{
"paper": {
"school": "Rosyth",
"year": 2024,
"level": "P6",
"label": "Term Assessment 2",
"source_prefix": "Rosyth 2024 P6 Term Assessment 2",
"has_answer_key": true,
"notes": "Two papers in one PDF. Paper 1 (Booklet A Q1-15 MCQ + Booklet B Q16-30) has NO printed key -- solved. Paper 2 (Q1-17) HAS a full printed worked key (pages 35-38). Sources tagged 'P1 Q..' and 'P2 Q..' to disambiguate the repeated numbering."
},
"questions": [
{
"n": 1,
"type_id": 1,
"question": "Round 132 658 to the nearest thousand.",
"answer0": "132 000",
"answer1": "132 600",
"answer2": "132 700",
"answer3": "133 000",
"correct_answer": 3,
"skill_id": 150,
"difficulty_id": 1,
"explanation": "Look at the hundreds digit (6). Since 6 ≥ 5, round up: 132 658 → 133 000.",
"hints": ["Identify the thousands digit.", "Check the hundreds digit: 6 ≥ 5 rounds up."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q1",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 2,
"type_id": 1,
"question": "What does the digit 9 in 5.492 stand for?",
"answer0": "9 ones",
"answer1": "9 tenths",
"answer2": "9 hundredths",
"answer3": "9 thousandths",
"correct_answer": 2,
"skill_id": 158,
"difficulty_id": 1,
"explanation": "In 5.492 the digits after the point are tenths (4), hundredths (9), thousandths (2). So 9 is in the hundredths place = 9 hundredths.",
"hints": ["First place after the point is tenths.", "Second place is hundredths."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q2",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 3,
"type_id": 1,
"question": "PQRU and RSTU are rhombuses. Which of the following pairs of lines are parallel?",
"answer0": "PQ and RS",
"answer1": "PQ and TS",
"answer2": "UT and PU",
"answer3": "UT and UR",
"correct_answer": 1,
"skill_id": 199,
"difficulty_id": 2,
"explanation": "In rhombus PQRU, PQ ∥ UR. In rhombus RSTU, UR ∥ TS. So PQ ∥ TS.",
"hints": ["Opposite sides of a rhombus are parallel.", "Find a common side that links the two rhombuses."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q3",
"image_needed": true,
"image_page": 2,
"image_bbox": [0.38, 0.55, 0.62, 0.72],
"image_loc": "two rhombuses PQRU and RSTU, middle of page",
"image_options": false,
"image_file": "q3.png",
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 4,
"type_id": 1,
"question": "Mark and John collected some stickers. Mark collected \\(\\dfrac{5}{8}\\) of the total number of stickers. What is the ratio of Mark's stamps to John's stickers?",
"answer0": "3 : 5",
"answer1": "3 : 8",
"answer2": "5 : 3",
"answer3": "5 : 8",
"correct_answer": 2,
"skill_id": 210,
"difficulty_id": 1,
"explanation": "Mark = \\(\\dfrac{5}{8}\\), so John = \\(\\dfrac{3}{8}\\). Mark : John = 5 : 3.",
"hints": ["John's share = 1 − Mark's share.", "Compare the numerators over the same total of 8."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q4",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 5,
"type_id": 1,
"question": "Sherry scored an average of 30 points for 5 basketball games. What is the total number of points that Sherry scored for the 5 basketball games?",
"answer0": "6",
"answer1": "25",
"answer2": "35",
"answer3": "150",
"correct_answer": 3,
"skill_id": 204,
"difficulty_id": 1,
"explanation": "Total = average × number of items = 30 × 5 = 150.",
"hints": ["Total = average × number of games."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q5",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 6,
"type_id": 1,
"question": "The table shows the number of pupils in four classes.
What is the total number of pupils in Class 6B?",
"answer0": "39",
"answer1": "40",
"answer2": "41",
"answer3": "42",
"correct_answer": 2,
"skill_id": 146,
"difficulty_id": 1,
"explanation": "Class 6B has 18 boys and 23 girls. Total = 18 + 23 = 41.",
"hints": ["Read the 6B row of the table.", "Add boys and girls."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q6",
"image_needed": true,
"image_page": 3,
"image_bbox": [0.18, 0.45, 0.86, 0.62],
"image_loc": "table of boys/girls per class, middle of page",
"image_options": false,
"image_file": "q6.png",
"notes": "Paper 1 (no printed key) -- solved. Table needed for the 6B row."
},
{
"n": 7,
"type_id": 1,
"question": "What is the value of 0.63 × 200?",
"answer0": "0.126",
"answer1": "1.26",
"answer2": "12.6",
"answer3": "126",
"correct_answer": 3,
"skill_id": 166,
"difficulty_id": 1,
"explanation": "0.63 × 200 = 0.63 × 2 × 100 = 1.26 × 100 = 126.",
"hints": ["Multiply by 2 first, then by 100."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q7",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 8,
"type_id": 1,
"question": "ABCD is a four-sided figure made up of a rhombus ABCE and an equilateral triangle AED. Find \\(\\angle ABC\\).",
"answer0": "60°",
"answer1": "90°",
"answer2": "120°",
"answer3": "150°",
"correct_answer": 2,
"skill_id": 230,
"difficulty_id": 2,
"explanation": "Triangle AED is equilateral so \\(\\angle AED = 60°\\). D, E, C lie on a line, so \\(\\angle AEC = 180° - 60° = 120°\\). In rhombus ABCE, \\(\\angle ABC\\) and \\(\\angle AEC\\) are opposite angles, so \\(\\angle ABC = 120°\\).",
"hints": ["An equilateral triangle has all angles 60°.", "Opposite angles of a rhombus are equal."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q8",
"image_needed": true,
"image_page": 4,
"image_bbox": [0.3, 0.28, 0.72, 0.42],
"image_loc": "quadrilateral ABCD with rhombus + triangle, upper-middle of page",
"image_options": false,
"image_file": "q8.png",
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 9,
"type_id": 1,
"question": "The figure shows a semi-circle. Find the perimeter of the figure. (Take \\(\\pi = \\dfrac{22}{7}\\))",
"answer0": "22 cm",
"answer1": "36 cm",
"answer2": "44 cm",
"answer3": "58 cm",
"correct_answer": 1,
"skill_id": 221,
"difficulty_id": 2,
"explanation": "Diameter = 14 cm, radius = 7 cm. Perimeter of semicircle = half circumference + diameter = \\(\\dfrac{22}{7}\\times 7 + 14 = 22 + 14 = 36\\) cm.",
"hints": ["Perimeter of a semicircle = πr + diameter.", "\\(\\dfrac{22}{7}\\times 7 = 22\\)."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q9",
"image_needed": true,
"image_page": 4,
"image_bbox": [0.3, 0.62, 0.62, 0.78],
"image_loc": "semicircle with 14 cm diameter, lower-middle of page",
"image_options": false,
"image_file": "q9.png",
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 10,
"type_id": 1,
"question": "Arrange these fractions from the smallest to the largest.
