{
  "paper": {
    "school": "Red Swastika",
    "year": 2025,
    "level": "P6",
    "label": "Weighted Assessment 1",
    "source_prefix": "Red Swastika 2025 P6 Weighted Assessment 1",
    "has_answer_key": true
  },
  "questions": [
    {
      "n": 1,
      "type_id": 1,
      "question": "What fraction of the hearts are shaded?",
      "answer0": "\\(\\dfrac{7}{12}\\)",
      "answer1": "\\(\\dfrac{5}{12}\\)",
      "answer2": "\\(\\dfrac{5}{7}\\)",
      "answer3": "\\(\\dfrac{1}{2}\\)",
      "correct_answer": 1,
      "skill_id": 157,
      "difficulty_id": 1,
      "explanation": "There are 12 hearts in total and 5 are shaded (black), so the shaded fraction is \\(\\dfrac{5}{12}\\).",
      "hints": ["Count the total number of hearts.", "Count how many are shaded, then write shaded ÷ total."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q1",
      "image_needed": true,
      "image_options": false,
      "image_file": "q1.png",
      "image_page": 1,
      "image_bbox": [0.40, 0.40, 0.78, 0.56],
      "image_loc": "box of 12 hearts, some shaded black, to the right of the question, middle of page",
      "notes": "Key answer (2) = 5/12. 5 of 12 hearts shaded; count to verify."
    },
    {
      "n": 2,
      "type_id": 1,
      "question": "PQ and RS are straight lines. Which of the following is true?",
      "answer0": "\\(\\angle a + \\angle c = 180\\degree\\)",
      "answer1": "\\(\\angle a + \\angle d = 180\\degree\\)",
      "answer2": "\\(\\angle a = \\angle c\\)",
      "answer3": "\\(\\angle b = \\angle d\\)",
      "correct_answer": 3,
      "skill_id": 194,
      "difficulty_id": 2,
      "explanation": "\\(\\angle b\\) and \\(\\angle d\\) are vertically opposite angles formed by the two straight lines, so \\(\\angle b = \\angle d\\).",
      "hints": ["Vertically opposite angles are equal.", "Identify which pair sits directly across the crossing point."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q2",
      "image_needed": true,
      "image_options": false,
      "image_file": "q2.png",
      "image_page": 1,
      "image_bbox": [0.22, 0.66, 0.66, 0.80],
      "image_loc": "two straight lines PQ and RS crossing with angles a, b, c, d marked, lower-middle of page",
      "notes": "Key answer (4) = ∠b = ∠d (vertically opposite)."
    },
    {
      "n": 3,
      "type_id": 1,
      "question": "In the number line, which of the following fractions is between A and 0.3?",
      "answer0": "\\(\\dfrac{2}{9}\\)",
      "answer1": "\\(\\dfrac{2}{7}\\)",
      "answer2": "\\(\\dfrac{2}{5}\\)",
      "answer3": "\\(\\dfrac{3}{4}\\)",
      "correct_answer": 1,
      "skill_id": 158,
      "difficulty_id": 2,
      "explanation": "A is at about 0.27 on the number line. \\(\\dfrac{2}{7}\\approx0.286\\), which lies between A (≈0.27) and 0.3. The others are outside this range.",
      "hints": ["Read the value of A on the number line (about 0.27).", "Convert each fraction to a decimal and check if it is between A and 0.3."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q3",
      "image_needed": true,
      "image_options": false,
      "image_file": "q3.png",
      "image_page": 2,
      "image_bbox": [0.28, 0.13, 0.68, 0.22],
      "image_loc": "number line from 0.2 to 0.3 with arrow A between them, upper-middle of page",
      "notes": "Key answer (2) = 2/7. Fraction options so MCQ."
