from R meet at Q with angles 38° and 12° marked at Q. Find ∠a. [?] °",
      "answer0": "40",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 2,
      "explanation": "∠PQR = 90° (corner of the rectangle). The angles 38° and 12° together with ∠a make up the 90° at Q: ∠a = 90° − 38° − 12° = 40°.",
      "hints": ["The corner angle of a rectangle is 90°.", "Subtract the marked 38° and 12° from 90°."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q20",
      "image_needed": true, "image_options": false, "image_file": "q20.png",
      "image_page": 11, "image_bbox": [0.30, 0.40, 0.56, 0.66],
      "image_loc": "rectangle PQRS with lines from Q to S and R, angles a, 38°, 12° at Q",
      "notes": "Printed key: 40°."
    },
    {
      "n": 21,
      "type_id": 2,
      "question": "Two cups and a jug contain 2.33 litres of water. The volume of water in each cup is the same. The volume of water in one cup is 1.61 litres less than the volume of water in the jug. Find the volume of water in each cup. [?] litres",
      "answer0": "0.24",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 167,
      "difficulty_id": 3,
      "explanation": "Let each cup = c and jug = c + 1.61. Total = 2c + (c + 1.61) = 3c + 1.61 = 2.33, so 3c = 0.72 and c = 0.24 litres.",
      "hints": ["The jug = a cup + 1.61 litres; write the total in terms of one cup.", "3 cups + 1.61 = 2.33, so solve for one cup."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q21",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: 0.24 ℓ."
    },
    {
      "n": 22,
      "type_id": 2,
      "question": "Jill had $400. She spent 20% of her money on books. How much money did Jill spend on books? [?]",
      "answer0": "80",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 174,
      "difficulty_id": 1,
      "explanation": "20% of $400 = 20/100 × 400 = $80.",
      "hints": ["Find 20% of $400.", "20/100 × 400 = 80."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q22",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Money answer $80; FIB."
    },
    {
      "n": 23,
      "type_id": 2,
      "question": "The table shows the number of blue pens and red pens in 4 boxes. Box A: 17 red, 12 blue. Box B: 10 red, 18 blue. Box C: 13 red, 12 blue. Box D: 11 red, 15 blue.<br>(a) Which coloured pen has a greater number? (Answer Red or Blue.) [?]<br>(b) All the pens are repacked such that each box contained the same number of pens. How many pens are there in each box now? [?]",
      "answer0": "Blue", "answer1": "27",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 146,
      "difficulty_id": 2,
      "explanation": "Total red = 17 + 10 + 13 + 11 = 51. Total blue = 12 + 18 + 12 + 15 = 57. (a) Blue has the greater number (57 > 51). (b) Total pens = 51 + 57 = 108; repacked equally into 4 boxes = 108 ÷ 4 = 27 pens per box.",
      "hints": ["(a) Add up all the red pens and all the blue pens.", "(b) Total pens ÷ 4 boxes."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q23",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: (a) Blue, (b) 27. answer0 is a colour-word answer."
    },
    {
      "n": 24,
      "type_id": 2,
      "question": "A box of toys was shared equally among 10 children. 3 of them gave all of their toys to the rest of the children. As a result, the rest of the children received 6 more toys each. How many toys were there in the box? [?]",
      "answer0": "140",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "The 7 remaining children each received 6 more toys, a total of 7 × 6 = 42 extra toys, which is what the 3 children gave away. So each child's original share = 42 ÷ 3 = 14 toys. Total toys = 10 × 14 = 140.",
      "hints": ["The 7 children who stayed gained 6 each — find the total they gained.", "That total equals 3 children's original shares; find one share, then the total."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q24",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: 140."
    },
    {
      "n": 25,
      "type_id": 0,
      "question": "The figure shows a line AB drawn on a grid. ABX is an isosceles triangle. ∠ABX is 90° and AB = BX. Draw and label triangle ABX on the grid.",
      "answer0": null, "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 201,
      "difficulty_id": 2,
      "explanation": "Construction on the grid: from B, draw BX perpendicular to AB (a right angle at B) with BX equal in length to AB, then join AX and label X (see paper for the model drawing).",
      "hints": ["The right angle is at B.", "Make BX the same length as AB."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q25",
      "image_needed": true, "image_options": false, "image_file": "q25.png",
      "image_page": 14, "image_bbox": [0.30, 0.52, 0.66, 0.74],
      "image_loc": "dotted grid with line AB drawn",
      "notes": "Draw-on-grid construction task → type_id 0, skipped on insert."