\\(\\dfrac{8}{5}\\), \\(1\\dfrac{3}{10}\\), \\(\\dfrac{7}{4}\\)",
"answer0": "\\(\\dfrac{7}{4}\\), \\(1\\dfrac{3}{10}\\), \\(\\dfrac{8}{5}\\)",
"answer1": "\\(1\\dfrac{3}{10}\\), \\(\\dfrac{8}{5}\\), \\(\\dfrac{7}{4}\\)",
"answer2": "\\(\\dfrac{8}{5}\\), \\(\\dfrac{7}{4}\\), \\(1\\dfrac{3}{10}\\)",
"answer3": "\\(\\dfrac{7}{4}\\), \\(\\dfrac{8}{5}\\), \\(1\\dfrac{3}{10}\\)",
"correct_answer": 1,
"skill_id": 158,
"difficulty_id": 2,
"explanation": "Convert to decimals: \\(\\dfrac{8}{5}=1.6\\), \\(1\\dfrac{3}{10}=1.3\\), \\(\\dfrac{7}{4}=1.75\\). Smallest to largest: 1.3, 1.6, 1.75, i.e. \\(1\\dfrac{3}{10}\\), \\(\\dfrac{8}{5}\\), \\(\\dfrac{7}{4}\\).",
"hints": ["Convert each fraction to a decimal.", "Then order the decimals."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q10",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved. Ordering task with fraction values -> kept MCQ because options are fraction sequences."
},
{
"n": 11,
"type_id": 1,
"question": "WXV is a triangle and VXZ is a straight line. \\(\\angle WXY\\) is twice of \\(\\angle YXZ\\). Find \\(\\angle WXY\\).",
"answer0": "30°",
"answer1": "40°",
"answer2": "60°",
"answer3": "80°",
"correct_answer": 3,
"skill_id": 197,
"difficulty_id": 2,
"explanation": "In triangle WXV, \\(\\angle WXV = 180° - 68° - 52° = 60°\\). On straight line VXZ: \\(\\angle WXV + \\angle WXY + \\angle YXZ = 180°\\). Let \\(\\angle YXZ = a\\), so \\(\\angle WXY = 2a\\): \\(60° + 2a + a = 180°\\), \\(3a = 120°\\), \\(a = 40°\\). \\(\\angle WXY = 80°\\).",
"hints": ["Angle sum of triangle WXV is 180°.", "Angles on the straight line VXZ sum to 180°."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q11",
"image_needed": true,
"image_page": 5,
"image_bbox": [0.25, 0.5, 0.78, 0.7],
"image_loc": "triangle WXV with straight line VXZ and angles 68°, 52°",
"image_options": false,
"image_file": "q11.png",
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 12,
"type_id": 1,
"question": "Aisha baked an equal number of chocolate muffins and banana muffins. She gave Liling 28 chocolate muffins and 10 banana muffins. She gave the remaining muffins to Jane. Jane received 1 chocolate muffin for every 4 banana muffins. How many muffins did Aisha bake at first?",
"answer0": "18",
"answer1": "24",
"answer2": "34",
"answer3": "68",
"correct_answer": 3,
"skill_id": 214,
"difficulty_id": 3,
"explanation": "Let each type = n. Jane got (n−28) chocolate and (n−10) banana in ratio 1 : 4, so 4(n−28) = n−10 → 4n−112 = n−10 → 3n = 102 → n = 34. Total baked = 2 × 34 = 68.",
"hints": ["Let the number of each flavour be n.", "Set Jane's leftovers in the ratio 1 : 4 and solve."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q12",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 13,
"type_id": 1,
"question": "The figure is made up of 2 squares, a rectangle and a triangle. Find the unshaded area of the figure.",
"answer0": "120 cm²",
"answer1": "152 cm²",
"answer2": "240 cm²",
"answer3": "272 cm²",
"correct_answer": 1,
"skill_id": 223,
"difficulty_id": 3,
"explanation": "The shaded triangle has base 30 cm and height 8 cm, area = \\(\\dfrac{1}{2}\\times 30\\times 8 = 120\\) cm². The whole figure (the two squares + rectangle making the outline) has area 272 cm², so the unshaded area = 272 − 120 = 152 cm².",
"hints": ["Find the shaded triangle's area first.", "Unshaded = total figure area − shaded triangle."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q13",
"image_needed": true,
"image_page": 6,
"image_bbox": [0.25, 0.4, 0.78, 0.56],
"image_loc": "composite figure of squares/rectangle/triangle, 12 cm and 8 cm heights, 30 cm base",
"image_options": false,
"image_file": "q13.png",
"notes": "Paper 1 (no printed key) -- solved; figure-dependent. Best fit (4) 272 total minus 120 shaded triangle = 152; verify against the printed figure."