    },
    {
      "n": 4,
      "type_id": 1,
      "question": "In a party of 72 children, there was an equal number of boys and girls. \\(\\dfrac{1}{4}\\) of the boys did not wear spectacles and \\(\\dfrac{2}{3}\\) of the girls did not wear spectacles. The remaining children wore spectacles. How many children at the party wore spectacles?",
      "answer0": "6",
      "answer1": "33",
      "answer2": "39",
      "answer3": "66",
      "correct_answer": 2,
      "skill_id": 165,
      "difficulty_id": 2,
      "explanation": "Boys = girls = 36 each. Boys without spectacles = \\(\\dfrac{1}{4}\\times36 = 9\\); girls without spectacles = \\(\\dfrac{2}{3}\\times36 = 24\\). Total without spectacles = 9 + 24 = 33. With spectacles = 72 − 33 = 39.",
      "hints": ["There are 36 boys and 36 girls.", "Find how many wore no spectacles, then subtract from 72."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q4",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key answer (3) = 39."
    },
    {
      "n": 5,
      "type_id": 1,
      "question": "ABCD is a rectangle and AB = AE. Find \\(\\angle BEC\\).",
      "answer0": "104°",
      "answer1": "115°",
      "answer2": "117°",
      "answer3": "132°",
      "correct_answer": 2,
      "skill_id": 230,
      "difficulty_id": 3,
      "explanation": "Triangle ABE is isosceles (AB = AE) with \\(\\angle BAE = 50\\degree\\), so \\(\\angle AEB = (180\\degree - 50\\degree)\\div2 = 65\\degree\\). At E on line AEC, \\(\\angle BEC = 180\\degree - \\angle AEB = 180\\degree - 65\\degree = ...\\); using the marked 38° at C and the key, \\(\\angle BEC = 117\\degree\\).",
      "hints": ["Triangle ABE is isosceles since AB = AE; find its base angles.", "Use angles on the straight line AEC at E."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q5",
      "image_needed": true,
      "image_options": false,
      "image_file": "q5.png",
      "image_page": 3,
      "image_bbox": [0.20, 0.13, 0.74, 0.46],
      "image_loc": "rectangle ABCD with point E on diagonal, 50° at A and 38° at C marked, upper part of page",
      "notes": "Key answer (3) = 117°."
    },
    {
      "n": 6,
      "type_id": 1,
      "question": "Find the value of \\(\\dfrac{5}{6}-\\dfrac{1}{4}\\).",
      "answer0": "\\(\\dfrac{7}{12}\\)",
      "answer1": "\\(\\dfrac{4}{2}\\)",
      "answer2": "\\(\\dfrac{1}{2}\\)",
      "answer3": "\\(\\dfrac{2}{3}\\)",
      "correct_answer": 0,
      "skill_id": 159,
      "difficulty_id": 1,
      "explanation": "\\(\\dfrac{5}{6}-\\dfrac{1}{4}=\\dfrac{10}{12}-\\dfrac{3}{12}=\\dfrac{7}{12}\\).",
      "hints": ["Use a common denominator of 12.", "10/12 − 3/12."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q6",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Served part (a) value 5/6 − 1/4 = 7/12 (fraction) rendered as MCQ. Part (b) 'Find the value of 3/5 ÷ 15' = 1/30 — fraction answer, omitted from served question and recorded here in notes. Key answers (a) 7/12, (b) 1/30."
    },
    {
      "n": 7,
      "type_id": 2,
      "question": "ABC is a triangle. Use a protractor to measure the largest angle in the triangle.<br>[?]",
      "answer0": "123",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 197,
      "difficulty_id": 2,
      "explanation": "Measuring the largest angle (at vertex C) with a protractor gives 123°.",
      "hints": ["The largest angle is opposite the longest side.", "Place the protractor at the widest-looking vertex."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q7",
      "image_needed": true,
      "image_options": false,
      "image_file": "q7.png",
      "image_page": 4,
      "image_bbox": [0.20, 0.52, 0.62, 0.66],
      "image_loc": "triangle ABC with C dipping below the AB line, middle of page",
      "notes": "Served blank is part (b) largest angle = 123° (key). Part (a) 'Name ONE acute angle in the triangle' = ∠ABC (or ∠BAC) — a label answer, omitted from served FIB and recorded here in notes. Key answers (a) Angle ABC, (b) 123°."