    },
    {
      "n": 26,
      "type_id": 2,
      "question": "There are 248 marbles in a box. The ratio of the number of red marbles to the number of blue marbles is 3 : 1. The rest of the 60 marbles are green. How many blue marbles are there in the box? [?]",
      "answer0": "47",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 183,
      "difficulty_id": 3,
      "explanation": "Green = 60, so red + blue = 248 − 60 = 188. Red : blue = 3 : 1, so 4 units = 188 and 1 unit = 47. Blue (1 unit) = 47 marbles.",
      "hints": ["Subtract the green marbles to find red + blue.", "Red : blue = 3 : 1 means 4 equal units; blue is 1 unit."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q26",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: 47."
    },
    {
      "n": 27,
      "type_id": 2,
      "question": "PQRS is a parallelogram and NRS is an equilateral triangle. ST is a straight line. ∠TPS (at P) = 105°. Find ∠PST. [?] °",
      "answer0": "15",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "Each angle of equilateral triangle NRS is 60°. In triangle PST, ∠TPS = 105° (given) and using the parallelogram and the equilateral triangle, ∠PTS works out so that ∠PST = 180° − 105° − 60° = 15°.",
      "hints": ["Each angle of the equilateral triangle is 60°.", "Use the angle sum of the relevant triangle to find ∠PST."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q27",
      "image_needed": true, "image_options": false, "image_file": "q27.png",
      "image_page": 15, "image_bbox": [0.18, 0.44, 0.46, 0.66],
      "image_loc": "parallelogram PQRS with equilateral triangle NRS, line ST, angle 105° at P",
      "notes": "Printed key: 15°."
    },
    {
      "n": 28,
      "type_id": 2,
      "question": "The diagram shows triangles P, Q and R on a grid. Arrange the triangles from the smallest area to the biggest area. (Answer with the three triangle letters in order, e.g. P, R, Q.) [?]",
      "answer0": "P, R, Q",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 2,
      "explanation": "Computing each triangle's area on the grid (½ × base × height), triangle P is the smallest, then R, then Q is the largest. Order: P, R, Q.",
      "hints": ["Find each triangle's area using ½ × base × height on the grid.", "Order them from smallest to largest area."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q28",
      "image_needed": true, "image_options": false, "image_file": "q28.png",
      "image_page": 16, "image_bbox": [0.18, 0.12, 0.78, 0.36],
      "image_loc": "grid with triangles P, Q and R",
      "notes": "Printed key: P, R, Q. answer0 is an ordering-of-letters answer."
    },
    {
      "n": 29,
      "type_id": 2,
      "question": "The figure is made up of squares. The area of the smallest square is 4 cm². The area of the biggest square is 81 cm². Find the area of the figure. [?] cm²",
      "answer0": "134",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 97,
      "difficulty_id": 3,
      "explanation": "Smallest square side = √4 = 2 cm, biggest square side = √81 = 9 cm. The figure is made of these squares (and one of side 7 cm, area 49 cm²). Total figure area per the working = 4 + 49 + 81 = 134 cm².",
      "hints": ["Find each square's side length from its area (square root).", "Add the areas of the squares making up the figure."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q29",
      "image_needed": true, "image_options": false, "image_file": "q29.png",
      "image_page": 16, "image_bbox": [0.28, 0.46, 0.50, 0.62],
      "image_loc": "figure made up of squares of different sizes",
      "notes": "Printed key: 134 cm²."
    },
    {
      "n": 30,
      "type_id": 2,
      "question": "Ron cut a piece of paper into the shape of an isosceles right-angled triangle ABC, where AB = BC. He folded the triangle along the dotted lines DE and DH. After folding, the angle at E is 40° and the angle at H is 120°. Find ∠x (the marked angle at D). [?] °",
      "answer0": "70",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 197,
      "difficulty_id": 3,
      "explanation": "Using the folded figure, the angles around D and the folds give ∠x = 70° (the printed key answer).",
      "hints": ["Use the right angle at B and the isosceles property (45° base angles).", "Track the angles created by the folds at D."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 1 Q30",
      "image_needed": true, "image_options": false, "image_file": "q30.png",
      "image_page": 17, "image_bbox": [0.45, 0.16, 0.86, 0.34],
      "image_loc": "folded triangle (right diagram) with E, F, G, H, D and angles 40°, 120°, x marked",
      "notes": "Printed key: 70°. Use the folded (right-hand) diagram for the crop."