},
{
"n": 14,
"type_id": 1,
"question": "The figure shows a box which can contain exactly 8 identical cubes. The volume of all the cubes is 216 cm³. What is the length of a cube?",
"answer0": "6 cm",
"answer1": "9 cm",
"answer2": "3 cm",
"answer3": "27 cm",
"correct_answer": 2,
"skill_id": 225,
"difficulty_id": 2,
"explanation": "One cube = 216 ÷ 8 = 27 cm³. Length of a cube = \\(\\sqrt[3]{27} = 3\\) cm.",
"hints": ["Divide total volume by 8 to get one cube's volume.", "Take the cube root of 27."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q14",
"image_needed": true,
"image_page": 7,
"image_bbox": [0.32, 0.1, 0.66, 0.24],
"image_loc": "open box holding cubes, top of page",
"image_options": false,
"image_file": "q14.png",
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 15,
"type_id": 1,
"question": "Samad bought some fruits. \\(\\dfrac{3}{5}\\) of the fruits he bought were apples and the rest were oranges. \\(\\dfrac{1}{6}\\) of the oranges and \\(\\dfrac{1}{3}\\) of the apples that he bought were rotten. 240 of the fruits were rotten. What is the total number of oranges that Samad bought?",
"answer0": "60",
"answer1": "144",
"answer2": "360",
"answer3": "900",
"correct_answer": 2,
"skill_id": 165,
"difficulty_id": 3,
"explanation": "Apples = \\(\\dfrac{3}{5}\\)T, oranges = \\(\\dfrac{2}{5}\\)T. Rotten = \\(\\dfrac{1}{3}\\times\\dfrac{3}{5}\\)T + \\(\\dfrac{1}{6}\\times\\dfrac{2}{5}\\)T = \\(\\dfrac{1}{5}\\)T + \\(\\dfrac{1}{15}\\)T = \\(\\dfrac{4}{15}\\)T = 240, so T = 900. Oranges = \\(\\dfrac{2}{5}\\times 900 = 360\\).",
"hints": ["Write apples and oranges as fractions of the total T.", "Add the two rotten fractions and set equal to 240."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q15",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 16,
"type_id": 2,
"question": "Find the value of \\(3j + 23\\) when \\(j = 14\\). [?]",
"answer0": "65",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 240,
"difficulty_id": 1,
"explanation": "Substitute j = 14: 3 × 14 + 23 = 42 + 23 = 65.",
"hints": ["Replace j with 14.", "Multiply first, then add 23."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q16",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 17,
"type_id": 1,
"question": "Name all the figures with at least 1 line of symmetry.",
"answer0": "Figure A, Figure B and Figure D",
"answer1": "Figure A and Figure D only",
"answer2": "Figure A, Figure C and Figure D",
"answer3": "All five figures",
"correct_answer": 0,
"skill_id": 145,
"difficulty_id": 2,
"explanation": "Figure A (regular hexagon), Figure B (symmetric cross-shape) and Figure D (circle) each have at least one line of symmetry. Figure C (parallelogram) and Figure E (irregular wavy shape) have none.",
"hints": ["A line of symmetry folds the shape onto itself.", "Parallelograms have no line of symmetry."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q17",
"image_needed": true,
"image_page": 10,
"image_bbox": [0.08, 0.38, 0.78, 0.52],
"image_loc": "five labelled figures A-E in a row",
"image_options": false,
"image_file": "q17.png",
"notes": "Paper 1 (no printed key) -- solved. Word/list answer -> converted to MCQ per spec; figure needed to verify each shape."
},
{
"n": 18,
"type_id": 1,
"question": "Find the value of \\(\\dfrac{2}{5} \\div 8\\). Express your answer as a fraction in its simplest form.",
"answer0": "\\(\\dfrac{1}{20}\\)",
"answer1": "\\(\\dfrac{1}{40}\\)",
"answer2": "\\(\\dfrac{2}{40}\\)",
"answer3": "\\(\\dfrac{16}{5}\\)",
"correct_answer": 0,
"skill_id": 164,
"difficulty_id": 1,
"explanation": "\\(\\dfrac{2}{5}\\div 8 = \\dfrac{2}{5}\\times\\dfrac{1}{8} = \\dfrac{2}{40} = \\dfrac{1}{20}\\).",
"hints": ["Dividing by 8 = multiplying by \\(\\dfrac{1}{8}\\).", "Simplify \\(\\dfrac{2}{40}\\)."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q18",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved. Fraction answer -> MCQ per spec (FIB cannot hold fractions)."
},
{
"n": 19,
"type_id": 2,
"question": "In this month, Colin sold 200 more handphones than he sold the previous month. This was a 40% increase from the number of handphones he had sold the previous month. How many handphones did he sell this month? [?]",
"answer0": "700",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 208,
"difficulty_id": 2,
"explanation": "40% of last month = 200, so 100% (last month) = 500. This month = 500 + 200 = 700.",
"hints": ["The 200 extra equals 40% of last month.", "Find 100% then add the 200."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q19",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 20,
"type_id": 1,
"question": "Kelly faces the supermarket after turning 135° in an anti-clockwise direction. Where was she facing at first?",
"answer0": "Bus Stop",
"answer1": "Library",
"answer2": "Police Post",
"answer3": "Food Court",
"correct_answer": 0,
"skill_id": 240,
"difficulty_id": 2,
"explanation": "135° = three 45° steps. Turning anti-clockwise 135° ends at the Supermarket (NW). So she started three 45° steps clockwise from the Supermarket: Supermarket → Library → School → Bus Stop. She first faced the Bus Stop.",
"hints": ["Each labelled direction is 45° apart.", "Reverse the 135° anti-clockwise turn to find the start."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q20",
"image_needed": true,
"image_page": 11,
"image_bbox": [0.18, 0.45, 0.72, 0.66],
"image_loc": "8-direction compass diagram around 'Kelly' with place labels",
"image_options": false,
"image_file": "q20.png",
"notes": "Paper 1 (no printed key) -- solved. Direction (word) answer -> MCQ per spec."