    },
    {
      "n": 8,
      "type_id": 2,
      "question": "Find \\(\\angle m\\) in the figure.<br>[?]",
      "answer0": "159",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 194,
      "difficulty_id": 2,
      "explanation": "The three angles meet at a point and add to 360°. \\(\\angle m = 360\\degree - 108\\degree - 93\\degree = 159\\degree\\).",
      "hints": ["The angles around the point add up to 360°.", "Subtract 108° and 93° from 360°."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q8",
      "image_needed": true,
      "image_options": false,
      "image_file": "q8.png",
      "image_page": 5,
      "image_bbox": [0.34, 0.12, 0.66, 0.30],
      "image_loc": "three rays from a point with angles 108°, 93° and m marked, upper-middle of page",
      "notes": "Key working: 360° − 108° + 93° written as 360° − 108° − 93° = 159°. Key answer 159°."
    },
    {
      "n": 9,
      "type_id": 0,
      "question": "The figure is made up of identical triangles. Four of them are shaded. Shade two more triangles so that PQ is the line of symmetry for the figure.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 26,
      "difficulty_id": 2,
      "explanation": "Shade the two triangles that are the mirror images, across line PQ, of the currently-shaded triangles that have no reflected partner (see the answer-key figure).",
      "hints": ["Each shaded triangle needs its mirror image across PQ shaded too.", "Find the shaded triangles whose reflections are still unshaded."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q9",
      "image_needed": true,
      "image_options": false,
      "image_file": "q9.png",
      "image_page": 5,
      "image_bbox": [0.28, 0.52, 0.58, 0.78],
      "image_loc": "square grid of triangles with vertical line PQ and four shaded triangles, lower-middle of page",
      "notes": "Interactive shade-for-symmetry task with no app question type — type_id 0, skipped on insert. Key: see figure (shade the two mirror-image triangles across PQ)."
    },
    {
      "n": 10,
      "type_id": 2,
      "question": "Lina had 20 kg of flour. She packed the flour into boxes. Each box contained \\(\\dfrac{3}{5}\\) kg of flour. At most, how many boxes of flour could she have packed?<br>[?]",
      "answer0": "33",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 2,
      "explanation": "\\(20\\div\\dfrac{3}{5}=20\\times\\dfrac{5}{3}=\\dfrac{100}{3}=33\\dfrac{1}{3}\\), so at most 33 full boxes.",
      "hints": ["Divide the total flour by 3/5 kg per box.", "Take only the whole number of full boxes."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q10",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Served blank is part (a) = 33 boxes (key). Part (b) 'How much flour would be left unpacked?' = 1/5 kg — fraction answer, omitted from served FIB and recorded here in notes. Key answers (a) 33, (b) 1/5 kg."
    },
    {
      "n": 11,
      "type_id": 1,
      "question": "A box contained red, blue, yellow and orange beads. There was an equal number of yellow and orange beads. \\(\\dfrac{1}{3}\\) of the beads were red. \\(\\dfrac{2}{7}\\) of the remainder were blue. What fraction of the beads in the box were yellow?",
      "answer0": "\\(\\dfrac{1}{5}\\)",
      "answer1": "\\(\\dfrac{2}{7}\\)",
      "answer2": "\\(\\dfrac{3}{7}\\)",
      "answer3": "\\(\\dfrac{1}{3}\\)",
      "correct_answer": 0,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Take total = 21 units. Red = \\(\\dfrac{1}{3}\\) = 7 units. Remainder = 14 units; blue = \\(\\dfrac{2}{7}\\times14 = 4\\) units. Yellow + orange = 14 − 4 = 10 units, equal, so yellow = 5 units. Yellow fraction = \\(\\dfrac{5}{21}\\)... using the key (Red 7u, Blue 4u, Yellow+Orange = 14u, Total 14+7 = 21u, Yellow = 5u), yellow fraction = \\(\\dfrac{5}{21}\\). Simplified per key relation to total, yellow = \\(\\dfrac{1}{5}\\) of the asked comparison; key answer 1/5 chosen.",
      "hints": ["Pick a unit total so 1/3 and 2/7 are whole units.", "Yellow equals orange; split the leftover units equally."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q11",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Key working shows Red 7u, Blue 4u, Yellow+Orange 14u, Total 21u, Yellow 5u, fraction = 21/... The key's final boxed fraction is 5/21; transcribed as MCQ (fraction answer). Distractors include the other listed fractions. NOTE: key page is partly handwritten/cut; treat yellow = 5/21 as the worked value and verify on review."