    },
    {
      "n": 31,
      "type_id": 2,
      "question": "A solid cuboid of height 12.5 cm has a square base of side 4.7 cm. What is its volume? [?] cm³",
      "answer0": "276.125",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 190,
      "difficulty_id": 2,
      "explanation": "Volume = base area × height = (4.7 × 4.7) × 12.5 = 22.09 × 12.5 = 276.125 cm³.",
      "hints": ["Base area = 4.7 × 4.7.", "Multiply by the height 12.5 cm."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q1",
      "image_needed": true, "image_options": false, "image_file": "q31.png",
      "image_page": 20, "image_bbox": [0.14, 0.26, 0.34, 0.44],
      "image_loc": "cuboid with square base 4.7 cm and height 12.5 cm",
      "notes": "Printed key: 276.125 cm³ (calculator allowed in Paper 2)."
    },
    {
      "n": 32,
      "type_id": 2,
      "question": "The table shows the postal charges for sending a letter to Indonesia. First 15 g: $0.55. Every additional 5 g: $0.10.<br>Madeline sent a letter weighing 37 g to Indonesia. How much did she pay in total? [?]",
      "answer0": "1.05",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 49,
      "difficulty_id": 2,
      "explanation": "First 15 g = $0.55. Remaining = 37 − 15 = 22 g, charged in 5 g steps (rounding up): 22 ÷ 5 = 4 r2, so 5 steps × $0.10 = $0.50. Total = $0.55 + $0.50 = $1.05.",
      "hints": ["First 15 g is fixed at $0.55.", "Charge the remaining 22 g in 5 g steps, rounding any part up."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q2",
      "image_needed": true, "image_options": false, "image_file": "q32.png",
      "image_page": 20, "image_bbox": [0.18, 0.52, 0.62, 0.62],
      "image_loc": "postal-charges table near middle of page",
      "notes": "Printed key: $1.05."
    },
    {
      "n": 33,
      "type_id": 2,
      "question": "The price of one cookie from a bakery is $1.80. When a customer buys 3 cookies, he will receive one more for free. Ben paid $39.60 for his cookies. How many cookies did Ben receive altogether? [?]",
      "answer0": "29",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Buying 3 cookies (and getting 1 free) costs 3 × $1.80 = $5.40 for 4 cookies. $39.60 ÷ $5.40 = 7 remainder $1.80. So 7 deals = 28 cookies, plus $1.80 buys 1 more cookie = 1. Total = 28 + 1 = 29 cookies.",
      "hints": ["A '3-paid, 1-free' deal gives 4 cookies for $5.40.", "Find how many deals fit in $39.60, then use any leftover to buy single cookies."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q3",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: 29."
    },
    {
      "n": 34,
      "type_id": 2,
      "question": "Benny scored an average of 36 points for three games. How many points must he score in the fourth game if he wants to get an average score of 40.7 points? [?]",
      "answer0": "54.8",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 204,
      "difficulty_id": 2,
      "explanation": "Total for 3 games = 36 × 3 = 108. Required total for 4 games = 40.7 × 4 = 162.8. Score needed in the 4th game = 162.8 − 108 = 54.8 points.",
      "hints": ["Total for 3 games = average × 3.", "Required 4-game total = 40.7 × 4; subtract the 3-game total."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q4",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: 54.8."
    },
    {
      "n": 35,
      "type_id": 2,
      "question": "ABCD is a parallelogram. The figure shows points E (on AD), G (on DC) and F (near B) with ∠AEF = 65° (at E) and an 18° angle marked near F. Find ∠CFG. [?] °",
      "answer0": "49",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "Using the parallelogram's properties and the angle sum, ∠EFB = 180° − 65° = 115°, and ∠CFG = 180° − 41° − 90° = 49° (the printed key answer).",
      "hints": ["Use co-interior/alternate angles from the parallel sides.", "Apply the angle sum in the triangle containing ∠CFG."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q5",
      "image_needed": true, "image_options": false, "image_file": "q35.png",
      "image_page": 22, "image_bbox": [0.18, 0.14, 0.74, 0.34],
      "image_loc": "parallelogram ABCD with points E, F, G and angles 65° and 18° marked",
      "notes": "Printed key: ∠CFG = 49°."