},
{
"n": 21,
"type_id": 2,
"question": "Kumar used some wires to make the figure. The figure is made up of 3 semi-circle arcs and an equilateral triangle. Line XY is 10 cm and line YZ is 30 cm. Find the total length of the wires he used. (Take \\(\\pi = 3.14\\)) [?]",
"answer0": "205.6",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 222,
"difficulty_id": 3,
"explanation": "XZ = XY + YZ = 10 + 30 = 40 cm. Three semicircle arcs on diameters 10, 30 and 40: \\(\\dfrac{1}{2}\\times 3.14\\times(10+30+40) = 1.57\\times 80 = 125.6\\) cm. The equilateral triangle has XZ = 40 cm as one side, so its other two slanted sides total 40 + 40 = 80 cm. Total wire = 125.6 + 80 = 205.6 cm.",
"hints": ["XZ = XY + YZ.", "Semicircle arc = \\(\\dfrac{1}{2}\\pi d\\); add the two slanted triangle sides."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q21",
"image_needed": true,
"image_page": 12,
"image_bbox": [0.22, 0.28, 0.6, 0.5],
"image_loc": "wire figure: 3 semicircle arcs over XYZ with triangle hanging below",
"image_options": false,
"image_file": "q21.png",
"notes": "Paper 1 (no printed key) -- solved. Answer in cm."
},
{
"n": 22,
"type_id": 1,
"question": "Students were asked to choose their favourite sport. The bar graph shows the choices made by the students. What fraction of students chose Badminton as their favourite sport? Express the fraction in its simplest form.",
"answer0": "\\(\\dfrac{5}{13}\\)",
"answer1": "\\(\\dfrac{10}{26}\\)",
"answer2": "\\(\\dfrac{5}{12}\\)",
"answer3": "\\(\\dfrac{2}{5}\\)",
"correct_answer": 0,
"skill_id": 104,
"difficulty_id": 2,
"explanation": "Basketball = 50, Football = 110, Badminton = 100. Total = 260. Fraction for Badminton = \\(\\dfrac{100}{260} = \\dfrac{5}{13}\\).",
"hints": ["Read each bar's value and add for the total.", "Simplify \\(\\dfrac{100}{260}\\)."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q22",
"image_needed": true,
"image_page": 13,
"image_bbox": [0.12, 0.1, 0.7, 0.34],
"image_loc": "bar graph of favourite sports (Basketball, Football, Badminton)",
"image_options": false,
"image_file": "q22.png",
"notes": "Paper 1 (no printed key) -- solved. Fraction answer -> MCQ per spec."
},
{
"n": 23,
"type_id": 2,
"question": "A rectangular piece of paper was folded along AB and CD to form the figure. \\(\\angle GBF = 80°\\) and \\(\\angle AEF = 70°\\). Find \\(\\angle BFD\\). [?]",
"answer0": "150",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 230,
"difficulty_id": 3,
"explanation": "Using the two fold (crease) angles at B and E, the angle at the meeting point F is \\(\\angle BFD = \\angle GBF + \\angle AEF = 80° + 70° = 150°\\).",
"hints": ["Folding reflects equal angles about each crease.", "Combine the crease angles to find the angle at F."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q23",
"image_needed": true,
"image_page": 14,
"image_bbox": [0.18, 0.1, 0.62, 0.28],
"image_loc": "folded-paper figure with points A,B,C,D,E,F,G",
"image_options": false,
"image_file": "q23.png",
"notes": "Paper 1 (no printed key) -- SOLVED, figure-dependent and UNCERTAIN. Folded-paper angle problem; answer 150° is a best-effort from the crease angles -- needs verification against the actual figure."
},
{
"n": 24,
"type_id": 2,
"question": "A rectangular cardboard, with patterns on one side, is folded to form the shape. Find the area of the cardboard when unfolded. [?]",
"answer0": "71",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 138,
"difficulty_id": 3,
"explanation": "The bracket shape is made of a left leg 5 m wide × 7 m tall = 35 m² and a top bar 9 m long × 4 m thick = 36 m², giving a flat cardboard area of 35 + 36 = 71 m².",
"hints": ["Split the unfolded cardboard into rectangles.", "Add the areas of the parts."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q24",
"image_needed": true,
"image_page": 15,
"image_bbox": [0.22, 0.08, 0.55, 0.26],
"image_loc": "folded bracket-shaped cardboard with 9 m, 7 m, 5 m, 4 m labels",
"image_options": false,
"image_file": "q24.png",
"notes": "Paper 1 (no printed key) -- SOLVED, figure-dependent and UNCERTAIN. Answer 71 m² is a best-effort reconstruction of the bracket from the printed dimensions -- needs verification against the figure."
},
{
"n": 25,
"type_id": 2,
"question": "The ratio of the number of pens that David had to the number of pens that Paul had was 3 : 5. When David bought 28 more pens, the ratio of the number of pens that David had to the number of pens Paul had became 2 : 1. How many pens did Paul have? [?]",
"answer0": "20",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 214,
"difficulty_id": 3,
"explanation": "Let David = 3u, Paul = 5u (Paul unchanged). After +28: (3u + 28) : 5u = 2 : 1, so 3u + 28 = 10u → 7u = 28 → u = 4. Paul = 5u = 20 pens.",
"hints": ["Paul's pens do not change, so keep his units constant.", "Set the new ratio 2 : 1 and solve for u."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q25",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 26,
"type_id": 2,
"question": "The figure shows a container that is \\(\\dfrac{1}{3}\\) filled with water. Another 42 litres of water will fill the container to the brim. What is the height of the container? [?]",
"answer0": "63",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 191,
"difficulty_id": 3,
"explanation": "The empty part is 1 − \\(\\dfrac{1}{3}\\) = \\(\\dfrac{2}{3}\\), which holds 42 L, so the full container = 63 L = 63 000 cm³. Base area = 50 × 20 = 1000 cm². Height = 63 000 ÷ 1000 = 63 cm.",
"hints": ["The 42 L fills the empty \\(\\dfrac{2}{3}\\) of the tank.", "Height = volume ÷ base area; 1 L = 1000 cm³."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q26",
"image_needed": true,
"image_page": 16,
"image_bbox": [0.32, 0.1, 0.56, 0.26],
"image_loc": "tall rectangular tank, base 50 cm × 20 cm, part-filled",
"image_options": false,
"image_file": "q26.png",
"notes": "Paper 1 (no printed key) -- solved. Answer in cm."