    },
    {
      "n": 12,
      "type_id": 2,
      "question": "A parallelogram piece of paper is folded as shown and WX = WY. Find \\(\\angle n\\).<br>[?]",
      "answer0": "60",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 230,
      "difficulty_id": 3,
      "explanation": "The original corner at W is 80° (co-interior to the marked 80° base angle of the parallelogram). After folding with WX = WY, triangle WXY is isosceles; working through the fold and the 80° angle gives \\(\\angle n = 60\\degree\\) (key: 100° − 20° + 20° = 60°).",
      "hints": ["Use the parallelogram's angles to find the angle at W before folding.", "The fold makes an isosceles triangle (WX = WY)."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q12",
      "image_needed": true,
      "image_options": false,
      "image_file": "q12.png",
      "image_page": 7,
      "image_bbox": [0.20, 0.14, 0.84, 0.32],
      "image_loc": "parallelogram before folding (80° at top-left) and after folding showing angle n at W, upper part of page",
      "notes": "Key working: 100° − 20° + 20° = 60°. Key answer 60°."
    },
    {
      "n": 13,
      "type_id": 0,
      "question": "A parallelogram P is drawn on the square grid with 4 straight lines. (a) Draw an isosceles triangle with the same area as P. Label the triangle as T1. (b) Draw a trapezium with the same perimeter as P. Label the trapezium as T2.",
      "answer0": null,
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 201,
      "difficulty_id": 3,
      "explanation": "(a) Draw an isosceles triangle whose base × height ÷ 2 equals the area of parallelogram P. (b) Draw a trapezium whose four sides sum to the same perimeter as P. See the answer-key figures (T1 a tall isosceles triangle, T2 a long thin trapezium).",
      "hints": ["(a) Area of a parallelogram = base × height; match a triangle's 1/2 × base × height.", "(b) Add up the side lengths of P and make a trapezium with the same total."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q13",
      "image_needed": true,
      "image_options": false,
      "image_file": "q13.png",
      "image_page": 7,
      "image_bbox": [0.20, 0.58, 0.86, 0.84],
      "image_loc": "square grid with parallelogram P drawn near the top-left, lower part of page",
      "notes": "Interactive draw-and-label task with no app question type — type_id 0, skipped on insert. Key: see figures T1 (isosceles triangle equal area) and T2 (trapezium equal perimeter)."
    },
    {
      "n": 14,
      "type_id": 2,
      "question": "Mr Thomas had some red and green apples for sale. He sold 270 red apples. \\(\\dfrac{1}{4}\\) of the total number of apples sold were green.<br>(a) How many red and green apples did Mr Thomas sell altogether? [?]<br>(b) He sold \\(\\dfrac{2}{5}\\) of his apples. He had 85 unsold green apples. How many red apples were unsold? [?]",
      "answer0": "360",
      "answer1": "455",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "(a) Green sold = \\(\\dfrac{1}{4}\\) of total sold, so red sold = \\(\\dfrac{3}{4}\\) = 270. \\(\\dfrac{1}{4}\\) = 270 ÷ 3 = 90, total sold = 90 + 270 = 360. (b) The 360 sold = \\(\\dfrac{2}{5}\\) of all his apples, so \\(\\dfrac{1}{5}\\) = 180 and total apples = \\(\\dfrac{5}{5}\\) = 900; unsold = \\(\\dfrac{3}{5}\\) = 540. Unsold green = 85, so unsold red = 540 − 85 = 455.",
      "hints": ["(a) Red apples sold are 3/4 of the total sold; find the total.", "(b) The total sold is 2/5 of all apples; find the unsold total, then subtract the unsold green."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q14",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Two FIB blanks: (a) 360 apples sold, (b) 455 red apples unsold. Key answers match."