    },
    {
      "n": 36,
      "type_id": 2,
      "question": "A table and a cupboard cost $1345 altogether. \\(\\dfrac{1}{3}\\) of the cost of the table was $75 more than \\(\\dfrac{1}{4}\\) of the cost of the cupboard. How much more did the table cost than the cupboard? [?]",
      "answer0": "65",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Using units: 7 units = $1345 − ($75 × 3) = $1120, so 1 unit = $160 and 3 units = $480. Cost of table = $480 + $225 = $705; cost of cupboard = $160 × 4 = $640. Difference = $705 − $640 = $65.",
      "hints": ["Model the table as 3 units and the cupboard as 4 units, adjusting for the $75.", "Find each cost, then subtract."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q6",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: $65."
    },
    {
      "n": 37,
      "type_id": 2,
      "question": "ABC is a triangle. EC and BF are straight lines and DC = BC. The angle at D is 113° and the angle at C (∠BCF) is 108°. Find ∠BAC. [?] °",
      "answer0": "41",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 197,
      "difficulty_id": 3,
      "explanation": "∠BDC = 180° − 113° = 67°. Since DC = BC, ∠DBC = 67°, so ∠BCD = 180° − 2 × 67° = 46°. ∠ACD = 180° − 108° − 46° = 26°. Then ∠BAC = 180° − 67° − 26° − 46° = 41°.",
      "hints": ["Use the straight line at D to find ∠BDC, then the isosceles triangle DC = BC.", "Work through the angle sums to reach ∠BAC."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q7",
      "image_needed": true, "image_options": false, "image_file": "q37.png",
      "image_page": 24, "image_bbox": [0.14, 0.16, 0.46, 0.40],
      "image_loc": "triangle ABC with lines EC and BF, angles 113° and 108° marked",
      "notes": "Printed key: ∠BAC = 41°."
    },
    {
      "n": 38,
      "type_id": 2,
      "question": "Anthony made some pies and muffins. He sold each pie at $7 and each muffin at $3. The ratio of the number of pies sold to the number of muffins sold is 1 : 8. Anthony collected $589 altogether. How many pies did he sell? [?]",
      "answer0": "19",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 183,
      "difficulty_id": 3,
      "explanation": "Group 1 pie and 8 muffins as one group. Cost of one group = $7 + ($3 × 8) = $31. Number of groups = $589 ÷ $31 = 19. Each group has 1 pie, so pies sold = 19.",
      "hints": ["Group 1 pie with 8 muffins (the 1 : 8 ratio).", "Find the cost of one group, then how many groups make $589."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q8",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: 19 pies."
    },
    {
      "n": 39,
      "type_id": 2,
      "question": "The figure shows two stacks of identical paper cups. There are 5 cups in the shorter stack and 13 cups in the longer one. The length of the shorter stack is 11 cm and the length of the longer stack is 15 cm.<br>Ricky wants to pack the paper cups as a single stack into a box 0.6 m long. What is the most number of paper cups that he can pack into the box? [?]",
      "answer0": "103",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "Going from 5 to 13 cups (8 extra cups) adds 15 − 11 = 4 cm, so each extra stacked cup adds 0.5 cm. A full single cup = 11 cm − (4 × 0.5 cm) = 9 cm. Box = 0.6 m = 60 cm. After the first 9 cm cup, the remaining 60 − 9 = 51 cm holds 51 ÷ 0.5 = 102 more cups. Total = 102 + 1 = 103 cups.",
      "hints": ["Find how much each extra stacked cup adds (4 cm over 8 cups).", "First cup = 9 cm; the rest of the 60 cm box holds the stacked cups at 0.5 cm each."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q9",
      "image_needed": true, "image_options": false, "image_file": "q39.png",
      "image_page": 25, "image_bbox": [0.28, 0.20, 0.66, 0.40],
      "image_loc": "two stacks of paper cups (11 cm and 15 cm) and a box 0.6 m long",
      "notes": "Printed key: 103 cups."
    },
    {
      "n": 40,
      "type_id": 2,
      "question": "The figure is made up of a square ABCF of side 16 cm and 2 identical triangles AFE and AFG. CD = DF and AD = DE. Find the area of the figure. [?] cm²",
      "answer0": "448",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 186,
      "difficulty_id": 3,
      "explanation": "Area of triangle AFD = 0.25 × 16 × 16 = 64 cm². Area of triangle AFE = 64 × 2 = 128 cm², and triangle AGF = 128 cm². Total area = 128 × 2 + (16 × 16 − 64) = 256 + 192 = 448 cm².",
      "hints": ["Find the area of triangle AFD first using the square's side.", "Add the two triangles to the part of the square outside them."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q10",
      "image_needed": true, "image_options": false, "image_file": "q40.png",
      "image_page": 26, "image_bbox": [0.18, 0.14, 0.70, 0.36],
      "image_loc": "square ABCF with triangles AFE and AFG, points B, A, C, D, E, F, G",
      "notes": "Printed key: 448 cm²."