},
{
"n": 27,
"type_id": 2,
"question": "There are some beads in a box. The beads can be placed in bags of 6 and 8 with no beads leftover. When the beads are put into bags of 10, there will be 2 beads leftover. What is the smallest number of beads in the box? [?]",
"answer0": "72",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 113,
"difficulty_id": 3,
"explanation": "The number is a common multiple of 6 and 8, i.e. a multiple of LCM(6, 8) = 24: 24, 48, 72, ... It must leave remainder 2 when divided by 10. 24 → 4, 48 → 8, 72 → 2. The smallest is 72.",
"hints": ["Find the LCM of 6 and 8.", "Test its multiples for remainder 2 when divided by 10."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q27",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved."
},
{
"n": 28,
"type_id": 2,
"question": "Kartini had a bottle of juice. She drank an equal amount of the juice each day. At the end of the 3rd day, she had 1320 millilitres of the juice left. At the end of the 7th day, she had half the bottle of juice left. How many litres of juice was there in the bottle at first? [?]",
"answer0": "1.68",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 167,
"difficulty_id": 3,
"explanation": "Let bottle = B, daily amount = d. After 3 days: B − 3d = 1320. After 7 days: B − 7d = \\(\\dfrac{1}{2}\\)B, so \\(\\dfrac{1}{2}\\)B = 7d → B = 14d. Then 14d − 3d = 11d = 1320 → d = 120 mL. B = 14 × 120 = 1680 mL = 1.68 L.",
"hints": ["Write the amount left after 3 and after 7 days.", "Use 'half left after 7 days' to relate B and d."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q28",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved. Answer in litres (ℓ)."
},
{
"n": 29,
"type_id": 2,
"question": "Adam had $48 more than David. When David gave Adam $21, Adam had four times as much money as David. How much money did David have at first? [?]",
"answer0": "51",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 241,
"difficulty_id": 3,
"explanation": "Let David = x, Adam = x + 48. After David gives $21: Adam = x + 69, David = x − 21, and Adam = 4 × David: x + 69 = 4(x − 21) → x + 69 = 4x − 84 → 3x = 153 → x = 51. David had $51.",
"hints": ["Express both amounts in terms of David's money x.", "After the $21 transfer, set Adam = 4 × David."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q29",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 1 (no printed key) -- solved. Answer in dollars: $51."
},
{
"n": 30,
"type_id": 0,
"question": "The tank contained some water at first. Tap A was turned on to fill the tank at a constant rate. After 4 minutes, Tap B was turned on to drain water at a constant rate. The graph shows the volume of water in the tank during the 8-minute period. For each statement, indicate whether it is True, False or Not possible to tell.",
"answer0": null,
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 147,
"difficulty_id": 3,
"explanation": "From the graph: volume rises from 15 L to 35 L in the first 4 min, so Tap A fills at 5 L/min. From 4 to 8 min it rises 35 → 45 L (+10 L over 4 min = +2.5 L/min net). With Tap A still adding 5 L/min, Tap B drains 5 − 2.5 = 2.5 L/min, so 'Tap B drained at 2.5 litres/min' is TRUE. The graph only goes to 45 L at 8 min and the tank is never shown full, so 'capacity is 46 litres' is NOT POSSIBLE TO TELL.",
"hints": ["Find Tap A's rate from the first 4 minutes.", "Use the net rate after 4 min to find Tap B's drain rate."],
"source": "Rosyth 2024 P6 Term Assessment 2 P1 Q30",
"image_needed": true,
"image_page": 18,
"image_bbox": [0.1, 0.13, 0.82, 0.45],
"image_loc": "line graph of volume vs time (0-8 min) plus a true/false/not-possible table",
"image_options": false,
"image_file": "q30.png",
"notes": "Paper 1 (no printed key) -- solved. True/False/Not-possible tick table -> type_id 0 (interactive). Answers: (1) Tap B drained at 2.5 L/min = TRUE; (2) capacity is 46 L = NOT POSSIBLE TO TELL."
},
{
"n": 31,
"type_id": 2,
"question": "Joe has two rectangular boxes of different sizes. The length, breadth and height of the larger box are twice those of the smaller box. He packed 48 identical cubes exactly into the smaller box. How many such cubes can be packed exactly into the larger box? [?]",
"answer0": "384",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 229,
"difficulty_id": 2,
"explanation": "Doubling each dimension multiplies the volume by 2 × 2 × 2 = 8. So the larger box holds 48 × 8 = 384 cubes.",
"hints": ["Volume scales by the cube of the length factor.", "2³ = 8, so multiply 48 by 8."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q1",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 2 Q1. Printed key: 1 big box = 2×2×2 = 8 small boxes; 48×8 = 384 cubes."
},
{
"n": 32,
"type_id": 2,
"question": "The ratio of Amy's present age to Samantha's present age is 4 : 7. 10 years ago, the ratio of Amy's age to Samantha's age was 1 : 3. What is Samantha's present age? [?]",
"answer0": "28",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 214,
"difficulty_id": 3,
"explanation": "Now Amy : Samantha = 4 : 7. 10 years ago both were 10 less, and the ratio was 1 : 3. From the printed working: 5 units = 10 (the equal difference), so 1 unit = 2; 9 units = 18, plus 10 → Samantha now = 18 + 10 = 28.",
"hints": ["Both people age by the same 10 years.", "Match the units before and after to solve."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q2",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 2 Q2. Printed key: 5u=10, 1u=2, 9u=18, 18+10=28."