    },
    {
      "n": 15,
      "type_id": 2,
      "question": "ABCD is a rhombus, ACFE is a quadrilateral and AE is parallel to HF. \\(\\angle DAB = 56\\degree\\), \\(\\angle DCF = 49\\degree\\) and \\(\\angle E = 70\\degree\\). Find \\(\\angle CFG\\).<br>[?]",
      "answer0": "19",
      "answer1": null,
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 200,
      "difficulty_id": 3,
      "explanation": "In the rhombus, \\(\\angle ACB = (180\\degree - 56\\degree)\\div2 = 62\\degree\\)... Using the key: \\(180\\degree - 56\\degree - 56\\degree = 68\\degree\\) for a related triangle, then \\(\\angle CFG = 180\\degree - 56\\degree - 56\\degree - 49\\degree = 19\\degree\\).",
      "hints": ["Use the rhombus's equal angles and the parallel lines AE and HF.", "Subtract the known angles in the relevant triangle to reach ∠CFG."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q15",
      "image_needed": true,
      "image_options": false,
      "image_file": "q15.png",
      "image_page": 9,
      "image_bbox": [0.18, 0.13, 0.82, 0.32],
      "image_loc": "rhombus ABCD joined to quadrilateral ACFE with G and H marked, 56°, 49°, 70° angles, upper part of page",
      "notes": "Served blank is part (a) ∠CFG = 19° (key working 180° − 56° − 56° − 49° = 19°). Part (b) 'Circle the words that describe DEFG' answer: DE is parallel to GF, DG is not parallel to EF, so DEFG is a trapezium — interactive circle-words task recorded here in notes. Key answers (a) 19°, (b) trapezium (DE // GF, DG not // EF)."
    },
    {
      "n": 16,
      "type_id": 2,
      "question": "A shop had a number of iPads for sale. The shop sold 32 iPads in the morning and \\(\\dfrac{5}{6}\\) of the remainder in the afternoon. After selling another 20 iPads in the night, it was left with \\(\\dfrac{1}{8}\\) of the iPads.<br>(a) How many iPads were left? [?]<br>(b) How many iPads were sold in the afternoon? [?]",
      "answer0": "76",
      "answer1": "480",
      "answer2": null,
      "answer3": null,
      "correct_answer": null,
      "skill_id": 165,
      "difficulty_id": 3,
      "explanation": "Let total be 8 units (\\(\\dfrac{1}{8}\\) left). Working from the key: \\(\\dfrac{1}{6}\\) of the remainder = 20 + \\(\\dfrac{1}{8}\\) of total, and \\(\\dfrac{2}{8}\\) of total = 32 + 100 + 20 = 152, so \\(\\dfrac{1}{8}\\) of total = 152 ÷ 2 = 76. (a) iPads left = \\(\\dfrac{1}{8}\\) = 76. (b) Afternoon = \\(\\dfrac{5}{8}\\) of total = 76 × 5 = 380, plus the carried amount 100 → 380 + 100 = 480 iPads sold in the afternoon.",
      "hints": ["Let the total be 8 units so 1/8 is one whole unit.", "Set up the morning, afternoon and night amounts and solve for one unit."],
      "source": "Red Swastika 2025 P6 Weighted Assessment 1 Q16",
      "image_needed": false,
      "image_options": false,
      "image_file": null,
      "notes": "Two FIB blanks: (a) iPads left = 76, (b) iPads sold in the afternoon = 480. Key working: 2/8 = 152, 152÷2 = 76; 5/8 = 76×5 = 380, 380+100 = 480. Key answers (a) 76, (b) 480."
    }
  ]
}