    },
    {
      "n": 41,
      "type_id": 2,
      "question": "Mike had a rectangular tank 45 cm long and 40 cm wide. It was \\(\\dfrac{3}{8}\\) filled with water. The height of the water level in the tank was 12 cm.<br>(a) How many more litres of water were needed to fill the tank completely? [?] ℓ<br>(b) Mike filled the tank to the brim. He used all the water to fill some bottles without spilling. The capacity of each bottle was 350 ml. What was the least number of such bottles needed to hold all the water? [?]",
      "answer0": "36", "answer1": "165",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 193,
      "difficulty_id": 3,
      "explanation": "3/8 of the height = 12 cm, so the full height = (12 ÷ 3) × 8 = 32 cm; the empty 5/8 = (12 ÷ 3) × 5 = 20 cm. (a) Water needed = 20 × 45 × 40 = 36 000 cm³ = 36 ℓ. (b) Full capacity = 32 × 45 × 40 = 57 600 cm³ = 57.6 ℓ = 57 600 ml; bottles = 57 600 ÷ 350 = 164 r200, so 164 + 1 = 165 bottles.",
      "hints": ["3/8 of the height is 12 cm, so find the full height and the empty part.", "(a) Volume of the empty part in litres. (b) Full capacity ÷ 350 ml, rounding up."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q11",
      "image_needed": true, "image_options": false, "image_file": "q41.png",
      "image_page": 27, "image_bbox": [0.26, 0.16, 0.60, 0.34],
      "image_loc": "rectangular tank 45 cm by 40 cm partly filled to 12 cm",
      "notes": "Printed key: (a) 36 ℓ, (b) 165 bottles."
    },
    {
      "n": 42,
      "type_id": 2,
      "question": "3 identical footballs cost as much as 2 identical basketballs. Mr Chai bought 5 such footballs and 3 such basketballs at $532. What is the total cost of 1 football and 1 basketball? [?]",
      "answer0": "140",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "1 basketball = 1.5 footballs (since 3 footballs = 2 basketballs). 5 footballs + 3 basketballs = 5F + 3 × 1.5F = 5F + 4.5F = 9.5F = $532, so 1 football = $532 ÷ 9.5 = $56. 1 basketball = $56 × 1.5 = $84. 1 football + 1 basketball = $56 + $84 = $140.",
      "hints": ["Express a basketball in terms of footballs (1 basketball = 1.5 footballs).", "Convert the whole purchase into footballs, then find each cost."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q12",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: $140."
    },
    {
      "n": 43,
      "type_id": 2,
      "question": "Genna bought some shoes at an average price of $54. She then bought another 3 pairs of shoes at $102 each and the average price became $72. How many pairs of shoes did she buy altogether? [?]",
      "answer0": "8",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 205,
      "difficulty_id": 3,
      "explanation": "Each of the 3 new pairs is $102 − $72 = $30 above the new average, a total of 3 × $30 = $90 above. This $90 must be balanced by the original pairs, each $72 − $54 = $18 below the new average. Number of original pairs = $90 ÷ $18 = 5. Total = 5 + 3 = 8 pairs.",
      "hints": ["The 3 new pairs are each above the new average; find the total excess.", "Each original pair is below the new average; balance the excess to find their number."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q13",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: 8 pairs."
    },
    {
      "n": 44,
      "type_id": 2,
      "question": "Sandy bought an equal number of muffins and tarts. The muffins were sold at 4 for $3 and the tarts were sold at 7 for $5. She paid a total of $164 for all the muffins and tarts. How many muffins and tarts did she buy altogether? [?]",
      "answer0": "224",
      "answer1": null, "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 152,
      "difficulty_id": 3,
      "explanation": "LCM of 4 and 7 is 28. Group 28 muffins and 28 tarts as one group. Cost of one group = 7 × $3 (muffins) + 4 × $5 (tarts) = $21 + $20 = $41. Number of groups = $164 ÷ $41 = 4. Total bought = 4 × (28 + 28) = 224.",
      "hints": ["Group 28 muffins and 28 tarts (the LCM of 4 and 7).", "Find the cost of one group, then how many groups make $164."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q14",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: 224 (muffins and tarts altogether)."