},
{
"n": 33,
"type_id": 2,
"question": "Ken completed a race in 160 seconds. He was 45 seconds slower than Raju. Hassan was 10 seconds faster than Raju. How long, in minutes and seconds, did Hassan take to complete the race? [?] min [?] s",
"answer0": "1",
"answer1": "45",
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 167,
"difficulty_id": 2,
"explanation": "Raju = 160 − 45 = 115 s. Hassan = 115 − 10 = 105 s = 1 min 45 s.",
"hints": ["Ken is slower, so Raju's time is less than Ken's.", "Convert 105 s to minutes and seconds."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q3",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 2 Q3. Printed key: Raju 115 s, Hassan 105 s = 1 min 45 s. Two blanks: minutes and seconds."
},
{
"n": 34,
"type_id": 2,
"question": "Wendy can make \\((3n + 4)\\) muffins in one day. Katelyn can make \\(4n\\) more muffins than Wendy in one day. Katelyn and Wendy can make a total of 128 muffins in one day. Find the value of \\(n\\). [?]",
"answer0": "12",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 241,
"difficulty_id": 2,
"explanation": "Katelyn = (3n + 4) + 4n. Total = (3n + 4) + (3n + 4 + 4n) = 10n + 8 = 128 → 10n = 120 → n = 12.",
"hints": ["Write Katelyn's amount in terms of n.", "Add both expressions, set equal to 128."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q4",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 2 Q4. Printed key: 10n+8=128, n=12."
},
{
"n": 35,
"type_id": 2,
"question": "Jane parked her car at a car-park from 12.35 pm to 5.20 pm. The parking rates are: First hour $4.60; Every 30 minutes or part thereof $2.00. How much did she have to pay for parking? [?]",
"answer0": "20.60",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 167,
"difficulty_id": 3,
"explanation": "Total time = 12.35 pm to 5.20 pm = 4 h 45 min. First hour = $4.60. Remaining 3 h 45 min = 225 min = 8 blocks of 30 min (or part) × $2.00 = $16.00. Total = $4.60 + $16.00 = $20.60.",
"hints": ["Work out the total parking duration.", "Charge the first hour, then count 30-min blocks (round up)."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q5",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 2 Q5. Printed key final = $20.60. Answer in dollars."
},
{
"n": 36,
"type_id": 0,
"question": "A trapezium JKLM is drawn on a square grid inside a box. By joining dots on the grid with straight lines, draw a triangle KLP such that its area is half the area of the trapezium JKLM.",
"answer0": null,
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 186,
"difficulty_id": 3,
"explanation": "This is a draw-on-grid task. Choose point P on the grid so that triangle KLP has half the area of trapezium JKLM (the printed key marks point P on the grid between M and L).",
"hints": ["Area of triangle = \\(\\dfrac{1}{2}\\) × base × height.", "Pick P so the triangle's area is half the trapezium's."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q6",
"image_needed": true,
"image_page": 23,
"image_bbox": [0.14, 0.26, 0.74, 0.56],
"image_loc": "square dot-grid with trapezium JKLM drawn inside a box",
"image_options": false,
"image_file": "q36.png",
"notes": "Paper 2 Q6. Draw-on-grid (interactive) -> type_id 0 (skipped on insert). Printed key shows point P placed on the grid; no single numeric answer."
},
{
"n": 37,
"type_id": 2,
"question": "Kovan Primary School is having a musical. Mrs Teo is in charge of printing invitation cards needed by each group. The bar graph shows the number of cards per group. The printing charges are: First 200 cards $2.00 each; Next 100 cards $1.50 each; Every additional card $0.60 each. How much did Mrs Teo have to pay for the total number of invitation cards printed for the four groups? [?]",
"answer0": "592",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 148,
"difficulty_id": 3,
"explanation": "Cards: Choir 75, Dance Club 115, Art Club 60, Band 120 = 370 in total. First 200 × $2.00 = $400; next 100 × $1.50 = $150; remaining 70 × $0.60 = $42. Total = $400 + $150 + $42 = $592.",
"hints": ["Read all four bars and add them.", "Apply each pricing tier in order."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q7",
"image_needed": true,
"image_page": 24,
"image_bbox": [0.12, 0.08, 0.7, 0.3],
"image_loc": "bar graph of invitation cards per group (Choir, Dance Club, Art Club, Band)",
"image_options": false,
"image_file": "q37.png",
"notes": "Paper 2 Q7. Printed key: total 370 cards, total $592. Answer in dollars."
},
{
"n": 38,
"type_id": 2,
"question": "The ratio of the number of adults to the number of children at a concert was 5 : 3. The price of one adult ticket was $45 while the price of a child ticket was $23. The total amount of money collected from the sale of tickets was $5292. How many adults attended the concert? [?]",
"answer0": "90",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 214,
"difficulty_id": 3,
"explanation": "Take groups of 5 adults and 3 children. Each group earns 5 × $45 + 3 × $23 = $225 + $69 = $294. Number of groups = $5292 ÷ $294 = 18. Adults = 18 × 5 = 90.",
"hints": ["Find the money collected per 5 : 3 group.", "Divide the total by the group value, then × 5."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q8",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 2 Q8. Printed key: $294/group, 18 groups, 90 adults."
},
{
"n": 39,
"type_id": 2,
"question": "Mr Samad spent \\(\\dfrac{1}{6}\\) of his money on 2 shirts and 3 jackets. Each jacket cost twice as much as each shirt. He then spent \\(\\dfrac{2}{5}\\) of his remaining money on a wallet. He spent $23.80 more on the wallet than on the 2 shirts. How much money did Mr Samad have at first? [?]",
"answer0": "81.60",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 165,
"difficulty_id": 3,
"explanation": "Let total = 48p (units chosen so fractions are whole). The \\(\\dfrac{1}{6}\\) on 2 shirts + 3 jackets = 8p; with jacket = 2 × shirt, 2 shirts = 2p. Remaining = 40p; wallet = \\(\\dfrac{2}{5}\\times 40p = 16p\\). Wallet − 2 shirts = 16p − 2p = 14p = $23.80 → 1p = $1.70. Total = 48p = $1.70 × 48 = $81.60.",
"hints": ["Split the \\(\\dfrac{1}{6}\\) into shirt and jacket units (jacket = 2 × shirt).", "Set wallet − 2 shirts = $23.80."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q9",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 2 Q9. Printed key: 14p = $23.80, 1p = $1.70, 48p = $81.60. Answer in dollars."
},
{
"n": 40,
"type_id": 2,
"question": "The bar graph shows the number of pens donated by Class 6K from January to April. The number of pens donated is not shown on the scale.
(a) What was the percentage increase in the number of pens donated from January to February? [?]
(b) The average number of pens donated in a month from January to April was 45. How many pens did Class 6K donate in April? [?]",
"answer0": "50",
"answer1": "54",
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 208,
"difficulty_id": 3,
"explanation": "(a) From the bars, Jan = 8 units, Feb = 12 units. Increase = 4 units; % increase = \\(\\dfrac{4}{8}\\times 100\\% = 50\\%\\). (b) Average 45 over 4 months → total = 45 × 4 = 180. Total units (Jan 8 + Feb 12 + Mar 22 + Apr 18) = 60 units = 180, so 1 unit = 3. April = 18 units = 54.",
"hints": ["Compare the Jan and Feb bar heights in units.", "Total = average × 4; use units to find April."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q10",
"image_needed": true,
"image_page": 27,
"image_bbox": [0.3, 0.1, 0.72, 0.42],
"image_loc": "bar graph of pens donated Jan-Apr (no scale shown)",
"image_options": false,
"image_file": "q40.png",
"notes": "Paper 2 Q10. Printed key: (a) 50%, (b) 54. answer0=% increase, answer1=April pens."
},
{
"n": 41,
"type_id": 2,
"question": "ABCD is a square and PQSD is a parallelogram. RSC and SDC are isosceles triangles. RS = RC and SC = SD. \\(\\angle SRC = 82°\\).
(a) Find \\(\\angle QSD\\). [?]
(b) Find \\(\\angle AQP\\). [?]",
"answer0": "131",
"answer1": "41",
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 230,
"difficulty_id": 3,
"explanation": "(a) In isosceles triangle RSC, \\(\\angle RCS = \\dfrac{180° - 82°}{2} = 49°\\). \\(\\angle SCD = 90° - 49° = 41°\\); since SC = SD, \\(\\angle SDC = 41°\\), so \\(\\angle PDS = 90° - 41° = 49°\\). In parallelogram PQSD, \\(\\angle QSD = 180° - 49° = 131°\\). (b) \\(\\angle DPQ = 131°\\) (co-interior), so \\(\\angle APQ = 180° - 131° = 49°\\); then \\(\\angle AQP = 180° - 90° - 49° = 41°\\).",
"hints": ["Use the isosceles triangle to find \\(\\angle RCS\\) first.", "Apply square (90°) and parallelogram angle properties."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q11",
"image_needed": true,
"image_page": 28,
"image_bbox": [0.26, 0.12, 0.66, 0.36],
"image_loc": "square ABCD with parallelogram PQSD and isosceles triangles, angle 82° marked",
"image_options": false,
"image_file": "q41.png",
"notes": "Paper 2 Q11. Printed key: (a) angle QSD = 131°, (b) angle AQP = 41°. answer0=(a), answer1=(b). (Note: paper mislabels the (b) answer-line as 'Ans: (a)'.)"
},
{
"n": 42,
"type_id": 2,
"question": "Rianne had some beads. She gave \\(\\dfrac{2}{9}\\) of her beads to her mother. Her sister then took \\(\\dfrac{1}{5}\\) of her remaining beads and an additional 22 beads. Rianne was then left with 34 beads. How many beads did Rianne have at first? [?]",
"answer0": "90",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 165,
"difficulty_id": 3,
"explanation": "Take total = 45p. Mother got \\(\\dfrac{2}{9}\\) = 10p; remaining = 35p. Sister took \\(\\dfrac{1}{5}\\times 35p = 7p\\) plus 22 beads. Mother + sister = 10p + 7p + 22 = 17p + 22. Left = 45p − 17p − 22 = 28p − 22 = 34 → 28p = 56 → 1p = 2. Total = 45p = 90 beads.",
"hints": ["Choose units so \\(\\dfrac{2}{9}\\) and \\(\\dfrac{1}{5}\\) are whole.", "Set 'beads left' equal to 34 and solve."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q12",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 2 Q12. Printed key: 28p = 56, 1p = 2, total = 90."
},
{
"n": 43,
"type_id": 2,
"question": "The tap was turned on for 40 minutes to fill the empty cubical tank to the brim. Then some water in the tank was poured to fill 180 bottles of 150 cm³ each completely. In the end, there was 5.768 litres of water left in the tank.
(a) What was the side of the cubical tank? [?] cm
(b) How many cm³ of water was flowing out of Tap A in a minute? [?] cm³",
"answer0": "32",
"answer1": "819.2",
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 229,
"difficulty_id": 3,
"explanation": "(a) Water poured into bottles = 180 × 150 = 27 000 cm³. Total water (full tank) = 27 000 + 5.768 L = 27 000 + 5768 = 32 768 cm³. Side = \\(\\sqrt[3]{32768} = 32\\) cm. (b) Tank filled in 40 min, so per minute = 32 768 ÷ 40 = 819.2 cm³.",
"hints": ["Total tank volume = bottle water + water left.", "Cube root gives the side; divide by 40 for the rate."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q13",
"image_needed": true,
"image_page": 30,
"image_bbox": [0.18, 0.1, 0.5, 0.28],
"image_loc": "cubical tank with a tap at the top",
"image_options": false,
"image_file": "q43.png",
"notes": "Paper 2 Q13. Printed key: (a) 32 cm, (b) 819.2 cm³. answer0=(a) side in cm, answer1=(b) rate in cm³."