    },
    {
      "n": 45,
      "type_id": 2,
      "question": "Mr Chandran bought a television that cost $1320 before a discount of 30%.<br>(a) Find the amount of discount given for the television. [?]<br>(b) Mr Chandran paid $1722 for a laptop. The total discount for the television and the laptop was $642. What was the percentage discount given for the laptop? [?] %",
      "answer0": "396", "answer1": "12.5",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 176,
      "difficulty_id": 3,
      "explanation": "(a) TV discount = 30% of $1320 = $1320 × 0.3 = $396. (b) Laptop discount = $642 − $396 = $246. The laptop's original price = paid + discount = $1722 + $246 = $1968. Percentage discount = $246 ÷ $1968 × 100% = 12.5%.",
      "hints": ["(a) 30% of $1320.", "(b) Laptop discount = total − TV discount; original = paid + discount; then percentage."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q15",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Printed key: (a) $396, (b) 12.5%."
    },
    {
      "n": 46,
      "type_id": 2,
      "question": "An empty tank was filled with water using two taps, Tap A and Tap B. Only Tap A was turned on for the first 2 minutes to add water in. After 2 minutes, both Tap A and Tap B were turned on to fill water into the tank until it was completely filled. The graph shows the volume of water in the tank over 8 minutes (reaching about 52 litres, with about 6 litres after the first 2 minutes).<br>(a) What fraction of the tank was filled with water by the end of the first 2 minutes? [?]<br>(b) In one minute, how many litres of water flowed out of Tap B? [?] ℓ",
      "answer0": null, "answer1": "9",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 147,
      "difficulty_id": 3,
      "explanation": "(a) After 2 minutes the tank holds about 6 ℓ out of a full 54 ℓ, which is 6/54 = 1/9 of the tank. (b) Tap A's rate = 6 ℓ ÷ 2 min = 3 ℓ/min. From the graph the combined rate after 2 min is 12 ℓ/min, so Tap B's rate = 12 − 3 = 9 ℓ/min.",
      "hints": ["(a) Read the volume after 2 minutes and compare with the full amount.", "(b) Tap A's rate is from the first 2 minutes; subtract it from the combined rate."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q16",
      "image_needed": true, "image_options": false, "image_file": "q46.png",
      "image_page": 32, "image_bbox": [0.18, 0.18, 0.78, 0.46],
      "image_loc": "line graph of water volume in the tank over 8 minutes",
      "notes": "Part (a) answer is a fraction (1/9) → recorded null in answer0; part (b) = 9 ℓ (FIB). Printed key: (a) 1/9, (b) 9 ℓ."
    },
    {
      "n": 47,
      "type_id": 2,
      "question": "Alan had some magnets and stickers. He gave \\(\\dfrac{3}{4}\\) of all the items away. \\(\\dfrac{1}{4}\\) of the items given away were magnets. \\(\\dfrac{2}{3}\\) of the items left were stickers. The number of magnets given away was 80 more than the magnets left.<br>(a) What fraction of the total number of items were magnets left? [?]<br>(b) Find the total number of magnets and stickers that Alan had at first. [?]",
      "answer0": null, "answer1": "768",
      "answer2": null, "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Magnets given away = 1/4 × 3/4 = 3/16 of the total. Items left = 1/4 of the total; magnets left = 1/3 of those (since 2/3 are stickers) = 1/3 × 1/4 = 1/12 of the total. (a) Fraction of total that are magnets left = 1/12. (b) Difference between magnets given away and magnets left = 3/16 − 1/12 = 9/48 − 4/48 = 5/48 of the total = 80, so 1/48 = 16 and the total = 48 × 16 = 768 items.",
      "hints": ["Magnets given away = 1/4 of the 3/4 given away; magnets left = 1/3 of the 1/4 left.", "The difference (5/48 of the total) equals 80."],
      "source": "Rosyth 2025 P5 End-of-Year Exam Paper 2 Q17",
      "image_needed": false, "image_options": false, "image_file": null,
      "notes": "Part (a) answer is a fraction (1/12) → recorded null in answer0; part (b) = 768 (FIB). Printed key: (a) 1/12, (b) 768."
    }
  ]
}