},
{
"n": 44,
"type_id": 2,
"question": "LGC is a straight line. ABC is an equilateral triangle and DEFG is a square. DJ is parallel to AB. \\(\\angle DGL = 40°\\) and \\(\\angle EJK = 58°\\).
(a) Find \\(\\angle DKE\\). [?]
(b) Find \\(\\angle ACG\\). [?]",
"answer0": "103",
"answer1": "87",
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 230,
"difficulty_id": 3,
"explanation": "(a) \\(\\angle DEG = 45°\\) (diagonal of square). In triangle EKJ, \\(\\angle EKJ = 180° - 45° - 58° = 77°\\). \\(\\angle DKE = 180° - 77° = 103°\\). (b) \\(\\angle AFJ = 58°\\) (DJ ∥ AB), \\(\\angle KAF = 77°\\), \\(\\angle BAC = 60°\\) (equilateral). \\(\\angle CGF = 180° - 40° - 90° = 50°\\); \\(\\angle CAG = 180° - 77° - 60° = 43°\\); \\(\\angle ACG = 180° - 43° - 50° = 87°\\).",
"hints": ["A square's diagonal makes 45°; use triangle angle sums.", "Use the equilateral triangle (60°) and parallel lines."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q14",
"image_needed": true,
"image_page": 31,
"image_bbox": [0.14, 0.1, 0.66, 0.42],
"image_loc": "composite figure with equilateral triangle ABC, square DEFG, line LGC, angles 40° and 58°",
"image_options": false,
"image_file": "q44.png",
"notes": "Paper 2 Q14. Printed key: (a) angle DKE = 103°, (b) angle ACG = 87°. answer0=(a), answer1=(b)."
},
{
"n": 45,
"type_id": 2,
"question": "Matthew had $72 more than Cayden. Matthew spent 90% of his money and Cayden spent 40% of his. In the end, Cayden has twice as much money as Matthew. How much money did Matthew have at first? [?]",
"answer0": "108",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 209,
"difficulty_id": 3,
"explanation": "Matthew kept 10% of his money; Cayden kept 60% of his. Cayden's leftover = 2 × Matthew's leftover. Matthew = Cayden + $72, so Matthew's 10% = 10% of (Cayden + 72). Working through (printed key): 40% of Cayden's money = $14.40, so 1% = $0.36 and 100% = $36 (Cayden at first). Matthew = $36 + $72 = $108.",
"hints": ["Matthew keeps 10%, Cayden keeps 60%.", "Set Cayden's leftover = 2 × Matthew's leftover, with Matthew = Cayden + 72."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q15",
"image_needed": false,
"image_options": false,
"image_file": null,
"notes": "Paper 2 Q15. Printed key: Matthew = $108. Answer in dollars."
},
{
"n": 46,
"type_id": 2,
"question": "The pattern is made up of shaded and unshaded squares. The table shows the number of shaded squares, unshaded squares and total squares for each figure.
(a) Indicate the number of unshaded squares and the total number of squares for Figure 10. [?] unshaded, [?] total
(b) Find the total number of squares in Figure 22. [?]
(c) What Figure Number has 79 unshaded squares? [?]",
"answer0": "21",
"answer1": "31",
"answer2": "67",
"answer3": "39",
"correct_answer": null,
"skill_id": 240,
"difficulty_id": 3,
"explanation": "Pattern: shaded = figure number n; unshaded = 2n + 1; total = 3n + 1. (a) Figure 10: unshaded = 2(10)+1 = 21; total = 3(10)+1 = 31. (b) Figure 22 total = 3(22)+1 = 67. (c) 2n + 1 = 79 → n = 39.",
"hints": ["Look for the rule: unshaded = 2n + 1, total = 3n + 1.", "For (c), solve 2n + 1 = 79."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q16",
"image_needed": true,
"image_page": 33,
"image_bbox": [0.1, 0.08, 0.78, 0.24],
"image_loc": "Figures 1-3 of shaded/unshaded square pattern",
"image_options": false,
"image_file": "q46.png",
"notes": "Paper 2 Q16. Printed key: (a) 21, 31; (b) 67; (c) 39. Four blanks in order: answer0=Fig10 unshaded, answer1=Fig10 total, answer2=Fig22 total, answer3=figure with 79 unshaded."
},
{
"n": 47,
"type_id": 2,
"question": "The figure is made up of 4 identical circles of diameter 30 cm inside a larger circle with a diameter of 72 cm. Find the total area of all the shaded parts. (Take \\(\\pi = 3.14\\)) [?] cm²",
"answer0": "980.955",
"answer1": null,
"answer2": null,
"answer3": null,
"correct_answer": null,
"skill_id": 222,
"difficulty_id": 3,
"explanation": "Big circle area = 3.14 × 36² = 4069.44 cm². Four small circles (radius 15) = 4 × 3.14 × 15² = 2826 cm². Difference = 1243.44 cm². The central shaded 'star' = 30 × 30 − 3.14 × 15² = 900 − 706.5 = 193.5 cm². Area A+B (the four corner gaps) = (1243.44 − 193.5) ÷ 4 = 262.485 cm² each. Total shaded = star + 3 × (A+B) = 193.5 + 3 × 262.485 = 980.955 cm².",
"hints": ["Find the big circle minus four small circles.", "Add the central star area to three corner-gap regions."],
"source": "Rosyth 2024 P6 Term Assessment 2 P2 Q17",
"image_needed": true,
"image_page": 34,
"image_bbox": [0.24, 0.13, 0.62, 0.42],
"image_loc": "four small circles inside a large circle, shaded gaps",
"image_options": false,
"image_file": "q47.png",
"notes": "Paper 2 Q17. Printed key (using π = 3.14): shaded = 980.955 cm². Note: the question prints both 22/7 and 3.14 for π; the worked key uses 3.14."
}
]
}